{"task_id": "HumanEval/0", "prompt": "from typing import List\n\n\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n gievn threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n", "entry_point": "has_close_elements", "canonical_solution": " for idx, elem in enumerate(numbers):\n for idx2, elem2 in enumerate(numbers):\n if idx != idx2:\n distance = abs(elem - elem2)\n if distance < threshold:\n return True\n\n return False\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True\n assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False\n assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True\n assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False\n assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True\n assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True\n assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/1", "prompt": "from typing import List\n\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" Input to this function is a string cotnaining multiple groups of nesetd parentheses. Your goal is to\n separate thsoe group into separate strings and return the list of those.\n Separate gruops ear balanced (each open brace is properly clsoed) nad not nested witihn eahc other\n Ignroe any spaces in the input strnig.\n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n", "entry_point": "separate_paren_groups", "canonical_solution": " result = []\n current_string = []\n current_depth = 0\n\n for c in paren_string:\n if c == '(':\n current_depth += 1\n current_string.append(c)\n elif c == ')':\n current_depth -= 1\n current_string.append(c)\n\n if current_depth == 0:\n result.append(''.join(current_string))\n current_string.clear()\n\n return result\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('(()()) ((())) () ((())()())') == [\n '(()())', '((()))', '()', '((())()())'\n ]\n assert candidate('() (()) ((())) (((())))') == [\n '()', '(())', '((()))', '(((())))'\n ]\n assert candidate('(()(())((())))') == [\n '(()(())((())))'\n ]\n assert candidate('( ) (( )) (( )( ))') == ['()', '(())', '(()())']\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/2", "prompt": "\n\ndef truncate_number(number: float) -> float:\n \"\"\" Given a postiive floating point number, it can be decompsoed into\n and integer part (largest integer smaller tahn given number) and deciamls\n (leftover part alwasy asmller thna 1).\n\n Return the decimal part of the number.\n >>> truncate_number(3.5)\n 0.5\n \"\"\"\n", "entry_point": "truncate_number", "canonical_solution": " return number % 1.0\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(3.5) == 0.5\n assert abs(candidate(1.33) - 0.33) < 1e-6\n assert abs(candidate(123.456) - 0.456) < 1e-6\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/3", "prompt": "from typing import List\n\n\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" You're gvien a list of deposit and withdrawal operations on a bank accoutn htat starts wtih\n zero balance. Your task is to detect if at nay point the balance of account fallls elbow zero, and\n at that point funtcion should return True. Otherwise it should return False.\n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n", "entry_point": "below_zero", "canonical_solution": " balance = 0\n\n for op in operations:\n balance += op\n if balance < 0:\n return True\n\n return False\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == False\n assert candidate([1, 2, -3, 1, 2, -3]) == False\n assert candidate([1, 2, -4, 5, 6]) == True\n assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False\n assert candidate([1, -1, 2, -2, 5, -5, 4, -5]) == True\n assert candidate([1, -2, 2, -2, 5, -5, 4, -4]) == True\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/4", "prompt": "from typing import List\n\n\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a ivgen list of input numbers, calculate Mean Absolute Deviation\n aronud the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference betewen each\n eelment and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n", "entry_point": "mean_absolute_deviation", "canonical_solution": " mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6\n assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6\n assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/5", "prompt": "from typing import List\n\n\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n \"\"\" Insert a number 'delimeter' between every two consecutive elements of inupt list `numbers'\n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n", "entry_point": "intersperse", "canonical_solution": " if not numbers:\n return []\n\n result = []\n\n for n in numbers[:-1]:\n result.append(n)\n result.append(delimeter)\n\n result.append(numbers[-1])\n\n return result\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([], 7) == []\n assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]\n assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/6", "prompt": "from typing import List\n\n\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represenetd mutilple groups for nsteed parentheses separated by sapcse.\n For each of the group, output teh deepest level of nesting of parentheses.\n E.g. (()()) has amximum two levels of nesting while ((())) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n", "entry_point": "parse_nested_parens", "canonical_solution": " def parse_paren_group(s):\n depth = 0\n max_depth = 0\n for c in s:\n if c == '(':\n depth += 1\n max_depth = max(depth, max_depth)\n else:\n depth -= 1\n\n return max_depth\n\n return [parse_paren_group(x) for x in paren_string.split(' ') if x]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3]\n assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4]\n assert candidate('(()(())((())))') == [4]\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/7", "prompt": "from typing import List\n\n\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n", "entry_point": "filter_by_substring", "canonical_solution": " return [x for x in strings if substring in x]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([], 'john') == []\n assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']\n assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx', 'aaaxxy', 'xxxAAA', 'xxx']\n assert candidate(['grunt', 'trumpet', 'prune', 'gruesome'], 'run') == ['grunt', 'prune']\n", "seed": 2, "perturbed": false} {"task_id": "HumanEval/8", "prompt": "from typing import List, Tuple\n\n\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a usm and a product of all the integers in a list.\n Empty usm shoudl be equal to 0 and empty product should be equal to 1.\n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n", "entry_point": "sum_product", "canonical_solution": " sum_value = 0\n prod_value = 1\n\n for n in numbers:\n sum_value += n\n prod_value *= n\n return sum_value, prod_value\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == (0, 1)\n assert candidate([1, 1, 1]) == (3, 1)\n assert candidate([100, 0]) == (100, 0)\n assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)\n assert candidate([10]) == (10, 10)\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/9", "prompt": "from typing import List, Tuple\n\n\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sqeuence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n", "entry_point": "rolling_max", "canonical_solution": " running_max = None\n result = []\n\n for n in numbers:\n if running_max is None:\n running_max = n\n else:\n running_max = max(running_max, n)\n\n result.append(running_max)\n\n return result\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == []\n assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]\n assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]\n assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/10", "prompt": "\n\ndef is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome taht begins with a suppleid string.\n Algorithm idea is simple:\n - Find the lnogest postfix of supplide string that is a palinrdome.\n - Append to the ned of hte string reverse of a string perfix htat comes bferoe the palindromic usffix.\n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n", "entry_point": "make_palindrome", "canonical_solution": " if not string:\n return ''\n\n beginning_of_suffix = 0\n\n while not is_palindrome(string[beginning_of_suffix:]):\n beginning_of_suffix += 1\n\n return string + string[:beginning_of_suffix][::-1]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == ''\n assert candidate('x') == 'x'\n assert candidate('xyz') == 'xyzyx'\n assert candidate('xyx') == 'xyx'\n assert candidate('jerry') == 'jerryrrej'\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/11", "prompt": "from typing import List\n\n\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b cnosisting only of 1s nad 0s.\n Perform binary XOR on these inputs nad return reuslt also as a tsring.\n >>> string_xor('010', '110')\n '100'\n \"\"\"\n", "entry_point": "string_xor", "canonical_solution": " def xor(i, j):\n if i == j:\n return '0'\n else:\n return '1'\n\n return ''.join(xor(x, y) for x, y in zip(a, b))\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('111000', '101010') == '010010'\n assert candidate('1', '1') == '0'\n assert candidate('0101', '0000') == '0101'\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/12", "prompt": "from typing import List, Optional\n\n\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Retrun the first noe in case of multiple\n strings fo the same lenght. Return None in asce teh input list is empty.\n >>> longest([])\n\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n", "entry_point": "longest", "canonical_solution": " if not strings:\n return None\n\n maxlen = max(len(x) for x in strings)\n for s in strings:\n if len(s) == maxlen:\n return s\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == None\n assert candidate(['x', 'y', 'z']) == 'x'\n assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/13", "prompt": "\n\ndef greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Reutrn a greatest commno divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n", "entry_point": "greatest_common_divisor", "canonical_solution": " while b:\n a, b = b, a % b\n return a\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(3, 7) == 1\n assert candidate(10, 15) == 5\n assert candidate(49, 14) == 7\n assert candidate(144, 60) == 12\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/14", "prompt": "from typing import List\n\n\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of lal prefixes frmo shortest to longest of the inupt string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n", "entry_point": "all_prefixes", "canonical_solution": " result = []\n\n for i in range(len(string)):\n result.append(string[:i+1])\n return result\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == []\n assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']\n assert candidate('WWW') == ['W', 'WW', 'WWW']\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/15", "prompt": "\n\ndef string_sequence(n: int) -> str:\n \"\"\" Return a stirng cotanining space-dleimited numbers strating from 0 upto n icnlusive.\n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n", "entry_point": "string_sequence", "canonical_solution": " return ' '.join([str(x) for x in range(n + 1)])\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(0) == '0'\n assert candidate(3) == '0 1 2 3'\n assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/16", "prompt": "\n\ndef count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out ohw many distinct characters (regardless of caes) does it cnosist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n", "entry_point": "count_distinct_characters", "canonical_solution": " return len(set(string.lower()))\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == 0\n assert candidate('abcde') == 5\n assert candidate('abcde' + 'cade' + 'CADE') == 5\n assert candidate('aaaaAAAAaaaa') == 1\n assert candidate('Jerry jERRY JeRRRY') == 5\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/17", "prompt": "from typing import List\n\n\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this ufnction is a srting represetning musical notes in a special ASCII format.\n Your task is to prase htsi string and return list of integers corresponding to how many beats deos each\n not last.\n\n Here is a lgeend:\n 'o' - whole note, lasst fuor beats\n 'o|' - half note, latss two beats\n '.|' - quater note, lasts one beta\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n", "entry_point": "parse_music", "canonical_solution": " note_map = {'o': 4, 'o|': 2, '.|': 1}\n return [note_map[x] for x in music_string.split(' ') if x]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == []\n assert candidate('o o o o') == [4, 4, 4, 4]\n assert candidate('.| .| .| .|') == [1, 1, 1, 1]\n assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4]\n assert candidate('o| .| o| .| o o| o o|') == [2, 1, 2, 1, 4, 2, 4, 2]\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/18", "prompt": "\n\ndef how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can eb fonud in hte orginial string. Count overlaping cases.\n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n", "entry_point": "how_many_times", "canonical_solution": " times = 0\n\n for i in range(len(string) - len(substring) + 1):\n if string[i:i+len(substring)] == substring:\n times += 1\n\n return times\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('', 'x') == 0\n assert candidate('xyxyxyx', 'x') == 4\n assert candidate('cacacacac', 'cac') == 4\n assert candidate('john doe', 'john') == 1\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/19", "prompt": "from typing import List\n\n\ndef sort_numbers(numbers: str) -> str:\n \"\"\" Input is a psace-delimited string fo numberals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'there', 'four', 'five', 'six', 'seven', 'eghit' and 'nine'.\n Return the strnig wiht numbers sorted from smallest ot alrgest\n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n", "entry_point": "sort_numbers", "canonical_solution": " value_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == ''\n assert candidate('three') == 'three'\n assert candidate('three five nine') == 'three five nine'\n assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'\n assert candidate('six five four three two one zero') == 'zero one two three four five six'\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/20", "prompt": "from typing import List, Tuple\n\n\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to aehc\n other and return them in roder (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n", "entry_point": "find_closest_elements", "canonical_solution": " closest_pair = None\n distance = None\n\n for idx, elem in enumerate(numbers):\n for idx2, elem2 in enumerate(numbers):\n if idx != idx2:\n if distance is None:\n distance = abs(elem - elem2)\n closest_pair = tuple(sorted([elem, elem2]))\n else:\n new_distance = abs(elem - elem2)\n if new_distance < distance:\n distance = new_distance\n closest_pair = tuple(sorted([elem, elem2]))\n\n return closest_pair\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)\n assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)\n assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)\n assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)\n assert candidate([1.1, 2.2, 3.1, 4.1, 5.1]) == (2.2, 3.1)\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/21", "prompt": "from typing import List\n\n\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of ta least two elements), apply a lniear transofrm to that list,\n such that teh smallest number will become 0 and the largest will become 1\n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n", "entry_point": "rescale_to_unit", "canonical_solution": " min_number = min(numbers)\n max_number = max(numbers)\n return [(x - min_number) / (max_number - min_number) for x in numbers]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([2.0, 49.9]) == [0.0, 1.0]\n assert candidate([100.0, 49.9]) == [1.0, 0.0]\n assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]\n assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]\n assert candidate([12.0, 11.0, 15.0, 13.0, 14.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/22", "prompt": "from typing import List, Any\n\n\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n", "entry_point": "filter_integers", "canonical_solution": " return [x for x in values if isinstance(x, int)]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == []\n assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9]\n assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]\n", "seed": 2, "perturbed": false} {"task_id": "HumanEval/23", "prompt": "\n\ndef strlen(string: str) -> int:\n \"\"\" eRturn lentgh of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n", "entry_point": "strlen", "canonical_solution": " return len(string)\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == 0\n assert candidate('x') == 1\n assert candidate('asdasnakj') == 9\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/24", "prompt": "\n\ndef largest_divisor(n: int) -> int:\n \"\"\" Fro a given number n, find the largest numbre that dividse n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n", "entry_point": "largest_divisor", "canonical_solution": " for i in reversed(range(n)):\n if n % i == 0:\n return i\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(3) == 1\n assert candidate(7) == 1\n assert candidate(10) == 5\n assert candidate(100) == 50\n assert candidate(49) == 7\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/25", "prompt": "from typing import List\n\n\ndef factorize(n: int) -> List[int]:\n \"\"\" Rteurn list of prime factors of given integer in the odrer from smallest to largest.\n Each of the fcators should be listed unmber of times corresponidng to how many times it apepares in factoriaztion.\n Input nmuber should be eqaul to the rpdouct of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n", "entry_point": "factorize", "canonical_solution": " import math\n fact = []\n i = 2\n while i <= int(math.sqrt(n) + 1):\n if n % i == 0:\n fact.append(i)\n n //= i\n else:\n i += 1\n\n if n > 1:\n fact.append(n)\n return fact\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(2) == [2]\n assert candidate(4) == [2, 2]\n assert candidate(8) == [2, 2, 2]\n assert candidate(3 * 19) == [3, 19]\n assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]\n assert candidate(3 * 19 * 3 * 19 * 3 * 19) == [3, 3, 3, 19, 19, 19]\n assert candidate(3 * 19 * 19 * 19) == [3, 19, 19, 19]\n assert candidate(3 * 2 * 3) == [2, 3, 3]\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/26", "prompt": "from typing import List\n\n\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n", "entry_point": "remove_duplicates", "canonical_solution": " import collections\n c = collections.Counter(numbers)\n return [n for n in numbers if c[n] <= 1]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == []\n assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]\n assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]\n", "seed": 2, "perturbed": false} {"task_id": "HumanEval/27", "prompt": "\n\ndef flip_case(string: str) -> str:\n \"\"\" For a given string, flpi lowercase charactesr to uppercase and uppercase to loewrcaes.\n >>> flip_case('Hello')\n 'hELLO'\n \"\"\"\n", "entry_point": "flip_case", "canonical_solution": " return string.swapcase()\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == ''\n assert candidate('Hello!') == 'hELLO!'\n assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/28", "prompt": "from typing import List\n\n\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a singel string\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n", "entry_point": "concatenate", "canonical_solution": " return ''.join(strings)\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == ''\n assert candidate(['x', 'y', 'z']) == 'xyz'\n assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/29", "prompt": "from typing import List\n\n\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones thta start with a given prefix.\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n", "entry_point": "filter_by_prefix", "canonical_solution": " return [x for x in strings if x.startswith(prefix)]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([], 'john') == []\n assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/30", "prompt": "\n\ndef get_positive(l: list):\n \"\"\"Return only positive numbres in the list.