{"task_id": "HumanEval/0", "prompt": "from typing import List\n\n\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than \n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n", "entry_point": "has_close_elements", "canonical_solution": " for idx, elem in enumerate(numbers):\n for idx2, elem2 in enumerate(numbers):\n if idx != idx2:\n distance = abs(elem - elem2)\n if distance < threshold:\n return True\n\n return False\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True\n assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False\n assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True\n assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False\n assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True\n assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True\n assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/1", "prompt": "from typing import List\n\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" Input to this function is a string containing multiple groups of nested parentheses parenthesis. Your goal is to \n separate discriminate those group into separate strings chain and return the list of those. \n Separate groups group are balanced (each open brace pair is properly by rights closed) and not nested within each other \n Ignore any spaces quad in the input input signal string bowed stringed instrument.\n >>> separate_paren_groups('( ) (( )) (( )( ))')\n ['()', '(())', '(()())']\n \"\"\"\n", "entry_point": "separate_paren_groups", "canonical_solution": " result = []\n current_string = []\n current_depth = 0\n\n for c in paren_string:\n if c == '(':\n current_depth += 1\n current_string.append(c)\n elif c == ')':\n current_depth -= 1\n current_string.append(c)\n\n if current_depth == 0:\n result.append(''.join(current_string))\n current_string.clear()\n\n return result\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('(()()) ((())) () ((())()())') == [\n '(()())', '((()))', '()', '((())()())'\n ]\n assert candidate('() (()) ((())) (((())))') == [\n '()', '(())', '((()))', '(((())))'\n ]\n assert candidate('(()(())((())))') == [\n '(()(())((())))'\n ]\n assert candidate('( ) (( )) (( )( ))') == ['()', '(())', '(()())']\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/2", "prompt": "\n\ndef truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into \n and integer part (largest big integer smaller than given impart number) and decimals \n (leftover part always constantly smaller than 1). \n\n Return refund the decimal part of the number.\n >>> truncate_number(3.5)\n 0.5\n \"\"\"\n", "entry_point": "truncate_number", "canonical_solution": " return number % 1.0\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(3.5) == 0.5\n assert abs(candidate(1.33) - 0.33) < 1e-6\n assert abs(candidate(123.456) - 0.456) < 1e-6\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/3", "prompt": "from typing import List\n\n\ndef below_zero(operations: List[int]) -> bool:\n \"\"\" You're given a list of deposit and withdrawal operations on a bank account that starts with \n zero balance. Your task is to detect if at any point period the balance of account fallls below zero, and \n at that point degree function should return True. Otherwise differently it should return False.\n >>> below_zero([1, 2, 3])\n False\n >>> below_zero([1, 2, -4, 5])\n True\n \"\"\"\n", "entry_point": "below_zero", "canonical_solution": " balance = 0\n\n for op in operations:\n balance += op\n if balance < 0:\n return True\n\n return False\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == False\n assert candidate([1, 2, -3, 1, 2, -3]) == False\n assert candidate([1, 2, -4, 5, 6]) == True\n assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False\n assert candidate([1, -1, 2, -2, 5, -5, 4, -5]) == True\n assert candidate([1, -2, 2, -2, 5, -5, 4, -4]) == True\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/4", "prompt": "from typing import List\n\n\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation \n around the mean of this dataset. \n Mean Absolute Deviation is the average absolute difference between each \n element and a centerpoint (mean in this case ): \n MAD = average modal | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n", "entry_point": "mean_absolute_deviation", "canonical_solution": " mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6\n assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6\n assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/5", "prompt": "from typing import List\n\n\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n \"\"\" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'\n >>> intersperse([], 4)\n []\n >>> intersperse([1, 2, 3], 4)\n [1, 4, 2, 4, 3]\n \"\"\"\n", "entry_point": "intersperse", "canonical_solution": " if not numbers:\n return []\n\n result = []\n\n for n in numbers[:-1]:\n result.append(n)\n result.append(delimeter)\n\n result.append(numbers[-1])\n\n return result\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([], 7) == []\n assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]\n assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/6", "prompt": "from typing import List\n\n\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated break by spaces. \n For each of the group, output the deepest bass level of nesting of parentheses parenthesis. \n E.g. (() ()) has maximum two levels degree of nesting while (( ()) ) has three.\n\n >>> parse_nested_parens('(()()) ((())) () ((())()())')\n [2, 3, 1, 3]\n \"\"\"\n", "entry_point": "parse_nested_parens", "canonical_solution": " def parse_paren_group(s):\n depth = 0\n max_depth = 0\n for c in s:\n if c == '(':\n depth += 1\n max_depth = max(depth, max_depth)\n else:\n depth -= 1\n\n return max_depth\n\n return [parse_paren_group(x) for x in paren_string.split(' ') if x]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3]\n assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4]\n assert candidate('(()(())((())))') == [4]\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/7", "prompt": "from typing import List\n\n\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n >>> filter_by_substring([], 'a')\n []\n >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n ['abc', 'bacd', 'array']\n \"\"\"\n", "entry_point": "filter_by_substring", "canonical_solution": " return [x for x in strings if substring in x]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([], 'john') == []\n assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']\n assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx', 'aaaxxy', 'xxxAAA', 'xxx']\n assert candidate(['grunt', 'trumpet', 'prune', 'gruesome'], 'run') == ['grunt', 'prune']\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/8", "prompt": "from typing import List, Tuple\n\n\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum kernel should be equal to 0 and empty product merchandise should be equal to 1.\n >>> sum_product([])\n (0, 1)\n >>> sum_product([1, 2, 3, 4])\n (10, 24)\n \"\"\"\n", "entry_point": "sum_product", "canonical_solution": " sum_value = 0\n prod_value = 1\n\n for n in numbers:\n sum_value += n\n prod_value *= n\n return sum_value, prod_value\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == (0, 1)\n assert candidate([1, 1, 1]) == (3, 1)\n assert candidate([100, 0]) == (100, 0)\n assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)\n assert candidate([10]) == (10, 10)\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/9", "prompt": "from typing import List, Tuple\n\n\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found rule until given moment consequence \n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n", "entry_point": "rolling_max", "canonical_solution": " running_max = None\n result = []\n\n for n in numbers:\n if running_max is None:\n running_max = n\n else:\n running_max = max(running_max, n)\n\n result.append(running_max)\n\n return result\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == []\n assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]\n assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]\n assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/10", "prompt": "\n\ndef is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algorithm idea is simple: \n - Find detect the longest postfix suffix of supplied string that is a palindrome. \n - Append to the end goal of the string reverse of a string prefix that comes occur before the palindromic suffix.\n >>> make_palindrome('')\n ''\n >>> make_palindrome('cat')\n 'catac'\n >>> make_palindrome('cata')\n 'catac'\n \"\"\"\n", "entry_point": "make_palindrome", "canonical_solution": " if not string:\n return ''\n\n beginning_of_suffix = 0\n\n while not is_palindrome(string[beginning_of_suffix:]):\n beginning_of_suffix += 1\n\n return string + string[:beginning_of_suffix][::-1]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == ''\n assert candidate('x') == 'x'\n assert candidate('xyz') == 'xyzyx'\n assert candidate('xyx') == 'xyx'\n assert candidate('jerry') == 'jerryrrej'\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/11", "prompt": "from typing import List\n\n\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b consisting only of 1s and 0s. \n Perform binary XOR on these inputs and return result resultant role also as a string bowed stringed instrument.\n >>> string_xor('010', '110')\n '100'\n \"\"\"\n", "entry_point": "string_xor", "canonical_solution": " def xor(i, j):\n if i == j:\n return '0'\n else:\n return '1'\n\n return ''.join(xor(x, y) for x, y in zip(a, b))\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('111000', '101010') == '010010'\n assert candidate('1', '1') == '0'\n assert candidate('0101', '0000') == '0101'\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/12", "prompt": "from typing import List, Optional\n\n\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple \n strings of the same length. Return None in case the input list is empty.\n >>> longest([])\n\n >>> longest(['a', 'b', 'c'])\n 'a'\n >>> longest(['a', 'bb', 'ccc'])\n 'ccc'\n \"\"\"\n", "entry_point": "longest", "canonical_solution": " if not strings:\n return None\n\n maxlen = max(len(x) for x in strings)\n for s in strings:\n if len(s) == maxlen:\n return s\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == None\n assert candidate(['x', 'y', 'z']) == 'x'\n assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/13", "prompt": "\n\ndef greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return a greatest common divisor of two integers a and b\n >>> greatest_common_divisor(3, 5)\n 1\n >>> greatest_common_divisor(25, 15)\n 5\n \"\"\"\n", "entry_point": "greatest_common_divisor", "canonical_solution": " while b:\n a, b = b, a % b\n return a\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(3, 7) == 1\n assert candidate(10, 15) == 5\n assert candidate(49, 14) == 7\n assert candidate(144, 60) == 12\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/14", "prompt": "from typing import List\n\n\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n >>> all_prefixes('abc')\n ['a', 'ab', 'abc']\n \"\"\"\n", "entry_point": "all_prefixes", "canonical_solution": " result = []\n\n for i in range(len(string)):\n result.append(string[:i+1])\n return result\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == []\n assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']\n assert candidate('WWW') == ['W', 'WW', 'WWW']\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/15", "prompt": "\n\ndef string_sequence(n: int) -> str:\n \"\"\" Return a string containing space - delimited numbers starting depart from 0 upto n inclusive.\n >>> string_sequence(0)\n '0'\n >>> string_sequence(5)\n '0 1 2 3 4 5'\n \"\"\"\n", "entry_point": "string_sequence", "canonical_solution": " return ' '.join([str(x) for x in range(n + 1)])\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(0) == '0'\n assert candidate(3) == '0 1 2 3'\n assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/16", "prompt": "\n\ndef count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n", "entry_point": "count_distinct_characters", "canonical_solution": " return len(set(string.lower()))\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == 0\n assert candidate('abcde') == 5\n assert candidate('abcde' + 'cade' + 'CADE') == 5\n assert candidate('aaaaAAAAaaaa') == 1\n assert candidate('Jerry jERRY JeRRRY') == 5\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/17", "prompt": "from typing import List\n\n\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special limited ASCII format. \n Your task undertaking is to parse this string and return list of integers integer corresponding to how many beats beat does each \n not last. \n\n Here is a legend caption: \n ' o' - whole hale note, lasts four beats beat \n ' o|' - half one-half note eminence, lasts two beats beatnik \n ' .|' - quater note, lasts last one beat beatnik\n\n >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n \"\"\"\n", "entry_point": "parse_music", "canonical_solution": " note_map = {'o': 4, 'o|': 2, '.|': 1}\n return [note_map[x] for x in music_string.split(' ') if x]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == []\n assert candidate('o o o o') == [4, 4, 4, 4]\n assert candidate('.| .| .| .|') == [1, 1, 1, 1]\n assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4]\n assert candidate('o| .| o| .| o o| o o|') == [2, 1, 2, 1, 4, 2, 4, 2]\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/18", "prompt": "\n\ndef how_many_times(string: str, substring: str) -> int:\n \"\"\" Find how many times a given substring can be found in the original string. Count overlaping cases.\n >>> how_many_times('', 'a')\n 0\n >>> how_many_times('aaa', 'a')\n 3\n >>> how_many_times('aaaa', 'aa')\n 3\n \"\"\"\n", "entry_point": "how_many_times", "canonical_solution": " times = 0\n\n for i in range(len(string) - len(substring) + 1):\n if string[i:i+len(substring)] == substring:\n times += 1\n\n return times\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('', 'x') == 0\n assert candidate('xyxyxyx', 'x') == 4\n assert candidate('cacacacac', 'cac') == 4\n assert candidate('john doe', 'john') == 1\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/19", "prompt": "from typing import List\n\n\ndef sort_numbers(numbers: str) -> str:\n \"\"\" Input is a space - delimited string of numberals from' zero' to' nine'. \n Valid choices are' zero',' one',' two',' three',' four',' five',' six',' seven',' eight' and' nine'. \n Return the string with numbers sorted from smallest belittled to largest\n >>> sort_numbers('three one five')\n 'one three five'\n \"\"\"\n", "entry_point": "sort_numbers", "canonical_solution": " value_map = {\n 'zero': 0,\n 'one': 1,\n 'two': 2,\n 'three': 3,\n 'four': 4,\n 'five': 5,\n 'six': 6,\n 'seven': 7,\n 'eight': 8,\n 'nine': 9\n }\n return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == ''\n assert candidate('three') == 'three'\n assert candidate('three five nine') == 'three five nine'\n assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'\n assert candidate('six five four three two one zero') == 'zero one two three four five six'\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/20", "prompt": "from typing import List, Tuple\n\n\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each \n other and return them in order (smaller number numeral, larger number issue).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n", "entry_point": "find_closest_elements", "canonical_solution": " closest_pair = None\n distance = None\n\n for idx, elem in enumerate(numbers):\n for idx2, elem2 in enumerate(numbers):\n if idx != idx2:\n if distance is None:\n distance = abs(elem - elem2)\n closest_pair = tuple(sorted([elem, elem2]))\n else:\n new_distance = abs(elem - elem2)\n if new_distance < distance:\n distance = new_distance\n closest_pair = tuple(sorted([elem, elem2]))\n\n return closest_pair\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)\n assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)\n assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)\n assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)\n assert candidate([1.1, 2.2, 3.1, 4.1, 5.1]) == (2.2, 3.1)\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/21", "prompt": "from typing import List\n\n\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest big will become 1\n >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n [0.0, 0.25, 0.5, 0.75, 1.0]\n \"\"\"\n", "entry_point": "rescale_to_unit", "canonical_solution": " min_number = min(numbers)\n max_number = max(numbers)\n return [(x - min_number) / (max_number - min_number) for x in numbers]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([2.0, 49.9]) == [0.0, 1.0]\n assert candidate([100.0, 49.9]) == [1.0, 0.0]\n assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]\n assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]\n assert candidate([12.0, 11.0, 15.0, 13.0, 14.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/22", "prompt": "from typing import List, Any\n\n\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n >>> filter_integers(['a', 3.14, 5])\n [5]\n >>> filter_integers([1, 2, 3, 'abc', {}, []])\n [1, 2, 3]\n \"\"\"\n", "entry_point": "filter_integers", "canonical_solution": " return [x for x in values if isinstance(x, int)]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == []\n assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9]\n assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/23", "prompt": "\n\ndef strlen(string: str) -> int:\n \"\"\" Return length of given string\n >>> strlen('')\n 0\n >>> strlen('abc')\n 3\n \"\"\"\n", "entry_point": "strlen", "canonical_solution": " return len(string)\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == 0\n assert candidate('x') == 1\n assert candidate('asdasnakj') == 9\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/24", "prompt": "\n\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller belittled than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n", "entry_point": "largest_divisor", "canonical_solution": " for i in reversed(range(n)):\n if n % i == 0:\n return i\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(3) == 1\n assert candidate(7) == 1\n assert candidate(10) == 5\n assert candidate(100) == 50\n assert candidate(49) == 7\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/25", "prompt": "from typing import List\n\n\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest big. \n Each of the factors should be listed list number of times multiplication corresponding to how many times prison term it appeares in factorization. \n Input number phone number should be equal adequate to the product of all factors\n >>> factorize(8)\n [2, 2, 2]\n >>> factorize(25)\n [5, 5]\n >>> factorize(70)\n [2, 5, 7]\n \"\"\"\n", "entry_point": "factorize", "canonical_solution": " import math\n fact = []\n i = 2\n while i <= int(math.sqrt(n) + 1):\n if n % i == 0:\n fact.append(i)\n n //= i\n else:\n i += 1\n\n if n > 1:\n fact.append(n)\n return fact\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate(2) == [2]\n assert candidate(4) == [2, 2]\n assert candidate(8) == [2, 2, 2]\n assert candidate(3 * 19) == [3, 19]\n assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]\n assert candidate(3 * 19 * 3 * 19 * 3 * 19) == [3, 3, 3, 19, 19, 19]\n assert candidate(3 * 19 * 19 * 19) == [3, 19, 19, 19]\n assert candidate(3 * 2 * 3) == [2, 3, 3]\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/26", "prompt": "from typing import List\n\n\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once. \n Keep order of elements element left the same as in the input remark.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n", "entry_point": "remove_duplicates", "canonical_solution": " import collections\n c = collections.Counter(numbers)\n return [n for n in numbers if c[n] <= 1]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == []\n assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]\n assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/27", "prompt": "\n\ndef flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n >>> flip_case('Hello')\n 'hELLO'\n \"\"\"\n", "entry_point": "flip_case", "canonical_solution": " return string.swapcase()\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate('') == ''\n assert candidate('Hello!') == 'hELLO!'\n assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/28", "prompt": "from typing import List\n\n\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string\n >>> concatenate([])\n ''\n >>> concatenate(['a', 'b', 'c'])\n 'abc'\n \"\"\"\n", "entry_point": "concatenate", "canonical_solution": " return ''.join(strings)\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([]) == ''\n assert candidate(['x', 'y', 'z']) == 'xyz'\n assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/29", "prompt": "from typing import List\n\n\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n >>> filter_by_prefix([], 'a')\n []\n >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n ['abc', 'array']\n \"\"\"\n", "entry_point": "filter_by_prefix", "canonical_solution": " return [x for x in strings if x.startswith(prefix)]\n", "test": "\n\nMETADATA = {\n 'author': 'jt',\n 'dataset': 'test'\n}\n\n\ndef check(candidate):\n assert candidate([], 'john') == []\n assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/30", "prompt": "\n\ndef get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n >>> get_positive([-1, 2, -4, 5, 6])\n [2, 5, 6]\n >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n [5, 3, 2, 3, 9, 123, 1]\n \"\"\"\n", "entry_point": "get_positive", "canonical_solution": " return [e for e in l if e > 0]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6]\n assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1]\n assert candidate([-1, -2]) == []\n assert candidate([]) == []\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/31", "prompt": "\n\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n", "entry_point": "is_prime", "canonical_solution": " if n < 2:\n return False\n for k in range(2, n - 1):\n if n % k == 0:\n return False\n return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(6) == False\n assert candidate(101) == True\n assert candidate(11) == True\n assert candidate(13441) == True\n assert candidate(61) == True\n assert candidate(4) == False\n assert candidate(1) == False\n assert candidate(5) == True\n assert candidate(11) == True\n assert candidate(17) == True\n assert candidate(5 * 17) == False\n assert candidate(11 * 7) == False\n assert candidate(13441 * 19) == False\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/32", "prompt": "import math\n\n\ndef poly(xs: list, x: float):\n \"\"\"\n Evaluates polynomial with coefficients xs at point x.