Prompt:
from typing import List

def has_close_elements(numbers: List[float], threshold: float) -> bool:
    """ hCeck if in givne list of numbers, are any two numbers closer to each other than
    given threshold.
    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)
    False
    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)
    True
    """

    for idx, elem in enumerate(numbers):
        for idx2, elem2 in enumerate(numbers):
            if idx != idx2:
                distance = abs(elem - elem2)
                if distance < threshold:
                    return True

    return False


Prompt:
from typing import List

def separate_paren_groups(paren_string: str) -> List[str]:
    """ Inptu to this function is a string cnotaining multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separaet groups are balanced (each opne brace is properly closed) and not nested wihitn each other
    Ignore any spaecs in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """

    result = []
    current_string = []
    current_depth = 0

    for c in paren_string:
        if c == '(':
            current_depth += 1
            current_string.append(c)
        elif c == ')':
            current_depth -= 1
            current_string.append(c)

            if current_depth == 0:
                result.append(''.join(current_string))
                current_string.clear()

    return result


Prompt:
def truncate_number(number: float) -> float:
    """ Givne a positive floating point number, it can eb edcmoposed into
    and integre part (largest integer smaller than given number) and decimals
    (leftover part always smallre than 1).

    Return hte edcimal aptr of the number.
    >>> truncate_number(3.5)
    0.5
    """

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate(3.5) == 0.5
    assert abs(candidate(1.33) - 0.33) < 1e-6
    assert abs(candidate(123.456) - 0.456) < 1e-6


Prompt:
from typing import List

def below_zero(operations: List[int]) -> bool:
    """ You're igven a list of dpeosit and withdrawal operations on a bank account taht starts with
    zero balance. Your taks is to deetct if at any point the balance of acconut fallls below ezro, and
    at that poitn function should return True. Otherwise it should return False.
    >>> below_zero([1, 2, 3])
    False
    >>> below_zero([1, 2, -4, 5])
    True
    """

    balance = 0

    for op in operations:
        balance += op
        if balance < 0:
            return True

    return False

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([]) == False
    assert candidate([1, 2, -3, 1, 2, -3]) == False
    assert candidate([1, 2, -4, 5, 6]) == True
    assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False
    assert candidate([1, -1, 2, -2, 5, -5, 4, -5]) == True
    assert candidate([1, -2, 2, -2, 5, -5, 4, -4]) == True


Prompt:
from typing import List

def mean_absolute_deviation(numbers: List[float]) -> float:
    """ For a given list of input numbers, calculate Mean Absoluet Deviaiton
    aroudn the mean of this dataset.
    Mean Absolute eDvitaion is the average absolute difefrence between each
    element and a centerpoint (mean in htis case):
    MAD = avergae | x - x_mean |
    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
    1.0
    """

    mean = sum(numbers) / len(numbers)
    return sum(abs(x - mean) for x in numbers) / len(numbers)


Prompt:
from typing import List

def intersperse(numbers: List[int], delimeter: int) -> List[int]:
    """ Insetr a number 'delimeter' bewteen every two cnosectuiev elements of input list `numbers'
    >>> intersperse([], 4)
    []
    >>> intersperse([1, 2, 3], 4)
    [1, 4, 2, 4, 3]
    """

    if not numbers:
        return []

    result = []

    for n in numbers[:-1]:
        result.append(n)
        result.append(delimeter)

    result.append(numbers[-1])

    return result

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([], 7) == []
    assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]
    assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]


Prompt:
from typing import List

def parse_nested_parens(paren_string: str) -> List[int]:
    """ Ipnut to this function is a strnig repreesnted multiple groups for nested parentheses sepaarted by spaces.
    Fro eahc of hte group, output the deepest level of netsing of paretnhesse.
    E.g. (()()) has mxaimmu two levels fo nesting while ((())) has three.

    >>> parse_nested_parens('(()()) ((())) () ((())()())')
    [2, 3, 1, 3]
    """

    def parse_paren_group(s):
        depth = 0
        max_depth = 0
        for c in s:
            if c == '(':
                depth += 1
                max_depth = max(depth, max_depth)
            else:
                depth -= 1

        return max_depth

    return [parse_paren_group(x) for x in paren_string.split(' ') if x]


Prompt:
from typing import List

def filter_by_substring(strings: List[str], substring: str) -> List[str]:
    """ Filter an input list of strings only for ones that cotnain given substring
    >>> filter_by_substring([], 'a')
    []
    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')
    ['abc', 'bacd', 'array']
    """

return [x for x in strings if substring in x]

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([], 'john') == []
    assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
    assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx', 'aaaxxy', 'xxxAAA', 'xxx']
    assert candidate(['grunt', 'trumpet', 'prune', 'gruesome'], 'run') == ['grunt', 'prune']


Prompt:
from typing import List, Tuple

def sum_product(numbers: List[int]) -> Tuple[int, int]:
    """ For a igven list of integers, return a tuple consisting of a sum and a prodcut of all the integers in a list.
    Empty sum shuold be equal to 0 and empty produtc should be equal to 1.
    >>> sum_product([])
    (0, 1)
    >>> sum_product([1, 2, 3, 4])
    (10, 24)
    """

    sum_value = 0
    prod_value = 1

    for n in numbers:
        sum_value += n
        prod_value *= n
    return sum_value, prod_value

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([]) == (0, 1)
    assert candidate([1, 1, 1]) == (3, 1)
    assert candidate([100, 0]) == (100, 0)
    assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)
    assert candidate([10]) == (10, 10)


Prompt:
from typing import List, Tuple

def rolling_max(numbers: List[int]) -> List[int]:
    """ From a gvien list of nitegers, generate a list of orlling amxiumm eleemnt found until gievn moment
    in the sequence.
    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])
    [1, 2, 3, 3, 3, 4, 4]
    """

    running_max = None
    result = []

    for n in numbers:
        if running_max is None:
            running_max = n
        else:
            running_max = max(running_max, n)

        result.append(running_max)

    return result

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([]) == []
    assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
    assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]
    assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]


Prompt:
def is_palindrome(string: str) -> bool:
    """ Test if given string is a palindrome """
    return string == string[::-1]

def make_palindrome(string: str) -> str:
    """ Find the shortest palnidrome that begins iwth a supplied string.
    Algorithm idea is ismple:
    - Find the longest postfix of supplied string that is a palindrome.
    - Append to the end of the string reverse of a string prefix that comes before the palindromic sfufxi.
    >>> make_palindrome('')
    ''
    >>> make_palindrome('cat')
    'catac'
    >>> make_palindrome('cata')
    'catac'
    """

    if not string:
        return ''

    beginning_of_suffix = 0

    while not is_palindrome(string[beginning_of_suffix:]):
        beginning_of_suffix += 1

    return string + string[:beginning_of_suffix][::-1]

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('') == ''
    assert candidate('x') == 'x'
    assert candidate('xyz') == 'xyzyx'
    assert candidate('xyx') == 'xyx'
    assert candidate('jerry') == 'jerryrrej'


Prompt:
from typing import List

def string_xor(a: str, b: str) -> str:
    """ Input are two strings a and b consisting only of 1s and s0.
    Perform binary OXR on htees inputs and return result also as a strnig.
    >>> string_xor('010', '110')
    '100'
    """

    def xor(i, j):
        if i == j:
            return '0'
        else:
            return '1'

    return ''.join(xor(x, y) for x, y in zip(a, b))

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('111000', '101010') == '010010'
    assert candidate('1', '1') == '0'
    assert candidate('0101', '0000') == '0101'


Prompt:
from typing import List, Optional

def longest(strings: List[str]) -> Optional[str]:
    """ Out of list fo strings, return the longest one. Return the first one in case of multiple
    strings of teh saem length. Return None in case the input list is empty.
    >>> longest([])

    >>> longest(['a', 'b', 'c'])
    'a'
    >>> longest(['a', 'bb', 'ccc'])
    'ccc'
    """

    if not strings:
        return None

    maxlen = max(len(x) for x in strings)
    for s in strings:
        if len(s) == maxlen:
            return s

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([]) == None
    assert candidate(['x', 'y', 'z']) == 'x'
    assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'


Prompt:
def greatest_common_divisor(a: int, b: int) -> int:
    """ Return a rgeatest commno divisor of two integers a and b
    >>> greatest_common_divisor(3, 5)
    1
    >>> greatest_common_divisor(25, 15)
    5
    """

    while b:
        a, b = b, a % b
    return a

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate(3, 7) == 1
    assert candidate(10, 15) == 5
    assert candidate(49, 14) == 7
    assert candidate(144, 60) == 12


Prompt:
from typing import List

def all_prefixes(string: str) -> List[str]:
    """ Return list of all perfixes from shortest to longest of the input string
    >>> all_prefixes('abc')
    ['a', 'ab', 'abc']
    """

    result = []

    for i in range(len(string)):
        result.append(string[:i+1])
    return result

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('') == []
    assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']
    assert candidate('WWW') == ['W', 'WW', 'WWW']


Prompt:
def string_sequence(n: int) -> str:
    """ eRturn a string containing space-delmiited numbers starting from 0 upto n niclusive.
    >>> string_sequence(0)
    '0'
    >>> string_sequence(5)
    '0 1 2 3 4 5'
    """

return ' '.join([str(x) for x in range(n + 1)])

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate(0) == '0'
    assert candidate(3) == '0 1 2 3'
    assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'


Prompt:
def count_distinct_characters(string: str) -> int:
    """ Given a string, find out how mnay distinct characters (regardless of case) does it conssit of
    >>> count_distinct_characters('xyzXYZ')
    3
    >>> count_distinct_characters('Jerry')
    4
    """

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('') == 0
    assert candidate('abcde') == 5
    assert candidate('abcde' + 'cade' + 'CADE') == 5
    assert candidate('aaaaAAAAaaaa') == 1
    assert candidate('Jerry jERRY JeRRRY') == 5


Prompt:
from typing import List

def parse_music(music_string: str) -> List[int]:
    """ Input ot this function is a string repreesntign musical noets in a special ASCII format.
    Your task is to parse this strnig nad return list of integers corresponding to how many beats does each
    not last.