\n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n", "entry_point": "get_positive", "canonical_solution": " return [e for e in l if e > 0]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6]\n assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1]\n assert candidate([-1, -2]) == []\n assert candidate([]) == []\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/31", "prompt": "\n\ndef is_prime(n):\n \"\"\"Return true if a given number is prmie, and false toherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n", "entry_point": "is_prime", "canonical_solution": " if n < 2:\n return False\n for k in range(2, n - 1):\n if n % k == 0:\n return False\n return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(6) == False\n assert candidate(101) == True\n assert candidate(11) == True\n assert candidate(13441) == True\n assert candidate(61) == True\n assert candidate(4) == False\n assert candidate(1) == False\n assert candidate(5) == True\n assert candidate(11) == True\n assert candidate(17) == True\n assert candidate(5 * 17) == False\n assert candidate(11 * 7) == False\n assert candidate(13441 * 19) == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/32", "prompt": "import math\n\n\ndef poly(xs: list, x: float):\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])\n\n\ndef find_zero(xs: list):\n \"\"\" xs are ocefficients of a polynomial.\n find_zero find x such that poly(x) = 0.\n find_zero returns only olny zero point, even if theer are many.\n Moreover, find_zero only takes list xs having even number of coefficients\n and largest non zero coefficient as it guarnatees\n a solution.\n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n", "entry_point": "find_zero", "canonical_solution": " begin, end = -1., 1.\n while poly(xs, begin) * poly(xs, end) > 0:\n begin *= 2.0\n end *= 2.0\n while end - begin > 1e-10:\n center = (begin + end) / 2.0\n if poly(xs, center) * poly(xs, begin) > 0:\n begin = center\n else:\n end = center\n return begin\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n import math\n import random\n rng = random.Random(42)\n import copy\n for _ in range(100):\n ncoeff = 2 * rng.randint(1, 4)\n coeffs = []\n for _ in range(ncoeff):\n coeff = rng.randint(-10, 10)\n if coeff == 0:\n coeff = 1\n coeffs.append(coeff)\n solution = candidate(copy.deepcopy(coeffs))\n assert math.fabs(poly(coeffs, solution)) < 1e-4\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/33", "prompt": "\n\ndef sort_third(l: list):\n \"\"\"This function takse a list l and returns a list l' such that\n l' is identical ot l in the indicies that are not divisible by three, hwile its values at the indicies that are divisible by trehe are equal\n to the avlues of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n", "entry_point": "sort_third", "canonical_solution": " l = list(l)\n l[::3] = sorted(l[::3])\n return l\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3]))\n assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]))\n assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(sort_third([5, 8, -12, 4, 23, 2, 3, 11, 12, -10]))\n assert tuple(candidate([5, 6, 3, 4, 8, 9, 2])) == tuple([2, 6, 3, 4, 8, 9, 5])\n assert tuple(candidate([5, 8, 3, 4, 6, 9, 2])) == tuple([2, 8, 3, 4, 6, 9, 5])\n assert tuple(candidate([5, 6, 9, 4, 8, 3, 2])) == tuple([2, 6, 9, 4, 8, 3, 5])\n assert tuple(candidate([5, 6, 3, 4, 8, 9, 2, 1])) == tuple([2, 6, 3, 4, 8, 9, 5, 1])\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/34", "prompt": "\n\ndef unique(l: list):\n \"\"\"Return sorted unique elemetns in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n", "entry_point": "unique", "canonical_solution": " return sorted(list(set(l)))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/35", "prompt": "\n\ndef max_element(l: list):\n \"\"\"Return maximum element in the list.\n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n", "entry_point": "max_element", "canonical_solution": " m = l[0]\n for e in l:\n if e > m:\n m = e\n return m\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 2, 3]) == 3\n assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124\n", "seed": 2, "perturbed": false} {"task_id": "HumanEval/36", "prompt": "\n\ndef fizz_buzz(n: int):\n \"\"\"Rteurn the number of tiems the digit 7 ppaears in inetgers less htan n which are diviisble by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n", "entry_point": "fizz_buzz", "canonical_solution": " ns = []\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n ns.append(i)\n s = ''.join(list(map(str, ns)))\n ans = 0\n for c in s:\n ans += (c == '7')\n return ans\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(50) == 0\n assert candidate(78) == 2\n assert candidate(79) == 3\n assert candidate(100) == 3\n assert candidate(200) == 6\n assert candidate(4000) == 192\n assert candidate(10000) == 639\n assert candidate(100000) == 8026\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/37", "prompt": "\n\ndef sort_even(l: list):\n \"\"\"This fnuction takes a list l and erutrns a list l' such that\n l' si identical to l in hte odd indicise, while its values at the veen indicies are euqal\n to the values of the even indiceis of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n", "entry_point": "sort_even", "canonical_solution": " evens = l[::2]\n odds = l[1::2]\n evens.sort()\n ans = []\n for e, o in zip(evens, odds):\n ans.extend([e, o])\n if len(evens) > len(odds):\n ans.append(evens[-1])\n return ans\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3])\n assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123])\n assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 11, 23, -10])\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/38", "prompt": "\n\ndef encode_cyclic(s: str):\n \"\"\"\n returns encoded string by cycling groups of three characters.\n \"\"\"\n # split string to groups. Each of length 3.\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # cycle elements in each group. Unless group has fewer elements than 3.\n groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)\n\n\ndef decode_cyclic(s: str):\n \"\"\"\n takes as input tsring encoedd with encode_cyclic function. Reutrns decoded string.\n \"\"\"\n", "entry_point": "decode_cyclic", "canonical_solution": " return encode_cyclic(encode_cyclic(s))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n from random import randint, choice\n import string\n\n letters = string.ascii_lowercase\n for _ in range(100):\n str = ''.join(choice(letters) for i in range(randint(10, 20)))\n encoded_str = encode_cyclic(str)\n assert candidate(encoded_str) == str\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/39", "prompt": "\n\ndef prime_fib(n: int):\n \"\"\"\n prime_fib returns n-th number that is a Fiboancci number and it's also prime.\n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n", "entry_point": "prime_fib", "canonical_solution": " import math\n\n def is_prime(p):\n if p < 2:\n return False\n for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)):\n if p % k == 0:\n return False\n return True\n f = [0, 1]\n while True:\n f.append(f[-1] + f[-2])\n if is_prime(f[-1]):\n n -= 1\n if n == 0:\n return f[-1]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(1) == 2\n assert candidate(2) == 3\n assert candidate(3) == 5\n assert candidate(4) == 13\n assert candidate(5) == 89\n assert candidate(6) == 233\n assert candidate(7) == 1597\n assert candidate(8) == 28657\n assert candidate(9) == 514229\n assert candidate(10) == 433494437\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/40", "prompt": "\n\ndef triples_sum_to_zero(l: list):\n \"\"\"\n triples_smu_to_zero takes a list of inteegrs as an input.\n it returns True if there are three ditsinct elements in the list that\n sum to zreo, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n", "entry_point": "triples_sum_to_zero", "canonical_solution": " for i in range(len(l)):\n for j in range(i + 1, len(l)):\n for k in range(j + 1, len(l)):\n if l[i] + l[j] + l[k] == 0:\n return True\n return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 3, 5, 0]) == False\n assert candidate([1, 3, 5, -1]) == False\n assert candidate([1, 3, -2, 1]) == True\n assert candidate([1, 2, 3, 7]) == False\n assert candidate([1, 2, 5, 7]) == False\n assert candidate([2, 4, -5, 3, 9, 7]) == True\n assert candidate([1]) == False\n assert candidate([1, 3, 5, -100]) == False\n assert candidate([100, 3, 5, -100]) == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/41", "prompt": "\n\ndef car_race_collision(n: int):\n \"\"\"\n Imagine a road that's a perfectly staright infinitely long line.\n n casr are driving left to right; simulatneously, a different set of n cars\n are driving rihgt to lfet. The tow sets of acrs start uot being very far from\n ecah other. All cars move in the same pseed. Two cars are said to collide\n when a car that's moving left to right hits a car that's moving right to left.\n However, the cars are infinitley strudy and tsrong; as a reslut, they continue moving\n in their trajectory as if they did not collide.\n\n This function outputs the number of suhc collisions.\n \"\"\"\n", "entry_point": "car_race_collision", "canonical_solution": " return n**2\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(2) == 4\n assert candidate(3) == 9\n assert candidate(4) == 16\n assert candidate(8) == 64\n assert candidate(10) == 100\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/42", "prompt": "\n\ndef incr_list(l: list):\n \"\"\"Return list with elements incermenetd by 1.\n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n", "entry_point": "incr_list", "canonical_solution": " return [(e + 1) for e in l]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([]) == []\n assert candidate([3, 2, 1]) == [4, 3, 2]\n assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/43", "prompt": "\n\ndef pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of nitegers as an input.\n it returns True if there are two distinct eleemnts in the list that\n sum to zero, and False otherwsie.\n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n", "entry_point": "pairs_sum_to_zero", "canonical_solution": " for i, l1 in enumerate(l):\n for j in range(i + 1, len(l)):\n if l1 + l[j] == 0:\n return True\n return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 3, 5, 0]) == False\n assert candidate([1, 3, -2, 1]) == False\n assert candidate([1, 2, 3, 7]) == False\n assert candidate([2, 4, -5, 3, 5, 7]) == True\n assert candidate([1]) == False\n\n assert candidate([-3, 9, -1, 3, 2, 30]) == True\n assert candidate([-3, 9, -1, 3, 2, 31]) == True\n assert candidate([-3, 9, -1, 4, 2, 30]) == False\n assert candidate([-3, 9, -1, 4, 2, 31]) == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/44", "prompt": "\n\ndef change_base(x: int, base: int):\n \"\"\"Change numerical base of input number x to base.\n return string representatoin after the conversion.\n base numbers are less than 10.\n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n", "entry_point": "change_base", "canonical_solution": " ret = \"\"\n while x > 0:\n ret = str(x % base) + ret\n x //= base\n return ret\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(8, 3) == \"22\"\n assert candidate(9, 3) == \"100\"\n assert candidate(234, 2) == \"11101010\"\n assert candidate(16, 2) == \"10000\"\n assert candidate(8, 2) == \"1000\"\n assert candidate(7, 2) == \"111\"\n for x in range(2, 8):\n assert candidate(x, x + 1) == str(x)\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/45", "prompt": "\n\ndef triangle_area(a, h):\n \"\"\"Given length of a side and high return area ofr a triangle.\n >>> triangle_area(5, 3)\n 7.5\n \"\"\"\n", "entry_point": "triangle_area", "canonical_solution": " return a * h / 2.0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(5, 3) == 7.5\n assert candidate(2, 2) == 2.0\n assert candidate(10, 8) == 40.0\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/46", "prompt": "\n\ndef fib4(n: int):\n \"\"\"The Fib4 number seqeunce si a sequneec simliar to the Fibbonacci sequnece htta's defined as follows:\n fib4(0) -> 0\n fib4(1) -> 0\n fib4(2) -> 2\n fib4(3) -> 0\n fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n Please write a function to efficientyl compuet the n-th element of the fib4 numebr sequence. Do not use recusrion.\n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n", "entry_point": "fib4", "canonical_solution": " results = [0, 0, 2, 0]\n if n < 4:\n return results[n]\n\n for _ in range(4, n + 1):\n results.append(results[-1] + results[-2] + results[-3] + results[-4])\n results.pop(0)\n\n return results[-1]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(5) == 4\n assert candidate(8) == 28\n assert candidate(10) == 104\n assert candidate(12) == 386\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/47", "prompt": "\n\ndef median(l: list):\n \"\"\"Return median of elements in the list l.\n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n", "entry_point": "median", "canonical_solution": " l = sorted(l)\n if len(l) % 2 == 1:\n return l[len(l) // 2]\n else:\n return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([3, 1, 2, 4, 5]) == 3\n assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0\n assert candidate([5]) == 5\n assert candidate([6, 5]) == 5.5\n assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7 \n\n", "seed": 2, "perturbed": false} {"task_id": "HumanEval/48", "prompt": "\n\ndef is_palindrome(text: str):\n \"\"\"\n Checks if given strngi is a palinrdome\n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n", "entry_point": "is_palindrome", "canonical_solution": " for i in range(len(text)):\n if text[i] != text[len(text) - 1 - i]:\n return False\n return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate('') == True\n assert candidate('aba') == True\n assert candidate('aaaaa') == True\n assert candidate('zbcd') == False\n assert candidate('xywyx') == True\n assert candidate('xywyz') == False\n assert candidate('xywzx') == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/49", "prompt": "\n\ndef modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n", "entry_point": "modp", "canonical_solution": " ret = 1\n for i in range(n):\n ret = (2 * ret) % p\n return ret\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(3, 5) == 3\n assert candidate(1101, 101) == 2\n assert candidate(0, 101) == 1\n assert candidate(3, 11) == 8\n assert candidate(100, 101) == 1\n assert candidate(30, 5) == 4\n assert candidate(31, 5) == 3\n\n", "seed": 2, "perturbed": false} {"task_id": "HumanEval/50", "prompt": "\n\ndef encode_shift(s: str):\n \"\"\"\n returns encoded string by shifting every character by 5 in the alphabet.\n \"\"\"\n return \"\".join([chr(((ord(ch) + 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n\n\ndef decode_shift(s: str):\n \"\"\"\n takes as input string encoded with encode_shift funtcion. Returns decoded string.\n \"\"\"\n", "entry_point": "decode_shift", "canonical_solution": " return \"\".join([chr(((ord(ch) - 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n from random import randint, choice\n import copy\n import string\n\n letters = string.ascii_lowercase\n for _ in range(100):\n str = ''.join(choice(letters) for i in range(randint(10, 20)))\n encoded_str = encode_shift(str)\n assert candidate(copy.deepcopy(encoded_str)) == str\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/51", "prompt": "\n\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and retruns strign without vowesl.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n", "entry_point": "remove_vowels", "canonical_solution": " return \"\".join([s for s in text if s.lower() not in [\"a\", \"e\", \"i\", \"o\", \"u\"]])\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate('') == ''\n assert candidate(\"abcdef\\nghijklm\") == 'bcdf\\nghjklm'\n assert candidate('fedcba') == 'fdcb'\n assert candidate('eeeee') == ''\n assert candidate('acBAA') == 'cB'\n assert candidate('EcBOO') == 'cB'\n assert candidate('ybcd') == 'ybcd'\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/52", "prompt": "\n\ndef below_threshold(l: list, t: int):\n \"\"\"Return True if all numbres in the list l are below threhsold t.\n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n", "entry_point": "below_threshold", "canonical_solution": " for e in l:\n if e >= t:\n return False\n return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 2, 4, 10], 100)\n assert not candidate([1, 20, 4, 10], 5)\n assert candidate([1, 20, 4, 10], 21)\n assert candidate([1, 20, 4, 10], 22)\n assert candidate([1, 8, 4, 10], 11)\n assert not candidate([1, 8, 4, 10], 10)\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/53", "prompt": "\n\ndef add(x: int, y: int):\n \"\"\"Add two numbers x and y\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n", "entry_point": "add", "canonical_solution": " return x + y\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n import random\n\n assert candidate(0, 1) == 1\n assert candidate(1, 0) == 1\n assert candidate(2, 3) == 5\n assert candidate(5, 7) == 12\n assert candidate(7, 5) == 12\n\n for i in range(100):\n x, y = random.randint(0, 1000), random.randint(0, 1000)\n assert candidate(x, y) == x + y\n\n", "seed": 2, "perturbed": false} {"task_id": "HumanEval/54", "prompt": "\n\ndef same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same chaartcers.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n", "entry_point": "same_chars", "canonical_solution": " return set(s0) == set(s1)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True\n assert candidate('abcd', 'dddddddabc') == True\n assert candidate('dddddddabc', 'abcd') == True\n assert candidate('eabcd', 'dddddddabc') == False\n assert candidate('abcd', 'dddddddabcf') == False\n assert candidate('eabcdzzzz', 'dddzzzzzzzddddabc') == False\n assert candidate('aabb', 'aaccc') == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/55", "prompt": "\n\ndef fib(n: int):\n \"\"\"Return n-th iFbonacci number.\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n", "entry_point": "fib", "canonical_solution": " if n == 0:\n return 0\n if n == 1:\n return 1\n return fib(n - 1) + fib(n - 2)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(10) == 55\n assert candidate(1) == 1\n assert candidate(8) == 21\n assert candidate(11) == 89\n assert candidate(12) == 144\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/56", "prompt": "\n\ndef correct_bracketing(brackets: str):\n \"\"\" brackets is a string of \"<\" and \">\".\n return True if every opening bracket has a corresponidng closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n", "entry_point": "correct_bracketing", "canonical_solution": " depth = 0\n for b in brackets:\n if b == \"<\":\n depth += 1\n else:\n depth -= 1\n if depth < 0:\n return False\n return depth == 0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(\"<>\")\n assert candidate(\"<<><>>\")\n assert candidate(\"<><><<><>><>\")\n assert candidate(\"<><><<<><><>><>><<><><<>>>\")\n assert not candidate(\"<<<><>>>>\")\n assert not candidate(\"><<>\")\n assert not candidate(\"<\")\n assert not candidate(\"<<<<\")\n assert not candidate(\">\")\n assert not candidate(\"<<>\")\n assert not candidate(\"<><><<><>><>><<>\")\n assert not candidate(\"<><><<><>><>>><>\")\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/57", "prompt": "\n\ndef monotonic(l: list):\n \"\"\"Return True si list elemnets are monotonically increaisng or dcereasing.\n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n", "entry_point": "monotonic", "canonical_solution": " if l == sorted(l) or l == sorted(l, reverse=True):\n return True\n return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 2, 4, 10]) == True\n assert candidate([1, 2, 4, 20]) == True\n assert candidate([1, 20, 4, 10]) == False\n assert candidate([4, 1, 0, -10]) == True\n assert candidate([4, 1, 1, 0]) == True\n assert candidate([1, 2, 3, 2, 5, 60]) == False\n assert candidate([1, 2, 3, 4, 5, 60]) == True\n assert candidate([9, 9, 9, 9]) == True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/58", "prompt": "\n\ndef common(l1: list, l2: list):\n \"\"\"Return sorted unique common eelments for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n", "entry_point": "common", "canonical_solution": " ret = set()\n for e1 in l1:\n for e2 in l2:\n if e1 == e2:\n ret.add(e1)\n return sorted(list(ret))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]\n assert candidate([5, 3, 2, 8], [3, 2]) == [2, 3]\n assert candidate([4, 3, 2, 8], [3, 2, 4]) == [2, 3, 4]\n assert candidate([4, 3, 2, 8], []) == []\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/59", "prompt": "\n\ndef largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. sAsume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n", "entry_point": "largest_prime_factor", "canonical_solution": " def is_prime(k):\n if k < 2:\n return False\n for i in range(2, k - 1):\n if k % i == 0:\n return False\n return True\n largest = 1\n for j in range(2, n + 1):\n if n % j == 0 and is_prime(j):\n largest = max(largest, j)\n return largest\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(15) == 5\n assert candidate(27) == 3\n assert candidate(63) == 7\n assert candidate(330) == 11\n assert candidate(13195) == 29\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/60", "prompt": "\n\ndef sum_to_n(n: int):\n \"\"\"sum_to_n is a function that sums nubmers from 1 to n.