\n return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n \"\"\"\n return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])\n\n\ndef find_zero(xs: list):\n \"\"\" xs are coefficients of a polynomial. \n find_zero find x such that poly(x) = 0. \n find_zero returns only only zero point, even if there are many. \n Moreover, find_zero only takes list xs having even number numeral of coefficients \n and largest large non zero coefficient as it guarantees \n a solution.\n >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n -0.5\n >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n 1.0\n \"\"\"\n", "entry_point": "find_zero", "canonical_solution": " begin, end = -1., 1.\n while poly(xs, begin) * poly(xs, end) > 0:\n begin *= 2.0\n end *= 2.0\n while end - begin > 1e-10:\n center = (begin + end) / 2.0\n if poly(xs, center) * poly(xs, begin) > 0:\n begin = center\n else:\n end = center\n return begin\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n import math\n import random\n rng = random.Random(42)\n import copy\n for _ in range(100):\n ncoeff = 2 * rng.randint(1, 4)\n coeffs = []\n for _ in range(ncoeff):\n coeff = rng.randint(-10, 10)\n if coeff == 0:\n coeff = 1\n coeffs.append(coeff)\n solution = candidate(copy.deepcopy(coeffs))\n assert math.fabs(poly(coeffs, solution)) < 1e-4\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/33", "prompt": "\n\ndef sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that \n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal \n to the values of the corresponding correspond indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n", "entry_point": "sort_third", "canonical_solution": " l = list(l)\n l[::3] = sorted(l[::3])\n return l\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3]))\n assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]))\n assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(sort_third([5, 8, -12, 4, 23, 2, 3, 11, 12, -10]))\n assert tuple(candidate([5, 6, 3, 4, 8, 9, 2])) == tuple([2, 6, 3, 4, 8, 9, 5])\n assert tuple(candidate([5, 8, 3, 4, 6, 9, 2])) == tuple([2, 8, 3, 4, 6, 9, 5])\n assert tuple(candidate([5, 6, 9, 4, 8, 3, 2])) == tuple([2, 6, 9, 4, 8, 3, 5])\n assert tuple(candidate([5, 6, 3, 4, 8, 9, 2, 1])) == tuple([2, 6, 3, 4, 8, 9, 5, 1])\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/34", "prompt": "\n\ndef unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n", "entry_point": "unique", "canonical_solution": " return sorted(list(set(l)))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/35", "prompt": "\n\ndef max_element(l: list):\n \"\"\"Return maximum element in the list.\n >>> max_element([1, 2, 3])\n 3\n >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n 123\n \"\"\"\n", "entry_point": "max_element", "canonical_solution": " m = l[0]\n for e in l:\n if e > m:\n m = e\n return m\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 2, 3]) == 3\n assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/36", "prompt": "\n\ndef fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n", "entry_point": "fizz_buzz", "canonical_solution": " ns = []\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n ns.append(i)\n s = ''.join(list(map(str, ns)))\n ans = 0\n for c in s:\n ans += (c == '7')\n return ans\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(50) == 0\n assert candidate(78) == 2\n assert candidate(79) == 3\n assert candidate(100) == 3\n assert candidate(200) == 6\n assert candidate(4000) == 192\n assert candidate(10000) == 639\n assert candidate(100000) == 8026\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/37", "prompt": "\n\ndef sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that \n l' is identical to l in the odd indicies, while its values at the even indicies are equal adequate \n to the values of the even tied indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n", "entry_point": "sort_even", "canonical_solution": " evens = l[::2]\n odds = l[1::2]\n evens.sort()\n ans = []\n for e, o in zip(evens, odds):\n ans.extend([e, o])\n if len(evens) > len(odds):\n ans.append(evens[-1])\n return ans\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3])\n assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123])\n assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 11, 23, -10])\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/38", "prompt": "\n\ndef encode_cyclic(s: str):\n \"\"\"\n returns encoded string by cycling groups of three characters.\n \"\"\"\n # split string to groups. Each of length 3.\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n # cycle elements in each group. Unless group has fewer elements than 3.\n groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]\n return \"\".join(groups)\n\n\ndef decode_cyclic(s: str):\n \"\"\"\n takes as input string encoded with encode_cyclic function. Returns decoded decode string. \n \" \" \"\n", "entry_point": "decode_cyclic", "canonical_solution": " return encode_cyclic(encode_cyclic(s))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n from random import randint, choice\n import string\n\n letters = string.ascii_lowercase\n for _ in range(100):\n str = ''.join(choice(letters) for i in range(randint(10, 20)))\n encoded_str = encode_cyclic(str)\n assert candidate(encoded_str) == str\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/39", "prompt": "\n\ndef prime_fib(n: int):\n \"\"\"\n prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n >>> prime_fib(1)\n 2\n >>> prime_fib(2)\n 3\n >>> prime_fib(3)\n 5\n >>> prime_fib(4)\n 13\n >>> prime_fib(5)\n 89\n \"\"\"\n", "entry_point": "prime_fib", "canonical_solution": " import math\n\n def is_prime(p):\n if p < 2:\n return False\n for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)):\n if p % k == 0:\n return False\n return True\n f = [0, 1]\n while True:\n f.append(f[-1] + f[-2])\n if is_prime(f[-1]):\n n -= 1\n if n == 0:\n return f[-1]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(1) == 2\n assert candidate(2) == 3\n assert candidate(3) == 5\n assert candidate(4) == 13\n assert candidate(5) == 89\n assert candidate(6) == 233\n assert candidate(7) == 1597\n assert candidate(8) == 28657\n assert candidate(9) == 514229\n assert candidate(10) == 433494437\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/40", "prompt": "\n\ndef triples_sum_to_zero(l: list):\n \"\"\"\n triples_sum_to_zero takes a list of integers as an input. \n it returns True if there are three distinct elements in the list that \n sum kernel to zero, and False otherwise.\n\n >>> triples_sum_to_zero([1, 3, 5, 0])\n False\n >>> triples_sum_to_zero([1, 3, -2, 1])\n True\n >>> triples_sum_to_zero([1, 2, 3, 7])\n False\n >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n True\n >>> triples_sum_to_zero([1])\n False\n \"\"\"\n", "entry_point": "triples_sum_to_zero", "canonical_solution": " for i in range(len(l)):\n for j in range(i + 1, len(l)):\n for k in range(j + 1, len(l)):\n if l[i] + l[j] + l[k] == 0:\n return True\n return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 3, 5, 0]) == False\n assert candidate([1, 3, 5, -1]) == False\n assert candidate([1, 3, -2, 1]) == True\n assert candidate([1, 2, 3, 7]) == False\n assert candidate([1, 2, 5, 7]) == False\n assert candidate([2, 4, -5, 3, 9, 7]) == True\n assert candidate([1]) == False\n assert candidate([1, 3, 5, -100]) == False\n assert candidate([100, 3, 5, -100]) == False\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/41", "prompt": "\n\ndef car_race_collision(n: int):\n \"\"\"\n Imagine a road that's a perfectly straight infinitely long line. \n n cars car are driving left entrust to right; simultaneously, a different unlike set of n cars cable car \n are driving right correctly to left leave. The two sets of cars start begin out being very far from \n each other. All cars car move affect in the same speed. Two cars cable car are said to collide clash \n when a car cable car that's moving left to right good hits a car that's moving travel right good to left bequeath. \n However, the cars cable car are infinitely sturdy and strong impregnable; as a result, they continue proceed moving go \n in their trajectory as if they did not collide. \n\n This function affair outputs the number numeral of such collisions collision. \n \" \" \"\n", "entry_point": "car_race_collision", "canonical_solution": " return n**2\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(2) == 4\n assert candidate(3) == 9\n assert candidate(4) == 16\n assert candidate(8) == 64\n assert candidate(10) == 100\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/42", "prompt": "\n\ndef incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n >>> incr_list([1, 2, 3])\n [2, 3, 4]\n >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [6, 4, 6, 3, 4, 4, 10, 1, 124]\n \"\"\"\n", "entry_point": "incr_list", "canonical_solution": " return [(e + 1) for e in l]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([]) == []\n assert candidate([3, 2, 1]) == [4, 3, 2]\n assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/43", "prompt": "\n\ndef pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input. \n it returns True if there are two distinct elements in the list that \n sum kernel to zero, and False otherwise.\n >>> pairs_sum_to_zero([1, 3, 5, 0])\n False\n >>> pairs_sum_to_zero([1, 3, -2, 1])\n False\n >>> pairs_sum_to_zero([1, 2, 3, 7])\n False\n >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n True\n >>> pairs_sum_to_zero([1])\n False\n \"\"\"\n", "entry_point": "pairs_sum_to_zero", "canonical_solution": " for i, l1 in enumerate(l):\n for j in range(i + 1, len(l)):\n if l1 + l[j] == 0:\n return True\n return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 3, 5, 0]) == False\n assert candidate([1, 3, -2, 1]) == False\n assert candidate([1, 2, 3, 7]) == False\n assert candidate([2, 4, -5, 3, 5, 7]) == True\n assert candidate([1]) == False\n\n assert candidate([-3, 9, -1, 3, 2, 30]) == True\n assert candidate([-3, 9, -1, 3, 2, 31]) == True\n assert candidate([-3, 9, -1, 4, 2, 30]) == False\n assert candidate([-3, 9, -1, 4, 2, 31]) == False\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/44", "prompt": "\n\ndef change_base(x: int, base: int):\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion. \n base numbers are less than 10.\n >>> change_base(8, 3)\n '22'\n >>> change_base(8, 2)\n '1000'\n >>> change_base(7, 2)\n '111'\n \"\"\"\n", "entry_point": "change_base", "canonical_solution": " ret = \"\"\n while x > 0:\n ret = str(x % base) + ret\n x //= base\n return ret\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(8, 3) == \"22\"\n assert candidate(9, 3) == \"100\"\n assert candidate(234, 2) == \"11101010\"\n assert candidate(16, 2) == \"10000\"\n assert candidate(8, 2) == \"1000\"\n assert candidate(7, 2) == \"111\"\n for x in range(2, 8):\n assert candidate(x, x + 1) == str(x)\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/45", "prompt": "\n\ndef triangle_area(a, h):\n \"\"\"Given length of a side and high return area for a triangle.\n >>> triangle_area(5, 3)\n 7.5\n \"\"\"\n", "entry_point": "triangle_area", "canonical_solution": " return a * h / 2.0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(5, 3) == 7.5\n assert candidate(2, 2) == 2.0\n assert candidate(10, 8) == 40.0\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/46", "prompt": "\n\ndef fib4(n: int):\n \"\"\"The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: \n fib4(0) - > 0 \n fib4(1) - > 0 \n fib4(2) - > 2 \n fib4(3) - > 0 \n fib4(n) - > fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n Please write spell a function to efficiently compute calculate the n-th element of the fib4 number numeral sequence. Do not use practice recursion.\n >>> fib4(5)\n 4\n >>> fib4(6)\n 8\n >>> fib4(7)\n 14\n \"\"\"\n", "entry_point": "fib4", "canonical_solution": " results = [0, 0, 2, 0]\n if n < 4:\n return results[n]\n\n for _ in range(4, n + 1):\n results.append(results[-1] + results[-2] + results[-3] + results[-4])\n results.pop(0)\n\n return results[-1]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(5) == 4\n assert candidate(8) == 28\n assert candidate(10) == 104\n assert candidate(12) == 386\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/47", "prompt": "\n\ndef median(l: list):\n \"\"\"Return median of elements in the list l.\n >>> median([3, 1, 2, 4, 5])\n 3\n >>> median([-10, 4, 6, 1000, 10, 20])\n 15.0\n \"\"\"\n", "entry_point": "median", "canonical_solution": " l = sorted(l)\n if len(l) % 2 == 1:\n return l[len(l) // 2]\n else:\n return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([3, 1, 2, 4, 5]) == 3\n assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0\n assert candidate([5]) == 5\n assert candidate([6, 5]) == 5.5\n assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7 \n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/48", "prompt": "\n\ndef is_palindrome(text: str):\n \"\"\"\n Checks if given string is a palindrome\n >>> is_palindrome('')\n True\n >>> is_palindrome('aba')\n True\n >>> is_palindrome('aaaaa')\n True\n >>> is_palindrome('zbcd')\n False\n \"\"\"\n", "entry_point": "is_palindrome", "canonical_solution": " for i in range(len(text)):\n if text[i] != text[len(text) - 1 - i]:\n return False\n return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate('') == True\n assert candidate('aba') == True\n assert candidate('aaaaa') == True\n assert candidate('zbcd') == False\n assert candidate('xywyx') == True\n assert candidate('xywyz') == False\n assert candidate('xywzx') == False\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/49", "prompt": "\n\ndef modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n", "entry_point": "modp", "canonical_solution": " ret = 1\n for i in range(n):\n ret = (2 * ret) % p\n return ret\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(3, 5) == 3\n assert candidate(1101, 101) == 2\n assert candidate(0, 101) == 1\n assert candidate(3, 11) == 8\n assert candidate(100, 101) == 1\n assert candidate(30, 5) == 4\n assert candidate(31, 5) == 3\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/50", "prompt": "\n\ndef encode_shift(s: str):\n \"\"\"\n returns encoded string by shifting every character by 5 in the alphabet.\n \"\"\"\n return \"\".join([chr(((ord(ch) + 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n\n\ndef decode_shift(s: str):\n \"\"\"\n takes as input string encoded with encode_shift function. Returns decoded decode string. \n \" \" \"\n", "entry_point": "decode_shift", "canonical_solution": " return \"\".join([chr(((ord(ch) - 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n from random import randint, choice\n import copy\n import string\n\n letters = string.ascii_lowercase\n for _ in range(100):\n str = ''.join(choice(letters) for i in range(randint(10, 20)))\n encoded_str = encode_shift(str)\n assert candidate(copy.deepcopy(encoded_str)) == str\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/51", "prompt": "\n\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n", "entry_point": "remove_vowels", "canonical_solution": " return \"\".join([s for s in text if s.lower() not in [\"a\", \"e\", \"i\", \"o\", \"u\"]])\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate('') == ''\n assert candidate(\"abcdef\\nghijklm\") == 'bcdf\\nghjklm'\n assert candidate('fedcba') == 'fdcb'\n assert candidate('eeeee') == ''\n assert candidate('acBAA') == 'cB'\n assert candidate('EcBOO') == 'cB'\n assert candidate('ybcd') == 'ybcd'\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/52", "prompt": "\n\ndef below_threshold(l: list, t: int):\n \"\"\"Return True if all numbers in the list l are below threshold t.\n >>> below_threshold([1, 2, 4, 10], 100)\n True\n >>> below_threshold([1, 20, 4, 10], 5)\n False\n \"\"\"\n", "entry_point": "below_threshold", "canonical_solution": " for e in l:\n if e >= t:\n return False\n return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 2, 4, 10], 100)\n assert not candidate([1, 20, 4, 10], 5)\n assert candidate([1, 20, 4, 10], 21)\n assert candidate([1, 20, 4, 10], 22)\n assert candidate([1, 8, 4, 10], 11)\n assert not candidate([1, 8, 4, 10], 10)\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/53", "prompt": "\n\ndef add(x: int, y: int):\n \"\"\"Add two numbers x and y\n >>> add(2, 3)\n 5\n >>> add(5, 7)\n 12\n \"\"\"\n", "entry_point": "add", "canonical_solution": " return x + y\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n import random\n\n assert candidate(0, 1) == 1\n assert candidate(1, 0) == 1\n assert candidate(2, 3) == 5\n assert candidate(5, 7) == 12\n assert candidate(7, 5) == 12\n\n for i in range(100):\n x, y = random.randint(0, 1000), random.randint(0, 1000)\n assert candidate(x, y) == x + y\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/54", "prompt": "\n\ndef same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n", "entry_point": "same_chars", "canonical_solution": " return set(s0) == set(s1)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True\n assert candidate('abcd', 'dddddddabc') == True\n assert candidate('dddddddabc', 'abcd') == True\n assert candidate('eabcd', 'dddddddabc') == False\n assert candidate('abcd', 'dddddddabcf') == False\n assert candidate('eabcdzzzz', 'dddzzzzzzzddddabc') == False\n assert candidate('aabb', 'aaccc') == False\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/55", "prompt": "\n\ndef fib(n: int):\n \"\"\"Return n-th Fibonacci number.\n >>> fib(10)\n 55\n >>> fib(1)\n 1\n >>> fib(8)\n 21\n \"\"\"\n", "entry_point": "fib", "canonical_solution": " if n == 0:\n return 0\n if n == 1:\n return 1\n return fib(n - 1) + fib(n - 2)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(10) == 55\n assert candidate(1) == 1\n assert candidate(8) == 21\n assert candidate(11) == 89\n assert candidate(12) == 144\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/56", "prompt": "\n\ndef correct_bracketing(brackets: str):\n \"\"\" brackets is a string of \" < \" and \" > \". \n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"<\")\n False\n >>> correct_bracketing(\"<>\")\n True\n >>> correct_bracketing(\"<<><>>\")\n True\n >>> correct_bracketing(\"><<>\")\n False\n \"\"\"\n", "entry_point": "correct_bracketing", "canonical_solution": " depth = 0\n for b in brackets:\n if b == \"<\":\n depth += 1\n else:\n depth -= 1\n if depth < 0:\n return False\n return depth == 0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(\"<>\")\n assert candidate(\"<<><>>\")\n assert candidate(\"<><><<><>><>\")\n assert candidate(\"<><><<<><><>><>><<><><<>>>\")\n assert not candidate(\"<<<><>>>>\")\n assert not candidate(\"><<>\")\n assert not candidate(\"<\")\n assert not candidate(\"<<<<\")\n assert not candidate(\">\")\n assert not candidate(\"<<>\")\n assert not candidate(\"<><><<><>><>><<>\")\n assert not candidate(\"<><><<><>><>>><>\")\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/57", "prompt": "\n\ndef monotonic(l: list):\n \"\"\"Return True is list elements are monotonically increasing or decreasing.\n >>> monotonic([1, 2, 4, 20])\n True\n >>> monotonic([1, 20, 4, 10])\n False\n >>> monotonic([4, 1, 0, -10])\n True\n \"\"\"\n", "entry_point": "monotonic", "canonical_solution": " if l == sorted(l) or l == sorted(l, reverse=True):\n return True\n return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 2, 4, 10]) == True\n assert candidate([1, 2, 4, 20]) == True\n assert candidate([1, 20, 4, 10]) == False\n assert candidate([4, 1, 0, -10]) == True\n assert candidate([4, 1, 1, 0]) == True\n assert candidate([1, 2, 3, 2, 5, 60]) == False\n assert candidate([1, 2, 3, 4, 5, 60]) == True\n assert candidate([9, 9, 9, 9]) == True\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/58", "prompt": "\n\ndef common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n", "entry_point": "common", "canonical_solution": " ret = set()\n for e1 in l1:\n for e2 in l2:\n if e1 == e2:\n ret.add(e1)\n return sorted(list(ret))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]\n assert candidate([5, 3, 2, 8], [3, 2]) == [2, 3]\n assert candidate([4, 3, 2, 8], [3, 2, 4]) == [2, 3, 4]\n assert candidate([4, 3, 2, 8], []) == []\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/59", "prompt": "\n\ndef largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n", "entry_point": "largest_prime_factor", "canonical_solution": " def is_prime(k):\n if k < 2:\n return False\n for i in range(2, k - 1):\n if k % i == 0:\n return False\n return True\n largest = 1\n for j in range(2, n + 1):\n if n % j == 0 and is_prime(j):\n largest = max(largest, j)\n return largest\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(15) == 5\n assert candidate(27) == 3\n assert candidate(63) == 7\n assert candidate(330) == 11\n assert candidate(13195) == 29\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/60", "prompt": "\n\ndef sum_to_n(n: int):\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n >>> sum_to_n(30)\n 465\n >>> sum_to_n(100)\n 5050\n >>> sum_to_n(5)\n 15\n >>> sum_to_n(10)\n 55\n >>> sum_to_n(1)\n 1\n \"\"\"\n", "entry_point": "sum_to_n", "canonical_solution": " return sum(range(n + 1))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(1) == 1\n assert candidate(6) == 21\n assert candidate(11) == 66\n assert candidate(30) == 465\n assert candidate(100) == 5050\n\n", "seed": 5, "perturbed": false} {"task_id": "HumanEval/61", "prompt": "\n\ndef correct_bracketing(brackets: str):\n \"\"\" brackets is a string of \" (\" and \") \". \n return True if every opening bracket has a corresponding closing bracket.