I0218 15:36:12.138049 140279694163968 graph.py:498] ceva_menelaus_hint
I0218 15:36:12.139024 140279694163968 graph.py:499] a b c = triangle; d = free; e = on_line b c, on_line a d; f = on_line c a, on_line b d; g = on_line a b, on_line c d; h = on_line c a, on_pline h b e f; i = on_line c d, on_pline i e a b; j = on_line b f, on_pline j e a c ? eqratio f h f a g b g a
I0218 15:36:15.467568 140279694163968 alphageometry.py:191] 
==========================
 * From theorem premises:
A B C D E F G H : Points
B,E,C are collinear [00]
A,D,E are collinear [01]
A,F,C are collinear [02]
B,D,F are collinear [03]
A,B,G are collinear [04]
G,D,C are collinear [05]
HB ∥ EF [06]
A,H,C are collinear [07]

 * Auxiliary Constructions:
I J : Points
IE ∥ AB [08]
D,I,C are collinear [09]
JE ∥ AC [10]
B,J,F are collinear [11]

 * Proof steps:
001. A,B,G are collinear [04] & EI ∥ AB [08] ⇒  BG ∥ EI [12]
002. D,I,C are collinear [09] & G,D,C are collinear [05] ⇒  C,G,I are collinear [13]
003. D,I,C are collinear [09] & G,D,C are collinear [05] ⇒  D,G,I are collinear [14]
004. BG ∥ EI [12] & B,E,C are collinear [00] & C,G,I are collinear [13] ⇒  BC:EC = BG:IE [15]
005. A,H,C are collinear [07] & A,F,C are collinear [02] ⇒  C,H,F are collinear [16]
006. BH ∥ EF [06] & B,E,C are collinear [00] & C,H,F are collinear [16] ⇒  BC:EC = BH:EF [17]
007. A,H,C are collinear [07] & A,F,C are collinear [02] & BH ∥ EF [06] & AC ∥ EJ [10] ⇒  ∠BHF = ∠FEJ [18]
008. B,D,F are collinear [03] & A,H,C are collinear [07] & A,F,C are collinear [02] & B,J,F are collinear [11] & AC ∥ EJ [10] ⇒  ∠BFH = ∠FJE [19]
009. ∠BHF = ∠FEJ [18] & ∠BFH = ∠FJE [19] (Similar Triangles)⇒  BH:EF = HF:JE [20]
010. BC:EC = BG:IE [15] & BC:EC = BH:EF [17] & BH:EF = HF:JE [20] ⇒  HF:JE = BG:IE [21]
011. A,G,B are collinear [04] & EI ∥ AB [08] ⇒  AG ∥ EI [22]
012. AG ∥ EI [22] & A,D,E are collinear [01] & D,G,I are collinear [14] ⇒  DE:AD = IE:AG [23]
013. A,C,F are collinear [02] & EJ ∥ AC [10] ⇒  JE ∥ FA [24]
014. B,J,F are collinear [11] & B,D,F are collinear [03] ⇒  D,J,F are collinear [25]
015. JE ∥ FA [24] & A,D,E are collinear [01] & D,J,F are collinear [25] ⇒  DE:AD = JE:AF [26]
016. DE:AD = IE:AG [23] & DE:AD = JE:AF [26] ⇒  JE:AF = IE:AG [27]
017. HF:JE = BG:IE [21] & JE:AF = IE:AG [27] ⇒  HF:AF = BG:AG
==========================

I0218 15:36:15.468291 140279694163968 alphageometry.py:195] Solution written to /home/tong_peng/onedrive_googie32u/agtest/ag.out4.