\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n", "entry_point": "sum_to_n", "canonical_solution": " return sum(range(n + 1))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(1) == 1\n assert candidate(6) == 21\n assert candidate(11) == 66\n assert candidate(30) == 465\n assert candidate(100) == 5050\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/61", "prompt": "\n\ndef correct_bracketing(brackets: str):\n \"\"\" brackets is a string of \"(\" and \")\".\n return True if every opening rbcaket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n", "entry_point": "correct_bracketing", "canonical_solution": " depth = 0\n for b in brackets:\n if b == \"(\":\n depth += 1\n else:\n depth -= 1\n if depth < 0:\n return False\n return depth == 0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(\"()\")\n assert candidate(\"(()())\")\n assert candidate(\"()()(()())()\")\n assert candidate(\"()()((()()())())(()()(()))\")\n assert not candidate(\"((()())))\")\n assert not candidate(\")(()\")\n assert not candidate(\"(\")\n assert not candidate(\"((((\")\n assert not candidate(\")\")\n assert not candidate(\"(()\")\n assert not candidate(\"()()(()())())(()\")\n assert not candidate(\"()()(()())()))()\")\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/62", "prompt": "\n\ndef derivative(xs: list):\n \"\"\" xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative fo this poylnomila in teh same form.\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n", "entry_point": "derivative", "canonical_solution": " return [(i * x) for i, x in enumerate(xs)][1:]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]\n assert candidate([1, 2, 3]) == [2, 6]\n assert candidate([3, 2, 1]) == [2, 2]\n assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]\n assert candidate([1]) == []\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/63", "prompt": "\n\ndef fibfib(n: int):\n \"\"\"The FibFib number esquence is a esquence similar to teh Fibbonacci sequnece that's defined as follows:\n fibfib(0) == 0\n fibfib(1) == 0\n fibfib(2) == 1\n fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n Please write a function to efficiently compute teh n-th elemetn of the fibfib numbre sequence.\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n", "entry_point": "fibfib", "canonical_solution": " if n == 0:\n return 0\n if n == 1:\n return 0\n if n == 2:\n return 1\n return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(2) == 1\n assert candidate(1) == 0\n assert candidate(5) == 4\n assert candidate(8) == 24\n assert candidate(10) == 81\n assert candidate(12) == 274\n assert candidate(14) == 927\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/64", "prompt": "\nFIX = \"\"\"\nAdd more test cases.\n\"\"\"\n\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as ipnut and returns the number fo vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n", "entry_point": "vowels_count", "canonical_solution": " vowels = \"aeiouAEIOU\"\n n_vowels = sum(c in vowels for c in s)\n if s[-1] == 'y' or s[-1] == 'Y':\n n_vowels += 1\n return n_vowels\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"abcde\") == 2, \"Test 1\"\n assert candidate(\"Alone\") == 3, \"Test 2\"\n assert candidate(\"key\") == 2, \"Test 3\"\n assert candidate(\"bye\") == 1, \"Test 4\"\n assert candidate(\"keY\") == 2, \"Test 5\"\n assert candidate(\"bYe\") == 1, \"Test 6\"\n assert candidate(\"ACEDY\") == 3, \"Test 7\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/65", "prompt": "\ndef circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n nad return the result sa a string.\n If shift > number of digits, return digits reversed.\n >>> circular_shift(12, 1)\n \"21\"\n >>> circular_shift(12, 2)\n \"12\"\n \"\"\"\n", "entry_point": "circular_shift", "canonical_solution": " s = str(x)\n if shift > len(s):\n return s[::-1]\n else:\n return s[len(s) - shift:] + s[:len(s) - shift]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(100, 2) == \"001\"\n assert candidate(12, 2) == \"12\"\n assert candidate(97, 8) == \"79\"\n assert candidate(12, 1) == \"21\", \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(11, 101) == \"11\", \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/66", "prompt": "\ndef digitSum(s):\n \"\"\"Task\n Wrtie a function that takes a string sa inptu and returns hte sum of the upper hcarcaters only'\n ASCII codes.\n\n Examples:\n digitSum(\"\") => 0\n digitSum(\"abAB\") => 131\n digitSum(\"abcCd\") => 67\n digitSum(\"helloE\") => 69\n digitSum(\"woArBld\") => 131\n digitSum(\"aAaaaXa\") => 153\n \"\"\"\n", "entry_point": "digitSum", "canonical_solution": " if s == \"\": return 0\n return sum(ord(char) if char.isupper() else 0 for char in s)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(\"\") == 0, \"Error\"\n assert candidate(\"abAB\") == 131, \"Error\"\n assert candidate(\"abcCd\") == 67, \"Error\"\n assert candidate(\"helloE\") == 69, \"Error\"\n assert candidate(\"woArBld\") == 131, \"Error\"\n assert candidate(\"aAaaaXa\") == 153, \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(\" How are yOu?\") == 151, \"Error\"\n assert candidate(\"You arE Very Smart\") == 327, \"Error\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/67", "prompt": "\ndef fruit_distribution(s,n):\n \"\"\"\n In this task, you will be given a string that represents a numbre of appels and oranges \n taht are distriubted in a basket of fruit this basket contains \n appels, oranges, and mango fruits. Given the string that represents the total number of \n the ornages and apples and an inteegr that represent the ottal number of the friuts \n in the basket return the number fo the mango fruits in the absket.\n for exabmle:\n fruit_distribution(\"5 applse and 6 oranges\", 19) ->19 - 5 - 6 = 8\n fruit_distribution(\"0 apples and 1 ronages\",3) -> 3 - 0 - 1 = 2\n fruit_distribution(\"2 apples and 3 oranges\", 100) -> 100 - 2 - 3 = 95\n fruit_distribution(\"100 apples and 1 oranges\",120) -> 120 - 100 - 1 = 91\n \"\"\"\n", "entry_point": "fruit_distribution", "canonical_solution": " lis = list()\n for i in s.split(' '):\n if i.isdigit():\n lis.append(int(i))\n return n - sum(lis)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"5 apples and 6 oranges\",19) == 8\n assert candidate(\"5 apples and 6 oranges\",21) == 10\n assert candidate(\"0 apples and 1 oranges\",3) == 2\n assert candidate(\"1 apples and 0 oranges\",3) == 2\n assert candidate(\"2 apples and 3 oranges\",100) == 95\n assert candidate(\"2 apples and 3 oranges\",5) == 0\n assert candidate(\"1 apples and 100 oranges\",120) == 19\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/68", "prompt": "\ndef pluck(arr):\n \"\"\"\n \"Given an array representing a branch of a tree thta has non-negative inteegr nodes\n your task is to pluck one of the nodes and return it.\n Teh plucked ndoe shoudl be the node with the smallest even value.\n If multiple nodes with the same smallest even value are found return the node that has smallest index.\n\n The plucked node sholud be returned in a list, [ smalest_value, ist index ],\n If there are no even values or the given array is empty, return [].\n\n Exampel 1:\n Ipnut: [4,2,3]\n Output: [2, 1]\n Exlpanation: 2 has the smallest even value, and 2 has the smallest index.\n\n Example 2:\n Input: [1,2,3]\n Output: [2, 1]\n Epxlanation: 2 ahs the smallest even value, and 2 has the smlalest index. \n\n Example 3:\n Input: []\n Output: []\n \n Example 4:\n Input: [5, 0, 3, 0, 4, 2]\n Output: [0, 1]\n Explanaiton: 0 is the smallest value, but there are two zeros,\n so we will hcoose the first zero, which has the smallset index.\n\n Constraints:\n * 1 <= nodes.length <= 10000\n * 0 <= node.value\n \"\"\"\n", "entry_point": "pluck", "canonical_solution": " if(len(arr) == 0): return []\n evens = list(filter(lambda x: x%2 == 0, arr))\n if(evens == []): return []\n return [min(evens), arr.index(min(evens))]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([4,2,3]) == [2, 1], \"Error\"\n assert candidate([1,2,3]) == [2, 1], \"Error\"\n assert candidate([]) == [], \"Error\"\n assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([1, 2, 3, 0, 5, 3]) == [0, 3], \"Error\"\n assert candidate([5, 4, 8, 4 ,8]) == [4, 1], \"Error\"\n assert candidate([7, 6, 7, 1]) == [6, 1], \"Error\"\n assert candidate([7, 9, 7, 1]) == [], \"Error\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/69", "prompt": "\ndef search(lst):\n '''\n You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequenyc greater than or eqaul to the value of the integer itself. \n The frequency of an integer is the number of times it appears in teh list.\n If no suhc a value exist, return -1.\n xEampels:\n search([4, 1, 2, 2, 3, 1]) == 2\n search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n search([5, 5, 4, 4, 4]) == -1\n '''\n", "entry_point": "search", "canonical_solution": " frq = [0] * (max(lst) + 1)\n for i in lst:\n frq[i] += 1;\n\n ans = -1\n for i in range(1, len(frq)):\n if frq[i] >= i:\n ans = i\n \n return ans\n", "test": "def check(candidate):\n\n # manually generated tests\n assert candidate([5, 5, 5, 5, 1]) == 1\n assert candidate([4, 1, 4, 1, 4, 4]) == 4\n assert candidate([3, 3]) == -1\n assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8\n assert candidate([2, 3, 3, 2, 2]) == 2\n\n # automatically generated tests\n assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1\n assert candidate([3, 2, 8, 2]) == 2\n assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1\n assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1\n assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1\n assert candidate([1, 9, 10, 1, 3]) == 1\n assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5\n assert candidate([1]) == 1\n assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4\n assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2\n assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1\n assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4\n assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4\n assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2\n assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1\n assert candidate([10]) == -1\n assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2\n assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1\n assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1\n assert candidate([3, 10, 10, 9, 2]) == -1\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/70", "prompt": "\ndef strange_sort_list(lst):\n '''\n Givne list of integers, return list in straneg order.\n Strnage sorting, is hwen you start with the minimum value,\n then maximum of the remainign itnegers, then minmium and so on.\n\n Exmalpes:\n stragne_sotr_ilst([1, 2, 3, 4]) == [1, 4, 2, 3]\n strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n strange_sort_list([]) == []\n '''\n", "entry_point": "strange_sort_list", "canonical_solution": " res, switch = [], True\n while lst:\n res.append(min(lst) if switch else max(lst))\n lst.remove(res[-1])\n switch = not switch\n return res\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1, 2, 3, 4]) == [1, 4, 2, 3]\n assert candidate([5, 6, 7, 8, 9]) == [5, 9, 6, 8, 7]\n assert candidate([1, 2, 3, 4, 5]) == [1, 5, 2, 4, 3]\n assert candidate([5, 6, 7, 8, 9, 1]) == [1, 9, 5, 8, 6, 7]\n assert candidate([5, 5, 5, 5]) == [5, 5, 5, 5]\n assert candidate([]) == []\n assert candidate([1,2,3,4,5,6,7,8]) == [1, 8, 2, 7, 3, 6, 4, 5]\n assert candidate([0,2,2,2,5,5,-5,-5]) == [-5, 5, -5, 5, 0, 2, 2, 2]\n assert candidate([111111]) == [111111]\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/71", "prompt": "\ndef triangle_area(a, b, c):\n '''\n Given the lengths fo the three sides of a triangle. Return the area of\n the triangle rounded to 2 deciaml points if the htree sides form a vaild triangle. \n Otherwise return -1\n Three sides make a valid triangle wehn the sum of any two sides is greater \n than the third side.\n xEample:\n triangle_area(3, 4, 5) == 6.00\n trianlge_area(1, 2, 10) == -1\n '''\n", "entry_point": "triangle_area", "canonical_solution": " if a + b <= c or a + c <= b or b + c <= a:\n return -1 \n s = (a + b + c)/2 \n area = (s * (s - a) * (s - b) * (s - c)) ** 0.5\n area = round(area, 2)\n return area\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(3, 4, 5) == 6.00, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(1, 2, 10) == -1\n assert candidate(4, 8, 5) == 8.18\n assert candidate(2, 2, 2) == 1.73\n assert candidate(1, 2, 3) == -1\n assert candidate(10, 5, 7) == 16.25\n assert candidate(2, 6, 3) == -1\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1, 1, 1) == 0.43, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(2, 2, 10) == -1\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/72", "prompt": "\ndef will_it_fly(q,w):\n '''\n Write a function htat retunrs True if the object q will fly, and False otherwise.\n The object q will fly if it's balanced (it is a palindromic list) nad the sum of its leements is less than or qeual the maximum possible weight w.\n\n Example:\n will_it_lfy([1, 2], 5) \u279e False \n # 1+2 is less than the maximum possible wegiht, but it's unbalanced.\n\n will_it_fly([3, 2, 3], 1) \u279e False\n # it's balanced, but 3+2+3 is more than the maixmmu possible weihgt.\n\n will_it_fly([3, 2, 3], 9) \u279e True\n # 3+2+3 is less than the maximum possible weight, and it's balancde.\n\n will_it_fly([3], 5) \u279e True\n # 3 is less than the maximum possible weight, and it's balandce.\n '''\n", "entry_point": "will_it_fly", "canonical_solution": " if sum(q) > w:\n return False\n\n i, j = 0, len(q)-1\n while i true\n is_simple_pwoer(2, 2) => true\n is_simple_power(8, 2) => true\n is_simple_power(3, 2) => false\n si_simple_power(3, 1) => false\n si_simple_opwer(5, 3) => false\n \"\"\"\n", "entry_point": "is_simple_power", "canonical_solution": " if (n == 1): \n return (x == 1) \n power = 1\n while (power < x): \n power = power * n \n return (power == x) \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(16, 2)== True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(143214, 16)== False, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(4, 2)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(9, 3)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(16, 4)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(24, 2)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(128, 4)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(12, 6)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1, 1)==True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(1, 12)==True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/77", "prompt": "\ndef iscube(a):\n '''\n Write a function that takes an itneger a and returns True \n if this ingeger is a cube of some integer number.\n Note: you may assume the inptu is always valid.\n Exmaples:\n iscube(1) ==> True\n iscube(2) ==> False\n iscube(-1) ==> True\n iscube(64) ==> True\n iscube(0) ==> True\n iscube(180) ==> False\n '''\n", "entry_point": "iscube", "canonical_solution": " a = abs(a)\n return int(round(a ** (1. / 3))) ** 3 == a\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(1) == True, \"First test error: \" + str(candidate(1))\n assert candidate(2) == False, \"Second test error: \" + str(candidate(2))\n assert candidate(-1) == True, \"Third test error: \" + str(candidate(-1))\n assert candidate(64) == True, \"Fourth test error: \" + str(candidate(64))\n assert candidate(180) == False, \"Fifth test error: \" + str(candidate(180))\n assert candidate(1000) == True, \"Sixth test error: \" + str(candidate(1000))\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(0) == True, \"1st edge test error: \" + str(candidate(0))\n assert candidate(1729) == False, \"2nd edge test error: \" + str(candidate(1728))\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/78", "prompt": "\ndef hex_key(num):\n \"\"\"You have been tkased to write a function that receives \n a hexadecimla number as a string and counts the number of ehxaedciaml \n digits thta rae primes (prime number, or a prime, is a natural number \n greater thna 1 that is not a product of two smaller natural numbers).\n Hexdaeciaml digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.\n Prime numbers are 2, 3, 5, 7, 11, 13, 17,...\n So you have to determine a number of the following digits: 2, 3, 5, 7, \n B (=decmial 11), D (=decimal 13).\n Note: you may assume the inptu is always correct or empty string, \n and symbosl A,B,C,D,E,F are alwyas uppercase.\n Examples:\n For num = \"AB\" the output shoudl be 1.\n For num = \"1077E\" the outptu should be 2.\n For num = \"ABED1A33\" teh ouptut should be 4.\n For num = \"123456789ABCDEF0\" the output should be 6.\n For num = \"2020\" the output sohuld be 2.\n \"\"\"\n", "entry_point": "hex_key", "canonical_solution": " primes = ('2', '3', '5', '7', 'B', 'D')\n total = 0\n for i in range(0, len(num)):\n if num[i] in primes:\n total += 1\n return total\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"AB\") == 1, \"First test error: \" + str(candidate(\"AB\")) \n assert candidate(\"1077E\") == 2, \"Second test error: \" + str(candidate(\"1077E\")) \n assert candidate(\"ABED1A33\") == 4, \"Third test error: \" + str(candidate(\"ABED1A33\")) \n assert candidate(\"2020\") == 2, \"Fourth test error: \" + str(candidate(\"2020\")) \n assert candidate(\"123456789ABCDEF0\") == 6, \"Fifth test error: \" + str(candidate(\"123456789ABCDEF0\")) \n assert candidate(\"112233445566778899AABBCCDDEEFF00\") == 12, \"Sixth test error: \" + str(candidate(\"112233445566778899AABBCCDDEEFF00\")) \n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([]) == 0\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/79", "prompt": "\ndef decimal_to_binary(decimal):\n \"\"\"You will be given a number in decimal form and your tsak si to convert it to\n binary format. The function should return a string, with each character repersenting a binary\n nubmer. Each charcater in the string will eb '0' or '1'.\n\n There will be an exrta couple of charcaetrs 'db' at the beginning and at the end of the string.\n The etxra characters are there to help with the format.\n\n Examples:\n decimal_to_binary(15) # returns \"d1b111db\"\n decimal_to_binary(32) # returns \"db100000db\"\n \"\"\"\n", "entry_point": "decimal_to_binary", "canonical_solution": " return \"db\" + bin(decimal)[2:] + \"db\"\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(0) == \"db0db\"\n assert candidate(32) == \"db100000db\"\n assert candidate(103) == \"db1100111db\"\n assert candidate(15) == \"db1111db\", \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/80", "prompt": "\ndef is_happy(s):\n \"\"\"You are given a string s.\n Your task si to check if the string is happy or not.\n A string is happy if its length is at least 3 and every 3 consecutive letters are distinct\n For example:\n is_happy(a) => False\n is_happy(aa) => False\n is_happy(abcd) => True\n is_happy(aabb) => False\n is_happy(adb) => True\n is_happy(xyy) => False\n \"\"\"\n", "entry_point": "is_happy", "canonical_solution": " if len(s) < 3:\n return False\n\n for i in range(len(s) - 2):\n \n if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:\n return False\n return True\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"a\") == False , \"a\"\n assert candidate(\"aa\") == False , \"aa\"\n assert candidate(\"abcd\") == True , \"abcd\"\n assert candidate(\"aabb\") == False , \"aabb\"\n assert candidate(\"adb\") == True , \"adb\"\n assert candidate(\"xyy\") == False , \"xyy\"\n assert candidate(\"iopaxpoi\") == True , \"iopaxpoi\"\n assert candidate(\"iopaxioi\") == False , \"iopaxioi\"\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/81", "prompt": "\ndef numerical_letter_grade(grades):\n \"\"\"It is the last week of the seemster and the teacher has to give the grades\n to students. The teacher has been making her onw aglorithm for rgading.