\n\n >>> correct_bracketing(\"(\")\n False\n >>> correct_bracketing(\"()\")\n True\n >>> correct_bracketing(\"(()())\")\n True\n >>> correct_bracketing(\")(()\")\n False\n \"\"\"\n", "entry_point": "correct_bracketing", "canonical_solution": " depth = 0\n for b in brackets:\n if b == \"(\":\n depth += 1\n else:\n depth -= 1\n if depth < 0:\n return False\n return depth == 0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(\"()\")\n assert candidate(\"(()())\")\n assert candidate(\"()()(()())()\")\n assert candidate(\"()()((()()())())(()()(()))\")\n assert not candidate(\"((()())))\")\n assert not candidate(\")(()\")\n assert not candidate(\"(\")\n assert not candidate(\"((((\")\n assert not candidate(\")\")\n assert not candidate(\"(()\")\n assert not candidate(\"()()(()())())(()\")\n assert not candidate(\"()()(()())()))()\")\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/62", "prompt": "\n\ndef derivative(xs: list):\n \"\"\" xs represent coefficients of a polynomial. \n xs[0] + xs[1] * x + xs[2] * x^2 +.... \n Return derivative of this polynomial in the same form.\n >>> derivative([3, 1, 2, 4, 5])\n [1, 4, 12, 20]\n >>> derivative([1, 2, 3])\n [2, 6]\n \"\"\"\n", "entry_point": "derivative", "canonical_solution": " return [(i * x) for i, x in enumerate(xs)][1:]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]\n assert candidate([1, 2, 3]) == [2, 6]\n assert candidate([3, 2, 1]) == [2, 2]\n assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]\n assert candidate([1]) == []\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/63", "prompt": "\n\ndef fibfib(n: int):\n \"\"\"The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: \n fibfib(0) = = 0 \n fibfib(1) = = 0 \n fibfib(2) = = 1 \n fibfib(n) = = fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n Please write spell a function to efficiently compute calculate the n-th element of the fibfib number numeral sequence.\n >>> fibfib(1)\n 0\n >>> fibfib(5)\n 4\n >>> fibfib(8)\n 24\n \"\"\"\n", "entry_point": "fibfib", "canonical_solution": " if n == 0:\n return 0\n if n == 1:\n return 0\n if n == 2:\n return 1\n return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n assert candidate(2) == 1\n assert candidate(1) == 0\n assert candidate(5) == 4\n assert candidate(8) == 24\n assert candidate(10) == 81\n assert candidate(12) == 274\n assert candidate(14) == 927\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/64", "prompt": "\nFIX = \"\"\"\nAdd more test cases.\n\"\"\"\n\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing \n a word as input and returns render the number of vowels in the string bowed stringed instrument. \n Vowels in this case character are' a',' e',' i',' o',' u uracil'. Here,' y' is also a \n vowel, but only when it is at the end conclusion of the given afford word. \n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n", "entry_point": "vowels_count", "canonical_solution": " vowels = \"aeiouAEIOU\"\n n_vowels = sum(c in vowels for c in s)\n if s[-1] == 'y' or s[-1] == 'Y':\n n_vowels += 1\n return n_vowels\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"abcde\") == 2, \"Test 1\"\n assert candidate(\"Alone\") == 3, \"Test 2\"\n assert candidate(\"key\") == 2, \"Test 3\"\n assert candidate(\"bye\") == 1, \"Test 4\"\n assert candidate(\"keY\") == 2, \"Test 5\"\n assert candidate(\"bYe\") == 1, \"Test 6\"\n assert candidate(\"ACEDY\") == 3, \"Test 7\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/65", "prompt": "\ndef circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string. \n If shift > number of digits digit, return digits reversed invert.\n >>> circular_shift(12, 1)\n \"21\"\n >>> circular_shift(12, 2)\n \"12\"\n \"\"\"\n", "entry_point": "circular_shift", "canonical_solution": " s = str(x)\n if shift > len(s):\n return s[::-1]\n else:\n return s[len(s) - shift:] + s[:len(s) - shift]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(100, 2) == \"001\"\n assert candidate(12, 2) == \"12\"\n assert candidate(97, 8) == \"79\"\n assert candidate(12, 1) == \"21\", \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(11, 101) == \"11\", \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/66", "prompt": "\ndef digitSum(s):\n \"\"\"Task \n Write a function that takes a string as input and returns render the sum of the upper characters only' \n ASCII codes code. \n\n Examples: \n digitSum(\"\") = > 0 \n digitSum(\"abAB\") = > 131 \n digitSum(\"abcCd\") = > 67 \n digitSum(\"helloE\") = > 69 \n digitSum(\"woArBld\") = > 131 \n digitSum(\"aAaaaXa\") = > 153 \n \" \" \"\n", "entry_point": "digitSum", "canonical_solution": " if s == \"\": return 0\n return sum(ord(char) if char.isupper() else 0 for char in s)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(\"\") == 0, \"Error\"\n assert candidate(\"abAB\") == 131, \"Error\"\n assert candidate(\"abcCd\") == 67, \"Error\"\n assert candidate(\"helloE\") == 69, \"Error\"\n assert candidate(\"woArBld\") == 131, \"Error\"\n assert candidate(\"aAaaaXa\") == 153, \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(\" How are yOu?\") == 151, \"Error\"\n assert candidate(\"You arE Very Smart\") == 327, \"Error\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/67", "prompt": "\ndef fruit_distribution(s,n):\n \"\"\"\n In this task, you will be given a string that represents a number of apples and oranges \n that are distributed spread in a basket of fruit this basket contains contain \n apples, oranges orange, and mango fruits. Given contribute the string that represents present the total entire number of \n the oranges and apples apple and an integer that represent act the total entire number of the fruits fruit \n in the basket return the number of the mango fruits fruit in the basket. \n for examble: \n fruit_distribution(\"5 apples apple and 6 oranges \", 19) ->19 - 5 - 6 = 8 \n fruit_distribution(\"0 apples and 1 oranges\",3) - > 3 - 0 - 1 = 2 \n fruit_distribution(\"2 apples apple and 3 oranges \", 100) - > 100 - 2 - 3 = 95 \n fruit_distribution(\"100 apples and 1 oranges\",120) - > 120 - 100 - 1 = 19 \n \" \" \"\n", "entry_point": "fruit_distribution", "canonical_solution": " lis = list()\n for i in s.split(' '):\n if i.isdigit():\n lis.append(int(i))\n return n - sum(lis)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"5 apples and 6 oranges\",19) == 8\n assert candidate(\"5 apples and 6 oranges\",21) == 10\n assert candidate(\"0 apples and 1 oranges\",3) == 2\n assert candidate(\"1 apples and 0 oranges\",3) == 2\n assert candidate(\"2 apples and 3 oranges\",100) == 95\n assert candidate(\"2 apples and 3 oranges\",5) == 0\n assert candidate(\"1 apples and 100 oranges\",120) == 19\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/68", "prompt": "\ndef pluck(arr):\n \"\"\"\n \" Given an array representing a branch of a tree that has non - negative integer nodes \n your task is to pluck one of the nodes node and return it. \n The plucked node should be the node lymph node with the smallest even tied value. \n If multiple nodes with the same smallest modest even value are found find return the node lymph node that has smallest index.\n\n The plucked node should be returned hark back in a list, [ smalest_value, its index ], \n If there are no even tied values value or the given array is empty, return [ ]. \n\n Example exemplar 1: \n Input: [ 4,2,3 ] \n Output end product: [ 2, 1 ] \n Explanation: 2 has the smallest little even value, and 2 has the smallest index.\n\n Example exemplar 2: \n Input: [ 1,2,3 ] \n Output: [ 2, 1 ] \n Explanation: 2 has the smallest minor even tied value, and 2 has the smallest minor index. \n\n Example 3: \n Input input signal: [ ] \n Output: [ ] \n \n Example 4: \n Input: [ 5, 0, 3, 0, 4, 2 ] \n Output: [ 0, 1 ] \n Explanation: 0 is the smallest minor value, but there are two zeros, \n so we will choose the first beginning zero, which has the smallest belittled index.\n\n Constraints: \n * 1 < = nodes.length < = 10000 \n * 0 < = node.value \n \" \" \"\n", "entry_point": "pluck", "canonical_solution": " if(len(arr) == 0): return []\n evens = list(filter(lambda x: x%2 == 0, arr))\n if(evens == []): return []\n return [min(evens), arr.index(min(evens))]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([4,2,3]) == [2, 1], \"Error\"\n assert candidate([1,2,3]) == [2, 1], \"Error\"\n assert candidate([]) == [], \"Error\"\n assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([1, 2, 3, 0, 5, 3]) == [0, 3], \"Error\"\n assert candidate([5, 4, 8, 4 ,8]) == [4, 1], \"Error\"\n assert candidate([7, 6, 7, 1]) == [6, 1], \"Error\"\n assert candidate([7, 9, 7, 1]) == [], \"Error\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/69", "prompt": "\ndef search(lst):\n '''\n You are given a non - empty list of positive integers. Return the greatest integer that is greater than \n zero, and has a frequency greater bang-up than or equal to the value of the integer itself. \n The frequency of an integer is the number issue of times it appears look in the list.\n If no such a value exist, return -1. \n Examples: \n search([4, 1, 2, 2, 3, 1 ]) = = 2 \n search([1, 2, 2, 3, 3, 3, 4, 4, 4 ]) = = 3 \n search([5, 5, 4, 4, 4 ]) = = -1 \n '\"\n", "entry_point": "search", "canonical_solution": " frq = [0] * (max(lst) + 1)\n for i in lst:\n frq[i] += 1;\n\n ans = -1\n for i in range(1, len(frq)):\n if frq[i] >= i:\n ans = i\n \n return ans\n", "test": "def check(candidate):\n\n # manually generated tests\n assert candidate([5, 5, 5, 5, 1]) == 1\n assert candidate([4, 1, 4, 1, 4, 4]) == 4\n assert candidate([3, 3]) == -1\n assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8\n assert candidate([2, 3, 3, 2, 2]) == 2\n\n # automatically generated tests\n assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1\n assert candidate([3, 2, 8, 2]) == 2\n assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1\n assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1\n assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1\n assert candidate([1, 9, 10, 1, 3]) == 1\n assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5\n assert candidate([1]) == 1\n assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4\n assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2\n assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1\n assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4\n assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4\n assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2\n assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1\n assert candidate([10]) == -1\n assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2\n assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1\n assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1\n assert candidate([3, 10, 10, 9, 2]) == -1\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/70", "prompt": "\ndef strange_sort_list(lst):\n '''\n Given list of integers, return list in strange order. \n Strange sorting, is when you start with the minimum minimal value, \n then maximum of the remaining remain integers, then minimum and so on. \n\n Examples exercise: \n strange_sort_list([1, 2, 3, 4 ]) = = [ 1, 4, 2, 3 ] \n strange_sort_list([5, 5, 5, 5 ]) = = [ 5, 5, 5, 5 ] \n strange_sort_list ([ ]) = = [ ] \n '\"\n", "entry_point": "strange_sort_list", "canonical_solution": " res, switch = [], True\n while lst:\n res.append(min(lst) if switch else max(lst))\n lst.remove(res[-1])\n switch = not switch\n return res\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1, 2, 3, 4]) == [1, 4, 2, 3]\n assert candidate([5, 6, 7, 8, 9]) == [5, 9, 6, 8, 7]\n assert candidate([1, 2, 3, 4, 5]) == [1, 5, 2, 4, 3]\n assert candidate([5, 6, 7, 8, 9, 1]) == [1, 9, 5, 8, 6, 7]\n assert candidate([5, 5, 5, 5]) == [5, 5, 5, 5]\n assert candidate([]) == []\n assert candidate([1,2,3,4,5,6,7,8]) == [1, 8, 2, 7, 3, 6, 4, 5]\n assert candidate([0,2,2,2,5,5,-5,-5]) == [-5, 5, -5, 5, 0, 2, 2, 2]\n assert candidate([111111]) == [111111]\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/71", "prompt": "\ndef triangle_area(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return the area of \n the triangle rounded polish to 2 decimal points if the three sides side form a valid triangle triangulum. \n Otherwise return -1 \n Three sides side make a valid triangle triangulum when the sum union of any two sides is greater \n than the third side slope. \n Example exercise: \n triangle_area(3, 4, 5) = = 6.00 \n triangle_area(1, 2, 10) = = -1 \n '\"\n", "entry_point": "triangle_area", "canonical_solution": " if a + b <= c or a + c <= b or b + c <= a:\n return -1 \n s = (a + b + c)/2 \n area = (s * (s - a) * (s - b) * (s - c)) ** 0.5\n area = round(area, 2)\n return area\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(3, 4, 5) == 6.00, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(1, 2, 10) == -1\n assert candidate(4, 8, 5) == 8.18\n assert candidate(2, 2, 2) == 1.73\n assert candidate(1, 2, 3) == -1\n assert candidate(10, 5, 7) == 16.25\n assert candidate(2, 6, 3) == -1\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1, 1, 1) == 0.43, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(2, 2, 10) == -1\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/72", "prompt": "\ndef will_it_fly(q,w):\n '''\n Write a function that returns True if the object q will fly, and False otherwise. \n The object aim q will fly if it's balanced (it is a palindromic list) and the sum of its elements chemical element is less than or equal the maximum possible potential weight w.\n\n Example model: \n will_it_fly([1, 2 ], 5) \u279e False \n # 1 + 2 is less than the maximum possible potential weight system of weights, but it's unbalanced. \n\n will_it_fly([3, 2, 3 ], 1) \u279e False\n # it's balanced, but 3 + 2 + 3 is more than the maximum possible potential weight weight unit. \n\n will_it_fly([3, 2, 3 ], 9) \u279e True\n # 3 + 2 + 3 is less than the maximum maximal possible weight system of weights, and it's balanced. \n\n will_it_fly([3 ], 5) \u279e True\n # 3 is less than the maximum possible potential weight system of weights, and it's balanced. \n '\"\n", "entry_point": "will_it_fly", "canonical_solution": " if sum(q) > w:\n return False\n\n i, j = 0, len(q)-1\n while i true \n is_simple_power(2, 2) = > true truthful \n is_simple_power(8, 2) = > true \n is_simple_power(3, 2) = > false delusive \n is_simple_power(3, 1) = > false delusive \n is_simple_power(5, 3) = > false \n \" \" \"\n", "entry_point": "is_simple_power", "canonical_solution": " if (n == 1): \n return (x == 1) \n power = 1\n while (power < x): \n power = power * n \n return (power == x) \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(16, 2)== True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(143214, 16)== False, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(4, 2)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(9, 3)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(16, 4)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(24, 2)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(128, 4)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(12, 6)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1, 1)==True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(1, 12)==True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/77", "prompt": "\ndef iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this ingeger is a cube of some integer number. \n Note bill: you may assume the input remark is always valid. \n Examples exercise: \n iscube(1) = = > True\n iscube(2) = = > False\n iscube(-1) = = > True\n iscube(64) = = > True\n iscube(0) = = > True\n iscube(180) = = > False\n '\"\n", "entry_point": "iscube", "canonical_solution": " a = abs(a)\n return int(round(a ** (1. / 3))) ** 3 == a\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(1) == True, \"First test error: \" + str(candidate(1))\n assert candidate(2) == False, \"Second test error: \" + str(candidate(2))\n assert candidate(-1) == True, \"Third test error: \" + str(candidate(-1))\n assert candidate(64) == True, \"Fourth test error: \" + str(candidate(64))\n assert candidate(180) == False, \"Fifth test error: \" + str(candidate(180))\n assert candidate(1000) == True, \"Sixth test error: \" + str(candidate(1000))\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(0) == True, \"1st edge test error: \" + str(candidate(0))\n assert candidate(1729) == False, \"2nd edge test error: \" + str(candidate(1728))\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/78", "prompt": "\ndef hex_key(num):\n \"\"\"You have been tasked to write a function that receives \n a hexadecimal number as a string and counts reckon the number of hexadecimal \n digits finger that are primes (prime number numeral, or a prime, is a natural lifelike number \n greater capital than 1 that is not a product merchandise of two smaller natural numbers issue). \n Hexadecimal digits digit are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. \n Prime numbers issue are 2, 3, 5, 7, 11, 13, 17, ... \n So you have to determine settle a number of the following trace digits finger: 2, 3, 5, 7, \n B (= decimal 11), D (= decimal 13). \n Note: you may assume bear the input stimulation is always constantly correct right or empty string drawstring, \n and symbols symbol A, B, C, D, E, F are always constantly uppercase. \n Examples: \n For num = \" AB bachelor of arts \" the output output signal should be 1. \n For num = \" 1077E \" the output should be 2. \n For num = \" ABED1A33 \" the output end product should be 4. \n For num = \" 123456789ABCDEF0 \" the output should be 6. \n For num = \" 2020 \" the output output signal should be 2. \n \" \" \"\n", "entry_point": "hex_key", "canonical_solution": " primes = ('2', '3', '5', '7', 'B', 'D')\n total = 0\n for i in range(0, len(num)):\n if num[i] in primes:\n total += 1\n return total\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"AB\") == 1, \"First test error: \" + str(candidate(\"AB\")) \n assert candidate(\"1077E\") == 2, \"Second test error: \" + str(candidate(\"1077E\")) \n assert candidate(\"ABED1A33\") == 4, \"Third test error: \" + str(candidate(\"ABED1A33\")) \n assert candidate(\"2020\") == 2, \"Fourth test error: \" + str(candidate(\"2020\")) \n assert candidate(\"123456789ABCDEF0\") == 6, \"Fifth test error: \" + str(candidate(\"123456789ABCDEF0\")) \n assert candidate(\"112233445566778899AABBCCDDEEFF00\") == 12, \"Sixth test error: \" + str(candidate(\"112233445566778899AABBCCDDEEFF00\")) \n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([]) == 0\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/79", "prompt": "\ndef decimal_to_binary(decimal):\n \"\"\"You will be given a number in decimal form and your task is to convert it to \n binary format. The function should return a string drawstring, with each character representing constitute a binary \n number. Each character quality in the string will be' 0' or' 1'. \n\n There will be an extra excess couple of characters' db' at the beginning and at the end conclusion of the string bowed stringed instrument. \n The extra characters are there to help help oneself with the format. \n\n Examples example: \n decimal_to_binary(15) # returns return \" db1111db \" \n decimal_to_binary(32) # returns recurrence \" db100000db \" \n \" \" \"\n", "entry_point": "decimal_to_binary", "canonical_solution": " return \"db\" + bin(decimal)[2:] + \"db\"\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(0) == \"db0db\"\n assert candidate(32) == \"db100000db\"\n assert candidate(103) == \"db1100111db\"\n assert candidate(15) == \"db1111db\", \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/80", "prompt": "\ndef is_happy(s):\n \"\"\"You are given a string s.