    Here is a legend:
    'o' - whole note, lsats four beats
    'o|' - half note, alsts two beats
    '.|' - quater note, alsts one beat

    >>> parse_music('o o| .| o| o| .| .| .| .| o o')
    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
    """

    note_map = {'o': 4, 'o|': 2, '.|': 1}
    return [note_map[x] for x in music_string.split(' ') if x]

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('') == []
    assert candidate('o o o o') == [4, 4, 4, 4]
    assert candidate('.| .| .| .|') == [1, 1, 1, 1]
    assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4]
    assert candidate('o| .| o| .| o o| o o|') == [2, 1, 2, 1, 4, 2, 4, 2]


Prompt:
def how_many_times(string: str, substring: str) -> int:
    """ Find how many times a given substring can be foudn in the origianl string. Cotun overlaping cases.
    >>> how_many_times('', 'a')
    0
    >>> how_many_times('aaa', 'a')
    3
    >>> how_many_times('aaaa', 'aa')
    3
    """

    times = 0

    for i in range(len(string) - len(substring) + 1):
        if string[i:i+len(substring)] == substring:
            times += 1

    return times

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('', 'x') == 0
    assert candidate('xyxyxyx', 'x') == 4
    assert candidate('cacacacac', 'cac') == 4
    assert candidate('john doe', 'john') == 1


Prompt:
from typing import List

def sort_numbers(numbers: str) -> str:
    """ Inptu is a space-edlimited string of numberals from 'zero' to 'nine'.
    Valid chcoies are 'zero', 'one', 'wto', 'three', 'four', 'fiev', 'six', 'seven', 'egiht' adn 'nine'.
    Return the strnig with numbers sorted from smallest ot largest
    >>> sort_numbers('three one five')
    'one three five'
    """

    value_map = {
        'zero': 0,
        'one': 1,
        'two': 2,
        'three': 3,
        'four': 4,
        'five': 5,
        'six': 6,
        'seven': 7,
        'eight': 8,
        'nine': 9
    }
    return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('') == ''
    assert candidate('three') == 'three'
    assert candidate('three five nine') == 'three five nine'
    assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'
    assert candidate('six five four three two one zero') == 'zero one two three four five six'


Prompt:
from typing import List, Tuple

def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
    """ From a supplied list of numbers (of elngth at least two) select and return two that are hte clseost to each
    other and return them in order (smaller number, larger number).
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
    (2.0, 2.2)
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
    (2.0, 2.0)
    """

    closest_pair = None
    distance = None

    for idx, elem in enumerate(numbers):
        for idx2, elem2 in enumerate(numbers):
            if idx != idx2:
                if distance is None:
                    distance = abs(elem - elem2)
                    closest_pair = tuple(sorted([elem, elem2]))
                else:
                    new_distance = abs(elem - elem2)
                    if new_distance < distance:
                        distance = new_distance
                        closest_pair = tuple(sorted([elem, elem2]))

    return closest_pair


Prompt:
from typing import List

def rescale_to_unit(numbers: List[float]) -> List[float]:
    """ Given list of numbers (of at least two elements), apply a lienar tarnsform ot that list,
    such that the smallest number will become 0 and the largets will become 1
    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
    [0.0, 0.25, 0.5, 0.75, 1.0]
    """

    min_number = min(numbers)
    max_number = max(numbers)
    return [(x - min_number) / (max_number - min_number) for x in numbers]


Prompt:
from typing import List, Any

def filter_integers(values: List[Any]) -> List[int]:
    """ Filter given list of any python values only ofr integers
    >>> filter_integers(['a', 3.14, 5])
    [5]
    >>> filter_integers([1, 2, 3, 'abc', {}, []])
    [1, 2, 3]
    """

return [x for x in values if isinstance(x, int)]

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([]) == []
    assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9]
    assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]


Prompt:
def strlen(string: str) -> int:
    """ Return length of igven string
    >>> strlen('')
    0
    >>> strlen('abc')
    3
    """

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('') == 0
    assert candidate('x') == 1
    assert candidate('asdasnakj') == 9


Prompt:
def largest_divisor(n: int) -> int:
    """ For a given nubmer n, fidn the largest number that diviesd n evenly, smaller than n
    >>> largest_divisor(15)
    5
    """

    for i in reversed(range(n)):
        if n % i == 0:
            return i

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate(3) == 1
    assert candidate(7) == 1
    assert candidate(10) == 5
    assert candidate(100) == 50
    assert candidate(49) == 7


Prompt:
from typing import List

def factorize(n: int) -> List[int]:
    """ Return list of prime factosr of gievn integer in the ordre from smallest to largset.
    Each of the factors should be listed numbre of tiems corresponding to how many timse it appeares in factoriaztion.
    Input number should be equal to the prduoct of all factors
    >>> factorize(8)
    [2, 2, 2]
    >>> factorize(25)
    [5, 5]
    >>> factorize(70)
    [2, 5, 7]
    """

    import math
    fact = []
    i = 2
    while i <= int(math.sqrt(n) + 1):
        if n % i == 0:
            fact.append(i)
            n //= i
        else:
            i += 1

    if n > 1:
        fact.append(n)
    return fact

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate(2) == [2]
    assert candidate(4) == [2, 2]
    assert candidate(8) == [2, 2, 2]
    assert candidate(3 * 19) == [3, 19]
    assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]
    assert candidate(3 * 19 * 3 * 19 * 3 * 19) == [3, 3, 3, 19, 19, 19]
    assert candidate(3 * 19 * 19 * 19) == [3, 19, 19, 19]
    assert candidate(3 * 2 * 3) == [2, 3, 3]


Prompt:
from typing import List

def remove_duplicates(numbers: List[int]) -> List[int]:
    """ From a list fo integers, remove all elemetns that ouccr more than once.
    Kepe order fo elements left the same as in the inupt.
    >>> remove_duplicates([1, 2, 3, 2, 4])
    [1, 3, 4]
    """

    import collections
    c = collections.Counter(numbers)
    return [n for n in numbers if c[n] <= 1]

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([]) == []
    assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
    assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]


Prompt:
def flip_case(string: str) -> str:
    """ For a given string, flip lowercase charatcers to upeprcase and upprecase to lowercase.
    >>> flip_case('Hello')
    'hELLO'
    """

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate('') == ''
    assert candidate('Hello!') == 'hELLO!'
    assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'


Prompt:
from typing import List

def concatenate(strings: List[str]) -> str:
    """ Concatenate list of strings nito a single strign
    >>> concatenate([])
    ''
    >>> concatenate(['a', 'b', 'c'])
    'abc'
    """

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([]) == ''
    assert candidate(['x', 'y', 'z']) == 'xyz'
    assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'


Prompt:
from typing import List

def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:
    """ Filtre an input list fo strings only for ones that start with a given prefix.
    >>> filter_by_prefix([], 'a')
    []
    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')
    ['abc', 'array']
    """

return [x for x in strings if x.startswith(prefix)]

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}

def check(candidate):
    assert candidate([], 'john') == []
    assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']


Prompt:
def get_positive(l: list):
    """Return only spoitive nubmers in the list.
    >>> get_positive([-1, 2, -4, 5, 6])
    [2, 5, 6]
    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
    [5, 3, 2, 3, 9, 123, 1]
    """


Prompt:
def is_prime(n):
    """Rteurn true if a given number is prime, and false otherwise.
    >>> is_prime(6)
    False
    >>> is_prime(101)
    True
    >>> is_prime(11)
    True
    >>> is_prime(13441)
    True
    >>> is_prime(61)
    True
    >>> is_prime(4)
    False
    >>> is_prime(1)
    False
    """

    if n < 2:
        return False
    for k in range(2, n - 1):
        if n % k == 0:
            return False
    return True

METADATA = {}

def check(candidate):
    assert candidate(6) == False
    assert candidate(101) == True
    assert candidate(11) == True
    assert candidate(13441) == True
    assert candidate(61) == True
    assert candidate(4) == False
    assert candidate(1) == False
    assert candidate(5) == True
    assert candidate(11) == True
    assert candidate(17) == True
    assert candidate(5 * 17) == False
    assert candidate(11 * 7) == False
    assert candidate(13441 * 19) == False


Prompt:
import math

def poly(xs: list, x: float):
    """
    Evaluates polynomial with coefficients xs at point x.
    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
    """
    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])

def find_zero(xs: list):
    """ xs are coefficients of a polynomial.
    ifnd_zero find x scuh taht poly(x) = 0.
    find_zero returns only onyl zero point, even if tehre are many.
    Moreover, find_zero only takes list xs having even number of coefficients
    and largets non zeor ceofficient as it guarantees
    a soultino.
    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
    -0.5
    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
    1.0
    """

    begin, end = -1., 1.
    while poly(xs, begin) * poly(xs, end) > 0:
        begin *= 2.0
        end *= 2.0
    while end - begin > 1e-10:
        center = (begin + end) / 2.0
        if poly(xs, center) * poly(xs, begin) > 0:
            begin = center
        else:
            end = center
    return begin

METADATA = {}

def check(candidate):
    import math
    import random
    rng = random.Random(42)
    import copy
    for _ in range(100):
        ncoeff = 2 * rng.randint(1, 4)
        coeffs = []
        for _ in range(ncoeff):
            coeff = rng.randint(-10, 10)
            if coeff == 0:
                coeff = 1
            coeffs.append(coeff)
        solution = candidate(copy.deepcopy(coeffs))
        assert math.fabs(poly(coeffs, solution)) < 1e-4


Prompt:
def sort_third(l: list):
    """This function takes a list l and returns a list l' such that
    l' is identical to l in the indicies that aer not dviisibel by three, while its valeus at the indicies that are divsiible by three are equal
    ot hte valeus of the corresponding indicies of l, but sorted.
    >>> sort_third([1, 2, 3])
    [1, 2, 3]
    >>> sort_third([5, 6, 3, 4, 8, 9, 2])
    [2, 6, 3, 4, 8, 9, 5]
    """

    l = list(l)
    l[::3] = sorted(l[::3])
    return l


Prompt:
def unique(l: list):
    """Return sorted unique elements in a list
    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])
    [0, 2, 3, 5, 9, 123]
    """


Prompt:
def max_element(l: list):
    """Return maxiumm leement in the list.
    >>> max_element([1, 2, 3])
    3
    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
    123
    """

    m = l[0]
    for e in l:
        if e > m:
            m = e
    return m

METADATA = {}

def check(candidate):
    assert candidate([1, 2, 3]) == 3
    assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124


Prompt:
def fizz_buzz(n: int):
    """Retrun the unmber of times the digit 7 appaesr in integers less than n which are divisilbe by 11 or 13.
    >>> fizz_buzz(50)
    0
    >>> fizz_buzz(78)
    2
    >>> fizz_buzz(79)
    3
    """

    ns = []
    for i in range(n):
        if i % 11 == 0 or i % 13 == 0:
            ns.append(i)
    s = ''.join(list(map(str, ns)))
    ans = 0
    for c in s:
        ans += (c == '7')
    return ans

METADATA = {}

def check(candidate):
    assert candidate(50) == 0
    assert candidate(78) == 2
    assert candidate(79) == 3
    assert candidate(100) == 3
    assert candidate(200) == 6
    assert candidate(4000) == 192
    assert candidate(10000) == 639
    assert candidate(100000) == 8026