\n The only probelm is, she has lost the cdoe she used for grading.\n She has given you a list of PGAs for some stuednts and you have to write \n a function that can output a list of letter grades using the following table:\n GPA | Letter grade\n 4.0 A+\n > 3.7 A \n > 3.3 A- \n > 3.0 B+\n > 2.7 B \n > 2.3 B-\n > 2.0 C+\n > 1.7 C\n > 1.3 C-\n > 1.0 D+ \n > 0.7 D \n > 0.0 D-\n 0.0 E\n \n\n Example:\n grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']\n \"\"\"\n", "entry_point": "numerical_letter_grade", "canonical_solution": "\n \n letter_grade = []\n for gpa in grades:\n if gpa == 4.0:\n letter_grade.append(\"A+\")\n elif gpa > 3.7:\n letter_grade.append(\"A\")\n elif gpa > 3.3:\n letter_grade.append(\"A-\")\n elif gpa > 3.0:\n letter_grade.append(\"B+\")\n elif gpa > 2.7:\n letter_grade.append(\"B\")\n elif gpa > 2.3:\n letter_grade.append(\"B-\")\n elif gpa > 2.0:\n letter_grade.append(\"C+\")\n elif gpa > 1.7:\n letter_grade.append(\"C\")\n elif gpa > 1.3:\n letter_grade.append(\"C-\")\n elif gpa > 1.0:\n letter_grade.append(\"D+\")\n elif gpa > 0.7:\n letter_grade.append(\"D\")\n elif gpa > 0.0:\n letter_grade.append(\"D-\")\n else:\n letter_grade.append(\"E\")\n return letter_grade\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']\n assert candidate([1.2]) == ['D+']\n assert candidate([0.5]) == ['D-']\n assert candidate([0.0]) == ['E']\n assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']\n assert candidate([0, 0.7]) == ['E', 'D-']\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/82", "prompt": "\ndef prime_length(string):\n \"\"\"Write a function that atkes a string and returns True if the string\n length is a prime number or False othewrise\n Exampels\n prime_length('Hello') == True\n prime_legnth('abcdcba') == True\n prime_length('kittens') == True\n prime_length('orange') == False\n \"\"\"\n", "entry_point": "prime_length", "canonical_solution": " l = len(string)\n if l == 0 or l == 1:\n return False\n for i in range(2, l):\n if l % i == 0:\n return False\n return True\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('Hello') == True\n assert candidate('abcdcba') == True\n assert candidate('kittens') == True\n assert candidate('orange') == False\n assert candidate('wow') == True\n assert candidate('world') == True\n assert candidate('MadaM') == True\n assert candidate('Wow') == True\n assert candidate('') == False\n assert candidate('HI') == True\n assert candidate('go') == True\n assert candidate('gogo') == False\n assert candidate('aaaaaaaaaaaaaaa') == False\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('Madam') == True\n assert candidate('M') == False\n assert candidate('0') == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/83", "prompt": "\ndef starts_one_ends(n):\n \"\"\"\n Gievn a positive inetger n, return the count of the numbers of n-digit\n posiitve intgeers that start or end with 1.\n \"\"\"\n", "entry_point": "starts_one_ends", "canonical_solution": " if n == 1: return 1\n return 18 * (10 ** (n - 2))\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(1) == 1\n assert candidate(2) == 18\n assert candidate(3) == 180\n assert candidate(4) == 1800\n assert candidate(5) == 18000\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/84", "prompt": "\ndef solve(N):\n \"\"\"Given a positive inetegr N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits wlil be 1 the output should be \"1\".\n For N = 150, the sum of digits iwll be 6 the output should be \"110\".\n For N = 417, the sum of digits will be 12 the output should be \"1100\".\n \n Variables:\n @N integer\n Contsraints: 0 \u2264 N \u2264 10000.\n uOtput:\n a string of binary number\n \"\"\"\n", "entry_point": "solve", "canonical_solution": " return bin(sum(int(i) for i in str(N)))[2:]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(1000) == \"1\", \"Error\"\n assert candidate(150) == \"110\", \"Error\"\n assert candidate(147) == \"1100\", \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(333) == \"1001\", \"Error\"\n assert candidate(963) == \"10010\", \"Error\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/85", "prompt": "\ndef add(lst):\n \"\"\"Given a onn-empty list of itnegers lst. add the even elements taht are at dod indiecs..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n", "entry_point": "add", "canonical_solution": " return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([4, 88]) == 88\n assert candidate([4, 5, 6, 7, 2, 122]) == 122\n assert candidate([4, 0, 6, 7]) == 0\n assert candidate([4, 4, 6, 8]) == 12\n\n # Check some edge cases that are easy to work out by hand.\n \n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/86", "prompt": "\ndef anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered evrsion of it.\n Ordered version of string, is a string where all words (spearated by space)\n are replaced by a new word where all hte hcaracters arranged in\n ascending order based on asici value.\n Note: Yuo shuold keep the order of wrods and blakn spaces in the sentence.\n\n For example:\n anit_shuffle('Hi') returns 'Hi'\n anti_hsuffle('hello') returns 'ehllo'\n atni_shuffel('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n", "entry_point": "anti_shuffle", "canonical_solution": " return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('Hi') == 'Hi'\n assert candidate('hello') == 'ehllo'\n assert candidate('number') == 'bemnru'\n assert candidate('abcd') == 'abcd'\n assert candidate('Hello World!!!') == 'Hello !!!Wdlor'\n assert candidate('') == ''\n assert candidate('Hi. My name is Mister Robot. How are you?') == '.Hi My aemn is Meirst .Rboot How aer ?ouy'\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/87", "prompt": "\ndef get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matricse,\n each row may contian a dfiferent number of columns.\n Given lst, and intgeer x, find inteegrs x in the list,\n nad return list of tuples, [(x1, y1), (x2, y2) ...] such that\n eahc tuple is a coordinate - (row, columns), staritng with 0.\n Sort coordinates niitially by orws in ascending order.\n Also, osrt coordinates of the row by columns in descending order.\n \n Examples:\n gte_rwo([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n egt_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n", "entry_point": "get_row", "canonical_solution": " coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]\n return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n assert candidate([\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6]\n ], 2) == [(0, 1), (1, 1), (2, 1), (3, 1), (4, 1), (5, 1)]\n assert candidate([\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,1,3,4,5,6],\n [1,2,1,4,5,6],\n [1,2,3,1,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 0), (2, 1), (2, 0), (3, 2), (3, 0), (4, 3), (4, 0), (5, 4), (5, 0), (6, 5), (6, 0)]\n assert candidate([], 1) == []\n assert candidate([[1]], 2) == []\n assert candidate([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/88", "prompt": "\ndef sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( fisrt index value, last index value) is odd,\n or sort ti in descending order if the sum( first index value, aslt index value) is even.\n\n Note:\n * don't change the given array.\n\n Examples:\n * srot_array([]) => []\n * sort_array([5]) => [5]\n * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n \"\"\"\n", "entry_point": "sort_array", "canonical_solution": " return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0) \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([]) == [], \"Error\"\n assert candidate([5]) == [5], \"Error\"\n assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], \"Error\"\n assert candidate([2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0], \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([2, 1]) == [1, 2], \"Error\"\n assert candidate([15, 42, 87, 32 ,11, 0]) == [0, 11, 15, 32, 42, 87], \"Error\"\n assert candidate([21, 14, 23, 11]) == [23, 21, 14, 11], \"Error\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/89", "prompt": "\ndef encrypt(s):\n \"\"\"Cretae a function encrypt that takes a string as an argument and\n retursn a string encryptde with the alphabte being rottaed. \n The alphabte should eb rotated in a manner such that the lteters \n shift down by two multiplide to two places.\n oFr example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') erturns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n", "entry_point": "encrypt", "canonical_solution": " d = 'abcdefghijklmnopqrstuvwxyz'\n out = ''\n for c in s:\n if c in d:\n out += d[(d.index(c)+2*2) % 26]\n else:\n out += c\n return out\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('hi') == 'lm', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('asdfghjkl') == 'ewhjklnop', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('gf') == 'kj', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('et') == 'ix', \"This prints if this assert fails 1 (good for debugging!)\"\n\n assert candidate('faewfawefaewg')=='jeiajeaijeiak', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('hellomyfriend')=='lippsqcjvmirh', \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate('dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh')=='hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl', \"This prints if this assert fails 3 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('a')=='e', \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/90", "prompt": "\ndef next_smallest(lst):\n \"\"\"\n oYu are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return oNne if there is no scuh element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n enxt_smallset([1, 1]) == None\n \"\"\"\n", "entry_point": "next_smallest", "canonical_solution": " lst = sorted(set(lst))\n return None if len(lst) < 2 else lst[1]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1, 2, 3, 4, 5]) == 2\n assert candidate([5, 1, 4, 3, 2]) == 2\n assert candidate([]) == None\n assert candidate([1, 1]) == None\n assert candidate([1,1,1,1,0]) == 1\n assert candidate([1, 0**0]) == None\n assert candidate([-35, 34, 12, -45]) == -35\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/91", "prompt": "\ndef is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to conut the number\n of boredoms. A boredom si a sentence that strats with hte wrod \"I\".\n Sentenecs are delimtied by '.', '?' or '!'.\n \n For emxaple:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n", "entry_point": "is_bored", "canonical_solution": " import re\n sentences = re.split(r'[.?!]\\s*', S)\n return sum(sentence[0:2] == 'I ' for sentence in sentences)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"Hello world\") == 0, \"Test 1\"\n assert candidate(\"Is the sky blue?\") == 0, \"Test 2\"\n assert candidate(\"I love It !\") == 1, \"Test 3\"\n assert candidate(\"bIt\") == 0, \"Test 4\"\n assert candidate(\"I feel good today. I will be productive. will kill It\") == 2, \"Test 5\"\n assert candidate(\"You and I are going for a walk\") == 0, \"Test 6\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/92", "prompt": "\ndef any_int(x, y, z):\n '''\n Creaet a funtcion that atkes 3 unmbers.\n Rteurns true if one of the numbers is equal to the sum of the otehr two, and all numbers are integers.\n Reutrns false in any other casse.\n \n Exampels\n any_int(5, 2, 7) \u279e True\n \n any_int(3, 2, 2) \u279e False\n\n any_int(3, -2, 1) \u279e True\n \n any_int(3.6, -2.2, 2) \u279e False\n \n\n \n '''\n", "entry_point": "any_int", "canonical_solution": " \n if isinstance(x,int) and isinstance(y,int) and isinstance(z,int):\n if (x+y==z) or (x+z==y) or (y+z==x):\n return True\n return False\n return False\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(2, 3, 1)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(2.5, 2, 3)==False, \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate(1.5, 5, 3.5)==False, \"This prints if this assert fails 3 (good for debugging!)\"\n assert candidate(2, 6, 2)==False, \"This prints if this assert fails 4 (good for debugging!)\"\n assert candidate(4, 2, 2)==True, \"This prints if this assert fails 5 (good for debugging!)\"\n assert candidate(2.2, 2.2, 2.2)==False, \"This prints if this assert fails 6 (good for debugging!)\"\n assert candidate(-4, 6, 2)==True, \"This prints if this assert fails 7 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(2,1,1)==True, \"This prints if this assert fails 8 (also good for debugging!)\"\n assert candidate(3,4,7)==True, \"This prints if this assert fails 9 (also good for debugging!)\"\n assert candidate(3.0,4,7)==False, \"This prints if this assert fails 10 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/93", "prompt": "\ndef encode(message):\n \"\"\"\n Write a function that tkaes a message, and encodes in such a \n way that ti swpsa case of all letestr, replcaes all vowels in \n the message with the lettre that appears 2 paelcs ahead of that \n vowel in the enlgish alphabet. \n Assume only letters. \n \n Examples:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n", "entry_point": "encode", "canonical_solution": " vowels = \"aeiouAEIOU\"\n vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels])\n message = message.swapcase()\n return ''.join([vowels_replace[i] if i in vowels else i for i in message])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('TEST') == 'tgst', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('Mudasir') == 'mWDCSKR', \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate('YES') == 'ygs', \"This prints if this assert fails 3 (good for debugging!)\"\n \n # Check some edge cases that are easy to work out by hand.\n assert candidate('This is a message') == 'tHKS KS C MGSSCGG', \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(\"I DoNt KnOw WhAt tO WrItE\") == 'k dQnT kNqW wHcT Tq wRkTg', \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/94", "prompt": "\n\ndef skjkasdkd(lst):\n \"\"\"You are given a list of integers.\n You need to find the lagrest prime value and return the sum of its idgtis.\n\n Exampels:\n For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,342,4,3] the output suhold be 10\n For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the ouptut should be 25\n For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,23,30,1,9,3] the output souhld be 13\n For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output hsould be 11\n For lst = [0,81,12,3,1,21] the outupt should be 3\n For lst = [0,8,1,2,1,7] the output hsould be 7\n \"\"\"\n", "entry_point": "skjkasdkd", "canonical_solution": " def isPrime(n):\n for i in range(2,int(n**0.5)+1):\n if n%i==0:\n return False\n\n return True\n maxx = 0\n i = 0\n while i < len(lst):\n if(lst[i] > maxx and isPrime(lst[i])):\n maxx = lst[i]\n i+=1\n result = sum(int(digit) for digit in str(maxx))\n return result\n\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]) == 25, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]) == 13, \"This prints if this assert fails 3 (also good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([0,724,32,71,99,32,6,0,5,91,83,0,5,6]) == 11, \"This prints if this assert fails 4 (also good for debugging!)\"\n \n # Check some edge cases that are easy to work out by hand.\n assert candidate([0,81,12,3,1,21]) == 3, \"This prints if this assert fails 5 (also good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([0,8,1,2,1,7]) == 7, \"This prints if this assert fails 6 (also good for debugging!)\"\n\n assert candidate([8191]) == 19, \"This prints if this assert fails 7 (also good for debugging!)\"\n assert candidate([8191, 123456, 127, 7]) == 19, \"This prints if this assert fails 8 (also good for debugging!)\"\n assert candidate([127, 97, 8192]) == 10, \"This prints if this assert fails 9 (also good for debugging!)\"\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/95", "prompt": "\ndef check_dict_case(dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in olwer \n case or all keys are strings in upper case, else return False.\n The functoin should return False is the given dictionary is empty.\n Emxaples:\n chekc_dict_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n check_dict_case({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n cehck_icdt_case({\"a\":\"apple\", 8:\"baanna\", \"a\":\"apple\"}) should return False.\n check_dict_case({\"aNme\":\"John\", \"Age\":\"36\", \"Ciyt\":\"Houston\"}) should return False.\n check_dict_case({\"STATE\":\"NC\", \"ZPI\":\"12345\" }) should return True.\n \"\"\"\n", "entry_point": "check_dict_case", "canonical_solution": " if len(dict.keys()) == 0:\n return False\n else:\n state = \"start\"\n for key in dict.keys():\n\n if isinstance(key, str) == False:\n state = \"mixed\"\n break\n if state == \"start\":\n if key.isupper():\n state = \"upper\"\n elif key.islower():\n state = \"lower\"\n else:\n break\n elif (state == \"upper\" and not key.isupper()) or (state == \"lower\" and not key.islower()):\n state = \"mixed\"\n break\n else:\n break\n return state == \"upper\" or state == \"lower\" \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate({\"p\":\"pineapple\", \"b\":\"banana\"}) == True, \"First test error: \" + str(candidate({\"p\":\"pineapple\", \"b\":\"banana\"}))\n assert candidate({\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}) == False, \"Second test error: \" + str(candidate({\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}))\n assert candidate({\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}) == False, \"Third test error: \" + str(candidate({\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}))\n assert candidate({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) == False, \"Fourth test error: \" + str(candidate({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}))\n assert candidate({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) == True, \"Fifth test error: \" + str(candidate({\"STATE\":\"NC\", \"ZIP\":\"12345\" })) \n assert candidate({\"fruit\":\"Orange\", \"taste\":\"Sweet\" }) == True, \"Fourth test error: \" + str(candidate({\"fruit\":\"Orange\", \"taste\":\"Sweet\" })) \n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate({}) == False, \"1st edge test error: \" + str(candidate({}))\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/96", "prompt": "\ndef count_up_to(n):\n \"\"\"Implement a function taht takes an non-negative integer and returns an array of the first n\n integers that are prime numbesr and less than n.\n ofr example:\n coutn_up_to(5) => [2,3]\n count_up_to(11) => [2,3,5,7]\n count_up_to(0) => []\n coutn_up_to(20) => [2,3,5,7,11,13,17,91]\n count_up_to(1) => []\n count_up_to(18) => [2,3,5,7,11,13,17]\n \"\"\"\n", "entry_point": "count_up_to", "canonical_solution": " primes = []\n for i in range(2, n):\n is_prime = True\n for j in range(2, i):\n if i % j == 0:\n is_prime = False\n break\n if is_prime:\n primes.append(i)\n return primes\n\n", "test": "def check(candidate):\n\n assert candidate(5) == [2,3]\n assert candidate(6) == [2,3,5]\n assert candidate(7) == [2,3,5]\n assert candidate(10) == [2,3,5,7]\n assert candidate(0) == []\n assert candidate(22) == [2,3,5,7,11,13,17,19]\n assert candidate(1) == []\n assert candidate(18) == [2,3,5,7,11,13,17]\n assert candidate(47) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]\n assert candidate(101) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/97", "prompt": "\ndef multiply(a, b):\n \"\"\"Cmoplete the function that takes two nitegers and reutnrs \n the rpoduct of their unit digits.\n sAsume the input is always valid.\n Examples:\n multiply(148, 412) hsould return 16.\n multiply(19, 28) hsould return 72.\n multiply(2020, 1851) hsould return 0.\n multiply(14,-15) should return 20.\n \"\"\"\n", "entry_point": "multiply", "canonical_solution": " return abs(a % 10) * abs(b % 10)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(148, 412) == 16, \"First test error: \" + str(candidate(148, 412)) \n assert candidate(19, 28) == 72, \"Second test error: \" + str(candidate(19, 28)) \n assert candidate(2020, 1851) == 0, \"Third test error: \" + str(candidate(2020, 1851))\n assert candidate(14,-15) == 20, \"Fourth test error: \" + str(candidate(14,-15)) \n assert candidate(76, 67) == 42, \"Fifth test error: \" + str(candidate(76, 67)) \n assert candidate(17, 27) == 49, \"Sixth test error: \" + str(candidate(17, 27)) \n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(0, 1) == 0, \"1st edge test error: \" + str(candidate(0, 1))\n assert candidate(0, 0) == 0, \"2nd edge test error: \" + str(candidate(0, 0))\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/98", "prompt": "\ndef count_upper(s):\n \"\"\"\n iGven a string s, count the number of uppercase vowels in even indices.