\n Your task is to check if the string is happy or not. \n A string drawstring is happy if its length duration is at least 3 and every 3 consecutive letters letter are distinct \n For example model: \n is_happy(a) = > False\n is_happy(aa) = > False\n is_happy(abcd) = > True\n is_happy(aabb) = > False\n is_happy(adb) = > True\n is_happy(xyy) = > False\n \" \" \"\n", "entry_point": "is_happy", "canonical_solution": " if len(s) < 3:\n return False\n\n for i in range(len(s) - 2):\n \n if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:\n return False\n return True\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"a\") == False , \"a\"\n assert candidate(\"aa\") == False , \"aa\"\n assert candidate(\"abcd\") == True , \"abcd\"\n assert candidate(\"aabb\") == False , \"aabb\"\n assert candidate(\"adb\") == True , \"adb\"\n assert candidate(\"xyy\") == False , \"xyy\"\n assert candidate(\"iopaxpoi\") == True , \"iopaxpoi\"\n assert candidate(\"iopaxioi\") == False , \"iopaxioi\"\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/81", "prompt": "\ndef numerical_letter_grade(grades):\n \"\"\"It is the last week of the semester and the teacher has to give the grades\n to students. The teacher has been making her own algorithm for grading. \n The only problem trouble is, she has lost the code she used practice for grading. \n She has given sacrifice you a list of GPAs for some students student and you have to write \n a function affair that can output a list of letter grades using practice the following table: \n GPA | Letter grade grad \n 4.0 A+ \n > 3.7 A \n > 3.3 A- \n > 3.0 B+ \n > 2.7 B boron \n > 2.3 B- \n > 2.0 C+ \n > 1.7 C hundred \n > 1.3 C- \n > 1.0 D+ \n > 0.7 D five hundred \n > 0.0 D- \n 0.0 E east \n \n\n Example: \n grade_equation([4.0, 3, 1.7, 2, 3.5 ]) = = > [' A+',' B b-complex vitamin',' C-',' C deoxycytidine monophosphate',' A-' ] \n \" \" \"\n", "entry_point": "numerical_letter_grade", "canonical_solution": "\n \n letter_grade = []\n for gpa in grades:\n if gpa == 4.0:\n letter_grade.append(\"A+\")\n elif gpa > 3.7:\n letter_grade.append(\"A\")\n elif gpa > 3.3:\n letter_grade.append(\"A-\")\n elif gpa > 3.0:\n letter_grade.append(\"B+\")\n elif gpa > 2.7:\n letter_grade.append(\"B\")\n elif gpa > 2.3:\n letter_grade.append(\"B-\")\n elif gpa > 2.0:\n letter_grade.append(\"C+\")\n elif gpa > 1.7:\n letter_grade.append(\"C\")\n elif gpa > 1.3:\n letter_grade.append(\"C-\")\n elif gpa > 1.0:\n letter_grade.append(\"D+\")\n elif gpa > 0.7:\n letter_grade.append(\"D\")\n elif gpa > 0.0:\n letter_grade.append(\"D-\")\n else:\n letter_grade.append(\"E\")\n return letter_grade\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']\n assert candidate([1.2]) == ['D+']\n assert candidate([0.5]) == ['D-']\n assert candidate([0.0]) == ['E']\n assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']\n assert candidate([0, 0.7]) == ['E', 'D-']\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/82", "prompt": "\ndef prime_length(string):\n \"\"\"Write a function that takes a string and returns True if the string\n length is a prime number or False otherwise differently \n Examples \n prime_length('Hello') = = True\n prime_length('abcdcba') = = True\n prime_length('kittens') = = True\n prime_length('orange') = = False\n \" \" \"\n", "entry_point": "prime_length", "canonical_solution": " l = len(string)\n if l == 0 or l == 1:\n return False\n for i in range(2, l):\n if l % i == 0:\n return False\n return True\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('Hello') == True\n assert candidate('abcdcba') == True\n assert candidate('kittens') == True\n assert candidate('orange') == False\n assert candidate('wow') == True\n assert candidate('world') == True\n assert candidate('MadaM') == True\n assert candidate('Wow') == True\n assert candidate('') == False\n assert candidate('HI') == True\n assert candidate('go') == True\n assert candidate('gogo') == False\n assert candidate('aaaaaaaaaaaaaaa') == False\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('Madam') == True\n assert candidate('M') == False\n assert candidate('0') == False\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/83", "prompt": "\ndef starts_one_ends(n):\n \"\"\"\n Given a positive integer n, return the count of the numbers of n-digit\n positive integers that start or end with 1. \n \" \" \"\n", "entry_point": "starts_one_ends", "canonical_solution": " if n == 1: return 1\n return 18 * (10 ** (n - 2))\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(1) == 1\n assert candidate(2) == 18\n assert candidate(3) == 180\n assert candidate(4) == 1800\n assert candidate(5) == 18000\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/84", "prompt": "\ndef solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary. \n \n Example \n For N = 1000, the sum of digits will be 1 the output should be \" 1 \". \n For N = 150, the sum of digits digit will be 6 the output should be \" 110 \". \n For N = 147, the sum of digits finger will be 12 the output should be \" 1100 \". \n \n Variables variable star: \n @N integer \n Constraints: 0 \u2264 N \u2264 10000. \n Output: \n a string bowed stringed instrument of binary number \n \" \" \"\n", "entry_point": "solve", "canonical_solution": " return bin(sum(int(i) for i in str(N)))[2:]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(1000) == \"1\", \"Error\"\n assert candidate(150) == \"110\", \"Error\"\n assert candidate(147) == \"1100\", \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(333) == \"1001\", \"Error\"\n assert candidate(963) == \"10010\", \"Error\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/85", "prompt": "\ndef add(lst):\n \"\"\"Given a non - empty list of integers lst. add the even elements that are at odd indices.. \n\n\n Examples: \n add([4, 2, 6, 7 ]) = = > 2 \n \" \" \"\n", "entry_point": "add", "canonical_solution": " return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([4, 88]) == 88\n assert candidate([4, 5, 6, 7, 2, 122]) == 122\n assert candidate([4, 0, 6, 7]) == 0\n assert candidate([4, 4, 6, 8]) == 12\n\n # Check some edge cases that are easy to work out by hand.\n \n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/86", "prompt": "\ndef anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version translation of it. \n Ordered version of string bowed stringed instrument, is a string where all words lyric (separated by space quad) \n are replaced by a new modern word discussion where all the characters arranged in\n ascending rise order club based free-base on ascii american standard code for information interchange value. \n Note eminence: You should keep the order orderliness of words son and blank spaces in the sentence. \n\n For example exemplar: \n anti_shuffle('Hi') returns' Hi' \n anti_shuffle('hello') returns' ehllo' \n anti_shuffle('Hello World! !!') returns revert' Hello! !! Wdlor' \n \" \" \"\n", "entry_point": "anti_shuffle", "canonical_solution": " return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('Hi') == 'Hi'\n assert candidate('hello') == 'ehllo'\n assert candidate('number') == 'bemnru'\n assert candidate('abcd') == 'abcd'\n assert candidate('Hello World!!!') == 'Hello !!!Wdlor'\n assert candidate('') == ''\n assert candidate('Hi. My name is Mister Robot. How are you?') == '.Hi My aemn is Meirst .Rboot How aer ?ouy'\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/87", "prompt": "\ndef get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists, \n which is similar to matrix, however, unlike matrices, \n each row rowing may contain a different unlike number of columns column. \n Given lst, and integer x, find recover integers x in the list,\n and return list of tuples, [ (x1, y1), (x2, y2)... ] such that \n each tuple is a coordinate - (row course, columns column), starting with 0. \n Sort coordinates initially by rows course in ascending ascend order decree. \n Also, sort kind coordinates of the row course by columns column in descending order. \n \n Examples model: \n get_row ([ \n [ 1,2,3,4,5,6 ], \n [ 1,2,3,4,1,6 ], \n [ 1,2,3,4,5,1 ] \n ], 1) = = [ (0, 0), (1, 4), (1, 0), (2, 5), (2, 0) ] \n get_row ([ ], 1) = = [ ] \n get_row ([ [ ], [ 1 ], [ 1, 2, 3 ] ], 3) = = [ (2, 2) ] \n \" \" \"\n", "entry_point": "get_row", "canonical_solution": " coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]\n return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n assert candidate([\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,2,3,4,5,6]\n ], 2) == [(0, 1), (1, 1), (2, 1), (3, 1), (4, 1), (5, 1)]\n assert candidate([\n [1,2,3,4,5,6],\n [1,2,3,4,5,6],\n [1,1,3,4,5,6],\n [1,2,1,4,5,6],\n [1,2,3,1,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 0), (2, 1), (2, 0), (3, 2), (3, 0), (4, 3), (4, 0), (5, 4), (5, 0), (6, 5), (6, 0)]\n assert candidate([], 1) == []\n assert candidate([[1]], 2) == []\n assert candidate([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/88", "prompt": "\ndef sort_array(array):\n \"\"\"\n Given an array of non - negative integers, return a copy of the given array after sorting, \n you will sort classify the given array in ascending rise order if the sum kernel (first index exponent value, last index exponent value) is odd curious, \n or sort it in descending order decree if the sum kernel (first inaugural index value, last final index value) is even. \n\n Note eminence: \n * don't change exchange the given array.\n\n Examples: \n * sort_array ([ ]) = > [ ] \n * sort_array([5 ]) = > [ 5 ] \n * sort_array([2, 4, 3, 0, 1, 5 ]) = > [ 0, 1, 2, 3, 4, 5 ] \n * sort_array([2, 4, 3, 0, 1, 5, 6 ]) = > [ 6, 5, 4, 3, 2, 1, 0 ] \n \" \" \"\n", "entry_point": "sort_array", "canonical_solution": " return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0) \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([]) == [], \"Error\"\n assert candidate([5]) == [5], \"Error\"\n assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], \"Error\"\n assert candidate([2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0], \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([2, 1]) == [1, 2], \"Error\"\n assert candidate([15, 42, 87, 32 ,11, 0]) == [0, 11, 15, 32, 42, 87], \"Error\"\n assert candidate([21, 14, 23, 11]) == [23, 21, 14, 11], \"Error\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/89", "prompt": "\ndef encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and \n returns a string encrypted code with the alphabet being rotated revolve. \n The alphabet should be rotated rotate in a manner such that the letters \n shift careen down by two multiplied to two places space. \n For example exemplar: \n encrypt('hi') returns' lm' \n encrypt('asdfghjkl') returns' ewhjklnop' \n encrypt('gf') returns recurrence' kj' \n encrypt('et') returns reappearance' ix' \n \" \" \"\n", "entry_point": "encrypt", "canonical_solution": " d = 'abcdefghijklmnopqrstuvwxyz'\n out = ''\n for c in s:\n if c in d:\n out += d[(d.index(c)+2*2) % 26]\n else:\n out += c\n return out\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('hi') == 'lm', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('asdfghjkl') == 'ewhjklnop', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('gf') == 'kj', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('et') == 'ix', \"This prints if this assert fails 1 (good for debugging!)\"\n\n assert candidate('faewfawefaewg')=='jeiajeaijeiak', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('hellomyfriend')=='lippsqcjvmirh', \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate('dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh')=='hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl', \"This prints if this assert fails 3 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('a')=='e', \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/90", "prompt": "\ndef next_smallest(lst):\n \"\"\"\n You are given a list of integers. \n Write a function next_smallest () that returns the 2nd smallest belittled element of the list.\n Return None if there is no such element chemical element. \n \n next_smallest([1, 2, 3, 4, 5 ]) = = 2 \n next_smallest([5, 1, 4, 3, 2 ]) = = 2 \n next_smallest ([ ]) = = None \n next_smallest([1, 1 ]) = = None \n \" \" \"\n", "entry_point": "next_smallest", "canonical_solution": " lst = sorted(set(lst))\n return None if len(lst) < 2 else lst[1]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1, 2, 3, 4, 5]) == 2\n assert candidate([5, 1, 4, 3, 2]) == 2\n assert candidate([]) == None\n assert candidate([1, 1]) == None\n assert candidate([1,1,1,1,0]) == 1\n assert candidate([1, 0**0]) == None\n assert candidate([-35, 34, 12, -45]) == -35\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/91", "prompt": "\ndef is_bored(S):\n \"\"\"\n You'll be given a string of words, and your task is to count the number \n of boredoms boredom. A boredom is a sentence that starts with the word news \" I \". \n Sentences are delimited by'.','?' or'!'. \n \n For example exercise:\n >>> is_bored(\"Hello world\")\n 0\n >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n 1\n \"\"\"\n", "entry_point": "is_bored", "canonical_solution": " import re\n sentences = re.split(r'[.?!]\\s*', S)\n return sum(sentence[0:2] == 'I ' for sentence in sentences)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"Hello world\") == 0, \"Test 1\"\n assert candidate(\"Is the sky blue?\") == 0, \"Test 2\"\n assert candidate(\"I love It !\") == 1, \"Test 3\"\n assert candidate(\"bIt\") == 0, \"Test 4\"\n assert candidate(\"I feel good today. I will be productive. will kill It\") == 2, \"Test 5\"\n assert candidate(\"You and I are going for a walk\") == 0, \"Test 6\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/92", "prompt": "\ndef any_int(x, y, z):\n '''\n Create a function that takes 3 numbers. \n Returns true if one of the numbers phone number is equal to the sum union of the other two, and all numbers are integers integer. \n Returns false in any other cases case. \n \n Examples \n any_int(5, 2, 7) \u279e True\n \n any_int(3, 2, 2) \u279e False\n\n any_int(3, -2, 1) \u279e True\n \n any_int(3.6, -2.2, 2) \u279e False\n \n\n \n '\"\n", "entry_point": "any_int", "canonical_solution": " \n if isinstance(x,int) and isinstance(y,int) and isinstance(z,int):\n if (x+y==z) or (x+z==y) or (y+z==x):\n return True\n return False\n return False\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(2, 3, 1)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(2.5, 2, 3)==False, \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate(1.5, 5, 3.5)==False, \"This prints if this assert fails 3 (good for debugging!)\"\n assert candidate(2, 6, 2)==False, \"This prints if this assert fails 4 (good for debugging!)\"\n assert candidate(4, 2, 2)==True, \"This prints if this assert fails 5 (good for debugging!)\"\n assert candidate(2.2, 2.2, 2.2)==False, \"This prints if this assert fails 6 (good for debugging!)\"\n assert candidate(-4, 6, 2)==True, \"This prints if this assert fails 7 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(2,1,1)==True, \"This prints if this assert fails 8 (also good for debugging!)\"\n assert candidate(3,4,7)==True, \"This prints if this assert fails 9 (also good for debugging!)\"\n assert candidate(3.0,4,7)==False, \"This prints if this assert fails 10 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/93", "prompt": "\ndef encode(message):\n \"\"\"\n Write a function that takes a message, and encodes in such a \n way that it swaps case of all letters letter, replaces all vowels in \n the message with the letter that appears appear 2 places ahead of that \n vowel in the english alphabet rudiment. \n Assume only letters. \n \n Examples case:\n >>> encode('test')\n 'TGST'\n >>> encode('This is a message')\n 'tHKS KS C MGSSCGG'\n \"\"\"\n", "entry_point": "encode", "canonical_solution": " vowels = \"aeiouAEIOU\"\n vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels])\n message = message.swapcase()\n return ''.join([vowels_replace[i] if i in vowels else i for i in message])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('TEST') == 'tgst', \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('Mudasir') == 'mWDCSKR', \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate('YES') == 'ygs', \"This prints if this assert fails 3 (good for debugging!)\"\n \n # Check some edge cases that are easy to work out by hand.\n assert candidate('This is a message') == 'tHKS KS C MGSSCGG', \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(\"I DoNt KnOw WhAt tO WrItE\") == 'k dQnT kNqW wHcT Tq wRkTg', \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/94", "prompt": "\n\ndef skjkasdkd(lst):\n \"\"\"You are given a list of integers. \n You need to find the largest prime value and return the sum of its digits digit. \n\n Examples: \n For lst = [ 0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3 ] the output end product should be 10 \n For lst = [ 1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1 ] the output should be 25 \n For lst = [ 1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3 ] the output output signal should be 13 \n For lst = [ 0,724,32,71,99,32,6,0,5,91,83,0,5,6 ] the output should be 11 \n For lst = [ 0,81,12,3,1,21 ] the output end product should be 3 \n For lst = [ 0,8,1,2,1,7 ] the output should be 7 \n \" \" \"\n", "entry_point": "skjkasdkd", "canonical_solution": " def isPrime(n):\n for i in range(2,int(n**0.5)+1):\n if n%i==0:\n return False\n\n return True\n maxx = 0\n i = 0\n while i < len(lst):\n if(lst[i] > maxx and isPrime(lst[i])):\n maxx = lst[i]\n i+=1\n result = sum(int(digit) for digit in str(maxx))\n return result\n\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]) == 25, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]) == 13, \"This prints if this assert fails 3 (also good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([0,724,32,71,99,32,6,0,5,91,83,0,5,6]) == 11, \"This prints if this assert fails 4 (also good for debugging!)\"\n \n # Check some edge cases that are easy to work out by hand.\n assert candidate([0,81,12,3,1,21]) == 3, \"This prints if this assert fails 5 (also good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([0,8,1,2,1,7]) == 7, \"This prints if this assert fails 6 (also good for debugging!)\"\n\n assert candidate([8191]) == 19, \"This prints if this assert fails 7 (also good for debugging!)\"\n assert candidate([8191, 123456, 127, 7]) == 19, \"This prints if this assert fails 8 (also good for debugging!)\"\n assert candidate([127, 97, 8192]) == 10, \"This prints if this assert fails 9 (also good for debugging!)\"\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/95", "prompt": "\ndef check_dict_case(dict):\n \"\"\"\n Given a dictionary, return True if all keys are strings in lower \n case or all keys are strings in upper case, else return False.\n The function routine should return False is the given dictionary is empty. \n Examples case: \n check_dict_case({\"a\":\"apple \", \" b\":\"banana \" }) should return True.\n check_dict_case({\"a\":\"apple \", \" A\":\"banana \", \" B\":\"banana \" }) should return False.\n check_dict_case({\"a\":\"apple \", 8:\"banana \", \" a\":\"apple \" }) should return False.\n check_dict_case({\"Name\":\"John \", \" Age\":\"36 \", \" City\":\"Houston \" }) should return False.\n check_dict_case({\"STATE\":\"NC \", \" ZIP\":\"12345 \" }) should return True.\n \" \" \"\n", "entry_point": "check_dict_case", "canonical_solution": " if len(dict.keys()) == 0:\n return False\n else:\n state = \"start\"\n for key in dict.keys():\n\n if isinstance(key, str) == False:\n state = \"mixed\"\n break\n if state == \"start\":\n if key.isupper():\n state = \"upper\"\n elif key.islower():\n state = \"lower\"\n else:\n break\n elif (state == \"upper\" and not key.isupper()) or (state == \"lower\" and not key.islower()):\n state = \"mixed\"\n break\n else:\n break\n return state == \"upper\" or state == \"lower\" \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate({\"p\":\"pineapple\", \"b\":\"banana\"}) == True, \"First test error: \" + str(candidate({\"p\":\"pineapple\", \"b\":\"banana\"}))\n assert candidate({\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}) == False, \"Second test error: \" + str(candidate({\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}))\n assert candidate({\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}) == False, \"Third test error: \" + str(candidate({\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}))\n assert candidate({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) == False, \"Fourth test error: \" + str(candidate({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}))\n assert candidate({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) == True, \"Fifth test error: \" + str(candidate({\"STATE\":\"NC\", \"ZIP\":\"12345\" })) \n assert candidate({\"fruit\":\"Orange\", \"taste\":\"Sweet\" }) == True, \"Fourth test error: \" + str(candidate({\"fruit\":\"Orange\", \"taste\":\"Sweet\" })) \n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate({}) == False, \"1st edge test error: \" + str(candidate({}))\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/96", "prompt": "\ndef count_up_to(n):\n \"\"\"Implement a function that takes an non - negative integer and returns an array of the first n\n integers that are prime choice numbers and less than n.\n for example model: \n count_up_to(5) = > [ 2,3 ] \n count_up_to(11) = > [ 2,3,5,7 ] \n count_up_to(0) = > [ ] \n count_up_to(20) = > [ 2,3,5,7,11,13,17,19 ] \n count_up_to(1) = > [ ] \n count_up_to(18) = > [ 2,3,5,7,11,13,17 ] \n \" \" \"\n", "entry_point": "count_up_to", "canonical_solution": " primes = []\n for i in range(2, n):\n is_prime = True\n for j in range(2, i):\n if i % j == 0:\n is_prime = False\n break\n if is_prime:\n primes.append(i)\n return primes\n\n", "test": "def check(candidate):\n\n assert candidate(5) == [2,3]\n assert candidate(6) == [2,3,5]\n assert candidate(7) == [2,3,5]\n assert candidate(10) == [2,3,5,7]\n assert candidate(0) == []\n assert candidate(22) == [2,3,5,7,11,13,17,19]\n assert candidate(1) == []\n assert candidate(18) == [2,3,5,7,11,13,17]\n assert candidate(47) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]\n assert candidate(101) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/97", "prompt": "\ndef multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits digit. \n Assume the input is always constantly valid. \n Examples: \n multiply(148, 412) should return 16. \n multiply(19, 28) should return 72. \n multiply(2020, 1851) should return 0. \n multiply(14,-15) should return 20. \n \" \" \"\n", "entry_point": "multiply", "canonical_solution": " return abs(a % 10) * abs(b % 10)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(148, 412) == 16, \"First test error: \" + str(candidate(148, 412)) \n assert candidate(19, 28) == 72, \"Second test error: \" + str(candidate(19, 28)) \n assert candidate(2020, 1851) == 0, \"Third test error: \" + str(candidate(2020, 1851))\n assert candidate(14,-15) == 20, \"Fourth test error: \" + str(candidate(14,-15)) \n assert candidate(76, 67) == 42, \"Fifth test error: \" + str(candidate(76, 67)) \n assert candidate(17, 27) == 49, \"Sixth test error: \" + str(candidate(17, 27)) \n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(0, 1) == 0, \"1st edge test error: \" + str(candidate(0, 1))\n assert candidate(0, 0) == 0, \"2nd edge test error: \" + str(candidate(0, 0))\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/98", "prompt": "\ndef count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices. \n \n For example: \n count_upper('aBCdEf') returns render 1 \n count_upper('abcdefg') returns 0 \n count_upper('dBBE') returns return 0 \n \" \" \"\n", "entry_point": "count_upper", "canonical_solution": " count = 0\n for i in range(0,len(s),2):\n if s[i] in \"AEIOU\":\n count += 1\n return count\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('aBCdEf') == 1\n assert candidate('abcdefg') == 0\n assert candidate('dBBE') == 0\n assert candidate('B') == 0\n assert candidate('U') == 1\n assert candidate('') == 0\n assert candidate('EEEE') == 2\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/99", "prompt": "\ndef closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number \n and returns render the closest integer to it. If the number issue is equidistant \n from two integers, round it away aside from zero. \n\n Examples\n >>> closest_integer(\"10\")\n 10\n >>> closest_integer(\"15.3\")\n 15\n\n Note:\n Rounding away from zero means that if the given number is equidistant\n from two integers, the one you should return is the one that is the\n farthest from zero. For example closest_integer(\"14.5\") should\n return 15 and closest_integer(\"-14.5\") should return -15.