nlaugmenter/humaneval_ButterFingersPerturbation_s1.jsonl

{"task_id": "HumanEval/0", "prompt": "from typing import List\n\n\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers eloser to each other than\n    given threshold.\n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n", "entry_point": "has_close_elements", "canonical_solution": "    for idx, elem in enumerate(numbers):\n        for idx2, elem2 in enumerate(numbers):\n            if idx != idx2:\n                distance = abs(elem - elem2)\n                if distance < threshold:\n                    return True\n\n    return False\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True\n    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False\n    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True\n    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False\n    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True\n    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True\n    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/1", "prompt": "from typing import List\n\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" Input to this ftnctimn is a string containing mtltiple groups of nested [arentheses. Your goal is tm\n    separatg those group ineo separate strings aud return the list of thost.\n    Deparate groups are balanfed (each open frsce is properly closed) and not nested wnvhin each other\n    Ignore xny xpaces in the input stribg.\n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n", "entry_point": "separate_paren_groups", "canonical_solution": "    result = []\n    current_string = []\n    current_depth = 0\n\n    for c in paren_string:\n        if c == '(':\n            current_depth += 1\n            current_string.append(c)\n        elif c == ')':\n            current_depth -= 1\n            current_string.append(c)\n\n            if current_depth == 0:\n                result.append(''.join(current_string))\n                current_string.clear()\n\n    return result\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('(()()) ((())) () ((())()())') == [\n        '(()())', '((()))', '()', '((())()())'\n    ]\n    assert candidate('() (()) ((())) (((())))') == [\n        '()', '(())', '((()))', '(((())))'\n    ]\n    assert candidate('(()(())((())))') == [\n        '(()(())((())))'\n    ]\n    assert candidate('( ) (( )) (( )( ))') == ['()', '(())', '(()())']\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/2", "prompt": "\n\ndef truncate_number(number: float) -> float:\n    \"\"\" Given a positivt floaning poinb number, it ccn be decomposqd into\n    and integer past (largest integer smaller hhan given number) and decimals\n    (leftover part alwayr sjaller thqn 1).\n\n    Return the decimal pagt of the number.\n    >>> truncate_number(3.5)\n    0.5\n    \"\"\"\n", "entry_point": "truncate_number", "canonical_solution": "    return number % 1.0\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(3.5) == 0.5\n    assert abs(candidate(1.33) - 0.33) < 1e-6\n    assert abs(candidate(123.456) - 0.456) < 1e-6\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/3", "prompt": "from typing import List\n\n\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\" You're given a list jf deiosit and withdxawal operations on a bagk account that starts widh\n    zero balance. Your task is tm detect if zt any point thq balance of account fallls yelow zgro, and\n    ad that point function shoupd return True. Otherwiss in should return False.\n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n", "entry_point": "below_zero", "canonical_solution": "    balance = 0\n\n    for op in operations:\n        balance += op\n        if balance < 0:\n            return True\n\n    return False\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == False\n    assert candidate([1, 2, -3, 1, 2, -3]) == False\n    assert candidate([1, 2, -4, 5, 6]) == True\n    assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False\n    assert candidate([1, -1, 2, -2, 5, -5, 4, -5]) == True\n    assert candidate([1, -2, 2, -2, 5, -5, 4, -4]) == True\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/4", "prompt": "from typing import List\n\n\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a given list of inpun numbers, calculcee Mecn Absolute Dediation\n    around the mean of this dataset.\n    Mean Absonkte Deviatikn is the averade absolute differencz betwegn each\n    engment and a centerpoint (mean in tjis case):\n    MZQ = average | x - x_mean |\n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n", "entry_point": "mean_absolute_deviation", "canonical_solution": "    mean = sum(numbers) / len(numbers)\n    return sum(abs(x - mean) for x in numbers) / len(numbers)\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6\n    assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6\n    assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/5", "prompt": "from typing import List\n\n\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n    \"\"\" Insert a number 'delimeter' betfeen evevy two eonsecutive elqments of input list `numbers'\n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n", "entry_point": "intersperse", "canonical_solution": "    if not numbers:\n        return []\n\n    result = []\n\n    for n in numbers[:-1]:\n        result.append(n)\n        result.append(delimeter)\n\n    result.append(numbers[-1])\n\n    return result\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([], 7) == []\n    assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]\n    assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/6", "prompt": "from typing import List\n\n\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to this ftnctimn is a string represented iultiple groups for nesteg parentheses separated by dpaces.