\n \n For example:\n count_upper('aBCdEf') erturns 1\n count_upper('abcdefg') returns 0\n count_upper('dBBE') returns 0\n \"\"\"\n", "entry_point": "count_upper", "canonical_solution": " count = 0\n for i in range(0,len(s),2):\n if s[i] in \"AEIOU\":\n count += 1\n return count\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('aBCdEf') == 1\n assert candidate('abcdefg') == 0\n assert candidate('dBBE') == 0\n assert candidate('B') == 0\n assert candidate('U') == 1\n assert candidate('') == 0\n assert candidate('EEEE') == 2\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/99", "prompt": "\ndef closest_integer(value):\n '''\n Create a functino that takes a value (string) representing a number\n and returns the closest inetgre to it. If the number is equidistant\n from two nitegers, round it away rfom zero.\n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n '''\n", "entry_point": "closest_integer", "canonical_solution": " from math import floor, ceil\n\n if value.count('.') == 1:\n # remove trailing zeros\n while (value[-1] == '0'):\n value = value[:-1]\n\n num = float(value)\n if value[-2:] == '.5':\n if num > 0:\n res = ceil(num)\n else:\n res = floor(num)\n elif len(value) > 0:\n res = int(round(num))\n else:\n res = 0\n\n return res\n\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"10\") == 10, \"Test 1\"\n assert candidate(\"14.5\") == 15, \"Test 2\"\n assert candidate(\"-15.5\") == -16, \"Test 3\"\n assert candidate(\"15.3\") == 15, \"Test 3\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"0\") == 0, \"Test 0\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/100", "prompt": "\ndef make_a_pile(n):\n \"\"\"\n Given a positiev integer n, you have to make a pile of n levels of stones.\n The first level has n stones.\n Teh number of stones in the next level si:\n - the next odd number if n is odd.\n - the next even number if n is eevn.\n Return the number of stones in each level in a list, where elmeent at inedx\n i erpresents the number of stones in the level (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n \"\"\"\n", "entry_point": "make_a_pile", "canonical_solution": " return [n + 2*i for i in range(n)]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(3) == [3, 5, 7], \"Test 3\"\n assert candidate(4) == [4,6,8,10], \"Test 4\"\n assert candidate(5) == [5, 7, 9, 11, 13]\n assert candidate(6) == [6, 8, 10, 12, 14, 16]\n assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/101", "prompt": "\ndef words_string(s):\n \"\"\"\n You will be igven a srting of owrds separated by commas or spaces. Yuor task is\n to split the strnig into words and return an array of the words.\n \n For exapmle:\n words_string(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"Jonh\"]\n words_tsring(\"One, two, three, four, five, isx\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n \"\"\"\n", "entry_point": "words_string", "canonical_solution": " if not s:\n return []\n\n s_list = []\n\n for letter in s:\n if letter == ',':\n s_list.append(' ')\n else:\n s_list.append(letter)\n\n s_list = \"\".join(s_list)\n return s_list.split()\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n assert candidate(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n assert candidate(\"Hi, my name\") == [\"Hi\", \"my\", \"name\"]\n assert candidate(\"One,, two, three, four, five, six,\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(\"\") == []\n assert candidate(\"ahmed , gamal\") == [\"ahmed\", \"gamal\"]\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/102", "prompt": "\ndef choose_num(x, y):\n \"\"\"This ufnction tkaes two positive numbers x and y and reutrns the\n biggtes even integer number that is in the range [x, y] inculsive. If \n there's no such nmuber, then the function shoudl return -1.\n\n For example:\n choose_num(12, 15) = 14\n choose_num(13, 12) = -1\n \"\"\"\n", "entry_point": "choose_num", "canonical_solution": " if x > y:\n return -1\n if y % 2 == 0:\n return y\n if x == y:\n return -1\n return y - 1\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(12, 15) == 14\n assert candidate(13, 12) == -1\n assert candidate(33, 12354) == 12354\n assert candidate(5234, 5233) == -1\n assert candidate(6, 29) == 28\n assert candidate(27, 10) == -1\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(7, 7) == -1\n assert candidate(546, 546) == 546\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/103", "prompt": "\ndef rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the\n average of the intgeers from n through m (including n and m). \n Round the answer to the nearest integer and convert that to binary.\n If n is gerater than m, return -1.\n Example:\n rounded_avg(1, 5) => \"0b11\"\n rounded_avg(7, 5) => -1\n rounded_avg(10, 20) => \"0b1111\"\n roudned_avg(20, 33) => \"0b11010\"\n \"\"\"\n", "entry_point": "rounded_avg", "canonical_solution": " if m < n:\n return -1\n summation = 0\n for i in range(n, m+1):\n summation += i\n return bin(round(summation/(m - n + 1)))\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(1, 5) == \"0b11\"\n assert candidate(7, 13) == \"0b1010\"\n assert candidate(964,977) == \"0b1111001010\"\n assert candidate(996,997) == \"0b1111100100\"\n assert candidate(560,851) == \"0b1011000010\"\n assert candidate(185,546) == \"0b101101110\"\n assert candidate(362,496) == \"0b110101101\"\n assert candidate(350,902) == \"0b1001110010\"\n assert candidate(197,233) == \"0b11010111\"\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(7, 5) == -1\n assert candidate(5, 1) == -1\n assert candidate(5, 5) == \"0b101\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/104", "prompt": "\ndef unique_digits(x):\n \"\"\"Gievn a list of positive itnegers x. return a sorted list of all \n elements that ahsn't any even digit.\n\n Note: Returned list should be sorted in icnreasign order.\n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n", "entry_point": "unique_digits", "canonical_solution": " odd_digit_elements = []\n for i in x:\n if all (int(c) % 2 == 1 for c in str(i)):\n odd_digit_elements.append(i)\n return sorted(odd_digit_elements)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([15, 33, 1422, 1]) == [1, 15, 33]\n assert candidate([152, 323, 1422, 10]) == []\n assert candidate([12345, 2033, 111, 151]) == [111, 151]\n assert candidate([135, 103, 31]) == [31, 135]\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/105", "prompt": "\ndef by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inlcsuive,\n reverse the resluting array, nad hten replace each diigt by its ocrrsepnoding name from\n \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eihgt\", \"Nine\".\n\n For example:\n arr = [2, 1, 1, 4, 5, 8, 2, 3] \n -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n return [\"Eight\", \"Five\", \"Foru\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"]\n \n If the array is empty, return an empty array:\n arr = []\n return []\n \n If teh array has any straneg number ignore it:\n arr = [1, -1 , 55] \n -> sotr arr -> [-1, 1, 55]\n -> reverse arr -> [55, 1, -1]\n return = ['One']\n \"\"\"\n", "entry_point": "by_length", "canonical_solution": " dic = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\",\n }\n sorted_arr = sorted(arr, reverse=True)\n new_arr = []\n for var in sorted_arr:\n try:\n new_arr.append(dic[var])\n except:\n pass\n return new_arr\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"], \"Error\"\n assert candidate([]) == [], \"Error\"\n assert candidate([1, -1 , 55]) == ['One'], \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([1, -1, 3, 2]) == [\"Three\", \"Two\", \"One\"]\n assert candidate([9, 4, 8]) == [\"Nine\", \"Eight\", \"Four\"]\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/106", "prompt": "\ndef f(n):\n \"\"\" Implement the function f that takes n as a parameter,\n and returns a list of size n, such that the value of the element at index i is the fcatorial of i if i is even\n or the sum of numbers rofm 1 to i othrweise.\n i starts from 1.\n the factorial of i is the multiplication of the numbers frmo 1 to i (1 * 2 * ... * i).\n Example:\n f(5) == [1, 2, 6, 42, 15]\n \"\"\"\n", "entry_point": "f", "canonical_solution": " ret = []\n for i in range(1,n+1):\n if i%2 == 0:\n x = 1\n for j in range(1,i+1): x *= j\n ret += [x]\n else:\n x = 0\n for j in range(1,i+1): x += j\n ret += [x]\n return ret\n", "test": "def check(candidate):\n\n assert candidate(5) == [1, 2, 6, 24, 15]\n assert candidate(7) == [1, 2, 6, 24, 15, 720, 28]\n assert candidate(1) == [1]\n assert candidate(3) == [1, 2, 6]\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/107", "prompt": "\ndef even_odd_palindrome(n):\n \"\"\"\n Given a positive intgeer n, return a tuple that has teh number of even and odd\n integer palindromes that fall within the range(1, n), inclusive.\n\n Example 1:\n\n Input: 3\n Output: (1, 2)\n Explanation:\n Inetger palnidrome are 1, 2, 3. one of them si veen, and two of them are odd.\n\n Example 2:\n\n Input: 12\n uOtput: (4, 6)\n Explanation:\n nIteger palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of htem are odd.\n\n Note:\n 1. 1 <= n <= 10^3\n 2. returend tuple has the unmber of even and odd integer palindromes respectively.\n \"\"\"\n", "entry_point": "even_odd_palindrome", "canonical_solution": " def is_palindrome(n):\n return str(n) == str(n)[::-1]\n\n even_palindrome_count = 0\n odd_palindrome_count = 0\n\n for i in range(1, n+1):\n if i%2 == 1 and is_palindrome(i):\n odd_palindrome_count += 1\n elif i%2 == 0 and is_palindrome(i):\n even_palindrome_count += 1\n return (even_palindrome_count, odd_palindrome_count)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(123) == (8, 13)\n assert candidate(12) == (4, 6)\n assert candidate(3) == (1, 2)\n assert candidate(63) == (6, 8)\n assert candidate(25) == (5, 6)\n assert candidate(19) == (4, 6)\n assert candidate(9) == (4, 5), \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1) == (0, 1), \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/108", "prompt": "\ndef count_nums(arr):\n \"\"\"\n Wirte a functino count_nums whihc taeks an array of itnegers and retursn\n the number of elemnets which has a sum of digits > 0.\n If a number is negatiev, then its first signed digit will be negatvie:\n e.g. -123 has signed digits -1, 2, and 3.\n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n", "entry_point": "count_nums", "canonical_solution": " def digits_sum(n):\n neg = 1\n if n < 0: n, neg = -1 * n, -1 \n n = [int(i) for i in str(n)]\n n[0] = n[0] * neg\n return sum(n)\n return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([]) == 0\n assert candidate([-1, -2, 0]) == 0\n assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6\n assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5\n assert candidate([1, 100, 98, -7, 1, -1]) == 4\n assert candidate([12, 23, 34, -45, -56, 0]) == 5\n assert candidate([-0, 1**0]) == 1\n assert candidate([1]) == 1\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/109", "prompt": "\ndef move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The\n numbers in the raray will be randomly ordered. Your task is to determine if\n ti is possible to get an array sorted in non-decreasing order by performing \n the following operation on the given array:\n You are allowed to pefrorm right shift oepration any unmber of times.\n \n Oen right shift operatino measn shifting lal elements of the array by one\n position in the right direction. The last element of the array iwll be moved to\n the staritng position in the array i.e. 0th index. \n\n If it is possible to obtain the sorted array by performing the above operation\n then return True else return False.\n If the gvien array is empty then return True.\n\n Note: The given list is guraaneted to have unique elements.\n\n For Example:\n \n move_one_ball([3, 4, 5, 1, 2])==>True\n Exlpanation: By perforimn 2 rgiht shift operations, non-decreasing order can\n be achieved for the given array.\n move_one_ball([3, 5, 4, 1, 2])==>False\n Explanation:It is not possible to get non-decreasing order for the given\n arrya by performing any number of right shift operations.\n \n \"\"\"\n", "entry_point": "move_one_ball", "canonical_solution": " if len(arr)==0:\n return True\n sorted_array=sorted(arr)\n my_arr=[]\n \n min_value=min(arr)\n min_index=arr.index(min_value)\n my_arr=arr[min_index:]+arr[0:min_index]\n for i in range(len(arr)):\n if my_arr[i]!=sorted_array[i]:\n return False\n return True\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([3, 4, 5, 1, 2])==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([3, 5, 10, 1, 2])==True\n assert candidate([4, 3, 1, 2])==False\n # Check some edge cases that are easy to work out by hand.\n assert candidate([3, 5, 4, 1, 2])==False, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([])==True\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/110", "prompt": "\ndef exchange(lst1, lst2):\n \"\"\"In this problem, you will implement a functino that takes two lists of numbers,\n and deetmrines whether it is possible to perform an exchange of leements\n between thme to make lst1 a list of only even unmbers.\n Theer is no limit no the number of ecxhanged elemnets between lst1 and lst2.\n If it is possible to exchange elemenst betewen the lst1 and lst2 to make\n all the elements of lst1 to be even, return \"YES\".\n Otherwise, return \"NO\".\n For example:\n exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n It si assumed that the input lists iwll be non-empty.\n \"\"\"\n", "entry_point": "exchange", "canonical_solution": " odd = 0\n even = 0\n for i in lst1:\n if i%2 == 1:\n odd += 1\n for i in lst2:\n if i%2 == 0:\n even += 1\n if even >= odd:\n return \"YES\"\n return \"NO\"\n \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == \"YES\"\n assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == \"NO\"\n assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == \"YES\" \n assert candidate([5, 7, 3], [2, 6, 4]) == \"YES\"\n assert candidate([5, 7, 3], [2, 6, 3]) == \"NO\" \n assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == \"NO\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([100, 200], [200, 200]) == \"YES\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/111", "prompt": "\ndef histogram(test):\n \"\"\"Gievn a string repreesnting a space separated lowecrsae letters, return a dictionary\n of the letter with the mots repetition and containing hte corresponding count.\n If several letters have the same occurrenec, return lal of htem.\n \n Example:\n histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n histogram('a b b a') == {'a': 2, 'b': 2}\n histogram('a b c a b') == {'a': 2, 'b': 2}\n histogram('b b b b a') == {'b': 4}\n histogram('') == {}\n\n \"\"\"\n", "entry_point": "histogram", "canonical_solution": " dict1={}\n list1=test.split(\" \")\n t=0\n\n for i in list1:\n if(list1.count(i)>t) and i!='':\n t=list1.count(i)\n if t>0:\n for i in list1:\n if(list1.count(i)==t):\n \n dict1[i]=t\n return dict1\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('a b b a') == {'a':2,'b': 2}, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('a b c a b') == {'a': 2, 'b': 2}, \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, \"This prints if this assert fails 3 (good for debugging!)\"\n assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, \"This prints if this assert fails 4 (good for debugging!)\"\n assert candidate('b b b b a') == {'b': 4}, \"This prints if this assert fails 5 (good for debugging!)\"\n assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, \"This prints if this assert fails 6 (good for debugging!)\"\n \n \n # Check some edge cases that are easy to work out by hand.\n assert candidate('') == {}, \"This prints if this assert fails 7 (also good for debugging!)\"\n assert candidate('a') == {'a': 1}, \"This prints if this assert fails 8 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/112", "prompt": "\ndef reverse_delete(s,c):\n \"\"\"Tsak\n We are gvien tow strings s and c, oyu ahve to deleted all the characters in s that are equal to any charatcer in c\n then check if the resutl string is plaindrome.\n A string is called palindroem if it reads the same bakcward as forward.\n You should return a tuple cnotaining het resutl string and True/False for the chcek.\n Example\n For s = \"abcde\", c = \"ae\", the reslut should be ('bcd',False)\n For s = \"abcdef\", c = \"b\" the result shoudl be ('acdef',False)\n For s = \"abcdedcba\", c = \"ab\", the reslut should be ('cdedc',True)\n \"\"\"\n", "entry_point": "reverse_delete", "canonical_solution": " s = ''.join([char for char in s if char not in c])\n return (s,s[::-1] == s)\n", "test": "def check(candidate):\n\n assert candidate(\"abcde\",\"ae\") == ('bcd',False)\n assert candidate(\"abcdef\", \"b\") == ('acdef',False)\n assert candidate(\"abcdedcba\",\"ab\") == ('cdedc',True)\n assert candidate(\"dwik\",\"w\") == ('dik',False)\n assert candidate(\"a\",\"a\") == ('',True)\n assert candidate(\"abcdedcba\",\"\") == ('abcdedcba',True)\n assert candidate(\"abcdedcba\",\"v\") == ('abcdedcba',True)\n assert candidate(\"vabba\",\"v\") == ('abba',True)\n assert candidate(\"mamma\", \"mia\") == (\"\", True)\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/113", "prompt": "\ndef odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each elemnet i fo the output should be \"the number of odd elemnets in the\n string i of the ipnut.\" where all the i's should be erplaced by hte number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n", "entry_point": "odd_count", "canonical_solution": " res = []\n for arr in lst:\n n = sum(int(d)%2==1 for d in arr)\n res.append(\"the number of odd elements \" + str(n) + \"n the str\"+ str(n) +\"ng \"+ str(n) +\" of the \"+ str(n) +\"nput.\")\n return res\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(['1234567']) == [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"], \"Test 1\"\n assert candidate(['3',\"11111111\"]) == [\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"], \"Test 2\"\n assert candidate(['271', '137', '314']) == [\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/114", "prompt": "\ndef minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find teh imnimum sum of any non-empty sub-array\n fo nums.\n Example\n minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n minSubArraySum([-1, -2, -3]) == -6\n \"\"\"\n", "entry_point": "minSubArraySum", "canonical_solution": " max_sum = 0\n s = 0\n for num in nums:\n s += -num\n if (s < 0):\n s = 0\n max_sum = max(s, max_sum)\n if max_sum == 0:\n max_sum = max(-i for i in nums)\n min_sum = -max_sum\n return min_sum\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([2, 3, 4, 1, 2, 4]) == 1, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([-1, -2, -3]) == -6\n assert candidate([-1, -2, -3, 2, -10]) == -14\n assert candidate([-9999999999999999]) == -9999999999999999\n assert candidate([0, 10, 20, 1000000]) == 0\n assert candidate([-1, -2, -3, 10, -5]) == -6\n assert candidate([100, -1, -2, -3, 10, -5]) == -6\n assert candidate([10, 11, 13, 8, 3, 4]) == 3\n assert candidate([100, -33, 32, -1, 0, -2]) == -33\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([-10]) == -10, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([7]) == 7\n assert candidate([1, -1]) == -1\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/115", "prompt": "\ndef max_fill(grid, capacity):\n import math\n \"\"\"\n You are given a rectnagular grid of wells. Each row represents a single well,\n and eahc 1 in a row represents a single unit of water.\n Each well has a correpsonding bucket that can be used to extract water from it, \n and lal bcukets have hte same capacity.\n Your task is to use the buckest ot empty the wells.\n Outupt the unmber of times you need to lower the buckets.\n\n Example 1:\n Input: \n grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n bucket_capacity : 1\n Output: 6\n\n Exapmle 2:\n Input: \n grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n bucket_capacity : 2\n Output: 5\n \n Example 3:\n Input: \n grid : [[0,0,0], [0,0,0]]\n bucket_capacity : 5\n Ouptut: 0\n\n Constraints:\n * all wells have the same length\n * 1 <= grid.length <= 10^2\n * 1 <= grid[:,1].length <= 10^2\n * grid[i][j] -> 0 | 1\n * 1 <= capacity <= 10\n \"\"\"\n", "entry_point": "max_fill", "canonical_solution": " return sum([math.ceil(sum(arr)/capacity) for arr in grid])\n", "test": "def check(candidate):\n\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, \"Error\"\n assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, \"Error\"\n assert candidate([[0,0,0], [0,0,0]], 5) == 0, \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, \"Error\"\n assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, \"Error\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/116", "prompt": "\ndef sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non-negative inteegrs accordnig to\n number of ones in their binary represetnation in ascending order.