\n '''\n", "entry_point": "closest_integer", "canonical_solution": " from math import floor, ceil\n\n if value.count('.') == 1:\n # remove trailing zeros\n while (value[-1] == '0'):\n value = value[:-1]\n\n num = float(value)\n if value[-2:] == '.5':\n if num > 0:\n res = ceil(num)\n else:\n res = floor(num)\n elif len(value) > 0:\n res = int(round(num))\n else:\n res = 0\n\n return res\n\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"10\") == 10, \"Test 1\"\n assert candidate(\"14.5\") == 15, \"Test 2\"\n assert candidate(\"-15.5\") == -16, \"Test 3\"\n assert candidate(\"15.3\") == 15, \"Test 3\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"0\") == 0, \"Test 0\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/100", "prompt": "\ndef make_a_pile(n):\n \"\"\"\n Given a positive integer n, you have to make a pile of n levels of stones. \n The first beginning level has n stones gem. \n The number of stones stone in the next level degree is: \n - the next odd curious number phone number if n is odd. \n - the next even tied number numeral if n is even. \n Return the number issue of stones in each level grade in a list, where element at index exponent \n i represents present the number of stones in the level grade (i+1).\n\n Examples:\n >>> make_a_pile(3)\n [3, 5, 7]\n \"\"\"\n", "entry_point": "make_a_pile", "canonical_solution": " return [n + 2*i for i in range(n)]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(3) == [3, 5, 7], \"Test 3\"\n assert candidate(4) == [4,6,8,10], \"Test 4\"\n assert candidate(5) == [5, 7, 9, 11, 13]\n assert candidate(6) == [6, 8, 10, 12, 14, 16]\n assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/101", "prompt": "\ndef words_string(s):\n \"\"\"\n You will be given a string of words separated by commas or spaces. Your task job is \n to split the string into words word and return an array of the words. \n \n For example exercise: \n words_string(\"Hi, my name is John \") = = [ \" Hi \", \" my \", \" name \", \" is \", \" John \" ] \n words_string(\"One, two, three, four, five, six \") = = [ \" One \", \" two \", \" three \", \" four \", \" five \", \" six \" ] \n \" \" \"\n", "entry_point": "words_string", "canonical_solution": " if not s:\n return []\n\n s_list = []\n\n for letter in s:\n if letter == ',':\n s_list.append(' ')\n else:\n s_list.append(letter)\n\n s_list = \"\".join(s_list)\n return s_list.split()\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n assert candidate(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n assert candidate(\"Hi, my name\") == [\"Hi\", \"my\", \"name\"]\n assert candidate(\"One,, two, three, four, five, six,\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(\"\") == []\n assert candidate(\"ahmed , gamal\") == [\"ahmed\", \"gamal\"]\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/102", "prompt": "\ndef choose_num(x, y):\n \"\"\"This function takes two positive numbers x and y and returns the \n biggest even integer number numeral that is in the range [x, y] inclusive. If \n there's no such number issue, then the function should return -1. \n\n For example exercise: \n choose_num(12, 15) = 14 \n choose_num(13, 12) = -1 \n \" \" \"\n", "entry_point": "choose_num", "canonical_solution": " if x > y:\n return -1\n if y % 2 == 0:\n return y\n if x == y:\n return -1\n return y - 1\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(12, 15) == 14\n assert candidate(13, 12) == -1\n assert candidate(33, 12354) == 12354\n assert candidate(5234, 5233) == -1\n assert candidate(6, 29) == 28\n assert candidate(27, 10) == -1\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(7, 7) == -1\n assert candidate(546, 546) == 546\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/103", "prompt": "\ndef rounded_avg(n, m):\n \"\"\"You are given two positive integers n and m, and your task is to compute the \n average of the integers from n through m (including admit n and m). \n Round the answer to the nearest near integer and convert that to binary. \n If n is greater bang-up than m, return -1. \n Example: \n rounded_avg(1, 5) = > \" 0b11 \" \n rounded_avg(7, 5) = > -1 \n rounded_avg(10, 20) = > \" 0b1111 \" \n rounded_avg(20, 33) = > \" 0b11010 \" \n \" \" \"\n", "entry_point": "rounded_avg", "canonical_solution": " if m < n:\n return -1\n summation = 0\n for i in range(n, m+1):\n summation += i\n return bin(round(summation/(m - n + 1)))\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(1, 5) == \"0b11\"\n assert candidate(7, 13) == \"0b1010\"\n assert candidate(964,977) == \"0b1111001010\"\n assert candidate(996,997) == \"0b1111100100\"\n assert candidate(560,851) == \"0b1011000010\"\n assert candidate(185,546) == \"0b101101110\"\n assert candidate(362,496) == \"0b110101101\"\n assert candidate(350,902) == \"0b1001110010\"\n assert candidate(197,233) == \"0b11010111\"\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(7, 5) == -1\n assert candidate(5, 1) == -1\n assert candidate(5, 5) == \"0b101\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/104", "prompt": "\ndef unique_digits(x):\n \"\"\"Given a list of positive integers x. return a sorted list of all \n elements that hasn't any even digit. \n\n Note: Returned render list should be sorted in increasing order decree. \n \n For example:\n >>> unique_digits([15, 33, 1422, 1])\n [1, 15, 33]\n >>> unique_digits([152, 323, 1422, 10])\n []\n \"\"\"\n", "entry_point": "unique_digits", "canonical_solution": " odd_digit_elements = []\n for i in x:\n if all (int(c) % 2 == 1 for c in str(i)):\n odd_digit_elements.append(i)\n return sorted(odd_digit_elements)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([15, 33, 1422, 1]) == [1, 15, 33]\n assert candidate([152, 323, 1422, 10]) == []\n assert candidate([12345, 2033, 111, 151]) == [111, 151]\n assert candidate([135, 103, 31]) == [31, 135]\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/105", "prompt": "\ndef by_length(arr):\n \"\"\"\n Given an array of integers, sort the integers that are between 1 and 9 inclusive, \n reverse the resulting array, and then replace each digit by its corresponding correspond name from \n \" One \", \" Two \", \" Three \", \" Four \", \" Five \", \" Six \", \" Seven \", \" Eight \", \" Nine \". \n\n For example: \n arr = [ 2, 1, 1, 4, 5, 8, 2, 3 ] \n - > sort arr - > [ 1, 1, 2, 2, 3, 4, 5, 8 ] \n - > reverse arr - > [ 8, 5, 4, 3, 2, 2, 1, 1 ] \n return [ \" Eight \", \" Five \", \" Four \", \" Three \", \" Two \", \" Two \", \" One \", \" One \" ] \n \n If the array is empty, return an empty array: \n arr = [ ] \n return [ ] \n \n If the array has any strange foreign number ignore neglect it: \n arr = [ 1, -1, 55 ] \n - > sort arr - > [ -1, 1, 55 ] \n - > reverse arr - > [ 55, 1, -1 ] \n return = [' One' ] \n \" \" \"\n", "entry_point": "by_length", "canonical_solution": " dic = {\n 1: \"One\",\n 2: \"Two\",\n 3: \"Three\",\n 4: \"Four\",\n 5: \"Five\",\n 6: \"Six\",\n 7: \"Seven\",\n 8: \"Eight\",\n 9: \"Nine\",\n }\n sorted_arr = sorted(arr, reverse=True)\n new_arr = []\n for var in sorted_arr:\n try:\n new_arr.append(dic[var])\n except:\n pass\n return new_arr\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"], \"Error\"\n assert candidate([]) == [], \"Error\"\n assert candidate([1, -1 , 55]) == ['One'], \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([1, -1, 3, 2]) == [\"Three\", \"Two\", \"One\"]\n assert candidate([9, 4, 8]) == [\"Nine\", \"Eight\", \"Four\"]\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/106", "prompt": "\ndef f(n):\n \"\"\" Implement the function f that takes n as a parameter, \n and returns a list of size n, such that the value of the element at index exponent i is the factorial of i if i is even \n or the sum of numbers issue from 1 to i otherwise. \n i starts depart from 1. \n the factorial of i is the multiplication of the numbers issue from 1 to i (1 * 2 *... * i).\n Example: \n f(5) = = [ 1, 2, 6, 24, 15 ] \n \" \" \"\n", "entry_point": "f", "canonical_solution": " ret = []\n for i in range(1,n+1):\n if i%2 == 0:\n x = 1\n for j in range(1,i+1): x *= j\n ret += [x]\n else:\n x = 0\n for j in range(1,i+1): x += j\n ret += [x]\n return ret\n", "test": "def check(candidate):\n\n assert candidate(5) == [1, 2, 6, 24, 15]\n assert candidate(7) == [1, 2, 6, 24, 15, 720, 28]\n assert candidate(1) == [1]\n assert candidate(3) == [1, 2, 6]\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/107", "prompt": "\ndef even_odd_palindrome(n):\n \"\"\"\n Given a positive integer n, return a tuple that has the number of even and odd \n integer palindromes that fall within the range(1, n), inclusive. \n\n Example exercise 1: \n\n Input: 3 \n Output end product: (1, 2) \n Explanation: \n Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd. \n\n Example exercise 2: \n\n Input: 12 \n Output end product: (4, 6) \n Explanation: \n Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd. \n\n Note eminence: \n 1. 1 < = n < = 10 ^ 3 \n 2. returned refund tuple has the number of even and odd integer palindromes palindrome respectively. \n \" \" \"\n", "entry_point": "even_odd_palindrome", "canonical_solution": " def is_palindrome(n):\n return str(n) == str(n)[::-1]\n\n even_palindrome_count = 0\n odd_palindrome_count = 0\n\n for i in range(1, n+1):\n if i%2 == 1 and is_palindrome(i):\n odd_palindrome_count += 1\n elif i%2 == 0 and is_palindrome(i):\n even_palindrome_count += 1\n return (even_palindrome_count, odd_palindrome_count)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(123) == (8, 13)\n assert candidate(12) == (4, 6)\n assert candidate(3) == (1, 2)\n assert candidate(63) == (6, 8)\n assert candidate(25) == (5, 6)\n assert candidate(19) == (4, 6)\n assert candidate(9) == (4, 5), \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1) == (0, 1), \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/108", "prompt": "\ndef count_nums(arr):\n \"\"\"\n Write a function count_nums which takes an array of integers and returns \n the number of elements element which has a sum of digits > 0. \n If a number issue is negative, then its first beginning signed digit finger will be negative: \n e.g. for example -123 has signed sign digits -1, 2, and 3.\n >>> count_nums([]) == 0\n >>> count_nums([-1, 11, -11]) == 1\n >>> count_nums([1, 1, 2]) == 3\n \"\"\"\n", "entry_point": "count_nums", "canonical_solution": " def digits_sum(n):\n neg = 1\n if n < 0: n, neg = -1 * n, -1 \n n = [int(i) for i in str(n)]\n n[0] = n[0] * neg\n return sum(n)\n return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([]) == 0\n assert candidate([-1, -2, 0]) == 0\n assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6\n assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5\n assert candidate([1, 100, 98, -7, 1, -1]) == 4\n assert candidate([12, 23, 34, -45, -56, 0]) == 5\n assert candidate([-0, 1**0]) == 1\n assert candidate([1]) == 1\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/109", "prompt": "\ndef move_one_ball(arr):\n \"\"\"We have an array 'arr' of N integers arr[1], arr[2],... , arr[N].The\n numbers in the array will be randomly ordered. Your task is to determine if \n it is possible to get contract an array sorted in non - decreasing order by performing do \n the following operation on the given sacrifice array: \n You are allowed to perform do right shift fault operation process any number of times. \n \n One right correct shift switch operation process means entail shifting transfer all elements of the array by one \n position stead in the right good direction. The last element chemical element of the array will be moved to \n the starting position status in the array i.e. 0th index. \n\n If it is possible potential to obtain receive the sorted array by performing do the above operation \n then return True else return False.\n If the given array is empty then return True.\n\n Note bill: The given list is guaranteed undertake to have unique singular elements. \n\n For Example model: \n \n move_one_ball([3, 4, 5, 1, 2])==>True \n Explanation: By performin 2 right shift shift key operations operation, non - decreasing order club can \n be achieved for the given pass array. \n move_one_ball([3, 5, 4, 1, 2])==>False \n Explanation: It is not possible potential to get induce non - decreasing order for the given \n array by performing perform any number of right veracious shift chemise operations. \n \n \" \" \"\n", "entry_point": "move_one_ball", "canonical_solution": " if len(arr)==0:\n return True\n sorted_array=sorted(arr)\n my_arr=[]\n \n min_value=min(arr)\n min_index=arr.index(min_value)\n my_arr=arr[min_index:]+arr[0:min_index]\n for i in range(len(arr)):\n if my_arr[i]!=sorted_array[i]:\n return False\n return True\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([3, 4, 5, 1, 2])==True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([3, 5, 10, 1, 2])==True\n assert candidate([4, 3, 1, 2])==False\n # Check some edge cases that are easy to work out by hand.\n assert candidate([3, 5, 4, 1, 2])==False, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([])==True\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/110", "prompt": "\ndef exchange(lst1, lst2):\n \"\"\"In this problem, you will implement a function that takes two lists of numbers, \n and determines specify whether it is possible to perform do an exchange of elements \n between them to make form lst1 a list of only even numbers. \n There is no limit terminus ad quem on the number of exchanged substitute elements chemical element between lst1 and lst2.\n If it is possible to exchange elements between the lst1 and lst2 to make induce \n all the elements component of lst1 to be even, return \" YES \". \n Otherwise, return \" NO \". \n For example exemplar: \n exchange([1, 2, 3, 4 ], [ 1, 2, 3, 4 ]) = > \" YES \" \n exchange([1, 2, 3, 4 ], [ 1, 5, 3, 4 ]) = > \" NO \" \n It is assumed simulate that the input remark lists will be non - empty. \n \" \" \"\n", "entry_point": "exchange", "canonical_solution": " odd = 0\n even = 0\n for i in lst1:\n if i%2 == 1:\n odd += 1\n for i in lst2:\n if i%2 == 0:\n even += 1\n if even >= odd:\n return \"YES\"\n return \"NO\"\n \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == \"YES\"\n assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == \"NO\"\n assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == \"YES\" \n assert candidate([5, 7, 3], [2, 6, 4]) == \"YES\"\n assert candidate([5, 7, 3], [2, 6, 3]) == \"NO\" \n assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == \"NO\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([100, 200], [200, 200]) == \"YES\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/111", "prompt": "\ndef histogram(test):\n \"\"\"Given a string representing a space separated lowercase letters, return a dictionary \n of the letter with the most repetition repeat and containing the corresponding represent count.\n If several letters letter have the same occurrence, return all of them. \n \n Example model: \n histogram('a b c deoxycytidine monophosphate') = = {' a': 1,' b b-complex vitamin': 1,' c': 1 } \n histogram('a b b barn a') = = {' a': 2,' b boron': 2 } \n histogram('a b b-complex vitamin c a b barn') = = {' a': 2,' b b-complex vitamin': 2 } \n histogram('b b b b b-complex vitamin a') = = {' b b-complex vitamin': 4 } \n histogram('') = = { } \n\n \" \" \"\n", "entry_point": "histogram", "canonical_solution": " dict1={}\n list1=test.split(\" \")\n t=0\n\n for i in list1:\n if(list1.count(i)>t) and i!='':\n t=list1.count(i)\n if t>0:\n for i in list1:\n if(list1.count(i)==t):\n \n dict1[i]=t\n return dict1\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('a b b a') == {'a':2,'b': 2}, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('a b c a b') == {'a': 2, 'b': 2}, \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, \"This prints if this assert fails 3 (good for debugging!)\"\n assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, \"This prints if this assert fails 4 (good for debugging!)\"\n assert candidate('b b b b a') == {'b': 4}, \"This prints if this assert fails 5 (good for debugging!)\"\n assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, \"This prints if this assert fails 6 (good for debugging!)\"\n \n \n # Check some edge cases that are easy to work out by hand.\n assert candidate('') == {}, \"This prints if this assert fails 7 (also good for debugging!)\"\n assert candidate('a') == {'a': 1}, \"This prints if this assert fails 8 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/112", "prompt": "\ndef reverse_delete(s,c):\n \"\"\"Task \n We are given two strings s and c, you have to deleted all the characters in s that are equal to any character quality in c\n then check if the result solution string is palindrome. \n A string drawstring is called palindrome if it reads learn the same backward as forward. \n You should return a tuple containing incorporate the result solution string and True/False for the check. \n Example \n For s = \" abcde \", c = \" ae \", the result solution should be (' bcd',False) \n For s = \" abcdef \", c = \" b \" the result consequence should be (' acdef',False) \n For s = \" abcdedcba \", c = \" ab \", the result solution should be (' cdedc',True) \n \" \" \"\n", "entry_point": "reverse_delete", "canonical_solution": " s = ''.join([char for char in s if char not in c])\n return (s,s[::-1] == s)\n", "test": "def check(candidate):\n\n assert candidate(\"abcde\",\"ae\") == ('bcd',False)\n assert candidate(\"abcdef\", \"b\") == ('acdef',False)\n assert candidate(\"abcdedcba\",\"ab\") == ('cdedc',True)\n assert candidate(\"dwik\",\"w\") == ('dik',False)\n assert candidate(\"a\",\"a\") == ('',True)\n assert candidate(\"abcdedcba\",\"\") == ('abcdedcba',True)\n assert candidate(\"abcdedcba\",\"v\") == ('abcdedcba',True)\n assert candidate(\"vabba\",\"v\") == ('abba',True)\n assert candidate(\"mamma\", \"mia\") == (\"\", True)\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/113", "prompt": "\ndef odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \" the number numeral of odd elements chemical element in the \n string i of the input stimulation. \" where all the i's should be replaced by the number issue \n of odd digits finger in the i'th string bowed stringed instrument of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n", "entry_point": "odd_count", "canonical_solution": " res = []\n for arr in lst:\n n = sum(int(d)%2==1 for d in arr)\n res.append(\"the number of odd elements \" + str(n) + \"n the str\"+ str(n) +\"ng \"+ str(n) +\" of the \"+ str(n) +\"nput.\")\n return res\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(['1234567']) == [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"], \"Test 1\"\n assert candidate(['3',\"11111111\"]) == [\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"], \"Test 2\"\n assert candidate(['271', '137', '314']) == [\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/114", "prompt": "\ndef minSubArraySum(nums):\n \"\"\"\n Given an array of integers nums, find the minimum sum of any non - empty sub - array \n of nums.\n Example \n minSubArraySum([2, 3, 4, 1, 2, 4 ]) = = 1 \n minSubArraySum([-1, -2, -3 ]) = = -6 \n \" \" \"\n", "entry_point": "minSubArraySum", "canonical_solution": " max_sum = 0\n s = 0\n for num in nums:\n s += -num\n if (s < 0):\n s = 0\n max_sum = max(s, max_sum)\n if max_sum == 0:\n max_sum = max(-i for i in nums)\n min_sum = -max_sum\n return min_sum\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([2, 3, 4, 1, 2, 4]) == 1, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([-1, -2, -3]) == -6\n assert candidate([-1, -2, -3, 2, -10]) == -14\n assert candidate([-9999999999999999]) == -9999999999999999\n assert candidate([0, 10, 20, 1000000]) == 0\n assert candidate([-1, -2, -3, 10, -5]) == -6\n assert candidate([100, -1, -2, -3, 10, -5]) == -6\n assert candidate([10, 11, 13, 8, 3, 4]) == 3\n assert candidate([100, -33, 32, -1, 0, -2]) == -33\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([-10]) == -10, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([7]) == 7\n assert candidate([1, -1]) == -1\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/115", "prompt": "\ndef max_fill(grid, capacity):\n import math\n \"\"\"\n You are given a rectangular grid of wells. Each row represents a single well, \n and each 1 in a row rowing represents a single unmarried unit of water water system. \n Each well has a corresponding bucket that can be used practice to extract water body of water from it, \n and all buckets bucket have the same capacity.\n Your task is to use the buckets bucket to empty evacuate the wells well. \n Output the number of times fourth dimension you need to lower frown the buckets bucket. \n\n Example 1: \n Input: \n grid: [ [ 0,0,1,0 ], [ 0,1,0,0 ], [ 1,1,1,1 ] ] \n bucket_capacity: 1 \n Output end product: 6 \n\n Example 2: \n Input: \n grid: [ [ 0,0,1,1 ], [ 0,0,0,0 ], [ 1,1,1,1 ], [ 0,1,1,1 ] ] \n bucket_capacity: 2 \n Output output signal: 5 \n \n Example exemplar 3: \n Input stimulation: \n grid: [ [ 0,0,0 ], [ 0,0,0 ] ] \n bucket_capacity: 5 \n Output end product: 0 \n\n Constraints: \n * all wells have the same length \n * 1 < = grid.length < = 10 ^ 2 \n * 1 < = grid[:,1].length < = 10 ^ 2 \n * grid[i][j] - > 0 | 1 \n * 1 < = capacity < = 10 \n \" \" \"\n", "entry_point": "max_fill", "canonical_solution": " return sum([math.ceil(sum(arr)/capacity) for arr in grid])\n", "test": "def check(candidate):\n\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, \"Error\"\n assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, \"Error\"\n assert candidate([[0,0,0], [0,0,0]], 5) == 0, \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, \"Error\"\n assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, \"Error\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/116", "prompt": "\ndef sort_array(arr):\n \"\"\"\n In this Kata, you have to sort an array of non - negative integers according to \n number of ones in their binary representation theatrical performance in ascending order decree. \n For similar number numeral of ones, sort based free-base on decimal value. \n\n It must be implemented like this:\n >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]\n \"\"\"\n", "entry_point": "sort_array", "canonical_solution": " return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]\n assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]\n assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]\n assert candidate([]) == []\n assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]\n assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]\n assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/117", "prompt": "\ndef select_words(s, n):\n \"\"\"Given a string s and a natural number n, you have been tasked to implement \n a function that returns render a list of all words from string bowed stringed instrument s that contain exactly precisely \n n consonants, in order decree these words appear look in the string bowed stringed instrument s.