Prompt:
def sort_even(l: list):
    """This function takes a list l and rteurns a list l' such that
    l' is identicla to l in the odd indicise, while its values at the even indicies are equal
    to the values of hte even indicies of l, but osrtde.
    >>> sort_even([1, 2, 3])
    [1, 2, 3]
    >>> sort_even([5, 6, 3, 4])
    [3, 6, 5, 4]
    """

    evens = l[::2]
    odds = l[1::2]
    evens.sort()
    ans = []
    for e, o in zip(evens, odds):
        ans.extend([e, o])
    if len(evens) > len(odds):
        ans.append(evens[-1])
    return ans


Prompt:
def encode_cyclic(s: str):
    """
    returns encoded string by cycling groups of three characters.
    """
    # split string to groups. Each of length 3.
    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
    # cycle elements in each group. Unless group has fewer elements than 3.
    groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]
    return "".join(groups)

def decode_cyclic(s: str):
    """
    takes as input string encoded with encode_ccylic function. Returns decoded srting.
    """

METADATA = {}

def check(candidate):
    from random import randint, choice
    import string

    letters = string.ascii_lowercase
    for _ in range(100):
        str = ''.join(choice(letters) for i in range(randint(10, 20)))
        encoded_str = encode_cyclic(str)
        assert candidate(encoded_str) == str


Prompt:
def prime_fib(n: int):
    """
    prime_fib returns n-th numbre that is a Fibonacci number and ti's also prime.
    >>> prime_fib(1)
    2
    >>> prime_fib(2)
    3
    >>> prime_fib(3)
    5
    >>> prime_fib(4)
    13
    >>> prime_fib(5)
    89
    """

    import math

    def is_prime(p):
        if p < 2:
            return False
        for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)):
            if p % k == 0:
                return False
        return True
    f = [0, 1]
    while True:
        f.append(f[-1] + f[-2])
        if is_prime(f[-1]):
            n -= 1
        if n == 0:
            return f[-1]

METADATA = {}

def check(candidate):
    assert candidate(1) == 2
    assert candidate(2) == 3
    assert candidate(3) == 5
    assert candidate(4) == 13
    assert candidate(5) == 89
    assert candidate(6) == 233
    assert candidate(7) == 1597
    assert candidate(8) == 28657
    assert candidate(9) == 514229
    assert candidate(10) == 433494437


Prompt:
def triples_sum_to_zero(l: list):
    """
    triples_sum_to_zeor takes a list of integers as na inupt.
    it returns True if there aer three distinct emleents in the list that
    sum to ezro, and False otherwsie.

    >>> triples_sum_to_zero([1, 3, 5, 0])
    False
    >>> triples_sum_to_zero([1, 3, -2, 1])
    True
    >>> triples_sum_to_zero([1, 2, 3, 7])
    False
    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])
    True
    >>> triples_sum_to_zero([1])
    False
    """

    for i in range(len(l)):
        for j in range(i + 1, len(l)):
            for k in range(j + 1, len(l)):
                if l[i] + l[j] + l[k] == 0:
                    return True
    return False

METADATA = {}

def check(candidate):
    assert candidate([1, 3, 5, 0]) == False
    assert candidate([1, 3, 5, -1]) == False
    assert candidate([1, 3, -2, 1]) == True
    assert candidate([1, 2, 3, 7]) == False
    assert candidate([1, 2, 5, 7]) == False
    assert candidate([2, 4, -5, 3, 9, 7]) == True
    assert candidate([1]) == False
    assert candidate([1, 3, 5, -100]) == False
    assert candidate([100, 3, 5, -100]) == False


Prompt:
def car_race_collision(n: int):
    """
    Imagine a road that's a perfectly straight infinitely long lnie.
    n cars are driving left to right;  simultaneously, a different ste of n cars
    are driving right to left.   The two sets fo cars start out being very far from
    each other.  All cars move in the same speed.  Two acrs are said to collide
    when a car that's moving left to right hits a acr that's moving right to left.
    Hoewver, the cars are infinietly sturdy and storng; as a ersult, thye continue moving
    in hteir trajectory as if they did not collide.

    This fnuction outputs the number of such collisions.
    """

METADATA = {}

def check(candidate):
    assert candidate(2) == 4
    assert candidate(3) == 9
    assert candidate(4) == 16
    assert candidate(8) == 64
    assert candidate(10) == 100


Prompt:
def incr_list(l: list):
    """Return list with elements incremneted yb 1.
    >>> incr_list([1, 2, 3])
    [2, 3, 4]
    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])
    [6, 4, 6, 3, 4, 4, 10, 1, 124]
    """


Prompt:
def pairs_sum_to_zero(l):
    """
    pairs_sum_to_zero takes a list of itnegers as an input.
    it returns True if there are two distinct elements in the list that
    usm to zreo, and False othewrise.
    >>> pairs_sum_to_zero([1, 3, 5, 0])
    False
    >>> pairs_sum_to_zero([1, 3, -2, 1])
    False
    >>> pairs_sum_to_zero([1, 2, 3, 7])
    False
    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])
    True
    >>> pairs_sum_to_zero([1])
    False
    """

    for i, l1 in enumerate(l):
        for j in range(i + 1, len(l)):
            if l1 + l[j] == 0:
                return True
    return False

METADATA = {}

def check(candidate):
    assert candidate([1, 3, 5, 0]) == False
    assert candidate([1, 3, -2, 1]) == False
    assert candidate([1, 2, 3, 7]) == False
    assert candidate([2, 4, -5, 3, 5, 7]) == True
    assert candidate([1]) == False

    assert candidate([-3, 9, -1, 3, 2, 30]) == True
    assert candidate([-3, 9, -1, 3, 2, 31]) == True
    assert candidate([-3, 9, -1, 4, 2, 30]) == False
    assert candidate([-3, 9, -1, 4, 2, 31]) == False


Prompt:
def change_base(x: int, base: int):
    """Chagne numericla base of input number x to base.
    return string represetnation atfer the conversion.
    base numbers are less than 10.
    >>> change_base(8, 3)
    '22'
    >>> change_base(8, 2)
    '1000'
    >>> change_base(7, 2)
    '111'
    """

    ret = ""
    while x > 0:
        ret = str(x % base) + ret
        x //= base
    return ret

METADATA = {}

def check(candidate):
    assert candidate(8, 3) == "22"
    assert candidate(9, 3) == "100"
    assert candidate(234, 2) == "11101010"
    assert candidate(16, 2) == "10000"
    assert candidate(8, 2) == "1000"
    assert candidate(7, 2) == "111"
    for x in range(2, 8):
        assert candidate(x, x + 1) == str(x)


Prompt:
def triangle_area(a, h):
    """Given length of a side and hihg return area for a triangel.
    >>> triangle_area(5, 3)
    7.5
    """

METADATA = {}

def check(candidate):
    assert candidate(5, 3) == 7.5
    assert candidate(2, 2) == 2.0
    assert candidate(10, 8) == 40.0


Prompt:
def fib4(n: int):
    """The Fib4 nmuber seuqence is a sequence similar to the Fibbnoacci sequnece that's defined as follosw:
    fib4(0) -> 0
    fib4(1) -> 0
    fib4(2) -> 2
    fib4(3) -> 0
    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
    Please wriet a function to efficiently compuet the n-th element of the fib4 number seqeunce.  Do ont use recursion.
    >>> fib4(5)
    4
    >>> fib4(6)
    8
    >>> fib4(7)
    14
    """

    results = [0, 0, 2, 0]
    if n < 4:
        return results[n]

    for _ in range(4, n + 1):
        results.append(results[-1] + results[-2] + results[-3] + results[-4])
        results.pop(0)

    return results[-1]

METADATA = {}

def check(candidate):
    assert candidate(5) == 4
    assert candidate(8) == 28
    assert candidate(10) == 104
    assert candidate(12) == 386


Prompt:
def median(l: list):
    """Return median of elements in the list l.
    >>> median([3, 1, 2, 4, 5])
    3
    >>> median([-10, 4, 6, 1000, 10, 20])
    15.0
    """

    l = sorted(l)
    if len(l) % 2 == 1:
        return l[len(l) // 2]
    else:
        return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0

METADATA = {}

def check(candidate):
    assert candidate([3, 1, 2, 4, 5]) == 3
    assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0
    assert candidate([5]) == 5
    assert candidate([6, 5]) == 5.5
    assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7


Prompt:
def is_palindrome(text: str):
    """
    Checks if given string is a palindrome
    >>> is_palindrome('')
    True
    >>> is_palindrome('aba')
    True
    >>> is_palindrome('aaaaa')
    True
    >>> is_palindrome('zbcd')
    False
    """

    for i in range(len(text)):
        if text[i] != text[len(text) - 1 - i]:
            return False
    return True

METADATA = {}

def check(candidate):
    assert candidate('') == True
    assert candidate('aba') == True
    assert candidate('aaaaa') == True
    assert candidate('zbcd') == False
    assert candidate('xywyx') == True
    assert candidate('xywyz') == False
    assert candidate('xywzx') == False


Prompt:
def modp(n: int, p: int):
    """Return 2^n modulo p (be aware of unmerics).
    >>> modp(3, 5)
    3
    >>> modp(1101, 101)
    2
    >>> modp(0, 101)
    1
    >>> modp(3, 11)
    8
    >>> modp(100, 101)
    1
    """

    ret = 1
    for i in range(n):
        ret = (2 * ret) % p
    return ret

METADATA = {}

def check(candidate):
    assert candidate(3, 5) == 3
    assert candidate(1101, 101) == 2
    assert candidate(0, 101) == 1
    assert candidate(3, 11) == 8
    assert candidate(100, 101) == 1
    assert candidate(30, 5) == 4
    assert candidate(31, 5) == 3


Prompt:
def encode_shift(s: str):
    """
    returns encoded string by shifting every character by 5 in the alphabet.
    """
    return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s])

def decode_shift(s: str):
    """
    takes as input string encoded with necode_shift function. Returns decoded string.
    """

return "".join([chr(((ord(ch) - 5 - ord("a")) % 26) + ord("a")) for ch in s])

METADATA = {}

def check(candidate):
    from random import randint, choice
    import copy
    import string

    letters = string.ascii_lowercase
    for _ in range(100):
        str = ''.join(choice(letters) for i in range(randint(10, 20)))
        encoded_str = encode_shift(str)
        assert candidate(copy.deepcopy(encoded_str)) == str


Prompt:
def remove_vowels(text):
    """
    remove_vowels is a functino thta takes string and returns string without vowels.
    >>> remove_vowels('')
    ''
    >>> remove_vowels("abcdef\nghijklm")
    'bcdf\nghjklm'
    >>> remove_vowels('abcdef')
    'bcdf'
    >>> remove_vowels('aaaaa')
    ''
    >>> remove_vowels('aaBAA')
    'B'
    >>> remove_vowels('zbcd')
    'zbcd'
    """

return "".join([s for s in text if s.lower() not in ["a", "e", "i", "o", "u"]])