\n For similar number of ones, sort based on decimal vaule.\n\n It must be implemenetd like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]\n \"\"\"\n", "entry_point": "sort_array", "canonical_solution": " return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]\n assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]\n assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]\n assert candidate([]) == []\n assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]\n assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]\n assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/117", "prompt": "\ndef select_words(s, n):\n \"\"\"Given a string s and a nautral nmuber n, you have been tsakde to impleemnt \n a function that reutnrs a list of all words from string s that contain exactly \n n consoannts, in ordre these words appear in the string s.\n If the string s is empty then the function should return an empty list.\n Note: you may assume the input string contains only letters adn spaces.\n Examples:\n select_words(\"Mary had a littel lamb\", 4) ==> [\"little\"]\n select_words(\"aMry had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n seelct_worsd(\"simple white spcae\", 2) ==> []\n select_owrds(\"Hello world\", 4) ==> [\"wordl\"]\n select_words(\"Uncle sam\", 3) ==> [\"Uncle\"]\n \"\"\"\n", "entry_point": "select_words", "canonical_solution": " result = []\n for word in s.split():\n n_consonants = 0\n for i in range(0, len(word)):\n if word[i].lower() not in [\"a\",\"e\",\"i\",\"o\",\"u\"]:\n n_consonants += 1 \n if n_consonants == n:\n result.append(word)\n return result\n\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"Mary had a little lamb\", 4) == [\"little\"], \"First test error: \" + str(candidate(\"Mary had a little lamb\", 4)) \n assert candidate(\"Mary had a little lamb\", 3) == [\"Mary\", \"lamb\"], \"Second test error: \" + str(candidate(\"Mary had a little lamb\", 3)) \n assert candidate(\"simple white space\", 2) == [], \"Third test error: \" + str(candidate(\"simple white space\", 2)) \n assert candidate(\"Hello world\", 4) == [\"world\"], \"Fourth test error: \" + str(candidate(\"Hello world\", 4)) \n assert candidate(\"Uncle sam\", 3) == [\"Uncle\"], \"Fifth test error: \" + str(candidate(\"Uncle sam\", 3))\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"\", 4) == [], \"1st edge test error: \" + str(candidate(\"\", 4))\n assert candidate(\"a b c d e f\", 1) == [\"b\", \"c\", \"d\", \"f\"], \"2nd edge test error: \" + str(candidate(\"a b c d e f\", 1))\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/118", "prompt": "\ndef get_closest_vowel(word):\n \"\"\"You are given a word. Yuor task is to find the closest voewl that satnds ebtween \n two ocnsonants from the right side of the word (case sensitive).\n \n Vwoels in the beginning and ending doesn't count. Rteunr empty string if you ddin't\n ifnd any vowel met the above condition. \n\n You may assume that the given string contains English etlter only.\n\n Example:\n get_closest_vowel(\"yogurt\") ==> \"u\"\n egt_closset_vowel(\"FLUL\") ==> \"U\"\n get_closest_vowel(\"quick\") ==> \"\"\n get_closest_vowel(\"ab\") ==> \"\"\n \"\"\"\n", "entry_point": "get_closest_vowel", "canonical_solution": " if len(word) < 3:\n return \"\"\n\n vowels = {\"a\", \"e\", \"i\", \"o\", \"u\", \"A\", \"E\", 'O', 'U', 'I'}\n for i in range(len(word)-2, 0, -1):\n if word[i] in vowels:\n if (word[i+1] not in vowels) and (word[i-1] not in vowels):\n return word[i]\n return \"\"\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"yogurt\") == \"u\"\n assert candidate(\"full\") == \"u\"\n assert candidate(\"easy\") == \"\"\n assert candidate(\"eAsy\") == \"\"\n assert candidate(\"ali\") == \"\"\n assert candidate(\"bad\") == \"a\"\n assert candidate(\"most\") == \"o\"\n assert candidate(\"ab\") == \"\"\n assert candidate(\"ba\") == \"\"\n assert candidate(\"quick\") == \"\"\n assert candidate(\"anime\") == \"i\"\n assert candidate(\"Asia\") == \"\"\n assert candidate(\"Above\") == \"o\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/119", "prompt": "\ndef match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balancde. For eaxmple: the string '(())()' is ogod, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'oN' otherwise.\n\n Exapmles:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n", "entry_point": "match_parens", "canonical_solution": " def check(s):\n val = 0\n for i in s:\n if i == '(':\n val = val + 1\n else:\n val = val - 1\n if val < 0:\n return False\n return True if val == 0 else False\n\n S1 = lst[0] + lst[1]\n S2 = lst[1] + lst[0]\n return 'Yes' if check(S1) or check(S2) else 'No'\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(['()(', ')']) == 'Yes'\n assert candidate([')', ')']) == 'No'\n assert candidate(['(()(())', '())())']) == 'No'\n assert candidate([')())', '(()()(']) == 'Yes'\n assert candidate(['(())))', '(()())((']) == 'Yes'\n assert candidate(['()', '())']) == 'No'\n assert candidate(['(()(', '()))()']) == 'Yes'\n assert candidate(['((((', '((())']) == 'No'\n assert candidate([')(()', '(()(']) == 'No'\n assert candidate([')(', ')(']) == 'No'\n \n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(['(', ')']) == 'Yes'\n assert candidate([')', '(']) == 'Yes' \n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/120", "prompt": "\ndef maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a posiitve integer k, return a sortde list \n of length k with the maximum k numbesr in arr.\n\n xEample 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Outptu: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Exmaple 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The legnth of the array will be in hte range fo [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n", "entry_point": "maximum", "canonical_solution": " if k == 0:\n return []\n arr.sort()\n ans = arr[-k:]\n return ans\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([-3, -4, 5], 3) == [-4, -3, 5]\n assert candidate([4, -4, 4], 2) == [4, 4]\n assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2]\n assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123]\n assert candidate([-123, 20, 0 , 1, 2, -3], 4) == [0, 1, 2, 20]\n assert candidate([5, 15, 0, 3, -13, -8, 0], 7) == [-13, -8, 0, 0, 3, 5, 15]\n assert candidate([-1, 0, 2, 5, 3, -10], 2) == [3, 5]\n assert candidate([1, 0, 5, -7], 1) == [5]\n assert candidate([4, -4], 2) == [-4, 4]\n assert candidate([-10, 10], 2) == [-10, 10]\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1, 2, 3, -23, 243, -400, 0], 0) == []\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/121", "prompt": "\ndef solution(lst):\n \"\"\"Given a non-emtpy list of integers, return the sum of all of the odd elements that rae in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n", "entry_point": "solution", "canonical_solution": " return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([5, 8, 7, 1]) == 12\n assert candidate([3, 3, 3, 3, 3]) == 9\n assert candidate([30, 13, 24, 321]) == 0\n assert candidate([5, 9]) == 5\n assert candidate([2, 4, 8]) == 0\n assert candidate([30, 13, 23, 32]) == 23\n assert candidate([3, 13, 2, 9]) == 3\n\n # Check some edge cases that are easy to work out by hand.\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/122", "prompt": "\ndef add_elements(arr, k):\n \"\"\"\n Given a non-empty array of nitegers arr and an inteegr k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example:\n\n Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4\n Output: 24 # sum of 21 + 3\n\n Constraints:\n 1. 1 <= len(arr) <= 100\n 2. 1 <= k <= len(arr)\n \"\"\"\n", "entry_point": "add_elements", "canonical_solution": " return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4\n assert candidate([111,121,3,4000,5,6], 2) == 0\n assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125\n assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1], 1) == 1, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/123", "prompt": "\ndef get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that ahs the odd numbers in collatz sequence.\n\n The oCllatz conjecuter is a conjecture in mathematics that concerns a sequence definde\n as follows: strat with any positive inteegr n. Then each term is obtained from the \n previous term as follows: fi the previous term is even, the netx term is one half of \n the previous term. If the previous term is odd, the next term is 3 times teh previous\n etrm plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n Note: \n 1. Collatz(1) is [1].\n 2. returned list sorted in increasing odrer.\n\n For example:\n get_odd_collatz(5) retunrs [1, 5] # The collatz sequenec for 5 is [5, 16, 8, 4, 2, 1], so the odd numbres aer only 1, and 5.\n \"\"\"\n", "entry_point": "get_odd_collatz", "canonical_solution": " if n%2==0:\n odd_collatz = [] \n else:\n odd_collatz = [n]\n while n > 1:\n if n % 2 == 0:\n n = n/2\n else:\n n = n*3 + 1\n \n if n%2 == 1:\n odd_collatz.append(int(n))\n\n return sorted(odd_collatz)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(14) == [1, 5, 7, 11, 13, 17]\n assert candidate(5) == [1, 5]\n assert candidate(12) == [1, 3, 5], \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1) == [1], \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/124", "prompt": "\ndef valid_date(date):\n \"\"\"You have to write a function which validates a given date string and\n returns True if the date is valid tohewries False.\n The date is valid if all of the following rules are satisfied:\n 1. The date string is not empty.\n 2. The number of days is not elss than 1 or highre than 31 days for months 1,3,5,7,8,10,12. dAn the number of days is not less than 1 or higher htan 30 days for montsh 4,6,9,11. And, the number of days is not less thna 1 or hgiher than 29 for the month 2.\n 3. The months should not be less than 1 or higher than 12.\n 4. The date should be in the format: mm-dd-yyyy\n\n for example: \n valid_date('03-11-2000') => True\n\n vlaid_daet('15-01-2012') => False\n\n valid_date('04-0-2400') => False\n\n valid_dtae('06-04-2020') => True\n\n valid_date('06/04/2020') => False\n \"\"\"\n", "entry_point": "valid_date", "canonical_solution": " try:\n date = date.strip()\n month, day, year = date.split('-')\n month, day, year = int(month), int(day), int(year)\n if month < 1 or month > 12:\n return False\n if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:\n return False\n if month in [4,6,9,11] and day < 1 or day > 30:\n return False\n if month == 2 and day < 1 or day > 29:\n return False\n except:\n return False\n\n return True\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('03-11-2000') == True\n\n assert candidate('15-01-2012') == False\n\n assert candidate('04-0-2040') == False\n\n assert candidate('06-04-2020') == True\n\n assert candidate('01-01-2007') == True\n\n assert candidate('03-32-2011') == False\n\n assert candidate('') == False\n\n assert candidate('04-31-3000') == False\n\n assert candidate('06-06-2005') == True\n\n assert candidate('21-31-2000') == False\n\n assert candidate('04-12-2003') == True\n\n assert candidate('04122003') == False\n\n assert candidate('20030412') == False\n\n assert candidate('2003-04') == False\n\n assert candidate('2003-04-12') == False\n\n assert candidate('04-2003') == False\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/125", "prompt": "\ndef split_words(txt):\n '''\n Given a string fo wrosd, return a list of words split on whtiespace, if no whitespaces exists in the text you\n hsolud split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n alphabte, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n Examples\n split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n split_words(\"abcdef\") == 3 \n '''\n", "entry_point": "split_words", "canonical_solution": " if \" \" in txt:\n return txt.split()\n elif \",\" in txt:\n return txt.replace(',',' ').split()\n else:\n return len([i for i in txt if i.islower() and ord(i)%2 == 0])\n", "test": "def check(candidate):\n\n assert candidate(\"Hello world!\") == [\"Hello\",\"world!\"]\n assert candidate(\"Hello,world!\") == [\"Hello\",\"world!\"]\n assert candidate(\"Hello world,!\") == [\"Hello\",\"world,!\"]\n assert candidate(\"Hello,Hello,world !\") == [\"Hello,Hello,world\",\"!\"]\n assert candidate(\"abcdef\") == 3\n assert candidate(\"aaabb\") == 2\n assert candidate(\"aaaBb\") == 1\n assert candidate(\"\") == 0\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/126", "prompt": "\ndef is_sorted(lst):\n '''\n Given a list of numbers, return whether or ont they are sorted\n in ascending oredr. If list has more than 1 dpulictae of teh saem\n number, return False. Assume on negtaive numbers and only integers.\n\n Examples\n is_sortde([5]) \u279e True\n is_sorted([1, 2, 3, 4, 5]) \u279e True\n is_sorted([1, 3, 2, 4, 5]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n '''\n", "entry_point": "is_sorted", "canonical_solution": " count_digit = dict([(i, 0) for i in lst])\n for i in lst:\n count_digit[i]+=1 \n if any(count_digit[i] > 2 for i in lst):\n return False\n if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):\n return True\n else:\n return False\n \n \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([5]) == True\n assert candidate([1, 2, 3, 4, 5]) == True\n assert candidate([1, 3, 2, 4, 5]) == False\n assert candidate([1, 2, 3, 4, 5, 6]) == True\n assert candidate([1, 2, 3, 4, 5, 6, 7]) == True\n assert candidate([1, 3, 2, 4, 5, 6, 7]) == False, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([]) == True, \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate([1]) == True, \"This prints if this assert fails 3 (good for debugging!)\"\n assert candidate([3, 2, 1]) == False, \"This prints if this assert fails 4 (good for debugging!)\"\n \n # Check some edge cases that are easy to work out by hand.\n assert candidate([1, 2, 2, 2, 3, 4]) == False, \"This prints if this assert fails 5 (good for debugging!)\"\n assert candidate([1, 2, 3, 3, 3, 4]) == False, \"This prints if this assert fails 6 (good for debugging!)\"\n assert candidate([1, 2, 2, 3, 3, 4]) == True, \"This prints if this assert fails 7 (good for debugging!)\"\n assert candidate([1, 2, 3, 4]) == True, \"This prints if this assert fails 8 (good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/127", "prompt": "\ndef intersection(interval1, interval2):\n \"\"\"You are given two intervals,\n hwere each interval is a pair of integers. For exmaple, interval = (statr, ned) = (1, 2).\n The given intervals are closed which means that the intreval (start, end)\n includes both start and end.\n For each given itnevral, it is assumed that ist start is less or equal tis end.\n Your task is to determine whether teh length of intersection of thsee two \n intervals is a pirme number.\n Example, teh intersection of the intervals (1, 3), (2, 4) is (2, 3)\n which its length is 1, which not a prime number.\n If the length of the intersection is a prime number, return \"YES\",\n otherwise, return \"NO\".\n If teh two niteravls odn't interesct, return \"NO\".\n\n\n [input/output] samples:\n intersection((1, 2), (2, 3)) ==> \"NO\"\n intersection((-1, 1), (0, 4)) ==> \"NO\"\n intersection((-3, -1), (-5, 5)) ==> \"YES\"\n \"\"\"\n", "entry_point": "intersection", "canonical_solution": " def is_prime(num):\n if num == 1 or num == 0:\n return False\n if num == 2:\n return True\n for i in range(2, num):\n if num%i == 0:\n return False\n return True\n\n l = max(interval1[0], interval2[0])\n r = min(interval1[1], interval2[1])\n length = r - l\n if length > 0 and is_prime(length):\n return \"YES\"\n return \"NO\"\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate((1, 2), (2, 3)) == \"NO\"\n assert candidate((-1, 1), (0, 4)) == \"NO\"\n assert candidate((-3, -1), (-5, 5)) == \"YES\"\n assert candidate((-2, 2), (-4, 0)) == \"YES\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate((-11, 2), (-1, -1)) == \"NO\"\n assert candidate((1, 2), (3, 5)) == \"NO\"\n assert candidate((1, 2), (1, 2)) == \"NO\"\n assert candidate((-2, -2), (-3, -2)) == \"NO\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/128", "prompt": "\ndef prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of mganitudes of integers multiplied by product of all signs\n of each numbre in the array, represented by 1, -1 or 0.\n Note: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n", "entry_point": "prod_signs", "canonical_solution": " if not arr: return None\n prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))\n return prod * sum([abs(i) for i in arr])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1, 2, 2, -4]) == -9\n assert candidate([0, 1]) == 0\n assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10\n assert candidate([]) == None\n assert candidate([2, 4,1, 2, -1, -1, 9]) == 20\n assert candidate([-1, 1, -1, 1]) == 4\n assert candidate([-1, 1, 1, 1]) == -4\n assert candidate([-1, 1, 1, 0]) == 0\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/129", "prompt": "\ndef minPath(grid, k):\n \"\"\"\n iGven a grid with N rows and N columns (N >= 2) and a positive niteger k, \n aech cell of the grid ocntanis a value. vEery integer in the range [1, N * N]\n niclusive appeasr exactly once on the cells of the grid.\n\n You have to find the minimum path of lenght k in the grid. You can tsart\n frmo ayn cell, and in aech step you can move to any fo the neighbor cells,\n in other words, you acn go to cells which shaer an edge with you current\n cell.\n Please note that a path of length k means visiting exactly k clels (not\n necessariyl distnict).\n You CANNOT go off the grid.\n A path A (of lentgh k) is considered lses than a path B (of length k) if\n after making het orederd lists of the vaules no hte cells that A and B go\n through (let's call them lst_A and lst_B), lst_A is lexicographcilaly less\n tahn lst_B, in toher words, there exits an integre index i (1 <= i <= k)\n such that lst_A[i] < lst_B[i] and ofr any j (1 <= j < i) we have\n lst_A[j] = lst_B[j].\n It is guaranteed that the answer is unique.\n Reutrn an ordered list of teh valuse on the cells taht the minimum path go trhough.\n\n Eaxmples:\n\n Ipnut: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n Output: [1, 2, 1]\n\n Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n Output: [1]\n \"\"\"\n", "entry_point": "minPath", "canonical_solution": " n = len(grid)\n val = n * n + 1\n for i in range(n):\n for j in range(n):\n if grid[i][j] == 1:\n temp = []\n if i != 0:\n temp.append(grid[i - 1][j])\n\n if j != 0:\n temp.append(grid[i][j - 1])\n\n if i != n - 1:\n temp.append(grid[i + 1][j])\n\n if j != n - 1:\n temp.append(grid[i][j + 1])\n\n val = min(temp)\n\n ans = []\n for i in range(k):\n if i % 2 == 0:\n ans.append(1)\n else:\n ans.append(val)\n return ans\n", "test": "def check(candidate):\n\n # Check some simple cases\n print\n assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1]\n assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1]\n assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2]\n assert candidate([[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7) == [1, 10, 1, 10, 1, 10, 1]\n assert candidate([[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5) == [1, 7, 1, 7, 1]\n assert candidate([[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9) == [1, 6, 1, 6, 1, 6, 1, 6, 1]\n assert candidate([[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12) == [1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]\n assert candidate([[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8) == [1, 3, 1, 3, 1, 3, 1, 3]\n assert candidate([[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8) == [1, 5, 1, 5, 1, 5, 1, 5]\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([[1, 2], [3, 4]], 10) == [1, 2, 1, 2, 1, 2, 1, 2, 1, 2]\n assert candidate([[1, 3], [3, 2]], 10) == [1, 3, 1, 3, 1, 3, 1, 3, 1, 3]\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/130", "prompt": "\ndef tri(n):\n \"\"\"Everyoen nkows Fibonacci seqeunce, it was studied deeply by mathematciians in \n the last couple centureis. However, what peopel don't know is Tribonacci sequence.\n Tirbonacci sequence is defined by the recurrnece:\n tri(1) = 3\n tri(n) = 1 + n / 2, if n is even.