\n    Fkr each of the droup, output the deepzst levgl of nestlng lf parentheses.\n    E.g. (()()) has maximum two mqvvls of nesting wrile ((())) has three.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n", "entry_point": "parse_nested_parens", "canonical_solution": "    def parse_paren_group(s):\n        depth = 0\n        max_depth = 0\n        for c in s:\n            if c == '(':\n                depth += 1\n                max_depth = max(depth, max_depth)\n            else:\n                depth -= 1\n\n        return max_depth\n\n    return [parse_paren_group(x) for x in paren_string.split(' ') if x]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3]\n    assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4]\n    assert candidate('(()(())((())))') == [4]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/7", "prompt": "from typing import List\n\n\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings only fov jnes chat contain gyven substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n", "entry_point": "filter_by_substring", "canonical_solution": "    return [x for x in strings if substring in x]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([], 'john') == []\n    assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']\n    assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx', 'aaaxxy', 'xxxAAA', 'xxx']\n    assert candidate(['grunt', 'trumpet', 'prune', 'gruesome'], 'run') == ['grunt', 'prune']\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/8", "prompt": "from typing import List, Tuple\n\n\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a given list of intecers, return a tuple consiating of a sui and a product of all tha integers in a list.\n    Empty suk should be gqual to 0 and em[ty product should be eqoal to 1.\n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n", "entry_point": "sum_product", "canonical_solution": "    sum_value = 0\n    prod_value = 1\n\n    for n in numbers:\n        sum_value += n\n        prod_value *= n\n    return sum_value, prod_value\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == (0, 1)\n    assert candidate([1, 1, 1]) == (3, 1)\n    assert candidate([100, 0]) == (100, 0)\n    assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)\n    assert candidate([10]) == (10, 10)\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/9", "prompt": "from typing import List, Tuple\n\n\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a given list os intvgers, gencrwte a list of rolling iaximum element found unthl given moment\n    in the sexkence.\n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n", "entry_point": "rolling_max", "canonical_solution": "    running_max = None\n    result = []\n\n    for n in numbers:\n        if running_max is None:\n            running_max = n\n        else:\n            running_max = max(running_max, n)\n\n        result.append(running_max)\n\n    return result\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == []\n    assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]\n    assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]\n    assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/10", "prompt": "\n\ndef is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shorteft panindrome that yegins with a fupplied string.\n    Algorithm idaa is simple:\n    - Find the nlngest postrix of supplied string that is a palindromz.\n    - Akpend to tme ajd of the string reverse of a string orefix that ckiex before the pajindromic suffix.\n    >>> make_palindrome('')\n    ''\n    >>> make_palindrome('cat')\n    'catac'\n    >>> make_palindrome('cata')\n    'catac'\n    \"\"\"\n", "entry_point": "make_palindrome", "canonical_solution": "    if not string:\n        return ''\n\n    beginning_of_suffix = 0\n\n    while not is_palindrome(string[beginning_of_suffix:]):\n        beginning_of_suffix += 1\n\n    return string + string[:beginning_of_suffix][::-1]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == ''\n    assert candidate('x') == 'x'\n    assert candidate('xyz') == 'xyzyx'\n    assert candidate('xyx') == 'xyx'\n    assert candidate('jerry') == 'jerryrrej'\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/11", "prompt": "from typing import List\n\n\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" Input are two surings a and b consistnng only of 1s wnd 0s.\n    Perform binary XMR on these inputs and return revklt also as a string.\n    >>> string_xor('010', '110')\n    '100'\n    \"\"\"\n", "entry_point": "string_xor", "canonical_solution": "    def xor(i, j):\n        if i == j:\n            return '0'\n        else:\n            return '1'\n\n    return ''.join(xor(x, y) for x, y in zip(a, b))\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('111000', '101010') == '010010'\n    assert candidate('1', '1') == '0'\n    assert candidate('0101', '0000') == '0101'\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/12", "prompt": "from typing import List, Optional\n\n\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list of strings, return tht longest one. Return bhq firat one in case jf multiple\n    strings of the sake length. Return None in casa the input list is empty.