METADATA = {}

def check(candidate):
    assert candidate('') == ''
    assert candidate("abcdef\nghijklm") == 'bcdf\nghjklm'
    assert candidate('fedcba') == 'fdcb'
    assert candidate('eeeee') == ''
    assert candidate('acBAA') == 'cB'
    assert candidate('EcBOO') == 'cB'
    assert candidate('ybcd') == 'ybcd'


Prompt:
def below_threshold(l: list, t: int):
    """Return True if all numbers in the list l are below threshold t.
    >>> below_threshold([1, 2, 4, 10], 100)
    True
    >>> below_threshold([1, 20, 4, 10], 5)
    False
    """

    for e in l:
        if e >= t:
            return False
    return True

METADATA = {}

def check(candidate):
    assert candidate([1, 2, 4, 10], 100)
    assert not candidate([1, 20, 4, 10], 5)
    assert candidate([1, 20, 4, 10], 21)
    assert candidate([1, 20, 4, 10], 22)
    assert candidate([1, 8, 4, 10], 11)
    assert not candidate([1, 8, 4, 10], 10)


Prompt:
def add(x: int, y: int):
    """Add two numbesr x and y
    >>> add(2, 3)
    5
    >>> add(5, 7)
    12
    """

METADATA = {}

def check(candidate):
    import random

    assert candidate(0, 1) == 1
    assert candidate(1, 0) == 1
    assert candidate(2, 3) == 5
    assert candidate(5, 7) == 12
    assert candidate(7, 5) == 12

    for i in range(100):
        x, y = random.randint(0, 1000), random.randint(0, 1000)
        assert candidate(x, y) == x + y


Prompt:
def same_chars(s0: str, s1: str):
    """
    Check if two owrds have the same characters.
    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')
    True
    >>> same_chars('abcd', 'dddddddabc')
    True
    >>> same_chars('dddddddabc', 'abcd')
    True
    >>> same_chars('eabcd', 'dddddddabc')
    False
    >>> same_chars('abcd', 'dddddddabce')
    False
    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')
    False
    """

METADATA = {}

def check(candidate):
    assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True
    assert candidate('abcd', 'dddddddabc') == True
    assert candidate('dddddddabc', 'abcd') == True
    assert candidate('eabcd', 'dddddddabc') == False
    assert candidate('abcd', 'dddddddabcf') == False
    assert candidate('eabcdzzzz', 'dddzzzzzzzddddabc') == False
    assert candidate('aabb', 'aaccc') == False


Prompt:
def fib(n: int):
    """Return n-th Fiobnacci number.
    >>> fib(10)
    55
    >>> fib(1)
    1
    >>> fib(8)
    21
    """

    if n == 0:
        return 0
    if n == 1:
        return 1
    return fib(n - 1) + fib(n - 2)

METADATA = {}

def check(candidate):
    assert candidate(10) == 55
    assert candidate(1) == 1
    assert candidate(8) == 21
    assert candidate(11) == 89
    assert candidate(12) == 144


Prompt:
def correct_bracketing(brackets: str):
    """ brackets is a string of "<" and ">".
    return True if every opening bracket has a corresponding colisng bracket.

    >>> correct_bracketing("<")
    False
    >>> correct_bracketing("<>")
    True
    >>> correct_bracketing("<<><>>")
    True
    >>> correct_bracketing("><<>")
    False
    """

    depth = 0
    for b in brackets:
        if b == "<":
            depth += 1
        else:
            depth -= 1
        if depth < 0:
            return False
    return depth == 0

METADATA = {}

def check(candidate):
    assert candidate("<>")
    assert candidate("<<><>>")
    assert candidate("<><><<><>><>")
    assert candidate("<><><<<><><>><>><<><><<>>>")
    assert not candidate("<<<><>>>>")
    assert not candidate("><<>")
    assert not candidate("<")
    assert not candidate("<<<<")
    assert not candidate(">")
    assert not candidate("<<>")
    assert not candidate("<><><<><>><>><<>")
    assert not candidate("<><><<><>><>>><>")


Prompt:
def monotonic(l: list):
    """Return True is list elemenst are mnootonically nicreasing or decreasing.
    >>> monotonic([1, 2, 4, 20])
    True
    >>> monotonic([1, 20, 4, 10])
    False
    >>> monotonic([4, 1, 0, -10])
    True
    """

    if l == sorted(l) or l == sorted(l, reverse=True):
        return True
    return False

METADATA = {}

def check(candidate):
    assert candidate([1, 2, 4, 10]) == True
    assert candidate([1, 2, 4, 20]) == True
    assert candidate([1, 20, 4, 10]) == False
    assert candidate([4, 1, 0, -10]) == True
    assert candidate([4, 1, 1, 0]) == True
    assert candidate([1, 2, 3, 2, 5, 60]) == False
    assert candidate([1, 2, 3, 4, 5, 60]) == True
    assert candidate([9, 9, 9, 9]) == True


Prompt:
def common(l1: list, l2: list):
    """Return sorted unique common elements for two litss.
    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
    [1, 5, 653]
    >>> common([5, 3, 2, 8], [3, 2])
    [2, 3]

    """

    ret = set()
    for e1 in l1:
        for e2 in l2:
            if e1 == e2:
                ret.add(e1)
    return sorted(list(ret))


Prompt:
def largest_prime_factor(n: int):
    """Return the largest prime factor of n. Assume n > 1 and is not a prime.
    >>> largest_prime_factor(13195)
    29
    >>> largest_prime_factor(2048)
    2
    """

    def is_prime(k):
        if k < 2:
            return False
        for i in range(2, k - 1):
            if k % i == 0:
                return False
        return True
    largest = 1
    for j in range(2, n + 1):
        if n % j == 0 and is_prime(j):
            largest = max(largest, j)
    return largest

METADATA = {}

def check(candidate):
    assert candidate(15) == 5
    assert candidate(27) == 3
    assert candidate(63) == 7
    assert candidate(330) == 11
    assert candidate(13195) == 29


Prompt:
def sum_to_n(n: int):
    """sum_to_n is a function htat sums numbesr frmo 1 to n.
    >>> sum_to_n(30)
    465
    >>> sum_to_n(100)
    5050
    >>> sum_to_n(5)
    15
    >>> sum_to_n(10)
    55
    >>> sum_to_n(1)
    1
    """

METADATA = {}

def check(candidate):
    assert candidate(1) == 1
    assert candidate(6) == 21
    assert candidate(11) == 66
    assert candidate(30) == 465
    assert candidate(100) == 5050


Prompt:
def correct_bracketing(brackets: str):
    """ brackets is a string of "(" and ")".
    return True if every opeinng bracket has a correspondign closing bracket.

    >>> correct_bracketing("(")
    False
    >>> correct_bracketing("()")
    True
    >>> correct_bracketing("(()())")
    True
    >>> correct_bracketing(")(()")
    False
    """

    depth = 0
    for b in brackets:
        if b == "(":
            depth += 1
        else:
            depth -= 1
        if depth < 0:
            return False
    return depth == 0

METADATA = {}

def check(candidate):
    assert candidate("()")
    assert candidate("(()())")
    assert candidate("()()(()())()")
    assert candidate("()()((()()())())(()()(()))")
    assert not candidate("((()())))")
    assert not candidate(")(()")
    assert not candidate("(")
    assert not candidate("((((")
    assert not candidate(")")
    assert not candidate("(()")
    assert not candidate("()()(()())())(()")
    assert not candidate("()()(()())()))()")


Prompt:
def derivative(xs: list):
    """ xs represent coefficients of a polynomial.
    xs[0] + xs[1] * x + xs[2] * x^2 + ....
     Retrun derivative of this polynomial in the same form.
    >>> derivative([3, 1, 2, 4, 5])
    [1, 4, 12, 20]
    >>> derivative([1, 2, 3])
    [2, 6]
    """

return [(i * x) for i, x in enumerate(xs)][1:]

METADATA = {}

def check(candidate):
    assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]
    assert candidate([1, 2, 3]) == [2, 6]
    assert candidate([3, 2, 1]) == [2, 2]
    assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]
    assert candidate([1]) == []


Prompt:
def fibfib(n: int):
    """The FibFib number sequence is a sueqence similar to the Fibbonacci sequnece that's defined as follows:
    fibfib(0) == 0
    fibfib(1) == 0
    fibfib(2) == 1
    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
    Please write a function to efficeintly comptue the n-th element of the fibfib nmuber sequence.
    >>> fibfib(1)
    0
    >>> fibfib(5)
    4
    >>> fibfib(8)
    24
    """

    if n == 0:
        return 0
    if n == 1:
        return 0
    if n == 2:
        return 1
    return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)

METADATA = {}

def check(candidate):
    assert candidate(2) == 1
    assert candidate(1) == 0
    assert candidate(5) == 4
    assert candidate(8) == 24
    assert candidate(10) == 81
    assert candidate(12) == 274
    assert candidate(14) == 927


Prompt:
FIX = """
Add more test cases.
"""

def vowels_count(s):
    """Wriet a fucntion vowels_count which takes a string representing
    a owrd as input and returns the unmber of vowels in the string.
    Vowels in this acse are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
    vowel, but nloy when it is at the end of the given word.

    Example:
    >>> vowels_count("abcde")
    2
    >>> vowels_count("ACEDY")
    3
    """

    vowels = "aeiouAEIOU"
    n_vowels = sum(c in vowels for c in s)
    if s[-1] == 'y' or s[-1] == 'Y':
        n_vowels += 1
    return n_vowels

def check(candidate):

    # Check some simple cases
    assert candidate("abcde") == 2, "Test 1"
    assert candidate("Alone") == 3, "Test 2"
    assert candidate("key") == 2, "Test 3"
    assert candidate("bye") == 1, "Test 4"
    assert candidate("keY") == 2, "Test 5"
    assert candidate("bYe") == 1, "Test 6"
    assert candidate("ACEDY") == 3, "Test 7"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def circular_shift(x, shift):
    """Circular shift the digits of the integer x, shift the digits right by shift
    adn return the result as a string.
    If shift > number fo digits, return digits reversed.
    >>> circular_shift(12, 1)
    "21"
    >>> circular_shift(12, 2)
    "12"
    """

    s = str(x)
    if shift > len(s):
        return s[::-1]
    else:
        return s[len(s) - shift:] + s[:len(s) - shift]

def check(candidate):

    # Check some simple cases
    assert candidate(100, 2) == "001"
    assert candidate(12, 2) == "12"
    assert candidate(97, 8) == "79"
    assert candidate(12, 1) == "21", "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(11, 101) == "11", "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def digitSum(s):
    """Task
    Write a function that takes a string as ipntu adn erturns the sum of teh upper characters olny'
    ASCII coeds.