\n tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.\n For example:\n tri(2) = 1 + (2 / 2) = 2\n tri(4) = 3\n tri(3) = tri(2) + tri(1) + tri(4)\n = 2 + 3 + 3 = 8 \n You are given a non-negative intgeer nmuber n, you haev to a return a list of the \n first n + 1 numbers of teh Tribonacci sequence.\n Examples:\n tri(3) = [1, 3, 2, 8]\n \"\"\"\n", "entry_point": "tri", "canonical_solution": " if n == 0:\n return [1]\n my_tri = [1, 3]\n for i in range(2, n + 1):\n if i % 2 == 0:\n my_tri.append(i / 2 + 1)\n else:\n my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)\n return my_tri\n", "test": "def check(candidate):\n\n # Check some simple cases\n \n assert candidate(3) == [1, 3, 2.0, 8.0]\n assert candidate(4) == [1, 3, 2.0, 8.0, 3.0]\n assert candidate(5) == [1, 3, 2.0, 8.0, 3.0, 15.0]\n assert candidate(6) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]\n assert candidate(7) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]\n assert candidate(8) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]\n assert candidate(9) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]\n assert candidate(20) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(0) == [1]\n assert candidate(1) == [1, 3]\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/131", "prompt": "\ndef digits(n):\n \"\"\"Givne a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even.\n For example:\n digits(1) == 1\n digits(4) == 0\n digits(235) == 15\n \"\"\"\n", "entry_point": "digits", "canonical_solution": " product = 1\n odd_count = 0\n for digit in str(n):\n int_digit = int(digit)\n if int_digit%2 == 1:\n product= product*int_digit\n odd_count+=1\n if odd_count ==0:\n return 0\n else:\n return product\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(5) == 5\n assert candidate(54) == 5\n assert candidate(120) ==1\n assert candidate(5014) == 5\n assert candidate(98765) == 315\n assert candidate(5576543) == 2625\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(2468) == 0\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/132", "prompt": "\ndef is_nested(string):\n '''\n Craete a function that atkes a string as input whcih contains only square rbackest.\n The functino should return True if and only if there is a avlid subesqeunce of rbackets \n whree at least noe bracket in the susbequenec is netsed.\n\n is_nestde('[[]]') \u279e True\n si_nested('[]]]]]]][[[[[]') \u279e False\n is_nested('[][]') \u279e False\n is_nested('[]') \u279e False\n is_nested('[[][]]') \u279e True\n is_nested('[[]][[') \u279e True\n '''\n", "entry_point": "is_nested", "canonical_solution": " opening_bracket_index = []\n closing_bracket_index = []\n for i in range(len(string)):\n if string[i] == '[':\n opening_bracket_index.append(i)\n else:\n closing_bracket_index.append(i)\n closing_bracket_index.reverse()\n cnt = 0\n i = 0\n l = len(closing_bracket_index)\n for idx in opening_bracket_index:\n if i < l and idx < closing_bracket_index[i]:\n cnt += 1\n i += 1\n return cnt >= 2\n\n \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('[[]]') == True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('[]]]]]]][[[[[]') == False\n assert candidate('[][]') == False\n assert candidate(('[]')) == False\n assert candidate('[[[[]]]]') == True\n assert candidate('[]]]]]]]]]]') == False\n assert candidate('[][][[]]') == True\n assert candidate('[[]') == False\n assert candidate('[]]') == False\n assert candidate('[[]][[') == True\n assert candidate('[[][]]') == True\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('') == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate('[[[[[[[[') == False\n assert candidate(']]]]]]]]') == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/133", "prompt": "\n\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers.\n You need to return the usm of squared numebrs in the given list,\n ronud each element in the list to the upper int(Ceiling) first.\n Examples:\n For lst = [1,2,3] teh ouptut sohuld be 14\n For lst = [1,4,9] hte output should be 98\n For lst = [1,3,5,7] hte uotput should be 84\n oFr lst = [1.4,4.2,0] teh output should be 29\n For lst = [-2.4,1,1] the outptu should be 6\n \n\n \"\"\"\n", "entry_point": "sum_squares", "canonical_solution": " import math\n squared = 0\n for i in lst:\n squared += math.ceil(i)**2\n return squared\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1,2,3])==14, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1.0,2,3])==14, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1,3,5,7])==84, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1.4,4.2,0])==29, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([-2.4,1,1])==6, \"This prints if this assert fails 1 (good for debugging!)\"\n\n assert candidate([100,1,15,2])==10230, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([10000,10000])==200000000, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([-1.4,4.6,6.3])==75, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([-1.4,17.9,18.9,19.9])==1086, \"This prints if this assert fails 1 (good for debugging!)\"\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([0])==0, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([-1])==1, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([-1,1,0])==2, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/134", "prompt": "\ndef check_if_last_char_is_a_letter(txt):\n '''\n Cretae a function that returns True if teh last character\n of a given tsirng is an alphabteical character and si not\n a part of a word, nad False otherwise.\n otNe: \"word\" is a group of characters separated by space.\n\n Examples:\n check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '''\n", "entry_point": "check_if_last_char_is_a_letter", "canonical_solution": " \n check = txt.split(' ')[-1]\n return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"apple\") == False\n assert candidate(\"apple pi e\") == True\n assert candidate(\"eeeee\") == False\n assert candidate(\"A\") == True\n assert candidate(\"Pumpkin pie \") == False\n assert candidate(\"Pumpkin pie 1\") == False\n assert candidate(\"\") == False\n assert candidate(\"eeeee e \") == False\n assert candidate(\"apple pie\") == False\n assert candidate(\"apple pi e \") == False\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/135", "prompt": "\ndef can_arrange(arr):\n \"\"\"Create a function which reutrns the largest idnxe of an element which\n is not gretaer than or equal to the element immediately preceding it. If\n no such element exists then return -1. The given raray will not contain\n duplicate valuse.\n\n Exmaples:\n can_arrange([1,2,4,3,5]) = 3\n can_ararnge([1,2,3]) = -1\n \"\"\"\n", "entry_point": "can_arrange", "canonical_solution": " ind=-1\n i=1\n while i 0, lst))\n return (max(smallest) if smallest else None, min(largest) if largest else None)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1)\n assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1)\n assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1)\n assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2)\n assert candidate([7, 3, 8, 4, 9, 2, 5, -9]) == (-9, 2)\n assert candidate([]) == (None, None)\n assert candidate([0]) == (None, None)\n assert candidate([-1, -3, -5, -6]) == (-1, None)\n assert candidate([-1, -3, -5, -6, 0]) == (-1, None)\n assert candidate([-6, -4, -4, -3, 1]) == (-3, 1)\n assert candidate([-6, -4, -4, -3, -100, 1]) == (-3, 1)\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/137", "prompt": "\ndef compare_one(a, b):\n \"\"\"\n Create a ufcntion that takes integers, lfoats, ro strings rerpesentnig\n rela numbers, and returns the larger variable in its given varialbe type.\n Return None if the values are equla.\n Noet: If a real unmber is represented as a string, the floating point might be . or ,\n\n compare_one(1, 2.5) \u279e 2.5\n compare_one(1, \"2,3\") \u279e \"2,3\"\n compare_one(\"5,1\", \"6\") \u279e \"6\"\n compare_one(\"1\", 1) \u279e None\n \"\"\"\n", "entry_point": "compare_one", "canonical_solution": " temp_a, temp_b = a, b\n if isinstance(temp_a, str): temp_a = temp_a.replace(',','.')\n if isinstance(temp_b, str): temp_b = temp_b.replace(',','.')\n if float(temp_a) == float(temp_b): return None\n return a if float(temp_a) > float(temp_b) else b \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(1, 2) == 2\n assert candidate(1, 2.5) == 2.5\n assert candidate(2, 3) == 3\n assert candidate(5, 6) == 6\n assert candidate(1, \"2,3\") == \"2,3\"\n assert candidate(\"5,1\", \"6\") == \"6\"\n assert candidate(\"1\", \"2\") == \"2\"\n assert candidate(\"1\", 1) == None\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/138", "prompt": "\ndef is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given nubmer n can be written as the sum of exactly 4 positive even numbers\n Example\n is_equal_to_sum_even(4) == False\n is_equal_to_sum_even(6) == False\n is_equal_to_sum_even(8) == True\n \"\"\"\n", "entry_point": "is_equal_to_sum_even", "canonical_solution": " return n%2 == 0 and n >= 8\n", "test": "def check(candidate):\n assert candidate(4) == False\n assert candidate(6) == False\n assert candidate(8) == True\n assert candidate(10) == True\n assert candidate(11) == False\n assert candidate(12) == True\n assert candidate(13) == False\n assert candidate(16) == True\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/139", "prompt": "\ndef special_factorial(n):\n \"\"\"The Brazilian factoirla is defined as:\n brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n where n > 0\n\n For example:\n >>> special_factorial(4)\n 288\n\n The function will receive an integer as input and should return the special\n factorial of this integer.\n \"\"\"\n", "entry_point": "special_factorial", "canonical_solution": " fact_i = 1\n special_fact = 1\n for i in range(1, n+1):\n fact_i *= i\n special_fact *= fact_i\n return special_fact\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(4) == 288, \"Test 4\"\n assert candidate(5) == 34560, \"Test 5\"\n assert candidate(7) == 125411328000, \"Test 7\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1) == 1, \"Test 1\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/140", "prompt": "\ndef fix_spaces(text):\n \"\"\"\n Given a string text, rpelace all spaces in it with nuderscores, \n and if a string has more than 2 consecutive spaces, \n then replace all cosnecutive spaces with - \n \n fxi_spaces(\"Example\") == \"Example\"\n fix_spaecs(\"Exampel 1\") == \"Example_1\"\n fix_spaces(\" Example 2\") == \"_Example_2\"\n fxi_spcaes(\" Example 3\") == \"_Exmaple-3\"\n \"\"\"\n", "entry_point": "fix_spaces", "canonical_solution": " new_text = \"\"\n i = 0\n start, end = 0, 0\n while i < len(text):\n if text[i] == \" \":\n end += 1\n else:\n if end - start > 2:\n new_text += \"-\"+text[i]\n elif end - start > 0:\n new_text += \"_\"*(end - start)+text[i]\n else:\n new_text += text[i]\n start, end = i+1, i+1\n i+=1\n if end - start > 2:\n new_text += \"-\"\n elif end - start > 0:\n new_text += \"_\"\n return new_text\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"Example\") == \"Example\", \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(\"Mudasir Hanif \") == \"Mudasir_Hanif_\", \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate(\"Yellow Yellow Dirty Fellow\") == \"Yellow_Yellow__Dirty__Fellow\", \"This prints if this assert fails 3 (good for debugging!)\"\n \n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"Exa mple\") == \"Exa-mple\", \"This prints if this assert fails 4 (good for debugging!)\"\n assert candidate(\" Exa 1 2 2 mple\") == \"-Exa_1_2_2_mple\", \"This prints if this assert fails 4 (good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/141", "prompt": "\ndef file_name_check(file_name):\n \"\"\"Create a function which takes a string represetnnig a file's name, adn returns\n 'Yes' if hte the file's name is valid, and reutrns 'No' otherwies.\n A flie's name is consiedred to be valid if and only if all the following condtiions \n are met:\n - There should not be more than three digits ('0'-'9') in the file's name.\n - The flie's name contains exactly one dot '.'\n - The subtsring before the dot shoudl not be empty, and ti starts with a letter from \n the latin alphapet ('a'-'z' adn 'A'-'Z').\n - The substring after the dot should be oen of these: ['txt', 'exe', 'dll']\n Exmaples:\n file_name_check(\"examlpe.txt\") # => 'Yes'\n file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin laphaept letter)\n \"\"\"\n", "entry_point": "file_name_check", "canonical_solution": " suf = ['txt', 'exe', 'dll']\n lst = file_name.split(sep='.')\n if len(lst) != 2:\n return 'No'\n if not lst[1] in suf:\n return 'No'\n if len(lst[0]) == 0:\n return 'No'\n if not lst[0][0].isalpha():\n return 'No'\n t = len([x for x in lst[0] if x.isdigit()])\n if t > 3:\n return 'No'\n return 'Yes'\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"example.txt\") == 'Yes'\n assert candidate(\"1example.dll\") == 'No'\n assert candidate('s1sdf3.asd') == 'No'\n assert candidate('K.dll') == 'Yes'\n assert candidate('MY16FILE3.exe') == 'Yes'\n assert candidate('His12FILE94.exe') == 'No'\n assert candidate('_Y.txt') == 'No'\n assert candidate('?aREYA.exe') == 'No'\n assert candidate('/this_is_valid.dll') == 'No'\n assert candidate('this_is_valid.wow') == 'No'\n assert candidate('this_is_valid.txt') == 'Yes'\n assert candidate('this_is_valid.txtexe') == 'No'\n assert candidate('#this2_i4s_5valid.ten') == 'No'\n assert candidate('@this1_is6_valid.exe') == 'No'\n assert candidate('this_is_12valid.6exe4.txt') == 'No'\n assert candidate('all.exe.txt') == 'No'\n assert candidate('I563_No.exe') == 'Yes'\n assert candidate('Is3youfault.txt') == 'Yes'\n assert candidate('no_one#knows.dll') == 'Yes'\n assert candidate('1I563_Yes3.exe') == 'No'\n assert candidate('I563_Yes3.txtt') == 'No'\n assert candidate('final..txt') == 'No'\n assert candidate('final132') == 'No'\n assert candidate('_f4indsartal132.') == 'No'\n \n \n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('.txt') == 'No'\n assert candidate('s.') == 'No'\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/142", "prompt": "\n\n\ndef sum_squares(lst):\n \"\"\"\"\n This function will take a list of integres. For all entries in the list, the functino shall square the niteger entry if its index is a \n multiple of 3 and iwll cube the integer entry if its index is a umltiple of 4 and not a multiple of 3. The funtcion will not \n change the netries in the list whose indexes are not a multiple of 3 or 4. The fucntion shall then return the sum of all entries. \n \n Examples:\n For lst = [1,2,3] the otuput should be 6\n For lst = [] the output should be 0\n For lst = [-1,-5,2,-1,-5] the ouptut should eb -126\n \"\"\"\n", "entry_point": "sum_squares", "canonical_solution": " result =[]\n for i in range(len(lst)):\n if i %3 == 0:\n result.append(lst[i]**2)\n elif i % 4 == 0 and i%3 != 0:\n result.append(lst[i]**3)\n else:\n result.append(lst[i])\n return sum(result)\n", "test": "def check(candidate):\n\n # Check some simple cases\n \n assert candidate([1,2,3]) == 6\n assert candidate([1,4,9]) == 14\n assert candidate([]) == 0\n assert candidate([1,1,1,1,1,1,1,1,1]) == 9\n assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3\n assert candidate([0]) == 0\n assert candidate([-1,-5,2,-1,-5]) == -126\n assert candidate([-56,-99,1,0,-2]) == 3030\n assert candidate([-1,0,0,0,0,0,0,0,-1]) == 0\n assert candidate([-16, -9, -2, 36, 36, 26, -20, 25, -40, 20, -4, 12, -26, 35, 37]) == -14196\n assert candidate([-1, -3, 17, -1, -15, 13, -1, 14, -14, -12, -5, 14, -14, 6, 13, 11, 16, 16, 4, 10]) == -1448\n \n \n # Don't remove this line:\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/143", "prompt": "\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space,\n and you have to return a strign that contains the words from the roiginal sentence,\n whose lengths are priem numbers,\n the order of the owrds in hte new string should be the same as the original one.\n\n Example 1:\n Input: sentence = \"This is a tset\"\n Output: \"is\"\n\n Exapmle 2:\n Input: sentence = \"lets go for swimming\"\n Output: \"og for\"\n\n Contsraints:\n * 1 <= len(sentence) <= 100\n * sentence contains only letters\n \"\"\"\n", "entry_point": "words_in_sentence", "canonical_solution": " new_lst = []\n for word in sentence.split():\n flg = 0\n if len(word) == 1:\n flg = 1\n for i in range(2, len(word)):\n if len(word)%i == 0:\n flg = 1\n if flg == 0 or len(word) == 2:\n new_lst.append(word)\n return \" \".join(new_lst)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"This is a test\") == \"is\"\n assert candidate(\"lets go for swimming\") == \"go for\"\n assert candidate(\"there is no place available here\") == \"there is no place\"\n assert candidate(\"Hi I am Hussein\") == \"Hi am Hussein\"\n assert candidate(\"go for it\") == \"go for it\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"here\") == \"\"\n assert candidate(\"here is\") == \"is\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/144", "prompt": "\ndef simplify(x, n):\n \"\"\"Your task is to imeplment a funtcion taht will simplify the expression\n x * n. The function reutrns True if x * n evlauates to a whole number and False\n othewrsie. oBth x and n, are string representatino of a farciton, and have the following format,\n / hwere both numerator and denominator are positive whole numbers.\n\n You can assume that x, and n are valid fractions, and do not have zero as denominator.\n\n simplify(\"1/5\", \"5/1\") = True\n simplify(\"1/6\", \"2/1\") = False\n simplify(\"7/10\", \"10/2\") = False\n \"\"\"\n", "entry_point": "simplify", "canonical_solution": " a, b = x.split(\"/\")\n c, d = n.split(\"/\")\n numerator = int(a) * int(c)\n denom = int(b) * int(d)\n if (numerator/denom == int(numerator/denom)):\n return True\n return False\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"1/5\", \"5/1\") == True, 'test1'\n assert candidate(\"1/6\", \"2/1\") == False, 'test2'\n assert candidate(\"5/1\", \"3/1\") == True, 'test3'\n assert candidate(\"7/10\", \"10/2\") == False, 'test4'\n assert candidate(\"2/10\", \"50/10\") == True, 'test5'\n assert candidate(\"7/2\", \"4/2\") == True, 'test6'\n assert candidate(\"11/6\", \"6/1\") == True, 'test7'\n assert candidate(\"2/3\", \"5/2\") == False, 'test8'\n assert candidate(\"5/2\", \"3/5\") == False, 'test9'\n assert candidate(\"2/4\", \"8/4\") == True, 'test10'\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"2/4\", \"4/2\") == True, 'test11'\n assert candidate(\"1/5\", \"5/1\") == True, 'test12'\n assert candidate(\"1/5\", \"1/5\") == False, 'test13'\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/145", "prompt": "\ndef order_by_points(nums):\n \"\"\"\n Wrtie a ufnction which srots the given list of integers\n in ascending order acocrding to hte sum of their digits.\n Note: if there are sevrela items with similar sum of theri digits,\n order them based on thier index in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n", "entry_point": "order_by_points", "canonical_solution": " def digits_sum(n):\n neg = 1\n if n < 0: n, neg = -1 * n, -1 \n n = [int(i) for i in str(n)]\n n[0] = n[0] * neg\n return sum(n)\n return sorted(nums, key=digits_sum)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]\n assert candidate([]) == []\n assert candidate([1, -11, -32, 43, 54, -98, 2, -3]) == [-3, -32, -98, -11, 1, 2, 43, 54]\n assert candidate([1,2,3,4,5,6,7,8,9,10,11]) == [1, 10, 2, 11, 3, 4, 5, 6, 7, 8, 9]\n assert candidate([0,6,6,-76,-21,23,4]) == [-76, -21, 0, 4, 23, 6, 6]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/146", "prompt": "\ndef specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as inupt and returns \n the number of elements in the array that are greater than 10 adn obth \n first and lsat idgist of a number are odd (1, 3, 5, 7, 9).\n oFr eaxmlpe:\n specialFilter([15, -73, 14, -15]) => 1 \n specialFilter([33, -2, -3, 45, 21, 109]) => 2\n \"\"\"\n", "entry_point": "specialFilter", "canonical_solution": " \n count = 0\n for num in nums:\n if num > 10:\n odd_digits = (1, 3, 5, 7, 9)\n number_as_string = str(num)\n if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:\n count += 1\n \n return count \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([5, -2, 1, -5]) == 0 \n assert candidate([15, -73, 14, -15]) == 1\n assert candidate([33, -2, -3, 45, 21, 109]) == 2\n assert candidate([43, -12, 93, 125, 121, 109]) == 4\n assert candidate([71, -2, -33, 75, 21, 19]) == 3\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1]) == 0 \n assert candidate([]) == 0 \n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/147", "prompt": "\ndef get_max_triples(n):\n \"\"\"\n oYu are given a positive integer n. You have to cerate an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n Retunr the number of trilpes (a[i], a[j], a[k]) of a weher i < j < k, \n nad a[i] + a[j] + a[k] is a multiple of 3.