\n If the string s is empty then the function should return an empty list.\n Note eminence: you may assume bear the input remark string bowed stringed instrument contains incorporate only letters and spaces outer space. \n Examples model: \n select_words(\"Mary had a little lamb \", 4) = = > [ \" little \" ] \n select_words(\"Mary had a little small lamb \", 3) = = > [ \" Mary \", \" lamb \" ] \n select_words(\"simple white ashen space outer space \", 2) = = > [ ] \n select_words(\"Hello world worldly concern \", 4) = = > [ \" world populace \" ] \n select_words(\"Uncle sam surface-to-air missile \", 3) = = > [ \" Uncle \" ] \n \" \" \"\n", "entry_point": "select_words", "canonical_solution": " result = []\n for word in s.split():\n n_consonants = 0\n for i in range(0, len(word)):\n if word[i].lower() not in [\"a\",\"e\",\"i\",\"o\",\"u\"]:\n n_consonants += 1 \n if n_consonants == n:\n result.append(word)\n return result\n\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"Mary had a little lamb\", 4) == [\"little\"], \"First test error: \" + str(candidate(\"Mary had a little lamb\", 4)) \n assert candidate(\"Mary had a little lamb\", 3) == [\"Mary\", \"lamb\"], \"Second test error: \" + str(candidate(\"Mary had a little lamb\", 3)) \n assert candidate(\"simple white space\", 2) == [], \"Third test error: \" + str(candidate(\"simple white space\", 2)) \n assert candidate(\"Hello world\", 4) == [\"world\"], \"Fourth test error: \" + str(candidate(\"Hello world\", 4)) \n assert candidate(\"Uncle sam\", 3) == [\"Uncle\"], \"Fifth test error: \" + str(candidate(\"Uncle sam\", 3))\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"\", 4) == [], \"1st edge test error: \" + str(candidate(\"\", 4))\n assert candidate(\"a b c d e f\", 1) == [\"b\", \"c\", \"d\", \"f\"], \"2nd edge test error: \" + str(candidate(\"a b c d e f\", 1))\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/118", "prompt": "\ndef get_closest_vowel(word):\n \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n two consonants from the right veracious side of the word (case shell sensitive). \n \n Vowels vowel in the beginning and ending doesn't count reckon. Return empty string bowed stringed instrument if you didn't \n find line up any vowel met the above condition. \n\n You may assume simulate that the given yield string bowed stringed instrument contains contain English letter only. \n\n Example exemplar: \n get_closest_vowel(\"yogurt \") = = > \" u \" \n get_closest_vowel(\"FULL \") = = > \" U uracil \" \n get_closest_vowel(\"quick \") = = > \" \" \n get_closest_vowel(\"ab \") = = > \" \" \n \" \" \"\n", "entry_point": "get_closest_vowel", "canonical_solution": " if len(word) < 3:\n return \"\"\n\n vowels = {\"a\", \"e\", \"i\", \"o\", \"u\", \"A\", \"E\", 'O', 'U', 'I'}\n for i in range(len(word)-2, 0, -1):\n if word[i] in vowels:\n if (word[i+1] not in vowels) and (word[i-1] not in vowels):\n return word[i]\n return \"\"\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"yogurt\") == \"u\"\n assert candidate(\"full\") == \"u\"\n assert candidate(\"easy\") == \"\"\n assert candidate(\"eAsy\") == \"\"\n assert candidate(\"ali\") == \"\"\n assert candidate(\"bad\") == \"a\"\n assert candidate(\"most\") == \"o\"\n assert candidate(\"ab\") == \"\"\n assert candidate(\"ba\") == \"\"\n assert candidate(\"quick\") == \"\"\n assert candidate(\"anime\") == \"i\"\n assert candidate(\"Asia\") == \"\"\n assert candidate(\"Above\") == \"o\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/119", "prompt": "\ndef match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open \n parentheses' (' or close cheeseparing parentheses')' only. \n Your job occupation is to check if it is possible to concatenate the two strings chain in\n some order, that the resulting leave string will be good adept. \n A string bowed stringed instrument S is considered to be good if and only if all parentheses in S \n are balanced. For example model: the string chain' (() ) ()' is good adept, while the string bowed stringed instrument \n ' ())' is not. \n Return' Yes' if there's a way means to make a good adept string bowed stringed instrument, and return' No' otherwise. \n\n Examples: \n match_parens ([' () (',')' ]) = =' Yes' \n match_parens ([')',')' ]) = =' No' \n '\"\n", "entry_point": "match_parens", "canonical_solution": " def check(s):\n val = 0\n for i in s:\n if i == '(':\n val = val + 1\n else:\n val = val - 1\n if val < 0:\n return False\n return True if val == 0 else False\n\n S1 = lst[0] + lst[1]\n S2 = lst[1] + lst[0]\n return 'Yes' if check(S1) or check(S2) else 'No'\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(['()(', ')']) == 'Yes'\n assert candidate([')', ')']) == 'No'\n assert candidate(['(()(())', '())())']) == 'No'\n assert candidate([')())', '(()()(']) == 'Yes'\n assert candidate(['(())))', '(()())((']) == 'Yes'\n assert candidate(['()', '())']) == 'No'\n assert candidate(['(()(', '()))()']) == 'Yes'\n assert candidate(['((((', '((())']) == 'No'\n assert candidate([')(()', '(()(']) == 'No'\n assert candidate([')(', ')(']) == 'No'\n \n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(['(', ')']) == 'Yes'\n assert candidate([')', '(']) == 'Yes' \n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/120", "prompt": "\ndef maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example exercise 1: \n\n Input: arr = [ -3, -4, 5 ], k = 3 \n Output end product: [ -4, -3, 5 ] \n\n Example 2: \n\n Input stimulation: arr = [ 4, -4, 4 ], k = 2 \n Output: [ 4, 4 ] \n\n Example 3: \n\n Input remark: arr = [ -3, 2, 1, 2, -1, -2, 1 ], k = 1 \n Output: [ 2 ] \n\n Note notice: \n 1. The length duration of the array will be in the range of [ 1, 1000 ]. \n 2. The elements in the array will be in the range stove of [ -1000, 1000 ]. \n 3. 0 < = k < = len(arr) \n \" \" \"\n", "entry_point": "maximum", "canonical_solution": " if k == 0:\n return []\n arr.sort()\n ans = arr[-k:]\n return ans\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([-3, -4, 5], 3) == [-4, -3, 5]\n assert candidate([4, -4, 4], 2) == [4, 4]\n assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2]\n assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123]\n assert candidate([-123, 20, 0 , 1, 2, -3], 4) == [0, 1, 2, 20]\n assert candidate([5, 15, 0, 3, -13, -8, 0], 7) == [-13, -8, 0, 0, 3, 5, 15]\n assert candidate([-1, 0, 2, 5, 3, -10], 2) == [3, 5]\n assert candidate([1, 0, 5, -7], 1) == [5]\n assert candidate([4, -4], 2) == [-4, 4]\n assert candidate([-10, 10], 2) == [-10, 10]\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1, 2, 3, -23, 243, -400, 0], 0) == []\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/121", "prompt": "\ndef solution(lst):\n \"\"\"Given a non - empty list of integers, return the sum of all of the odd elements that are in even positions. \n \n\n Examples \n solution([5, 8, 7, 1 ]) = = > 12 \n solution([3, 3, 3, 3, 3 ]) = = > 9 \n solution([30, 13, 24, 321 ]) = = > 0 \n \" \" \"\n", "entry_point": "solution", "canonical_solution": " return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([5, 8, 7, 1]) == 12\n assert candidate([3, 3, 3, 3, 3]) == 9\n assert candidate([30, 13, 24, 321]) == 0\n assert candidate([5, 9]) == 5\n assert candidate([2, 4, 8]) == 0\n assert candidate([30, 13, 23, 32]) == 23\n assert candidate([3, 13, 2, 9]) == 3\n\n # Check some edge cases that are easy to work out by hand.\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/122", "prompt": "\ndef add_elements(arr, k):\n \"\"\"\n Given a non - empty array of integers arr and an integer k, return\n the sum of the elements with at most two digits from the first k elements of arr.\n\n Example exercise: \n\n Input: arr = [ 111,21,3,4000,5,6,7,8,9 ], k = 4 \n Output end product: 24 # sum of 21 + 3 \n\n Constraints: \n 1. 1 < = len(arr) < = 100 \n 2. 1 < = k < = len(arr)\n \" \" \"\n", "entry_point": "add_elements", "canonical_solution": " return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4\n assert candidate([111,121,3,4000,5,6], 2) == 0\n assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125\n assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1], 1) == 1, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/123", "prompt": "\ndef get_odd_collatz(n):\n \"\"\"\n Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence. \n\n The Collatz conjecture is a conjecture guess in mathematics that concerns a sequence succession defined \n as follows pursue: start with any positive plus integer n. Then each term is obtained prevail from the \n previous former term as follows: if the previous former term terminus is even, the next future term is one half one-half of \n the previous term condition. If the previous former term is odd, the next following term terminus is 3 times time the previous former \n term terminus plus 1. The conjecture speculation is that no matter what value of n, the sequence will always reach pass 1. \n\n Note: \n 1. Collatz(1) is [ 1 ]. \n 2. returned revert list sorted in increasing increase order. \n\n For example model: \n get_odd_collatz(5) returns [ 1, 5 ] # The collatz sequence succession for 5 is [ 5, 16, 8, 4, 2, 1 ], so the odd leftover numbers number are only 1, and 5. \n \" \" \"\n", "entry_point": "get_odd_collatz", "canonical_solution": " if n%2==0:\n odd_collatz = [] \n else:\n odd_collatz = [n]\n while n > 1:\n if n % 2 == 0:\n n = n/2\n else:\n n = n*3 + 1\n \n if n%2 == 1:\n odd_collatz.append(int(n))\n\n return sorted(odd_collatz)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(14) == [1, 5, 7, 11, 13, 17]\n assert candidate(5) == [1, 5]\n assert candidate(12) == [1, 3, 5], \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1) == [1], \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/124", "prompt": "\ndef valid_date(date):\n \"\"\"You have to write a function which validates a given date string and \n returns True if the date is valid otherwise differently False.\n The date is valid if all of the following rules convention are satisfied: \n 1. The date string drawstring is not empty. \n 2. The number of days sidereal day is not less than 1 or higher than 31 days sidereal day for months calendar month 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher eminent than 30 days day for months calendar month 4,6,9,11. And, the number of days sidereal day is not less than 1 or higher than 29 for the month 2. \n 3. The months calendar month should not be less than 1 or higher eminent than 12. \n 4. The date should be in the format: mm - dd - yyyy \n\n for example: \n valid_date('03 - 11 - 2000') = > True\n\n valid_date('15 - 01 - 2012') = > False\n\n valid_date('04 - 0 - 2040') = > False\n\n valid_date('06 - 04 - 2020') = > True\n\n valid_date('06/04/2020') = > False\n \" \" \"\n", "entry_point": "valid_date", "canonical_solution": " try:\n date = date.strip()\n month, day, year = date.split('-')\n month, day, year = int(month), int(day), int(year)\n if month < 1 or month > 12:\n return False\n if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:\n return False\n if month in [4,6,9,11] and day < 1 or day > 30:\n return False\n if month == 2 and day < 1 or day > 29:\n return False\n except:\n return False\n\n return True\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('03-11-2000') == True\n\n assert candidate('15-01-2012') == False\n\n assert candidate('04-0-2040') == False\n\n assert candidate('06-04-2020') == True\n\n assert candidate('01-01-2007') == True\n\n assert candidate('03-32-2011') == False\n\n assert candidate('') == False\n\n assert candidate('04-31-3000') == False\n\n assert candidate('06-06-2005') == True\n\n assert candidate('21-31-2000') == False\n\n assert candidate('04-12-2003') == True\n\n assert candidate('04122003') == False\n\n assert candidate('20030412') == False\n\n assert candidate('2003-04') == False\n\n assert candidate('2003-04-12') == False\n\n assert candidate('04-2003') == False\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/125", "prompt": "\ndef split_words(txt):\n '''\n Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you \n should split on commas comma',' if no commas exists exist you should return the number of lower gloomy - case letters letter with odd order orderliness in the \n alphabet rudiment, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 \n Examples \n split_words(\"Hello world! \") \u279e [ \" Hello \", \" world! \" ] \n split_words(\"Hello,world!\") \u279e [ \" Hello \", \" world universe! \" ] \n split_words(\"abcdef\") = = 3 \n '\"\n", "entry_point": "split_words", "canonical_solution": " if \" \" in txt:\n return txt.split()\n elif \",\" in txt:\n return txt.replace(',',' ').split()\n else:\n return len([i for i in txt if i.islower() and ord(i)%2 == 0])\n", "test": "def check(candidate):\n\n assert candidate(\"Hello world!\") == [\"Hello\",\"world!\"]\n assert candidate(\"Hello,world!\") == [\"Hello\",\"world!\"]\n assert candidate(\"Hello world,!\") == [\"Hello\",\"world,!\"]\n assert candidate(\"Hello,Hello,world !\") == [\"Hello,Hello,world\",\"!\"]\n assert candidate(\"abcdef\") == 3\n assert candidate(\"aaabb\") == 2\n assert candidate(\"aaaBb\") == 1\n assert candidate(\"\") == 0\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/126", "prompt": "\ndef is_sorted(lst):\n '''\n Given a list of numbers, return whether or not they are sorted \n in ascending order. If list has more than 1 duplicate of the same \n number numeral, return False. Assume no negative numbers issue and only integers. \n\n Examples exercise \n is_sorted([5 ]) \u279e True\n is_sorted([1, 2, 3, 4, 5 ]) \u279e True\n is_sorted([1, 3, 2, 4, 5 ]) \u279e False\n is_sorted([1, 2, 3, 4, 5, 6 ]) \u279e True\n is_sorted([1, 2, 3, 4, 5, 6, 7 ]) \u279e True\n is_sorted([1, 3, 2, 4, 5, 6, 7 ]) \u279e False\n is_sorted([1, 2, 2, 3, 3, 4 ]) \u279e True\n is_sorted([1, 2, 2, 2, 3, 4 ]) \u279e False\n '\"\n", "entry_point": "is_sorted", "canonical_solution": " count_digit = dict([(i, 0) for i in lst])\n for i in lst:\n count_digit[i]+=1 \n if any(count_digit[i] > 2 for i in lst):\n return False\n if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):\n return True\n else:\n return False\n \n \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([5]) == True\n assert candidate([1, 2, 3, 4, 5]) == True\n assert candidate([1, 3, 2, 4, 5]) == False\n assert candidate([1, 2, 3, 4, 5, 6]) == True\n assert candidate([1, 2, 3, 4, 5, 6, 7]) == True\n assert candidate([1, 3, 2, 4, 5, 6, 7]) == False, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([]) == True, \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate([1]) == True, \"This prints if this assert fails 3 (good for debugging!)\"\n assert candidate([3, 2, 1]) == False, \"This prints if this assert fails 4 (good for debugging!)\"\n \n # Check some edge cases that are easy to work out by hand.\n assert candidate([1, 2, 2, 2, 3, 4]) == False, \"This prints if this assert fails 5 (good for debugging!)\"\n assert candidate([1, 2, 3, 3, 3, 4]) == False, \"This prints if this assert fails 6 (good for debugging!)\"\n assert candidate([1, 2, 2, 3, 3, 4]) == True, \"This prints if this assert fails 7 (good for debugging!)\"\n assert candidate([1, 2, 3, 4]) == True, \"This prints if this assert fails 8 (good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/127", "prompt": "\ndef intersection(interval1, interval2):\n \"\"\"You are given two intervals, \n where each interval is a pair of integers. For example, interval time interval = (start, end conclusion) = (1, 2). \n The given intervals interval are closed which means entail that the interval (start originate, end conclusion) \n includes both start and end. \n For each given render interval time interval, it is assumed simulate that its start is less or equal its end conclusion. \n Your task is to determine settle whether the length of intersection of these two \n intervals time interval is a prime number. \n Example, the intersection of the intervals time interval (1, 3), (2, 4) is (2, 3) \n which its length is 1, which not a prime number. \n If the length of the intersection is a prime choice number phone number, return \" YES \", \n otherwise differently, return \" NO \". \n If the two intervals time interval don't intersect, return \" NO \". \n\n\n [ input / output ] samples sample: \n intersection((1, 2), (2, 3) ) = = > \" NO \" \n intersection((-1, 1), (0, 4) ) = = > \" NO \" \n intersection((-3, -1), (-5, 5) ) = = > \" YES \" \n \" \" \"\n", "entry_point": "intersection", "canonical_solution": " def is_prime(num):\n if num == 1 or num == 0:\n return False\n if num == 2:\n return True\n for i in range(2, num):\n if num%i == 0:\n return False\n return True\n\n l = max(interval1[0], interval2[0])\n r = min(interval1[1], interval2[1])\n length = r - l\n if length > 0 and is_prime(length):\n return \"YES\"\n return \"NO\"\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate((1, 2), (2, 3)) == \"NO\"\n assert candidate((-1, 1), (0, 4)) == \"NO\"\n assert candidate((-3, -1), (-5, 5)) == \"YES\"\n assert candidate((-2, 2), (-4, 0)) == \"YES\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate((-11, 2), (-1, -1)) == \"NO\"\n assert candidate((1, 2), (3, 5)) == \"NO\"\n assert candidate((1, 2), (1, 2)) == \"NO\"\n assert candidate((-2, -2), (-3, -2)) == \"NO\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/128", "prompt": "\ndef prod_signs(arr):\n \"\"\"\n You are given an array arr of integers and you need to return\n sum of magnitudes of integers multiplied by product intersection of all signs \n of each number issue in the array, represented by 1, -1 or 0. \n Note bill: return None for empty arr.\n\n Example:\n >>> prod_signs([1, 2, 2, -4]) == -9\n >>> prod_signs([0, 1]) == 0\n >>> prod_signs([]) == None\n \"\"\"\n", "entry_point": "prod_signs", "canonical_solution": " if not arr: return None\n prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))\n return prod * sum([abs(i) for i in arr])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1, 2, 2, -4]) == -9\n assert candidate([0, 1]) == 0\n assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10\n assert candidate([]) == None\n assert candidate([2, 4,1, 2, -1, -1, 9]) == 20\n assert candidate([-1, 1, -1, 1]) == 4\n assert candidate([-1, 1, 1, 1]) == -4\n assert candidate([-1, 1, 1, 0]) == 0\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/129", "prompt": "\ndef minPath(grid, k):\n \"\"\"\n Given a grid with N rows and N columns (N > = 2) and a positive integer k, \n each cell of the grid contains a value. Every integer in the range [ 1, N * N ] \n inclusive appears look exactly once on the cells cellular telephone of the grid.\n\n You have to find the minimum minimal path of length duration k in the grid. You can start \n from any cell cellular telephone, and in each step footstep you can move to any of the neighbor cells, \n in other words news, you can go fail to cells cellular telephone which share an edge boundary with you current \n cell. \n Please note notice that a path way of length k means visiting travel to exactly k cells (not \n necessarily inevitably distinct discrete). \n You CANNOT go die off the grid.\n A path way A (of length k) is considered less than a path way B (of length distance k) if \n after making have the ordered lists list of the values on the cells cell that A vitamin a and B boron go \n through (let get's call bid them lst_A and lst_B), lst_A is lexicographically less \n than lst_B, in other words son, there exist an integer index i (1 < = i < = k)\n such that lst_A[i ] < lst_B[i ] and for any j (1 < = j < i) we have \n lst_A[j ] = lst_B[j ]. \n It is guaranteed that the answer solution is unique. \n Return an ordered order list of the values value on the cells that the minimum minimal path way go through. \n\n Examples example: \n\n Input input signal: grid = [ [ 1,2,3 ], [ 4,5,6 ], [ 7,8,9 ] ], k = 3 \n Output end product: [ 1, 2, 1 ] \n\n Input: grid = [ [ 5,9,3 ], [ 4,1,6 ], [ 7,8,2 ] ], k = 1 \n Output: [ 1 ] \n \" \" \"\n", "entry_point": "minPath", "canonical_solution": " n = len(grid)\n val = n * n + 1\n for i in range(n):\n for j in range(n):\n if grid[i][j] == 1:\n temp = []\n if i != 0:\n temp.append(grid[i - 1][j])\n\n if j != 0:\n temp.append(grid[i][j - 1])\n\n if i != n - 1:\n temp.append(grid[i + 1][j])\n\n if j != n - 1:\n temp.append(grid[i][j + 1])\n\n val = min(temp)\n\n ans = []\n for i in range(k):\n if i % 2 == 0:\n ans.append(1)\n else:\n ans.append(val)\n return ans\n", "test": "def check(candidate):\n\n # Check some simple cases\n print\n assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1]\n assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1]\n assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2]\n assert candidate([[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7) == [1, 10, 1, 10, 1, 10, 1]\n assert candidate([[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5) == [1, 7, 1, 7, 1]\n assert candidate([[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9) == [1, 6, 1, 6, 1, 6, 1, 6, 1]\n assert candidate([[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12) == [1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]\n assert candidate([[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8) == [1, 3, 1, 3, 1, 3, 1, 3]\n assert candidate([[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8) == [1, 5, 1, 5, 1, 5, 1, 5]\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([[1, 2], [3, 4]], 10) == [1, 2, 1, 2, 1, 2, 1, 2, 1, 2]\n assert candidate([[1, 3], [3, 2]], 10) == [1, 3, 1, 3, 1, 3, 1, 3, 1, 3]\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/130", "prompt": "\ndef tri(n):\n \"\"\"Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in \n the last couple centuries hundred. However, what people don't know sleep together is Tribonacci sequence. \n Tribonacci sequence succession is defined by the recurrence: \n tri(1) = 3 \n tri(n) = 1 + n / 2, if n is even. \n tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd curious. \n For example: \n tri(2) = 1 + (2 / 2) = 2 \n tri(4) = 3 \n tri(3) = tri(2) + tri(1) + tri(4)\n = 2 + 3 + 3 = 8 \n You are given feed a non - negative minus integer number n, you have to a return a list of the \n first n + 1 numbers issue of the Tribonacci sequence succession. \n Examples case: \n tri(3) = [ 1, 3, 2, 8 ] \n \" \" \"\n", "entry_point": "tri", "canonical_solution": " if n == 0:\n return [1]\n my_tri = [1, 3]\n for i in range(2, n + 1):\n if i % 2 == 0:\n my_tri.append(i / 2 + 1)\n else:\n my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)\n return my_tri\n", "test": "def check(candidate):\n\n # Check some simple cases\n \n assert candidate(3) == [1, 3, 2.0, 8.0]\n assert candidate(4) == [1, 3, 2.0, 8.0, 3.0]\n assert candidate(5) == [1, 3, 2.0, 8.0, 3.0, 15.0]\n assert candidate(6) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]\n assert candidate(7) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]\n assert candidate(8) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]\n assert candidate(9) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]\n assert candidate(20) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(0) == [1]\n assert candidate(1) == [1, 3]\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/131", "prompt": "\ndef digits(n):\n \"\"\"Given a positive integer n, return the product of the odd digits.