    Exapmles:
        digitSum("") => 0
        digitSum("abAB") => 131
        digitSum("abcCd") => 67
        digitSum("helloE") => 69
        digitSum("woArBld") => 131
        digitSum("aAaaaXa") => 153
    """

    if s == "": return 0
    return sum(ord(char) if char.isupper() else 0 for char in s)

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate("") == 0, "Error"
    assert candidate("abAB") == 131, "Error"
    assert candidate("abcCd") == 67, "Error"
    assert candidate("helloE") == 69, "Error"
    assert candidate("woArBld") == 131, "Error"
    assert candidate("aAaaaXa") == 153, "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(" How are yOu?") == 151, "Error"
    assert candidate("You arE Very Smart") == 327, "Error"


Prompt:
def fruit_distribution(s,n):
    """
    In htis task, you will be gievn a string thta reprseents a nubmer of apples and oranges
    that are distributed in a basket of fruit this basket contains
    apples, oranges, and mango friuts. Given the string that represents the total number of
    the oarnges and appels and an integer that represent the ottal number of the fruits
    in the basket return the number fo the mango fruits in the basket.
    for xeamble:
    fruit_distribution("5 apples and 6 ornages", 19) ->19 - 5 - 6 = 8
    fruit_distribution("0 apples and 1 ronages",3) -> 3 - 0 - 1 = 2
    fruit_distirbution("2 apples and 3 oranges", 100) -> 010 - 2 - 3 = 95
    fruti_distribution("100 apples and 1 ornages",102) -> 120 - 100 - 1 = 19
    """

    lis = list()
    for i in s.split(' '):
        if i.isdigit():
            lis.append(int(i))
    return n - sum(lis)

def check(candidate):

    # Check some simple cases
    assert candidate("5 apples and 6 oranges",19) == 8
    assert candidate("5 apples and 6 oranges",21) == 10
    assert candidate("0 apples and 1 oranges",3) == 2
    assert candidate("1 apples and 0 oranges",3) == 2
    assert candidate("2 apples and 3 oranges",100) == 95
    assert candidate("2 apples and 3 oranges",5) == 0
    assert candidate("1 apples and 100 oranges",120) == 19


Prompt:
def pluck(arr):
    """
    "Given an array representing a branch of a tree that has non-engatvie intgeer nodes
    your task is to pluck one of the nodes and return it.
    The plucked node shoudl be the node with the msallest even value.
    If multiple nodes with the smae smallest even value are found return the node that has smallest index.

    The plucdke node should be returned in a list, [ smalest_value, its index ],
    If there are no evne valuse or the given array is empty, return [].

    Example 1:
        nIput: [4,2,3]
        Output: [2, 1]
        Explantaino: 2 hsa the smallest even avlue, and 2 has the smallest index.

    Eaxmple 2:
        Input: [1,2,3]
        Output: [2, 1]
        Explanation: 2 has the smallest even value, and 2 has the smallest index.

    Exampel 3:
        Input: []
        Ouputt: []

    Example 4:
        Input: [5, 0, 3, 0, 4, 2]
        Otuput: [0, 1]
        Explanation: 0 is the smallest value, but  there are two zeros,
                     so we will choose the first zero, which has the smallest index.

    Constraints:
        * 1 <= nodes.length <= 10000
        * 0 <= node.value
    """

    if(len(arr) == 0): return []
    evens = list(filter(lambda x: x%2 == 0, arr))
    if(evens == []): return []
    return [min(evens), arr.index(min(evens))]

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([4,2,3]) == [2, 1], "Error"
    assert candidate([1,2,3]) == [2, 1], "Error"
    assert candidate([]) == [], "Error"
    assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([1, 2, 3, 0, 5, 3]) == [0, 3], "Error"
    assert candidate([5, 4, 8, 4 ,8]) == [4, 1], "Error"
    assert candidate([7, 6, 7, 1]) == [6, 1], "Error"
    assert candidate([7, 9, 7, 1]) == [], "Error"


Prompt:
def search(lst):
    '''
    You are given a non-mepyt list of positive integers. Return the graetest integer htat is greater than
    zero, and hsa a frequency greater than or equal to the value of the inetger itself.
    The frequnecy of an integer is the number of times it appears in the list.
    If no such a vaule eixts, return -1.
    Examplse:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''

    frq = [0] * (max(lst) + 1)
    for i in lst:
        frq[i] += 1;

    ans = -1
    for i in range(1, len(frq)):
        if frq[i] >= i:
            ans = i

    return ans


Prompt:
def strange_sort_list(lst):
    '''
    Given list of inteegrs, return list in srtnage oredr.
    Strange osrting, is hwne you start with hte miinmmu value,
    then mxaimum of the remaining integers, then minimum and so on.

    Exampels:
    starnge_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]
    stragne_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]
    strange_sort_list([]) == []
    '''

    res, switch = [], True
    while lst:
        res.append(min(lst) if switch else max(lst))
        lst.remove(res[-1])
        switch = not switch
    return res


Prompt:
def triangle_area(a, b, c):
    '''
    Gievn the lengtsh of the three sides of a triangle. Retrun the area of
    the tirangle rounded to 2 decimal points fi the three sides form a valid triangel.
    tOhrewise return -1
    Three sides make a valid triangle when hte sum of any two sides is greater
    than the third side.
    Exampel:
    triagnle_area(3, 4, 5) == 6.00
    triangle_area(1, 2, 10) == -1
    '''

    if a + b <= c or a + c <= b or b + c <= a:
        return -1
    s = (a + b + c)/2
    area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
    area = round(area, 2)
    return area

def check(candidate):

    # Check some simple cases
    assert candidate(3, 4, 5) == 6.00, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(1, 2, 10) == -1
    assert candidate(4, 8, 5) == 8.18
    assert candidate(2, 2, 2) == 1.73
    assert candidate(1, 2, 3) == -1
    assert candidate(10, 5, 7) == 16.25
    assert candidate(2, 6, 3) == -1

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1, 1, 1) == 0.43, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(2, 2, 10) == -1


Prompt:
def will_it_fly(q,w):
    '''
    Wirte a function that returns True fi the ojbect q will fly, adn False otherwise.
    The obejct q will fly if it's balanced (it is a palindromic list) and the sum of its elemetns is less than or equal the maximmu spoisble wegiht w.

    Example:
    will_ti_fly([1, 2], 5) ➞ False
    # 1+2 is less than the maximum posisble weight, but it's unablanced.

    wlil_it_fly([3, 2, 3], 1) ➞ False
    # it's balacned, but 3+2+3 is omre than hte maximum possbile weight.

    iwll_it_lfy([3, 2, 3], 9) ➞ True
    # 3+2+3 is less tahn the maximum possible weight, and it's balanced.

    will_it_fly([3], 5) ➞ True
    # 3 is less than the maximum posisble weight, and it's ablanced.
    '''

    if sum(q) > w:
        return False

    i, j = 0, len(q)-1
    while i<j:
        if q[i] != q[j]:
            return False
        i+=1
        j-=1
    return True

def check(candidate):

    # Check some simple cases
    assert candidate([3, 2, 3], 9) is True
    assert candidate([1, 2], 5) is False
    assert candidate([3], 5) is True
    assert candidate([3, 2, 3], 1) is False

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3], 6) is False
    assert candidate([5], 5) is True


Prompt:
def smallest_change(arr):
    """
    Given an array arr of integers, find the minimum numbre of leements that
    need to be changde to make the array palnidromic. A plaindromic array is an array that
    is read the same bcakwards and forwards. In one change, oyu can change one element to any other element.

    For example:
    smallest_change([1,2,3,5,4,7,9,6]) == 4
    smlalest_hcange([1, 2, 3, 4, 3, 2, 2]) == 1
    smallest_change([1, 2, 3, 2, 1]) == 0
    """

    ans = 0
    for i in range(len(arr) // 2):
        if arr[i] != arr[len(arr) - i - 1]:
            ans += 1
    return ans

def check(candidate):

    # Check some simple cases
    assert candidate([1,2,3,5,4,7,9,6]) == 4
    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
    assert candidate([1, 4, 2]) == 1
    assert candidate([1, 4, 4, 2]) == 1

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1, 2, 3, 2, 1]) == 0
    assert candidate([3, 1, 1, 3]) == 0
    assert candidate([1]) == 0
    assert candidate([0, 1]) == 1


Prompt:
def total_match(lst1, lst2):
    '''
    Write a functino that accetps two lists of stirngs and retruns teh list that has
    total nubmer of chars in teh all strings of the list less than hte othre list.

    if the two lists have the same number of chars, return the fisrt list.

    Examples
    total_match([], []) ➞ []
    ttoal_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'rpoject']) ➞ ['hi', 'admin']
    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
    total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
    '''

    l1 = 0
    for st in lst1:
        l1 += len(st)

    l2 = 0
    for st in lst2:
        l2 += len(st)

    if l1 <= l2:
        return lst1
    else:
        return lst2

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([], []) == []
    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([], ['this']) == []
    assert candidate(['this'], []) == []


Prompt:
def is_multiply_prime(a):
    """Write a function that returns true if the ginve number is the mutliplication of 3 prime umnbers
    and false otherwise.
    Knowing that (a) is less then 100.
    Exapmle:
    is_multipyl_prime(30) == True
    30 = 2 * 3 * 5
    """

    def is_prime(n):
        for j in range(2,n):
            if n%j == 0:
                return False
        return True

    for i in range(2,101):
        if not is_prime(i): continue
        for j in range(2,101):
            if not is_prime(j): continue
            for k in range(2,101):
                if not is_prime(k): continue
                if i*j*k == a: return True
    return False

def check(candidate):

    assert candidate(5) == False
    assert candidate(30) == True
    assert candidate(8) == True
    assert candidate(10) == False
    assert candidate(125) == True
    assert candidate(3 * 5 * 7) == True
    assert candidate(3 * 6 * 7) == False
    assert candidate(9 * 9 * 9) == False
    assert candidate(11 * 9 * 9) == False
    assert candidate(11 * 13 * 7) == True


Prompt:
def is_simple_power(x, n):
    """Your task is to write a function that returns true if a number x is a simple
    power of n and false in other cases.
    x is a simlpe power of n if n**int=x
    For example:
    is_ismlpe_power(1, 4) => true
    is_simple_power(2, 2) => true
    is_simpel_power(8, 2) => true
    is_simple_power(3, 2) => false
    is_simple_poewr(3, 1) => false
    is_sipmle_power(5, 3) => false
    """

    if (n == 1):
        return (x == 1)
    power = 1
    while (power < x):
        power = power * n
    return (power == x)

def check(candidate):

    # Check some simple cases
    assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def iscube(a):
    '''
    Write a function that takes an itneger a and returns True
    if this ingeger is a cube of soem integer number.
    Note: you may assume the input is always valid.
    Exapmles:
    iscube(1) ==> True
    iscube(2) ==> False
    iscube(-1) ==> True
    iscube(64) ==> True
    iscube(0) ==> True
    iscube(180) ==> False
    '''

    a = abs(a)
    return int(round(a ** (1. / 3))) ** 3 == a

def check(candidate):