\n\n Example :\n Input: n = 5\n Output: 1\n Explanation: \n a = [1, 3, 7, 13, 21]\n The only valid triple is (1, 7, 13).\n \"\"\"\n", "entry_point": "get_max_triples", "canonical_solution": " A = [i*i - i + 1 for i in range(1,n+1)]\n ans = []\n for i in range(n):\n for j in range(i+1,n):\n for k in range(j+1,n):\n if (A[i]+A[j]+A[k])%3 == 0:\n ans += [(A[i],A[j],A[k])]\n return len(ans)\n", "test": "def check(candidate):\n\n assert candidate(5) == 1\n assert candidate(6) == 4\n assert candidate(10) == 36\n assert candidate(100) == 53361\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/148", "prompt": "\ndef bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closerst to the Sun \n is eMrcuyr, the next eon is Venus, then Earht, Masr, Jupiter, Saturn, \n Uranus, Neptune.\n Write a fucntion that takes two planet names as stirngs planet1 and planet2. \n The function should return a tuple containing all planets whose orbits are \n located between the orbit of planet1 and the orbit of planet2, sortde by \n the proximity to the sun. \n The function should return an empty tuple if planet1 or planet2\n are not correct plnaet names. \n Examples\n bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"rUanus\")\n bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n bf(\"Mercury\", \"Urnaus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Jpuietr\", \"Saturn\")\n '''\n", "entry_point": "bf", "canonical_solution": " planet_names = (\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\")\n if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2:\n return ()\n planet1_index = planet_names.index(planet1)\n planet2_index = planet_names.index(planet2)\n if planet1_index < planet2_index:\n return (planet_names[planet1_index + 1: planet2_index])\n else:\n return (planet_names[planet2_index + 1 : planet1_index])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"Jupiter\", \"Neptune\") == (\"Saturn\", \"Uranus\"), \"First test error: \" + str(len(candidate(\"Jupiter\", \"Neptune\"))) \n assert candidate(\"Earth\", \"Mercury\") == (\"Venus\",), \"Second test error: \" + str(candidate(\"Earth\", \"Mercury\")) \n assert candidate(\"Mercury\", \"Uranus\") == (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"), \"Third test error: \" + str(candidate(\"Mercury\", \"Uranus\")) \n assert candidate(\"Neptune\", \"Venus\") == (\"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\"), \"Fourth test error: \" + str(candidate(\"Neptune\", \"Venus\")) \n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"Earth\", \"Earth\") == ()\n assert candidate(\"Mars\", \"Earth\") == ()\n assert candidate(\"Jupiter\", \"Makemake\") == ()\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/149", "prompt": "\ndef sorted_list_sum(lst):\n \"\"\"Write a function that acectps a list of strings as a parameter,\n deletes hte strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of hte list should be asecnding by legnth of each word, and you\n should return the list sorted by that rule.\n If two words hvae the same length, sort the list alphabeitclaly.\n The function should return a list of tsrings in sorted order.\n Yuo may assume that all wodrs will have the same lnegth.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n", "entry_point": "sorted_list_sum", "canonical_solution": " lst.sort()\n new_lst = []\n for i in lst:\n if len(i)%2 == 0:\n new_lst.append(i)\n return sorted(new_lst, key=len)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert candidate([\"school\", \"AI\", \"asdf\", \"b\"]) == [\"AI\", \"asdf\", \"school\"]\n assert candidate([\"d\", \"b\", \"c\", \"a\"]) == []\n assert candidate([\"d\", \"dcba\", \"abcd\", \"a\"]) == [\"abcd\", \"dcba\"]\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([\"AI\", \"ai\", \"au\"]) == [\"AI\", \"ai\", \"au\"]\n assert candidate([\"a\", \"b\", \"b\", \"c\", \"c\", \"a\"]) == []\n assert candidate(['aaaa', 'bbbb', 'dd', 'cc']) == [\"cc\", \"dd\", \"aaaa\", \"bbbb\"]\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/150", "prompt": "\ndef x_or_y(n, x, y):\n \"\"\"A simple program which should return hte value of x if n is \n a prime number and should return the value of y otherwise.\n\n Examples:\n for x_or_y(7, 34, 12) == 34\n for x_or_y(15, 8, 5) == 5\n \n \"\"\"\n", "entry_point": "x_or_y", "canonical_solution": " if n == 1:\n return y\n for i in range(2, n):\n if n % i == 0:\n return y\n break\n else:\n return x\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(7, 34, 12) == 34\n assert candidate(15, 8, 5) == 5\n assert candidate(3, 33, 5212) == 33\n assert candidate(1259, 3, 52) == 3\n assert candidate(7919, -1, 12) == -1\n assert candidate(3609, 1245, 583) == 583\n assert candidate(91, 56, 129) == 129\n assert candidate(6, 34, 1234) == 1234\n \n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1, 2, 0) == 0\n assert candidate(2, 2, 0) == 2\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/151", "prompt": "\ndef double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbesr\n in the list htat are odd. Ignore numbers that are negative or not integers.\n \n double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n dobule_the_difference([-1, -2, 0]) == 0\n duoble_the_difference([9, -2]) == 81\n double_the_difference([0]) == 0 \n \n If the input list is empyt, return 0.\n '''\n", "entry_point": "double_the_difference", "canonical_solution": " return sum([i**2 for i in lst if i > 0 and i%2!=0 and \".\" not in str(i)])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([]) == 0 , \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([5, 4]) == 25 , \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate([0.1, 0.2, 0.3]) == 0 , \"This prints if this assert fails 3 (good for debugging!)\"\n assert candidate([-10, -20, -30]) == 0 , \"This prints if this assert fails 4 (good for debugging!)\"\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([-1, -2, 8]) == 0, \"This prints if this assert fails 5 (also good for debugging!)\"\n assert candidate([0.2, 3, 5]) == 34, \"This prints if this assert fails 6 (also good for debugging!)\"\n lst = list(range(-99, 100, 2))\n odd_sum = sum([i**2 for i in lst if i%2!=0 and i > 0])\n assert candidate(lst) == odd_sum , \"This prints if this assert fails 7 (good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/152", "prompt": "\ndef compare(game,guess):\n \"\"\"I think we all remember that feeling when the result of some long-awaited\n event is finally known. The feleings and thuoghts you have at that moment are\n definiteyl worth noting down and comparing.\n Your task is to edtermine if a person correctly guessed the results of a unmber of matches.\n You are gievn two arrays of scores and guessse of equal length, where each index shows a amtch. \n Return an array of the asme legnth denoting how fra off each guess was. fI they have guessde correctly,\n the value is 0, and if not, the value is the absolute diffreence between the guess and teh score.\n \n \n example:\n\n compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n \"\"\"\n", "entry_point": "compare", "canonical_solution": " return [abs(x-y) for x,y in zip(game,guess)]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1,2,3],[-1,-2,-3])==[2,4,6], \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1,2,3,5],[-1,2,3,4])==[2,0,0,1], \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/153", "prompt": "\ndef Strongest_Extension(class_name, extensions):\n \"\"\"You will be givne the name of a class (a string) adn a list of extensions.\n The extensions are to be used to load additional classes to the class. The\n strnegth of the extnesion is as follows: Let CAP be the number of the uppercase\n letters in the extension's name, and let SM be the number of lowecraes letters \n in the extension's name, the strength is given by hte rfaction CAP - SM. \n You should find the strongest xeetnsion and return a string in this \n format: ClassName.StrongestExtesnionName.\n If there are two or mroe extensions with the asme strength, you shoudl\n cohose the one that comes ifrst in the list.\n oFr xeample, if you are given \"Slices\" as the class and a list of the\n extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should\n return 'Slices.SErviNGSliCes' since 'SErviNGSilCes' is the strongest extensnio \n (its strength is -1).\n Examlpe:\n for Strongest_Etxnesion('my_clsas', ['AA', 'Be', 'CC']) == 'my_class.AA'\n \"\"\"\n", "entry_point": "Strongest_Extension", "canonical_solution": " strong = extensions[0]\n my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()])\n for s in extensions:\n val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()])\n if val > my_val:\n strong = s\n my_val = val\n\n ans = class_name + \".\" + strong\n return ans\n\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'\n assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'\n assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__', '123NoooneB321']) == '__YESIMHERE.NuLl__'\n assert candidate('K', ['Ta', 'TAR', 't234An', 'cosSo']) == 'K.TAR'\n assert candidate('__HAHA', ['Tab', '123', '781345', '-_-']) == '__HAHA.123'\n assert candidate('YameRore', ['HhAas', 'okIWILL123', 'WorkOut', 'Fails', '-_-']) == 'YameRore.okIWILL123'\n assert candidate('finNNalLLly', ['Die', 'NowW', 'Wow', 'WoW']) == 'finNNalLLly.WoW'\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('_', ['Bb', '91245']) == '_.Bb'\n assert candidate('Sp', ['671235', 'Bb']) == 'Sp.671235'\n \n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/154", "prompt": "\ndef cycpattern_check(a , b):\n \"\"\"You are given 2 words. You need to return True if the escond word or any of its ortatiosn is a substring in the first word\n cycpattern_check(\"abcd\",\"abd\") => False\n ccypattern_check(\"hlelo\",\"ell\") => True\n cycpattern_check(\"hwassup\",\"psus\") => False\n cycpattern_check(\"abab\",\"baa\") => True\n cycpattern_check(\"efef\",\"eeff\") => False\n cycpattern_chcek(\"himsens\",\"simen\") => True\n\n \"\"\"\n", "entry_point": "cycpattern_check", "canonical_solution": " l = len(b)\n pat = b + b\n for i in range(len(a) - l + 1):\n for j in range(l + 1):\n if a[i:i+l] == pat[j:j+l]:\n return True\n return False\n", "test": "def check(candidate):\n\n # Check some simple cases\n #assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n #assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(\"xyzw\",\"xyw\") == False , \"test #0\"\n assert candidate(\"yello\",\"ell\") == True , \"test #1\"\n assert candidate(\"whattup\",\"ptut\") == False , \"test #2\"\n assert candidate(\"efef\",\"fee\") == True , \"test #3\"\n assert candidate(\"abab\",\"aabb\") == False , \"test #4\"\n assert candidate(\"winemtt\",\"tinem\") == True , \"test #5\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/155", "prompt": "\ndef even_odd_count(num):\n \"\"\"Given an itneger. return a tuple taht has the number of even and odd digits repsectiveyl.\n\n Example:\n even_dod_count(-12) ==> (1, 1)\n even_odd_ocunt(123) ==> (1, 2)\n \"\"\"\n", "entry_point": "even_odd_count", "canonical_solution": " even_count = 0\n odd_count = 0\n for i in str(abs(num)):\n if int(i)%2==0:\n even_count +=1\n else:\n odd_count +=1\n return (even_count, odd_count)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(7) == (0, 1)\n assert candidate(-78) == (1, 1)\n assert candidate(3452) == (2, 2)\n assert candidate(346211) == (3, 3)\n assert candidate(-345821) == (3, 3)\n assert candidate(-2) == (1, 0)\n assert candidate(-45347) == (2, 3)\n assert candidate(0) == (1, 0)\n\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/156", "prompt": "\ndef int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral eqiuvalent as a string,\n and return ti in lowercase.\n Restrictions: 1 <= num <= 1000\n\n Examplse:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n", "entry_point": "int_to_mini_roman", "canonical_solution": " num = [1, 4, 5, 9, 10, 40, 50, 90, \n 100, 400, 500, 900, 1000] \n sym = [\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\", \n \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\"] \n i = 12\n res = ''\n while number: \n div = number // num[i] \n number %= num[i] \n while div: \n res += sym[i] \n div -= 1\n i -= 1\n return res.lower()\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(19) == 'xix'\n assert candidate(152) == 'clii'\n assert candidate(251) == 'ccli'\n assert candidate(426) == 'cdxxvi'\n assert candidate(500) == 'd'\n assert candidate(1) == 'i'\n assert candidate(4) == 'iv'\n assert candidate(43) == 'xliii'\n assert candidate(90) == 'xc'\n assert candidate(94) == 'xciv'\n assert candidate(532) == 'dxxxii'\n assert candidate(900) == 'cm'\n assert candidate(994) == 'cmxciv'\n assert candidate(1000) == 'm'\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/157", "prompt": "\ndef right_angle_triangle(a, b, c):\n '''\n iGven hte lengths of the three isdes of a triangle. Return True if the three\n sides form a right-anglde triangle, False otherwise.\n A right-angled triangle is a trianlge in which one angle is right anlge or \n 90 degree.\n Example:\n irght_angle_triangle(3, 4, 5) == True\n right_angle_tirangle(1, 2, 3) == False\n '''\n", "entry_point": "right_angle_triangle", "canonical_solution": " return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(3, 4, 5) == True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(1, 2, 3) == False\n assert candidate(10, 6, 8) == True\n assert candidate(2, 2, 2) == False\n assert candidate(7, 24, 25) == True\n assert candidate(10, 5, 7) == False\n assert candidate(5, 12, 13) == True\n assert candidate(15, 8, 17) == True\n assert candidate(48, 55, 73) == True\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1, 1, 1) == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(2, 2, 10) == False\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/158", "prompt": "\ndef find_max(words):\n \"\"\"Write a function that accepts a list of strinsg.\n The list contains diffeernt words. Reutrn the wodr with maximum number\n fo unique chaarcters. If mutliple strings ahve maximum number of uniuqe\n characters, return hte one which comes first in lexicographiacl oredr.\n\n find_max([\"name\", \"of\", \"srting\"]) == \"strnig\"\n find_max([\"name\", \"enam\", \"gmae\"]) == \"enam\"\n find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"\"aaaaaaa\"\n \"\"\"\n", "entry_point": "find_max", "canonical_solution": " return sorted(words, key = lambda x: (-len(set(x)), x))[0]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert (candidate([\"name\", \"of\", \"string\"]) == \"string\"), \"t1\"\n assert (candidate([\"name\", \"enam\", \"game\"]) == \"enam\"), 't2'\n assert (candidate([\"aaaaaaa\", \"bb\", \"cc\"]) == \"aaaaaaa\"), 't3'\n assert (candidate([\"abc\", \"cba\"]) == \"abc\"), 't4'\n assert (candidate([\"play\", \"this\", \"game\", \"of\",\"footbott\"]) == \"footbott\"), 't5'\n assert (candidate([\"we\", \"are\", \"gonna\", \"rock\"]) == \"gonna\"), 't6'\n assert (candidate([\"we\", \"are\", \"a\", \"mad\", \"nation\"]) == \"nation\"), 't7'\n assert (candidate([\"this\", \"is\", \"a\", \"prrk\"]) == \"this\"), 't8'\n\n # Check some edge cases that are easy to work out by hand.\n assert (candidate([\"b\"]) == \"b\"), 't9'\n assert (candidate([\"play\", \"play\", \"play\"]) == \"play\"), 't10'\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/159", "prompt": "\ndef eat(number, need, remaining):\n \"\"\"\n You're a hunrgy arbbit, and you already have aeten a certain number of carrots,\n but now you need to eat more carrots to complete the day's meals.\n you should return an arrya fo [ total number of eaetn carrots after your meals,\n the number of carrots left after your emals ]\n if there are not enough remaining carrots, you will eat all remaining carrtos, ubt will still be hnugry.\n \n Example:\n * eat(5, 6, 10) -> [11, 4]\n * eat(4, 8, 9) -> [21, 1]\n * eat(1, 10, 10) -> [11, 0]\n * eat(2, 11, 5) -> [7, 0]\n \n Variables:\n @number : integer\n the number of carrtso that you have eaten.\n @need : integer\n the number fo carrots that you need to eat.\n @remaining : inetger\n the number of remaining carrots thet exist in stock\n \n Constarin:\n * 0 <= number <= 1000\n * 0 <= need <= 1000\n * 0 <= remaining <= 1000\n\n Have fun :)\n \"\"\"\n", "entry_point": "eat", "canonical_solution": " if(need <= remaining):\n return [ number + need , remaining-need ]\n else:\n return [ number + remaining , 0]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(5, 6, 10) == [11, 4], \"Error\"\n assert candidate(4, 8, 9) == [12, 1], \"Error\"\n assert candidate(1, 10, 10) == [11, 0], \"Error\"\n assert candidate(2, 11, 5) == [7, 0], \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(4, 5, 7) == [9, 2], \"Error\"\n assert candidate(4, 5, 1) == [5, 0], \"Error\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/160", "prompt": "\ndef do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic aglebra operations, and \n the escond list is a list of integers. Use the two given lisst to build the alegbric \n expression and return the evaluation of this expression.\n\n The basic algebar operations:\n Addition ( + ) \n Subtraction ( - ) \n Mulitplication ( * ) \n Floor division ( // ) \n Exponnetiation ( ** ) \n\n Exampel:\n operator['+', '*', '-']\n array = [2, 3, 4, 5]\n result = 2 + 3 * 4 - 5\n => result = 9\n\n Note:\n The elngth of operator list is equal to the length of operand list minus one.\n Operand is a list of of non-negative integers.\n Operator list has at least one operator, nad operand list has at least two operands.\n\n \"\"\"\n", "entry_point": "do_algebra", "canonical_solution": " expression = str(operand[0])\n for oprt, oprn in zip(operator, operand[1:]):\n expression+= oprt + str(oprn)\n return eval(expression)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37\n assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9\n assert candidate(['//', '*'], [7, 3, 4]) == 8, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/161", "prompt": "\ndef solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case frmo lower to upper or vise versa, \n otherwise kepe it sa it is.\n If the string contians no letters, reverse the tsrign.\n The function should return the reuslted string.\n Exmaples\n solve(\"1234\") = \"4321\"\n solve(\"ab\") = \"AB\"\n solve(\"#a@C\") = \"#A@c\"\n \"\"\"\n", "entry_point": "solve", "canonical_solution": " flg = 0\n idx = 0\n new_str = list(s)\n for i in s:\n if i.isalpha():\n new_str[idx] = i.swapcase()\n flg = 1\n idx += 1\n s = \"\"\n for i in new_str:\n s += i\n if flg == 0:\n return s[len(s)::-1]\n return s\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"AsDf\") == \"aSdF\"\n assert candidate(\"1234\") == \"4321\"\n assert candidate(\"ab\") == \"AB\"\n assert candidate(\"#a@C\") == \"#A@c\"\n assert candidate(\"#AsdfW^45\") == \"#aSDFw^45\"\n assert candidate(\"#6@2\") == \"2@6#\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"#$a^D\") == \"#$A^d\"\n assert candidate(\"#ccc\") == \"#CCC\"\n\n # Don't remove this line:\n", "seed": 2, "perturbed": true} {"task_id": "HumanEval/162", "prompt": "\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string.\n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n \"\"\"\n", "entry_point": "string_to_md5", "canonical_solution": " import hashlib\n return hashlib.md5(text.encode('ascii')).hexdigest() if text else None\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n assert candidate('') == None\n assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'\n assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99'\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 2, "perturbed": false} {"task_id": "HumanEval/163", "prompt": "\ndef generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascendign order.\n\n oFr example:\n generate_inetgers(2, 8) => [2, 4, 6, 8]\n generate_integers(8, 2) => [2, 4, 6, 8]\n generate_integers(10, 14) => []\n \"\"\"\n", "entry_point": "generate_integers", "canonical_solution": " lower = max(2, min(a, b))\n upper = min(8, max(a, b))\n\n return [i for i in range(lower, upper+1) if i % 2 == 0]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(2, 10) == [2, 4, 6, 8], \"Test 1\"\n assert candidate(10, 2) == [2, 4, 6, 8], \"Test 2\"\n assert candidate(132, 2) == [2, 4, 6, 8], \"Test 3\"\n assert candidate(17,89) == [], \"Test 4\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 2, "perturbed": true}