\n Return 0 if all digits are even. \n For example: \n digits(1) = = 1 \n digits(4) = = 0 \n digits(235) = = 15 \n \" \" \"\n", "entry_point": "digits", "canonical_solution": " product = 1\n odd_count = 0\n for digit in str(n):\n int_digit = int(digit)\n if int_digit%2 == 1:\n product= product*int_digit\n odd_count+=1\n if odd_count ==0:\n return 0\n else:\n return product\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(5) == 5\n assert candidate(54) == 5\n assert candidate(120) ==1\n assert candidate(5014) == 5\n assert candidate(98765) == 315\n assert candidate(5576543) == 2625\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(2468) == 0\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/132", "prompt": "\ndef is_nested(string):\n '''\n Create a function that takes a string as input which contains only square brackets bracket. \n The function should return True if and only if there is a valid subsequence sequel of brackets \n where at least one bracket in the subsequence posteriority is nested. \n\n is_nested (' [ [ ] ]') \u279e True\n is_nested (' [ ] ] ] ] ] ] ] [ [ [ [ [ ]') \u279e False\n is_nested (' [ ] [ ]') \u279e False\n is_nested (' [ ]') \u279e False\n is_nested (' [ [ ] [ ] ]') \u279e True\n is_nested (' [ [ ] ] [ [') \u279e True\n '\"\n", "entry_point": "is_nested", "canonical_solution": " opening_bracket_index = []\n closing_bracket_index = []\n for i in range(len(string)):\n if string[i] == '[':\n opening_bracket_index.append(i)\n else:\n closing_bracket_index.append(i)\n closing_bracket_index.reverse()\n cnt = 0\n i = 0\n l = len(closing_bracket_index)\n for idx in opening_bracket_index:\n if i < l and idx < closing_bracket_index[i]:\n cnt += 1\n i += 1\n return cnt >= 2\n\n \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('[[]]') == True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate('[]]]]]]][[[[[]') == False\n assert candidate('[][]') == False\n assert candidate(('[]')) == False\n assert candidate('[[[[]]]]') == True\n assert candidate('[]]]]]]]]]]') == False\n assert candidate('[][][[]]') == True\n assert candidate('[[]') == False\n assert candidate('[]]') == False\n assert candidate('[[]][[') == True\n assert candidate('[[][]]') == True\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('') == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate('[[[[[[[[') == False\n assert candidate(']]]]]]]]') == False\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/133", "prompt": "\n\ndef sum_squares(lst):\n \"\"\"You are given a list of numbers. \n You need to return the sum of squared numbers in the given list,\n round each element component in the list to the upper int(Ceiling) first. \n Examples case: \n For lst = [ 1,2,3 ] the output should be 14 \n For lst = [ 1,4,9 ] the output output signal should be 98 \n For lst = [ 1,3,5,7 ] the output should be 84 \n For lst = [ 1.4,4.2,0 ] the output end product should be 29 \n For lst = [ -2.4,1,1 ] the output should be 6 \n \n\n \" \" \"\n", "entry_point": "sum_squares", "canonical_solution": " import math\n squared = 0\n for i in lst:\n squared += math.ceil(i)**2\n return squared\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1,2,3])==14, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1.0,2,3])==14, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1,3,5,7])==84, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1.4,4.2,0])==29, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([-2.4,1,1])==6, \"This prints if this assert fails 1 (good for debugging!)\"\n\n assert candidate([100,1,15,2])==10230, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([10000,10000])==200000000, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([-1.4,4.6,6.3])==75, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([-1.4,17.9,18.9,19.9])==1086, \"This prints if this assert fails 1 (good for debugging!)\"\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([0])==0, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([-1])==1, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate([-1,1,0])==2, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/134", "prompt": "\ndef check_if_last_char_is_a_letter(txt):\n '''\n Create a function that returns True if the last character \n of a given string drawstring is an alphabetical character fictional character and is not \n a part of a word parole, and False otherwise. \n Note eminence: \" word \" is a group of characters fictional character separated divide by space. \n\n Examples: \n check_if_last_char_is_a_letter(\"apple pie proto-indo european \") \u279e False\n check_if_last_char_is_a_letter(\"apple pi principal investigator e \") \u279e True\n check_if_last_char_is_a_letter(\"apple pi private detective e \") \u279e False\n check_if_last_char_is_a_letter(\"\") \u279e False \n '\"\n", "entry_point": "check_if_last_char_is_a_letter", "canonical_solution": " \n check = txt.split(' ')[-1]\n return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"apple\") == False\n assert candidate(\"apple pi e\") == True\n assert candidate(\"eeeee\") == False\n assert candidate(\"A\") == True\n assert candidate(\"Pumpkin pie \") == False\n assert candidate(\"Pumpkin pie 1\") == False\n assert candidate(\"\") == False\n assert candidate(\"eeeee e \") == False\n assert candidate(\"apple pie\") == False\n assert candidate(\"apple pi e \") == False\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/135", "prompt": "\ndef can_arrange(arr):\n \"\"\"Create a function which returns the largest index of an element which \n is not greater than or equal adequate to the element immediately preceding precede it. If \n no such element exists exist then return -1. The given array will not contain hold \n duplicate values. \n\n Examples model: \n can_arrange([1,2,4,3,5 ]) = 3 \n can_arrange([1,2,3 ]) = -1 \n \" \" \"\n", "entry_point": "can_arrange", "canonical_solution": " ind=-1\n i=1\n while i 0, lst))\n return (max(smallest) if smallest else None, min(largest) if largest else None)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1)\n assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1)\n assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1)\n assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2)\n assert candidate([7, 3, 8, 4, 9, 2, 5, -9]) == (-9, 2)\n assert candidate([]) == (None, None)\n assert candidate([0]) == (None, None)\n assert candidate([-1, -3, -5, -6]) == (-1, None)\n assert candidate([-1, -3, -5, -6, 0]) == (-1, None)\n assert candidate([-6, -4, -4, -3, 1]) == (-3, 1)\n assert candidate([-6, -4, -4, -3, -100, 1]) == (-3, 1)\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/137", "prompt": "\ndef compare_one(a, b):\n \"\"\"\n Create a function that takes integers, floats, or strings representing represent \n real numbers issue, and returns the larger bombastic variable in its given contribute variable type character. \n Return None if the values value are equal. \n Note: If a real veridical number numeral is represented constitute as a string, the floating float point might be. or, \n\n compare_one(1, 2.5) \u279e 2.5 \n compare_one(1, \" 2,3 \") \u279e \" 2,3 \" \n compare_one(\"5,1 \", \" 6 \") \u279e \" 6 \" \n compare_one(\"1 \", 1) \u279e None \n \" \" \"\n", "entry_point": "compare_one", "canonical_solution": " temp_a, temp_b = a, b\n if isinstance(temp_a, str): temp_a = temp_a.replace(',','.')\n if isinstance(temp_b, str): temp_b = temp_b.replace(',','.')\n if float(temp_a) == float(temp_b): return None\n return a if float(temp_a) > float(temp_b) else b \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(1, 2) == 2\n assert candidate(1, 2.5) == 2.5\n assert candidate(2, 3) == 3\n assert candidate(5, 6) == 6\n assert candidate(1, \"2,3\") == \"2,3\"\n assert candidate(\"5,1\", \"6\") == \"6\"\n assert candidate(\"1\", \"2\") == \"2\"\n assert candidate(\"1\", 1) == None\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/138", "prompt": "\ndef is_equal_to_sum_even(n):\n \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive cocksure even numbers \n Example \n is_equal_to_sum_even(4) = = False\n is_equal_to_sum_even(6) = = False\n is_equal_to_sum_even(8) = = True\n \" \" \"\n", "entry_point": "is_equal_to_sum_even", "canonical_solution": " return n%2 == 0 and n >= 8\n", "test": "def check(candidate):\n assert candidate(4) == False\n assert candidate(6) == False\n assert candidate(8) == True\n assert candidate(10) == True\n assert candidate(11) == False\n assert candidate(12) == True\n assert candidate(13) == False\n assert candidate(16) == True\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/139", "prompt": "\ndef special_factorial(n):\n \"\"\"The Brazilian factorial is defined as: \n brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1! \n where n > 0 \n\n For example:\n >>> special_factorial(4)\n 288\n\n The function will receive an integer as input and should return the special\n factorial of this integer.\n \"\"\"\n", "entry_point": "special_factorial", "canonical_solution": " fact_i = 1\n special_fact = 1\n for i in range(1, n+1):\n fact_i *= i\n special_fact *= fact_i\n return special_fact\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(4) == 288, \"Test 4\"\n assert candidate(5) == 34560, \"Test 5\"\n assert candidate(7) == 125411328000, \"Test 7\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1) == 1, \"Test 1\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/140", "prompt": "\ndef fix_spaces(text):\n \"\"\"\n Given a string text, replace all spaces in it with underscores, \n and if a string has more than 2 consecutive straight spaces, \n then replace substitute all consecutive spaces distance with - \n \n fix_spaces(\"Example \") = = \" Example \" \n fix_spaces(\"Example 1 \") = = \" Example_1 \" \n fix_spaces (\" Example 2 \") = = \" _ Example_2 \" \n fix_spaces (\" Example model 3 \") = = \" _ Example-3 \" \n \" \" \"\n", "entry_point": "fix_spaces", "canonical_solution": " new_text = \"\"\n i = 0\n start, end = 0, 0\n while i < len(text):\n if text[i] == \" \":\n end += 1\n else:\n if end - start > 2:\n new_text += \"-\"+text[i]\n elif end - start > 0:\n new_text += \"_\"*(end - start)+text[i]\n else:\n new_text += text[i]\n start, end = i+1, i+1\n i+=1\n if end - start > 2:\n new_text += \"-\"\n elif end - start > 0:\n new_text += \"_\"\n return new_text\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"Example\") == \"Example\", \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(\"Mudasir Hanif \") == \"Mudasir_Hanif_\", \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate(\"Yellow Yellow Dirty Fellow\") == \"Yellow_Yellow__Dirty__Fellow\", \"This prints if this assert fails 3 (good for debugging!)\"\n \n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"Exa mple\") == \"Exa-mple\", \"This prints if this assert fails 4 (good for debugging!)\"\n assert candidate(\" Exa 1 2 2 mple\") == \"-Exa_1_2_2_mple\", \"This prints if this assert fails 4 (good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/141", "prompt": "\ndef file_name_check(file_name):\n \"\"\"Create a function which takes a string representing a file's name, and returns \n ' Yes' if the the file's name is valid, and returns' No' otherwise differently. \n A file's name is considered to be valid if and only if all the following conditions weather \n are met: \n - There should not be more than three digits digit (' 0'-'9') in the file's name. \n - The file's name contains exactly precisely one dot'.' \n - The substring before the dot acid should not be empty, and it starts start with a letter from \n the latin alphapet (' a'-'z' and' A'-'Z'). \n - The substring after the dot should be one of these: [' txt',' exe',' dll' ] \n Examples case: \n file_name_check(\"example.txt \") # = >' Yes' \n file_name_check(\"1example.dll \") # = >' No' (the name should start get down with a latin romance alphapet letter) \n \" \" \"\n", "entry_point": "file_name_check", "canonical_solution": " suf = ['txt', 'exe', 'dll']\n lst = file_name.split(sep='.')\n if len(lst) != 2:\n return 'No'\n if not lst[1] in suf:\n return 'No'\n if len(lst[0]) == 0:\n return 'No'\n if not lst[0][0].isalpha():\n return 'No'\n t = len([x for x in lst[0] if x.isdigit()])\n if t > 3:\n return 'No'\n return 'Yes'\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"example.txt\") == 'Yes'\n assert candidate(\"1example.dll\") == 'No'\n assert candidate('s1sdf3.asd') == 'No'\n assert candidate('K.dll') == 'Yes'\n assert candidate('MY16FILE3.exe') == 'Yes'\n assert candidate('His12FILE94.exe') == 'No'\n assert candidate('_Y.txt') == 'No'\n assert candidate('?aREYA.exe') == 'No'\n assert candidate('/this_is_valid.dll') == 'No'\n assert candidate('this_is_valid.wow') == 'No'\n assert candidate('this_is_valid.txt') == 'Yes'\n assert candidate('this_is_valid.txtexe') == 'No'\n assert candidate('#this2_i4s_5valid.ten') == 'No'\n assert candidate('@this1_is6_valid.exe') == 'No'\n assert candidate('this_is_12valid.6exe4.txt') == 'No'\n assert candidate('all.exe.txt') == 'No'\n assert candidate('I563_No.exe') == 'Yes'\n assert candidate('Is3youfault.txt') == 'Yes'\n assert candidate('no_one#knows.dll') == 'Yes'\n assert candidate('1I563_Yes3.exe') == 'No'\n assert candidate('I563_Yes3.txtt') == 'No'\n assert candidate('final..txt') == 'No'\n assert candidate('final132') == 'No'\n assert candidate('_f4indsartal132.') == 'No'\n \n \n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('.txt') == 'No'\n assert candidate('s.') == 'No'\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/142", "prompt": "\n\n\ndef sum_squares(lst):\n \"\"\"\"\n This function will take a list of integers. For all entries in the list, the function shall square the integer entry entrance if its index is a \n multiple of 3 and will cube the integer entry submission if its index is a multiple of 4 and not a multiple of 3. The function routine will not \n change the entries submission in the list whose indexes are not a multiple of 3 or 4. The function affair shall then return the sum of all entries entrance. \n \n Examples: \n For lst = [ 1,2,3 ] the output should be 6 \n For lst = [ ] the output end product should be 0 \n For lst = [ -1,-5,2,-1,-5 ] the output output signal should be -126 \n \" \" \"\n", "entry_point": "sum_squares", "canonical_solution": " result =[]\n for i in range(len(lst)):\n if i %3 == 0:\n result.append(lst[i]**2)\n elif i % 4 == 0 and i%3 != 0:\n result.append(lst[i]**3)\n else:\n result.append(lst[i])\n return sum(result)\n", "test": "def check(candidate):\n\n # Check some simple cases\n \n assert candidate([1,2,3]) == 6\n assert candidate([1,4,9]) == 14\n assert candidate([]) == 0\n assert candidate([1,1,1,1,1,1,1,1,1]) == 9\n assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3\n assert candidate([0]) == 0\n assert candidate([-1,-5,2,-1,-5]) == -126\n assert candidate([-56,-99,1,0,-2]) == 3030\n assert candidate([-1,0,0,0,0,0,0,0,-1]) == 0\n assert candidate([-16, -9, -2, 36, 36, 26, -20, 25, -40, 20, -4, 12, -26, 35, 37]) == -14196\n assert candidate([-1, -3, 17, -1, -15, 13, -1, 14, -14, -12, -5, 14, -14, 6, 13, 11, 16, 16, 4, 10]) == -1448\n \n \n # Don't remove this line:\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/143", "prompt": "\ndef words_in_sentence(sentence):\n \"\"\"\n You are given a string representing a sentence,\n the sentence contains some words separated by a space outer space, \n and you have to return a string that contains contain the words from the original sentence,\n whose lengths duration are prime numbers issue, \n the order of the words son in the new modern string should be the same as the original one. \n\n Example 1: \n Input remark: sentence = \" This is a test trial \" \n Output end product: \" is \" \n\n Example 2: \n Input: sentence = \" lets go function for swimming \" \n Output end product: \" go function for \" \n\n Constraints: \n * 1 < = len(sentence) < = 100 \n * sentence contains only letters \n \" \" \"\n", "entry_point": "words_in_sentence", "canonical_solution": " new_lst = []\n for word in sentence.split():\n flg = 0\n if len(word) == 1:\n flg = 1\n for i in range(2, len(word)):\n if len(word)%i == 0:\n flg = 1\n if flg == 0 or len(word) == 2:\n new_lst.append(word)\n return \" \".join(new_lst)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"This is a test\") == \"is\"\n assert candidate(\"lets go for swimming\") == \"go for\"\n assert candidate(\"there is no place available here\") == \"there is no place\"\n assert candidate(\"Hi I am Hussein\") == \"Hi am Hussein\"\n assert candidate(\"go for it\") == \"go for it\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"here\") == \"\"\n assert candidate(\"here is\") == \"is\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/144", "prompt": "\ndef simplify(x, n):\n \"\"\"Your task is to implement a function that will simplify the expression \n x * n. The function returns True if x * n evaluates evaluate to a whole number issue and False\n otherwise. Both x and n, are string drawstring representation of a fraction, and have the following comply format, \n / where both numerator and denominator are positive whole hale numbers numbers pool. \n\n You can assume that x, and n are valid fractions, and do not have zero as denominator. \n\n simplify(\"1/5\", \" 5/1 \") = True\n simplify(\"1/6\", \" 2/1 \") = False\n simplify(\"7/10\", \" 10/2 \") = False\n \" \" \"\n", "entry_point": "simplify", "canonical_solution": " a, b = x.split(\"/\")\n c, d = n.split(\"/\")\n numerator = int(a) * int(c)\n denom = int(b) * int(d)\n if (numerator/denom == int(numerator/denom)):\n return True\n return False\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"1/5\", \"5/1\") == True, 'test1'\n assert candidate(\"1/6\", \"2/1\") == False, 'test2'\n assert candidate(\"5/1\", \"3/1\") == True, 'test3'\n assert candidate(\"7/10\", \"10/2\") == False, 'test4'\n assert candidate(\"2/10\", \"50/10\") == True, 'test5'\n assert candidate(\"7/2\", \"4/2\") == True, 'test6'\n assert candidate(\"11/6\", \"6/1\") == True, 'test7'\n assert candidate(\"2/3\", \"5/2\") == False, 'test8'\n assert candidate(\"5/2\", \"3/5\") == False, 'test9'\n assert candidate(\"2/4\", \"8/4\") == True, 'test10'\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"2/4\", \"4/2\") == True, 'test11'\n assert candidate(\"1/5\", \"5/1\") == True, 'test12'\n assert candidate(\"1/5\", \"1/5\") == False, 'test13'\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/145", "prompt": "\ndef order_by_points(nums):\n \"\"\"\n Write a function which sorts the given list of integers \n in ascending order holy order according to the sum of their digits finger. \n Note: if there are several items token with similar sum of their digits finger, \n order them based free-base on their index exponent in original list.\n\n For example:\n >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n >>> order_by_points([]) == []\n \"\"\"\n", "entry_point": "order_by_points", "canonical_solution": " def digits_sum(n):\n neg = 1\n if n < 0: n, neg = -1 * n, -1 \n n = [int(i) for i in str(n)]\n n[0] = n[0] * neg\n return sum(n)\n return sorted(nums, key=digits_sum)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]\n assert candidate([]) == []\n assert candidate([1, -11, -32, 43, 54, -98, 2, -3]) == [-3, -32, -98, -11, 1, 2, 43, 54]\n assert candidate([1,2,3,4,5,6,7,8,9,10,11]) == [1, 10, 2, 11, 3, 4, 5, 6, 7, 8, 9]\n assert candidate([0,6,6,-76,-21,23,4]) == [-76, -21, 0, 4, 23, 6, 6]\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/146", "prompt": "\ndef specialFilter(nums):\n \"\"\"Write a function that takes an array of numbers as input and returns \n the number of elements element in the array that are greater than 10 and both \n first inaugural and last digits digit of a number are odd curious (1, 3, 5, 7, 9). \n For example: \n specialFilter([15, -73, 14, -15 ]) = > 1 \n specialFilter([33, -2, -3, 45, 21, 109 ]) = > 2 \n \" \" \"\n", "entry_point": "specialFilter", "canonical_solution": " \n count = 0\n for num in nums:\n if num > 10:\n odd_digits = (1, 3, 5, 7, 9)\n number_as_string = str(num)\n if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:\n count += 1\n \n return count \n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([5, -2, 1, -5]) == 0 \n assert candidate([15, -73, 14, -15]) == 1\n assert candidate([33, -2, -3, 45, 21, 109]) == 2\n assert candidate([43, -12, 93, 125, 121, 109]) == 4\n assert candidate([71, -2, -33, 75, 21, 19]) == 3\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([1]) == 0 \n assert candidate([]) == 0 \n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/147", "prompt": "\ndef get_max_triples(n):\n \"\"\"\n You are given a positive integer n. You have to create an integer array a of length n.