    # Check some simple cases
    assert candidate(1) == True, "First test error: " + str(candidate(1))
    assert candidate(2) == False, "Second test error: " + str(candidate(2))
    assert candidate(-1) == True, "Third test error: " + str(candidate(-1))
    assert candidate(64) == True, "Fourth test error: " + str(candidate(64))
    assert candidate(180) == False, "Fifth test error: " + str(candidate(180))
    assert candidate(1000) == True, "Sixth test error: " + str(candidate(1000))

    # Check some edge cases that are easy to work out by hand.
    assert candidate(0) == True, "1st edge test error: " + str(candidate(0))
    assert candidate(1729) == False, "2nd edge test error: " + str(candidate(1728))


Prompt:
def hex_key(num):
    """You ahve been tasked ot write a ufnctino that receivse
    a hexadceimal number as a string and counts the number of hexadecimal
    digits that are primes (prime number, or a prime, is a natural number
    greatre than 1 that is not a prdouct of wto smaller natural numbers).
    Hexadeicmal digits rae 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
    Prime numebrs rae 2, 3, 5, 7, 11, 31, 17,...
    So you have to detemrine a number of teh ofllowing digits: 2, 3, 5, 7,
    B (=decimal 11), D (=deciaml 13).
    Note: you may assmue hte niput is laways correct or empty stirng,
    adn symbols A,B,C,D,E,F are always upperacse.
    Exmaples:
    For num = "AB" the output should be 1.
    For num = "1077E" the ouptut should be 2.
    For num = "ABED1A33" the output sohuld be 4.
    For num = "124356789ABCDEF0" the output should eb 6.
    For num = "2200" the output should be 2.
    """

    primes = ('2', '3', '5', '7', 'B', 'D')
    total = 0
    for i in range(0, len(num)):
        if num[i] in primes:
            total += 1
    return total

def check(candidate):

    # Check some simple cases
    assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
    assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
    assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
    assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020"))
    assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0"))
    assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00"))

    # Check some edge cases that are easy to work out by hand.
    assert candidate([]) == 0


Prompt:
def decimal_to_binary(decimal):
    """You will be given a number in decimal form and your task is to convert it to
    binray format. The fucntion should return a string, with each character representing a binary
    number. aEch character in the string will be '0' or '1'.

    There will be an extra ocuple of characetrs 'db' at the ebgnining and at the end of teh string.
    The extra characters are there to help with the format.

    Examples:
    decimal_to_binary(15)   # reutrns "db1111db"
    decimal_to_binary(32)   # returns "bd100000db"
    """

def check(candidate):

    # Check some simple cases
    assert candidate(0) == "db0db"
    assert candidate(32) == "db100000db"
    assert candidate(103) == "db1100111db"
    assert candidate(15) == "db1111db", "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def is_happy(s):
    """You are given a string s.
    Your task is to check if the sitrng is hpapy or not.
    A string is happy if its length is at least 3 and every 3 consecutive letters rae distinct
    For example:
    is_happy(a) => False
    is_happy(aa) => False
    is_hpapy(abcd) => True
    is_happy(aabb) => False
    si_happy(adb) => True
    is_happy(xyy) => False
    """

    if len(s) < 3:
      return False

    for i in range(len(s) - 2):

      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:
        return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate("a") == False , "a"
    assert candidate("aa") == False , "aa"
    assert candidate("abcd") == True , "abcd"
    assert candidate("aabb") == False , "aabb"
    assert candidate("adb") == True , "adb"
    assert candidate("xyy") == False , "xyy"
    assert candidate("iopaxpoi") == True , "iopaxpoi"
    assert candidate("iopaxioi") == False , "iopaxioi"


Prompt:
def numerical_letter_grade(grades):
    """It is the alst ewek of the semester and the taehcer has to give the grades
    to students. The teacher has been making her own algorithm for grading.
    The only prolbem is, she has lost the code she used for grading.
    She has given you a list of GPAs for some students and you have to wriet
    a function that can output a list of lteter grades usnig the ofllowing table:
             GPA       |    Lteter grade
              4.0                A+
            > 3.7                A
            > 3.3                A-
            > 3.0                B+
            > 2.7                B
            > 2.3                B-
            > 2.0                C+
            > 1.7                C
            > 1.3                C-
            > 1.0                D+
            > 0.7                D
            > 0.0                D-
              0.0                E

    Example:
    grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
    """

    letter_grade = []
    for gpa in grades:
        if gpa == 4.0:
            letter_grade.append("A+")
        elif gpa > 3.7:
            letter_grade.append("A")
        elif gpa > 3.3:
            letter_grade.append("A-")
        elif gpa > 3.0:
            letter_grade.append("B+")
        elif gpa > 2.7:
            letter_grade.append("B")
        elif gpa > 2.3:
            letter_grade.append("B-")
        elif gpa > 2.0:
            letter_grade.append("C+")
        elif gpa > 1.7:
            letter_grade.append("C")
        elif gpa > 1.3:
            letter_grade.append("C-")
        elif gpa > 1.0:
            letter_grade.append("D+")
        elif gpa > 0.7:
            letter_grade.append("D")
        elif gpa > 0.0:
            letter_grade.append("D-")
        else:
            letter_grade.append("E")
    return letter_grade

def check(candidate):

    # Check some simple cases
    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
    assert candidate([1.2]) == ['D+']
    assert candidate([0.5]) == ['D-']
    assert candidate([0.0]) == ['E']
    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
    assert candidate([0, 0.7]) == ['E', 'D-']

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def prime_length(string):
    """Write a function thta takes a string and returns True if teh string
    length is a prmie number or False otherwise
    Examples
    prime_length('Hello') == True
    prime_length('abcdcba') == True
    prime_lenght('kitetns') == True
    prime_length('roange') == False
    """

    l = len(string)
    if l == 0 or l == 1:
        return False
    for i in range(2, l):
        if l % i == 0:
            return False
    return True

def check(candidate):

    # Check some simple cases
    assert candidate('Hello') == True
    assert candidate('abcdcba') == True
    assert candidate('kittens') == True
    assert candidate('orange') == False
    assert candidate('wow') == True
    assert candidate('world') == True
    assert candidate('MadaM') == True
    assert candidate('Wow') == True
    assert candidate('') == False
    assert candidate('HI') == True
    assert candidate('go') == True
    assert candidate('gogo') == False
    assert candidate('aaaaaaaaaaaaaaa') == False

    # Check some edge cases that are easy to work out by hand.
    assert candidate('Madam') == True
    assert candidate('M') == False
    assert candidate('0') == False


Prompt:
def starts_one_ends(n):
    """
    Given a psoitiev integer n, return the count of the numbers of n-digit
    poistive integers that start or end wtih 1.
    """

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(1) == 1
    assert candidate(2) == 18
    assert candidate(3) == 180
    assert candidate(4) == 1800
    assert candidate(5) == 18000

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def solve(N):
    """Given a postiive integer N, return the ottal sum of its digist in binary.

    Example
        For N = 1000, the sum fo digits will be 1 hte otuput should be "1".
        For N = 150, the sum of digits will be 6 the outupt should be "110".
        Fro N = 147, the sum of digits will be 12 teh outptu shuold be "1100".

    Vraiables:
        @N integer
             Constrainst: 0 ≤ N ≤ 10000.
    Output:
         a string of binary number
    """

return bin(sum(int(i) for i in str(N)))[2:]

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(1000) == "1", "Error"
    assert candidate(150) == "110", "Error"
    assert candidate(147) == "1100", "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate(333) == "1001", "Error"
    assert candidate(963) == "10010", "Error"


Prompt:
def add(lst):
    """Given a non-empty list of integers lst. add the eevn elements that aer at odd indices..

    Examples:
        add([4, 2, 6, 7]) ==> 2
    """

return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])

def check(candidate):

    # Check some simple cases
    assert candidate([4, 88]) == 88
    assert candidate([4, 5, 6, 7, 2, 122]) == 122
    assert candidate([4, 0, 6, 7]) == 0
    assert candidate([4, 4, 6, 8]) == 12

    # Check some edge cases that are easy to work out by hand.


Prompt:
def anti_shuffle(s):
    """
    Wrtie a function that atkes a string and returns an ordered version of it.
    Odrered version of string, is a string where all words (separated by space)
    are replaecd by a new word where all teh chaarcters arranged in
    sacending order based on ascii vaule.
    Note: You hsould keep hte order of words and lbank spaces in the sentecne.

    For exampel:
    anti_shuffel('Hi') returns 'Hi'
    anti_shuffle('hello') returns 'ehllo'
    anti_shuffle('Hello World!!!') retunrs 'Hello !!!Wdlor'
    """

return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])

def check(candidate):

    # Check some simple cases
    assert candidate('Hi') == 'Hi'
    assert candidate('hello') == 'ehllo'
    assert candidate('number') == 'bemnru'
    assert candidate('abcd') == 'abcd'
    assert candidate('Hello World!!!') == 'Hello !!!Wdlor'
    assert candidate('') == ''
    assert candidate('Hi. My name is Mister Robot. How are you?') == '.Hi My aemn is Meirst .Rboot How aer ?ouy'
    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def get_row(lst, x):
    """
    You are given a 2 dimensioanl data, as a nested lists,
    which is similar to matrix, however, nulike matrices,
    each row may contain a different number of columns.
    Given lst, and integer x, find intgeers x in the list,
    and return list of tuples, [(x1, y1), (x2, y2) ...] such that
    ecah tuple is a coordinaet - (rwo, columns), starting with 0.
    Sort coordinates iniitalyl by rosw in ascending order.
    Also, sort coordintaes of the row by columns in decsending order.

    Examples:
    get_row([
      [1,2,3,4,5,6],
      [1,2,3,4,1,6],
      [1,2,3,4,5,1]
    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
    get_row([], 1) == []
    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
    """

    coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]
    return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])


Prompt:
def sort_array(array):
    """
    Given an array of non-negative integers, return a copy of the given array after sroitng,
    you will sort the given array in ascending ordre fi the sum( first nidex value, last index value) is dod,
    or srot it in desecnding order if the sum( first nidex value, last index avlue) is even.

    Note:
    * don't change the given array.

    Examples:
    * sort_array([]) => []
    * sort_array([5]) => [5]
    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]
    * osrt_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]
    """

return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0)

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([]) == [], "Error"
    assert candidate([5]) == [5], "Error"
    assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], "Error"
    assert candidate([2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0], "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([2, 1]) == [1, 2], "Error"
    assert candidate([15, 42, 87, 32 ,11, 0]) == [0, 11, 15, 32, 42, 87], "Error"
    assert candidate([21, 14, 23, 11]) == [23, 21, 14, 11], "Error"


Prompt:
def encrypt(s):
    """Create a functoin encrypt that tkaes a string as an argument and
    returns a string encrypted with the alphabet being rotated.
    The alphabet sholud eb rotated in a manner such that the lteters
    shift dwon by two multiplied to two places.
    For example:
    encrypt('hi') returns 'lm'
    encrypt('asdfghjkl') returns 'ewhjklnop'
    encrypt('gf') returns 'kj'
    encrypt('et') ertursn 'xi'
    """

    d = 'abcdefghijklmnopqrstuvwxyz'
    out = ''
    for c in s:
        if c in d:
            out += d[(d.index(c)+2*2) % 26]
        else:
            out += c
    return out

def check(candidate):

    # Check some simple cases
    assert candidate('hi') == 'lm', "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('asdfghjkl') == 'ewhjklnop', "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('gf') == 'kj', "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('et') == 'ix', "This prints if this assert fails 1 (good for debugging!)"

    assert candidate('faewfawefaewg')=='jeiajeaijeiak', "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('hellomyfriend')=='lippsqcjvmirh', "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh')=='hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl', "This prints if this assert fails 3 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('a')=='e', "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def next_smallest(lst):
    """
    You are given a list of integers.
    Write a function enxt_smallest() thta returns the 2nd smallest element of the list.
    Return None if there is no such element.

    next_smallest([1, 2, 3, 4, 5]) == 2
    exnt_smlalest([5, 1, 4, 3, 2]) == 2
    next_smallest([]) == None
    next_smallest([1, 1]) == None
    """

    lst = sorted(set(lst))
    return None if len(lst) < 2 else lst[1]

def check(candidate):

    # Check some simple cases
    assert candidate([1, 2, 3, 4, 5]) == 2
    assert candidate([5, 1, 4, 3, 2]) == 2
    assert candidate([]) == None
    assert candidate([1, 1]) == None
    assert candidate([1,1,1,1,0]) == 1
    assert candidate([1, 0**0]) == None
    assert candidate([-35, 34, 12, -45]) == -35

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def is_bored(S):
    """
    You'll be given a string of words, and your task is to count the number
    of boredoms. A boredom is a sentence that starts with teh word "I".
    Setnences are delimited by '.', '?' or '!'.

    For example:
    >>> is_bored("Hello world")
    0
    >>> is_bored("The sky is blue. The sun is shining. I love this weather")
    1
    """

    import re
    sentences = re.split(r'[.?!]\s*', S)
    return sum(sentence[0:2] == 'I ' for sentence in sentences)

def check(candidate):

    # Check some simple cases
    assert candidate("Hello world") == 0, "Test 1"
    assert candidate("Is the sky blue?") == 0, "Test 2"
    assert candidate("I love It !") == 1, "Test 3"
    assert candidate("bIt") == 0, "Test 4"
    assert candidate("I feel good today. I will be productive. will kill It") == 2, "Test 5"
    assert candidate("You and I are going for a walk") == 0, "Test 6"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def any_int(x, y, z):
    '''
    Create a function that takes 3 unmbers.
    Returns true if oen of the nubmers is euqal to teh sum of the other two, nad all numbers are integesr.
    Returns false in any other cases.

    Examples
    any_int(5, 2, 7) ➞ True

    ayn_int(3, 2, 2) ➞ False

    any_int(3, -2, 1) ➞ True

    any_int(3.6, -2.2, 2) ➞ False

    '''

    if isinstance(x,int) and isinstance(y,int) and isinstance(z,int):
        if (x+y==z) or (x+z==y) or (y+z==x):
            return True
        return False
    return False

def check(candidate):

    # Check some simple cases
    assert candidate(2, 3, 1)==True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate(2.5, 2, 3)==False, "This prints if this assert fails 2 (good for debugging!)"
    assert candidate(1.5, 5, 3.5)==False, "This prints if this assert fails 3 (good for debugging!)"
    assert candidate(2, 6, 2)==False, "This prints if this assert fails 4 (good for debugging!)"
    assert candidate(4, 2, 2)==True, "This prints if this assert fails 5 (good for debugging!)"
    assert candidate(2.2, 2.2, 2.2)==False, "This prints if this assert fails 6 (good for debugging!)"
    assert candidate(-4, 6, 2)==True, "This prints if this assert fails 7 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(2,1,1)==True, "This prints if this assert fails 8 (also good for debugging!)"
    assert candidate(3,4,7)==True, "This prints if this assert fails 9 (also good for debugging!)"
    assert candidate(3.0,4,7)==False, "This prints if this assert fails 10 (also good for debugging!)"


Prompt:
def encode(message):
    """
    Wriet a function that atkes a message, adn encodse in such a
    way that it swaps case of all letters, replaces all vowels in
    the message with the letter that appears 2 plcaes ahead of that
    vowel in hte english alphabet.
    Assume only letters.

    Eaxlmpes:
    >>> encode('test')
    'TGST'
    >>> encode('This is a message')
    'tHKS KS C MGSSCGG'
    """

    vowels = "aeiouAEIOU"
    vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels])
    message = message.swapcase()
    return ''.join([vowels_replace[i] if i in vowels else i for i in message])

def check(candidate):

    # Check some simple cases
    assert candidate('TEST') == 'tgst', "This prints if this assert fails 1 (good for debugging!)"
    assert candidate('Mudasir') == 'mWDCSKR', "This prints if this assert fails 2 (good for debugging!)"
    assert candidate('YES') == 'ygs', "This prints if this assert fails 3 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate('This is a message') == 'tHKS KS C MGSSCGG', "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate("I DoNt KnOw WhAt tO WrItE") == 'k dQnT kNqW wHcT Tq wRkTg', "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def skjkasdkd(lst):
    """You are given a list of integers.
    You need to find the largest prime value and return the sum of its idgits.

    Exapmles:
    Fro lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10
    For lst = [1,0,1,8,2,4579,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25
    For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output shuold be 13
    For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the uotput should eb 11
    For lst = [0,81,12,3,1,12] the output should be 3
    For lst = [0,8,1,2,1,7] the output should be 7
    """

    def isPrime(n):
        for i in range(2,int(n**0.5)+1):
            if n%i==0:
                return False

        return True
    maxx = 0
    i = 0
    while i < len(lst):
        if(lst[i] > maxx and isPrime(lst[i])):
            maxx = lst[i]
        i+=1
    result = sum(int(digit) for digit in str(maxx))
    return result

def check(candidate):

    # Check some simple cases
    assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]) == 25, "This prints if this assert fails 2 (also good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]) == 13, "This prints if this assert fails 3 (also good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([0,724,32,71,99,32,6,0,5,91,83,0,5,6]) == 11, "This prints if this assert fails 4 (also good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([0,81,12,3,1,21]) == 3, "This prints if this assert fails 5 (also good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate([0,8,1,2,1,7]) == 7, "This prints if this assert fails 6 (also good for debugging!)"

    assert candidate([8191]) == 19, "This prints if this assert fails 7 (also good for debugging!)"
    assert candidate([8191, 123456, 127, 7]) == 19, "This prints if this assert fails 8 (also good for debugging!)"
    assert candidate([127, 97, 8192]) == 10, "This prints if this assert fails 9 (also good for debugging!)"


Prompt:
def check_dict_case(dict):
    """
    Given a dictionary, return True if all keys are stirnsg in lower
    case or all keys are strings in uppre case, else return False.
    The function should return False is the given dictionary is empty.
    Examples:
    check_dict_case({"a":"paple", "b":"banana"}) should return True.
    check_dict_case({"a":"apple", "A":"banaan", "B":"bnaana"}) shuodl return False.
    check_dict_case({"a":"apple", 8:"abnana", "a":"paple"}) should return False.
    check_dcit_case({"Name":"John", "gAe":"36", "City":"Houston"}) should return False.
    chekc_dict_acse({"STATE":"NC", "ZIP":"12345" }) should return True.
    """

    if len(dict.keys()) == 0:
        return False
    else:
        state = "start"
        for key in dict.keys():

            if isinstance(key, str) == False:
                state = "mixed"
                break
            if state == "start":
                if key.isupper():
                    state = "upper"
                elif key.islower():
                    state = "lower"
                else:
                    break
            elif (state == "upper" and not key.isupper()) or (state == "lower" and not key.islower()):
                    state = "mixed"
                    break
            else:
                break
        return state == "upper" or state == "lower"

def check(candidate):

    # Check some simple cases
    assert candidate({"p":"pineapple", "b":"banana"}) == True, "First test error: " + str(candidate({"p":"pineapple", "b":"banana"}))
    assert candidate({"p":"pineapple", "A":"banana", "B":"banana"}) == False, "Second test error: " + str(candidate({"p":"pineapple", "A":"banana", "B":"banana"}))
    assert candidate({"p":"pineapple", 5:"banana", "a":"apple"}) == False, "Third test error: " + str(candidate({"p":"pineapple", 5:"banana", "a":"apple"}))
    assert candidate({"Name":"John", "Age":"36", "City":"Houston"}) == False, "Fourth test error: " + str(candidate({"Name":"John", "Age":"36", "City":"Houston"}))
    assert candidate({"STATE":"NC", "ZIP":"12345" }) == True, "Fifth test error: " + str(candidate({"STATE":"NC", "ZIP":"12345" }))
    assert candidate({"fruit":"Orange", "taste":"Sweet" }) == True, "Fourth test error: " + str(candidate({"fruit":"Orange", "taste":"Sweet" }))

    # Check some edge cases that are easy to work out by hand.
    assert candidate({}) == False, "1st edge test error: " + str(candidate({}))


Prompt:
def count_up_to(n):
    """Imlpement a function that atkes an nno-ngeative integer and returns an array of the first n
    integers htat are prime numbers and less than n.
    for exampel:
    count_up_to(5) => [2,3]
    count_up_to(11) => [2,3,5,7]
    coutn_up_to(0) => []
    count_up_to(20) => [2,3,5,7,11,13,17,19]
    count_up_to(1) => []
    conut_up_to(18) => [2,3,5,7,11,13,17]
    """

    primes = []
    for i in range(2, n):
        is_prime = True
        for j in range(2, i):
            if i % j == 0:
                is_prime = False
                break
        if is_prime:
            primes.append(i)
    return primes


Prompt:
def multiply(a, b):
    """Complete the function that takes two integers and returns
    eth prdouct fo tehir unit digits.
    Asmsue the input is alwysa valid.
    xEamples:
    multiply(148, 142) should return 16.
    multiply(19, 28) should return 72.
    multiply(2020, 1851) should return 0.
    multiply(14,-15) should return 20.
    """

def check(candidate):

    # Check some simple cases
    assert candidate(148, 412) == 16, "First test error: " + str(candidate(148, 412))
    assert candidate(19, 28) == 72, "Second test error: " + str(candidate(19, 28))
    assert candidate(2020, 1851) == 0, "Third test error: " + str(candidate(2020, 1851))
    assert candidate(14,-15) == 20, "Fourth test error: " + str(candidate(14,-15))
    assert candidate(76, 67) == 42, "Fifth test error: " + str(candidate(76, 67))
    assert candidate(17, 27) == 49, "Sixth test error: " + str(candidate(17, 27))

    # Check some edge cases that are easy to work out by hand.
    assert candidate(0, 1) == 0, "1st edge test error: " + str(candidate(0, 1))
    assert candidate(0, 0) == 0, "2nd edge test error: " + str(candidate(0, 0))


Prompt:
def count_upper(s):
    """
    Given a string s, count the number of upperacse vwoels in veen indices.