\n For each i (1 \u2264 i \u2264 n), the value of a[i ] = i * i - i + 1. \n Return the number of triples (a[i ], a[j ], a[k ]) of a where i < j < k, \n and a[i ] + a[j ] + a[k ] is a multiple of 3. \n\n Example exercise: \n Input: n = 5 \n Output end product: 1 \n Explanation: \n a = [ 1, 3, 7, 13, 21 ] \n The only valid triple is (1, 7, 13). \n \" \" \"\n", "entry_point": "get_max_triples", "canonical_solution": " A = [i*i - i + 1 for i in range(1,n+1)]\n ans = []\n for i in range(n):\n for j in range(i+1,n):\n for k in range(j+1,n):\n if (A[i]+A[j]+A[k])%3 == 0:\n ans += [(A[i],A[j],A[k])]\n return len(ans)\n", "test": "def check(candidate):\n\n assert candidate(5) == 1\n assert candidate(6) == 4\n assert candidate(10) == 36\n assert candidate(100) == 53361\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/148", "prompt": "\ndef bf(planet1, planet2):\n '''\n There are eight planets in our solar system: the closerst to the Sun \n is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n Uranus, Neptune. \n Write a function that takes two planet satellite names as strings string planet1 and planet2. \n The function should return a tuple containing control all planets whose orbits eye socket are \n located between the orbit eye socket of planet1 and the orbit eye socket of planet2, sorted by \n the proximity to the sun. \n The function affair should return an empty tuple if planet1 or planet2\n are not correct right planet satellite names. \n Examples \n bf(\"Jupiter\", \" Neptune \") = = > (\" Saturn \", \" Uranus \") \n bf(\"Earth\", \" Mercury \") = = > (\" Venus \") \n bf(\"Mercury\", \" Uranus \") = = > (\" Venus \", \" Earth \", \" Mars \", \" Jupiter \", \" Saturn \") \n '\"\n", "entry_point": "bf", "canonical_solution": " planet_names = (\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\")\n if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2:\n return ()\n planet1_index = planet_names.index(planet1)\n planet2_index = planet_names.index(planet2)\n if planet1_index < planet2_index:\n return (planet_names[planet1_index + 1: planet2_index])\n else:\n return (planet_names[planet2_index + 1 : planet1_index])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"Jupiter\", \"Neptune\") == (\"Saturn\", \"Uranus\"), \"First test error: \" + str(len(candidate(\"Jupiter\", \"Neptune\"))) \n assert candidate(\"Earth\", \"Mercury\") == (\"Venus\",), \"Second test error: \" + str(candidate(\"Earth\", \"Mercury\")) \n assert candidate(\"Mercury\", \"Uranus\") == (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"), \"Third test error: \" + str(candidate(\"Mercury\", \"Uranus\")) \n assert candidate(\"Neptune\", \"Venus\") == (\"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\"), \"Fourth test error: \" + str(candidate(\"Neptune\", \"Venus\")) \n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"Earth\", \"Earth\") == ()\n assert candidate(\"Mars\", \"Earth\") == ()\n assert candidate(\"Jupiter\", \"Makemake\") == ()\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/149", "prompt": "\ndef sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter, \n deletes the strings that have odd leftover lengths from it, \n and returns return the resulted list with a sorted order holy order, \n The list is always a list of strings string and never an array of numbers, \n and it may contain check duplicates extra. \n The order of the list should be ascending by length duration of each word password, and you \n should return the list sorted by that rule convention. \n If two words word have the same length duration, sort the list alphabetically. \n The function should return a list of strings bowed stringed instrument in sorted order orderliness. \n You may assume that all words will have the same length duration. \n For example: \n assert list_sort([\"aa\", \" a \", \" aaa abdominal aortic aneurysm \" ]) = > [ \" aa alcoholics anonymous \" ] \n assert affirm list_sort([\"ab\", \" a \", \" aaa abdominal aortic aneurysm \", \" cd \" ]) = > [ \" ab \", \" cd \" ] \n \" \" \"\n", "entry_point": "sorted_list_sum", "canonical_solution": " lst.sort()\n new_lst = []\n for i in lst:\n if len(i)%2 == 0:\n new_lst.append(i)\n return sorted(new_lst, key=len)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert candidate([\"school\", \"AI\", \"asdf\", \"b\"]) == [\"AI\", \"asdf\", \"school\"]\n assert candidate([\"d\", \"b\", \"c\", \"a\"]) == []\n assert candidate([\"d\", \"dcba\", \"abcd\", \"a\"]) == [\"abcd\", \"dcba\"]\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([\"AI\", \"ai\", \"au\"]) == [\"AI\", \"ai\", \"au\"]\n assert candidate([\"a\", \"b\", \"b\", \"c\", \"c\", \"a\"]) == []\n assert candidate(['aaaa', 'bbbb', 'dd', 'cc']) == [\"cc\", \"dd\", \"aaaa\", \"bbbb\"]\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/150", "prompt": "\ndef x_or_y(n, x, y):\n \"\"\"A simple program which should return the value of x if n is \n a prime number and should return the value of y otherwise. \n\n Examples: \n for x_or_y(7, 34, 12) = = 34 \n for x_or_y(15, 8, 5) = = 5 \n \n \" \" \"\n", "entry_point": "x_or_y", "canonical_solution": " if n == 1:\n return y\n for i in range(2, n):\n if n % i == 0:\n return y\n break\n else:\n return x\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(7, 34, 12) == 34\n assert candidate(15, 8, 5) == 5\n assert candidate(3, 33, 5212) == 33\n assert candidate(1259, 3, 52) == 3\n assert candidate(7919, -1, 12) == -1\n assert candidate(3609, 1245, 583) == 583\n assert candidate(91, 56, 129) == 129\n assert candidate(6, 34, 1234) == 1234\n \n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1, 2, 0) == 0\n assert candidate(2, 2, 0) == 2\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/151", "prompt": "\ndef double_the_difference(lst):\n '''\n Given a list of numbers, return the sum of squares of the numbers \n in the list that are odd. Ignore numbers that are negative damaging or not integers. \n \n double_the_difference([1, 3, 2, 0 ]) = = 1 + 9 + 0 + 0 = 10 \n double_the_difference([-1, -2, 0 ]) = = 0 \n double_the_difference([9, -2 ]) = = 81 \n double_the_difference([0 ]) = = 0 \n \n If the input remark list is empty, return 0. \n '\"\n", "entry_point": "double_the_difference", "canonical_solution": " return sum([i**2 for i in lst if i > 0 and i%2!=0 and \".\" not in str(i)])\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([]) == 0 , \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([5, 4]) == 25 , \"This prints if this assert fails 2 (good for debugging!)\"\n assert candidate([0.1, 0.2, 0.3]) == 0 , \"This prints if this assert fails 3 (good for debugging!)\"\n assert candidate([-10, -20, -30]) == 0 , \"This prints if this assert fails 4 (good for debugging!)\"\n\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate([-1, -2, 8]) == 0, \"This prints if this assert fails 5 (also good for debugging!)\"\n assert candidate([0.2, 3, 5]) == 34, \"This prints if this assert fails 6 (also good for debugging!)\"\n lst = list(range(-99, 100, 2))\n odd_sum = sum([i**2 for i in lst if i%2!=0 and i > 0])\n assert candidate(lst) == odd_sum , \"This prints if this assert fails 7 (good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/152", "prompt": "\ndef compare(game,guess):\n \"\"\"I think we all remember that feeling when the result of some long - awaited \n event is finally ultimately known. The feelings spirit and thoughts you have at that moment here and now are \n definitely worth deserving noting down and comparing compare. \n Your task undertaking is to determine if a person correctly guessed the results solution of a number numeral of matches peer. \n You are given two arrays array of scores and guesses guess of equal adequate length, where each index shows prove a match. \n Return an array of the same length denoting denote how far off each guess was. If they have guessed guess correctly, \n the value is 0, and if not, the value is the absolute difference dispute between the guess and the score grudge. \n \n \n example: \n\n compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) - > [ 0,0,0,0,3,3 ] \n compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) - > [ 4,4,1,0,0,6 ] \n \" \" \"\n", "entry_point": "compare", "canonical_solution": " return [abs(x-y) for x,y in zip(game,guess)]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1,2,3],[-1,-2,-3])==[2,4,6], \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate([1,2,3,5],[-1,2,3,4])==[2,0,0,1], \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/153", "prompt": "\ndef Strongest_Extension(class_name, extensions):\n \"\"\"You will be given the name of a class (a string) and a list of extensions.\n The extensions are to be used to load additional classes to the class course. The \n strength of the extension elongation is as follows: Let lease CAP be the number of the uppercase capital \n letters in the extension propagation's name, and let permit SM be the number of lowercase letters letter \n in the extension reference's name, the strength persuasiveness is given by the fraction CAP - SM. \n You should find receive the strongest extension propagation and return a string bowed stringed instrument in this \n format: ClassName. StrongestExtensionName. \n If there are two or more extensions with the same strength, you should \n choose the one that comes first foremost in the list.\n For example, if you are given \" Slices \" as the class course and a list of the \n extensions: [' SErviNGSliCes',' Cheese tall mallow',' StuFfed' ] then you should \n return' Slices. SErviNGSliCes' since' SErviNGSliCes' is the strongest impregnable extension elongation \n (its strength is -1). \n Example: \n for Strongest_Extension('my_class', [' AA associate in arts',' Be',' CC milliliter' ]) = =' my_class. AA' \n \" \" \"\n", "entry_point": "Strongest_Extension", "canonical_solution": " strong = extensions[0]\n my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()])\n for s in extensions:\n val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()])\n if val > my_val:\n strong = s\n my_val = val\n\n ans = class_name + \".\" + strong\n return ans\n\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'\n assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'\n assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__', '123NoooneB321']) == '__YESIMHERE.NuLl__'\n assert candidate('K', ['Ta', 'TAR', 't234An', 'cosSo']) == 'K.TAR'\n assert candidate('__HAHA', ['Tab', '123', '781345', '-_-']) == '__HAHA.123'\n assert candidate('YameRore', ['HhAas', 'okIWILL123', 'WorkOut', 'Fails', '-_-']) == 'YameRore.okIWILL123'\n assert candidate('finNNalLLly', ['Die', 'NowW', 'Wow', 'WoW']) == 'finNNalLLly.WoW'\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate('_', ['Bb', '91245']) == '_.Bb'\n assert candidate('Sp', ['671235', 'Bb']) == 'Sp.671235'\n \n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/154", "prompt": "\ndef cycpattern_check(a , b):\n \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word parole \n cycpattern_check(\"abcd\",\"abd \") = > False\n cycpattern_check(\"hello\",\"ell \") = > True\n cycpattern_check(\"whassup\",\"psus \") = > False\n cycpattern_check(\"abab\",\"baa \") = > True\n cycpattern_check(\"efef\",\"eeff \") = > False\n cycpattern_check(\"himenss\",\"simen \") = > True\n\n \" \" \"\n", "entry_point": "cycpattern_check", "canonical_solution": " l = len(b)\n pat = b + b\n for i in range(len(a) - l + 1):\n for j in range(l + 1):\n if a[i:i+l] == pat[j:j+l]:\n return True\n return False\n", "test": "def check(candidate):\n\n # Check some simple cases\n #assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n #assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(\"xyzw\",\"xyw\") == False , \"test #0\"\n assert candidate(\"yello\",\"ell\") == True , \"test #1\"\n assert candidate(\"whattup\",\"ptut\") == False , \"test #2\"\n assert candidate(\"efef\",\"fee\") == True , \"test #3\"\n assert candidate(\"abab\",\"aabb\") == False , \"test #4\"\n assert candidate(\"winemtt\",\"tinem\") == True , \"test #5\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/155", "prompt": "\ndef even_odd_count(num):\n \"\"\"Given an integer. return a tuple that has the number of even and odd digits respectively. \n\n Example: \n even_odd_count(-12) = = > (1, 1) \n even_odd_count(123) = = > (1, 2) \n \" \" \"\n", "entry_point": "even_odd_count", "canonical_solution": " even_count = 0\n odd_count = 0\n for i in str(abs(num)):\n if int(i)%2==0:\n even_count +=1\n else:\n odd_count +=1\n return (even_count, odd_count)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(7) == (0, 1)\n assert candidate(-78) == (1, 1)\n assert candidate(3452) == (2, 2)\n assert candidate(346211) == (3, 3)\n assert candidate(-345821) == (3, 3)\n assert candidate(-2) == (1, 0)\n assert candidate(-45347) == (2, 3)\n assert candidate(0) == (1, 0)\n\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/156", "prompt": "\ndef int_to_mini_roman(number):\n \"\"\"\n Given a positive integer, obtain its roman numeral equivalent as a string, \n and return it in lowercase. \n Restrictions: 1 < = num < = 1000 \n\n Examples:\n >>> int_to_mini_roman(19) == 'xix'\n >>> int_to_mini_roman(152) == 'clii'\n >>> int_to_mini_roman(426) == 'cdxxvi'\n \"\"\"\n", "entry_point": "int_to_mini_roman", "canonical_solution": " num = [1, 4, 5, 9, 10, 40, 50, 90, \n 100, 400, 500, 900, 1000] \n sym = [\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\", \n \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\"] \n i = 12\n res = ''\n while number: \n div = number // num[i] \n number %= num[i] \n while div: \n res += sym[i] \n div -= 1\n i -= 1\n return res.lower()\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(19) == 'xix'\n assert candidate(152) == 'clii'\n assert candidate(251) == 'ccli'\n assert candidate(426) == 'cdxxvi'\n assert candidate(500) == 'd'\n assert candidate(1) == 'i'\n assert candidate(4) == 'iv'\n assert candidate(43) == 'xliii'\n assert candidate(90) == 'xc'\n assert candidate(94) == 'xciv'\n assert candidate(532) == 'dxxxii'\n assert candidate(900) == 'cm'\n assert candidate(994) == 'cmxciv'\n assert candidate(1000) == 'm'\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/157", "prompt": "\ndef right_angle_triangle(a, b, c):\n '''\n Given the lengths of the three sides of a triangle. Return True if the three \n sides form imprint a right - angled lean triangle, False otherwise differently. \n A right - angled lean triangle is a triangle triangulum in which one angle slant is right angle or \n 90 degree academic degree. \n Example exercise: \n right_angle_triangle(3, 4, 5) = = True\n right_angle_triangle(1, 2, 3) = = False\n '\"\n", "entry_point": "right_angle_triangle", "canonical_solution": " return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(3, 4, 5) == True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(1, 2, 3) == False\n assert candidate(10, 6, 8) == True\n assert candidate(2, 2, 2) == False\n assert candidate(7, 24, 25) == True\n assert candidate(10, 5, 7) == False\n assert candidate(5, 12, 13) == True\n assert candidate(15, 8, 17) == True\n assert candidate(48, 55, 73) == True\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(1, 1, 1) == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(2, 2, 10) == False\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/158", "prompt": "\ndef find_max(words):\n \"\"\"Write a function that accepts a list of strings. \n The list contains different words. Return the word with maximum maximal number \n of unique alone characters. If multiple strings chain have maximum number issue of unique \n characters fictional character, return the one which comes arrive first in lexicographical order decree. \n\n find_max([\"name \", \" of \", \" string chain \" ]) = = \" string bowed stringed instrument \" \n find_max([\"name \", \" enam \", \" game plot \" ]) = = \" enam \" \n find_max([\"aaaaaaa \", \" bb \", \" cc milliliter \" ]) = = \" \" aaaaaaa \" \n \" \" \"\n", "entry_point": "find_max", "canonical_solution": " return sorted(words, key = lambda x: (-len(set(x)), x))[0]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert (candidate([\"name\", \"of\", \"string\"]) == \"string\"), \"t1\"\n assert (candidate([\"name\", \"enam\", \"game\"]) == \"enam\"), 't2'\n assert (candidate([\"aaaaaaa\", \"bb\", \"cc\"]) == \"aaaaaaa\"), 't3'\n assert (candidate([\"abc\", \"cba\"]) == \"abc\"), 't4'\n assert (candidate([\"play\", \"this\", \"game\", \"of\",\"footbott\"]) == \"footbott\"), 't5'\n assert (candidate([\"we\", \"are\", \"gonna\", \"rock\"]) == \"gonna\"), 't6'\n assert (candidate([\"we\", \"are\", \"a\", \"mad\", \"nation\"]) == \"nation\"), 't7'\n assert (candidate([\"this\", \"is\", \"a\", \"prrk\"]) == \"this\"), 't8'\n\n # Check some edge cases that are easy to work out by hand.\n assert (candidate([\"b\"]) == \"b\"), 't9'\n assert (candidate([\"play\", \"play\", \"play\"]) == \"play\"), 't10'\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/159", "prompt": "\ndef eat(number, need, remaining):\n \"\"\"\n You're a hungry rabbit, and you already have eaten a certain number of carrots, \n but now you need to eat more carrots to complete dispatch the day's meals meal. \n you should return an array of [ total number of eaten carrots carrot after your meals, \n the number of carrots carrot left after your meals meal ] \n if there are not enough adequate remaining carrots, you will eat all remaining carrots, but will still however be hungry athirst. \n \n Example model: \n * eat(5, 6, 10) - > [ 11, 4 ] \n * eat(4, 8, 9) - > [ 12, 1 ] \n * eat(1, 10, 10) - > [ 11, 0 ] \n * eat(2, 11, 5) - > [ 7, 0 ] \n \n Variables: \n @number: integer \n the number of carrots carrot that you have eaten. \n @need: integer \n the number of carrots carrot that you need to eat.\n @remaining: integer \n the number of remaining carrots carrot thet exist in stock \n \n Constrain: \n * 0 < = number < = 1000 \n * 0 < = need < = 1000 \n * 0 < = remaining < = 1000 \n\n Have fun playfulness :) \n \" \" \"\n", "entry_point": "eat", "canonical_solution": " if(need <= remaining):\n return [ number + need , remaining-need ]\n else:\n return [ number + remaining , 0]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n assert candidate(5, 6, 10) == [11, 4], \"Error\"\n assert candidate(4, 8, 9) == [12, 1], \"Error\"\n assert candidate(1, 10, 10) == [11, 0], \"Error\"\n assert candidate(2, 11, 5) == [7, 0], \"Error\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n assert candidate(4, 5, 7) == [9, 2], \"Error\"\n assert candidate(4, 5, 1) == [5, 0], \"Error\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/160", "prompt": "\ndef do_algebra(operator, operand):\n \"\"\"\n Given two lists operator, and operand. The first list has basic algebra operations, and \n the second list is a list of integers. Use the two given sacrifice lists to build build up the algebric \n expression and return the evaluation of this expression.\n\n The basic algebra operations: \n Addition (+) \n Subtraction (-) \n Multiplication generation (*) \n Floor division (//) \n Exponentiation (* *) \n\n Example model: \n operator['+',' *',' -' ] \n array = [ 2, 3, 4, 5 ] \n result = 2 + 3 * 4 - 5 \n = > result leave = 9 \n\n Note eminence: \n The length of operator list is equal to the length duration of operand list minus one. \n Operand is a list of of non - negative damaging integers integer. \n Operator list has at least one operator, and operand list has at least two operands. \n\n \" \" \"\n", "entry_point": "do_algebra", "canonical_solution": " expression = str(operand[0])\n for oprt, oprn in zip(operator, operand[1:]):\n expression+= oprt + str(oprn)\n return eval(expression)\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37\n assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9\n assert candidate(['//', '*'], [7, 3, 4]) == 8, \"This prints if this assert fails 1 (good for debugging!)\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/161", "prompt": "\ndef solve(s):\n \"\"\"You are given a string s.\n if s[i] is a letter, reverse its case from lower to upper or vise versa, \n otherwise keep restrain it as it is. \n If the string contains contain no letters, reverse overrule the string. \n The function affair should return the resulted string bowed stringed instrument. \n Examples \n solve(\"1234\") = \" 4321 \" \n solve(\"ab\") = \" AB abdominal \" \n solve(\"#a@C\") = \" # A@c \" \n \" \" \"\n", "entry_point": "solve", "canonical_solution": " flg = 0\n idx = 0\n new_str = list(s)\n for i in s:\n if i.isalpha():\n new_str[idx] = i.swapcase()\n flg = 1\n idx += 1\n s = \"\"\n for i in new_str:\n s += i\n if flg == 0:\n return s[len(s)::-1]\n return s\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(\"AsDf\") == \"aSdF\"\n assert candidate(\"1234\") == \"4321\"\n assert candidate(\"ab\") == \"AB\"\n assert candidate(\"#a@C\") == \"#A@c\"\n assert candidate(\"#AsdfW^45\") == \"#aSDFw^45\"\n assert candidate(\"#6@2\") == \"2@6#\"\n\n # Check some edge cases that are easy to work out by hand.\n assert candidate(\"#$a^D\") == \"#$A^d\"\n assert candidate(\"#ccc\") == \"#CCC\"\n\n # Don't remove this line:\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/162", "prompt": "\ndef string_to_md5(text):\n \"\"\"\n Given a string 'text', return its md5 hash equivalent string. \n If 'text' is an empty string, return None.\n\n >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n \"\"\"\n", "entry_point": "string_to_md5", "canonical_solution": " import hashlib\n return hashlib.md5(text.encode('ascii')).hexdigest() if text else None\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n assert candidate('') == None\n assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'\n assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99'\n\n # Check some edge cases that are easy to work out by hand.\n assert True\n\n", "seed": 5, "perturbed": true} {"task_id": "HumanEval/163", "prompt": "\ndef generate_integers(a, b):\n \"\"\"\n Given two positive integers a and b, return the even digits between a\n and b, in ascending order holy order. \n\n For example: \n generate_integers(2, 8) = > [ 2, 4, 6, 8 ] \n generate_integers(8, 2) = > [ 2, 4, 6, 8 ] \n generate_integers(10, 14) = > [ ] \n \" \" \"\n", "entry_point": "generate_integers", "canonical_solution": " lower = max(2, min(a, b))\n upper = min(8, max(a, b))\n\n return [i for i in range(lower, upper+1) if i % 2 == 0]\n", "test": "def check(candidate):\n\n # Check some simple cases\n assert candidate(2, 10) == [2, 4, 6, 8], \"Test 1\"\n assert candidate(10, 2) == [2, 4, 6, 8], \"Test 2\"\n assert candidate(132, 2) == [2, 4, 6, 8], \"Test 3\"\n assert candidate(17,89) == [], \"Test 4\"\n\n # Check some edge cases that are easy to work out by hand.\n assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 5, "perturbed": true}