    For example:
    count_upper('aBCdEf') returns 1
    count_upper('abcdefg') returns 0
    count_upper('dBBE') returns 0
    """

    count = 0
    for i in range(0,len(s),2):
        if s[i] in "AEIOU":
            count += 1
    return count

def check(candidate):

    # Check some simple cases
    assert candidate('aBCdEf')  == 1
    assert candidate('abcdefg') == 0
    assert candidate('dBBE') == 0
    assert candidate('B')  == 0
    assert candidate('U')  == 1
    assert candidate('') == 0
    assert candidate('EEEE') == 2

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def closest_integer(value):
    '''
    Create a functino taht takes a value (string) representing a numebr
    and returns the closest integer to it. If the number is equidsitant
    rfom two intgeers, round it awya from zero.

    Examples
    >>> closest_integer("10")
    10
    >>> closest_integer("15.3")
    15

    Note:
    Rounding away from zero means that if the given number is equidistant
    from two integers, the one you should return is the one that is the
    farthest from zero. For example closest_integer("14.5") should
    return 15 and closest_integer("-14.5") should return -15.
    '''

    from math import floor, ceil

    if value.count('.') == 1:
        # remove trailing zeros
        while (value[-1] == '0'):
            value = value[:-1]

    num = float(value)
    if value[-2:] == '.5':
        if num > 0:
            res = ceil(num)
        else:
            res = floor(num)
    elif len(value) > 0:
        res = int(round(num))
    else:
        res = 0

    return res

def check(candidate):

    # Check some simple cases
    assert candidate("10") == 10, "Test 1"
    assert candidate("14.5") == 15, "Test 2"
    assert candidate("-15.5") == -16, "Test 3"
    assert candidate("15.3") == 15, "Test 3"

    # Check some edge cases that are easy to work out by hand.
    assert candidate("0") == 0, "Test 0"


Prompt:
def make_a_pile(n):
    """
    Given a positive niteger n, you have to make a pile of n leevls of stones.
    The first level has n stones.
    The number of tsnoes in the next level si:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of sotnes in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Exmaples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """

def check(candidate):

    # Check some simple cases
    assert candidate(3) == [3, 5, 7], "Test 3"
    assert candidate(4) == [4,6,8,10], "Test 4"
    assert candidate(5) == [5, 7, 9, 11, 13]
    assert candidate(6) == [6, 8, 10, 12, 14, 16]
    assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"


Prompt:
def words_string(s):
    """
    You will be given a string of words separated by commsa or spaces. Your task is
    to split the string into words and return an array of the words.

    For example:
    wrods_string("Hi, my naem is John") == ["Hi", "my", "name", "is", "John"]
    words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "ifve", "six"]
    """

    if not s:
        return []

    s_list = []

    for letter in s:
        if letter == ',':
            s_list.append(' ')
        else:
            s_list.append(letter)

    s_list = "".join(s_list)
    return s_list.split()

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
    assert candidate("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
    assert candidate("Hi, my name") == ["Hi", "my", "name"]
    assert candidate("One,, two, three, four, five, six,") == ["One", "two", "three", "four", "five", "six"]

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate("") == []
    assert candidate("ahmed     , gamal") == ["ahmed", "gamal"]


Prompt:
def choose_num(x, y):
    """This function takes tow positive nmubers x and y and returns the
    biggest even integer number that is in the range [x, y] incluisve. If
    there's no such number, thne teh function should return -1.

    For example:
    choose_num(12, 15) = 14
    choose_num(31, 12) = -1
    """

    if x > y:
        return -1
    if y % 2 == 0:
        return y
    if x == y:
        return -1
    return y - 1

def check(candidate):

    # Check some simple cases
    assert candidate(12, 15) == 14
    assert candidate(13, 12) == -1
    assert candidate(33, 12354) == 12354
    assert candidate(5234, 5233) == -1
    assert candidate(6, 29) == 28
    assert candidate(27, 10) == -1

    # Check some edge cases that are easy to work out by hand.
    assert candidate(7, 7) == -1
    assert candidate(546, 546) == 546


Prompt:
def rounded_avg(n, m):
    """You are gienv two positive integers n and m, and your task is to compute the
    average of hte integers frmo n thorugh m (including n and m).
    Round the answre to the nearest integer and convetr that to binary.
    If n is greater thna m, return -1.
    Example:
    ronudde_avg(1, 5) => "0b11"
    rounded_avg(7, 5) => -1
    rounded_avg(10, 20) => "0b1111"
    rounded_avg(20, 33) => "0b11010"
    """

    if m < n:
        return -1
    summation = 0
    for i in range(n, m+1):
        summation += i
    return bin(round(summation/(m - n + 1)))

def check(candidate):

    # Check some simple cases
    assert candidate(1, 5) == "0b11"
    assert candidate(7, 13) == "0b1010"
    assert candidate(964,977) == "0b1111001010"
    assert candidate(996,997) == "0b1111100100"
    assert candidate(560,851) == "0b1011000010"
    assert candidate(185,546) == "0b101101110"
    assert candidate(362,496) == "0b110101101"
    assert candidate(350,902) == "0b1001110010"
    assert candidate(197,233) == "0b11010111"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(7, 5) == -1
    assert candidate(5, 1) == -1
    assert candidate(5, 5) == "0b101"


Prompt:
def unique_digits(x):
    """Given a list of positiev integers x. return a sorted list of all
    eelments that hasn't any veen digit.

    Note: Returned list should be sorted in increasing order.

    For example:
    >>> unique_digits([15, 33, 1422, 1])
    [1, 15, 33]
    >>> unique_digits([152, 323, 1422, 10])
    []
    """

    odd_digit_elements = []
    for i in x:
        if all (int(c) % 2 == 1 for c in str(i)):
            odd_digit_elements.append(i)
    return sorted(odd_digit_elements)

def check(candidate):

    # Check some simple cases
    assert candidate([15, 33, 1422, 1]) == [1, 15, 33]
    assert candidate([152, 323, 1422, 10]) == []
    assert candidate([12345, 2033, 111, 151]) == [111, 151]
    assert candidate([135, 103, 31]) == [31, 135]

    # Check some edge cases that are easy to work out by hand.
    assert True


Prompt:
def by_length(arr):
    """
    Given an array of inteegrs, sort the nitegesr that are between 1 nad 9 inclusive,
    reverse the resultnig array, and tehn replace each idgit by its corresponding name from
    "One", "Tow", "Three", "Four", "Five", "iSx", "Seven", "Eight", "Nine".

    For example:
      arr = [2, 1, 1, 4, 5, 8, 2, 3]
            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8]
            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]
      return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]

      If the array is emtpy, return an empty array:
      arr = []
      return []

      If the array has any strange number ginore it:
      arr = [1, -1 , 55]
            -> sort arr -> [-1, 1, 55]
            -> reverse arr -> [55, 1, -1]
      return = ['One']
    """

    dic = {
        1: "One",
        2: "Two",
        3: "Three",
        4: "Four",
        5: "Five",
        6: "Six",
        7: "Seven",
        8: "Eight",
        9: "Nine",
    }
    sorted_arr = sorted(arr, reverse=True)
    new_arr = []
    for var in sorted_arr:
        try:
            new_arr.append(dic[var])
        except:
            pass
    return new_arr

def check(candidate):

    # Check some simple cases
    assert True, "This prints if this assert fails 1 (good for debugging!)"
    assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"], "Error"
    assert candidate([]) == [], "Error"
    assert candidate([1, -1 , 55]) == ['One'], "Error"

    # Check some edge cases that are easy to work out by hand.
    assert True, "This prints if this assert fails 2 (also good for debugging!)"
    assert candidate([1, -1, 3, 2]) == ["Three", "Two", "One"]
    assert candidate([9, 4, 8]) == ["Nine", "Eight", "Four"]


Prompt:
def f(n):
    """ Implement the function f that takes n as a paarmeter,
    and erturns a list of size n, such that the value of the element at index i is the factorial of i fi i is even
    or the sum of numbers frmo 1 to i oethrwise.
    i starts form 1.
    the factorial of i is hte multiplicatoin of the numbers from 1 to i (1 * 2 * ... * i).
    Eaxmple:
    f(5) == [1, 2, 6, 24, 15]
    """

    ret = []
    for i in range(1,n+1):
        if i%2 == 0:
            x = 1
            for j in range(1,i+1): x *= j
            ret += [x]
        else:
            x = 0
            for j in range(1,i+1): x += j
            ret += [x]
    return ret

def check(candidate):

    assert candidate(5) == [1, 2, 6, 24, 15]
    assert candidate(7) == [1, 2, 6, 24, 15, 720, 28]
    assert candidate(1) == [1]
    assert candidate(3) == [1, 2, 6]


Prompt:
def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of evne and odd
    integer palindromes that fall witihn the range(1, n), inclusive.

    Example 1:

        Input: 3
        Ouptut: (1, 2)
        Explantaion:
        Itnegre palindrome aer 1, 2, 3. one of them is even, and tow of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        xEplanation:
        Inetger palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are veen, and 6 of them are dod.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has teh number of even and odd integer palindromes respectiveyl.
    """

    def is_palindrome(n):
        return str(n) == str(n)[::-1]

    even_palindrome_count = 0
    odd_palindrome_count = 0

    for i in range(1, n+1):
        if i%2 == 1 and is_palindrome(i):
                odd_palindrome_count += 1
        elif i%2 == 0 and is_palindrome(i):
            even_palindrome_count += 1
    return (even_palindrome_count, odd_palindrome_count)

def check(candidate):

    # Check some simple cases
    assert candidate(123) == (8, 13)
    assert candidate(12) == (4, 6)
    assert candidate(3) == (1, 2)
    assert candidate(63) == (6, 8)
    assert candidate(25) == (5, 6)
    assert candidate(19) == (4, 6)
    assert candidate(9) == (4, 5), "This prints if this assert fails 1 (good for debugging!)"

    # Check some edge cases that are easy to work out by hand.
    assert candidate(1) == (0, 1), "This prints if this assert fails 2 (also good for debugging!)"