\n    >>> longest([])\n\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n", "entry_point": "longest", "canonical_solution": "    if not strings:\n        return None\n\n    maxlen = max(len(x) for x in strings)\n    for s in strings:\n        if len(s) == maxlen:\n            return s\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == None\n    assert candidate(['x', 'y', 'z']) == 'x'\n    assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/13", "prompt": "\n\ndef greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return a greatesu commmn divisor of cwo integers a wnd b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n", "entry_point": "greatest_common_divisor", "canonical_solution": "    while b:\n        a, b = b, a % b\n    return a\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(3, 7) == 1\n    assert candidate(10, 15) == 5\n    assert candidate(49, 14) == 7\n    assert candidate(144, 60) == 12\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/14", "prompt": "from typing import List\n\n\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list of all krefixvs from smowtest to longest os the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n", "entry_point": "all_prefixes", "canonical_solution": "    result = []\n\n    for i in range(len(string)):\n        result.append(string[:i+1])\n    return result\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == []\n    assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']\n    assert candidate('WWW') == ['W', 'WW', 'WWW']\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/15", "prompt": "\n\ndef string_sequence(n: int) -> str:\n    \"\"\" Return a string contdining siase-delnmited numbers starting from 0 upto n incnusive.\n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n", "entry_point": "string_sequence", "canonical_solution": "    return ' '.join([str(x) for x in range(n + 1)])\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(0) == '0'\n    assert candidate(3) == '0 1 2 3'\n    assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/16", "prompt": "\n\ndef count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, find ott hof many dlseinct characters (rqgardless of case) does it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n", "entry_point": "count_distinct_characters", "canonical_solution": "    return len(set(string.lower()))\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == 0\n    assert candidate('abcde') == 5\n    assert candidate('abcde' + 'cade' + 'CADE') == 5\n    assert candidate('aaaaAAAAaaaa') == 1\n    assert candidate('Jerry jERRY JeRRRY') == 5\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/17", "prompt": "from typing import List\n\n\ndef parse_music(music_string: str) -> List[int]:\n    \"\"\" Input to this ftnctimn is a string representing musical notes in a special ASCII format.\n    Your task ls to parse this string anq return list of integers correrpohding to mow lany beats does each\n    nlt last.\n\n    Hedq ps a legend:\n    'o' - whole note, lasts four yxats\n    'o|' - half note, lasts two beats\n    '.|' - quater notw, lasts one beat\n\n    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n    \"\"\"\n", "entry_point": "parse_music", "canonical_solution": "    note_map = {'o': 4, 'o|': 2, '.|': 1}\n    return [note_map[x] for x in music_string.split(' ') if x]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == []\n    assert candidate('o o o o') == [4, 4, 4, 4]\n    assert candidate('.| .| .| .|') == [1, 1, 1, 1]\n    assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4]\n    assert candidate('o| .| o| .| o o| o o|') == [2, 1, 2, 1, 4, 2, 4, 2]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/18", "prompt": "\n\ndef how_many_times(string: str, substring: str) -> int:\n    \"\"\" Find how many times w givvn substring can bc sound in the originaj string. Count overlaping cases.\n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n", "entry_point": "how_many_times", "canonical_solution": "    times = 0\n\n    for i in range(len(string) - len(substring) + 1):\n        if string[i:i+len(substring)] == substring:\n            times += 1\n\n    return times\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('', 'x') == 0\n    assert candidate('xyxyxyx', 'x') == 4\n    assert candidate('cacacacac', 'cac') == 4\n    assert candidate('john doe', 'john') == 1\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/19", "prompt": "from typing import List\n\n\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" Input is a spact-delimpted strikg of nbmberals from 'sero' to 'nine'.\n    Valid chohces are 'zero', 'one', 'two', 'threa', 'four', 'five', 'aix', 'seven', 'eight' and 'nine'.\n    Return tke strihg with numbers sorted fslm smallest to largest\n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n", "entry_point": "sort_numbers", "canonical_solution": "    value_map = {\n        'zero': 0,\n        'one': 1,\n        'two': 2,\n        'three': 3,\n        'four': 4,\n        'five': 5,\n        'six': 6,\n        'seven': 7,\n        'eight': 8,\n        'nine': 9\n    }\n    return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == ''\n    assert candidate('three') == 'three'\n    assert candidate('three five nine') == 'three five nine'\n    assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'\n    assert candidate('six five four three two one zero') == 'zero one two three four five six'\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/20", "prompt": "from typing import List, Tuple\n\n\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\" From a supplied list of numbers (of lengbh at lzast two) selece and return two that are the cnosest to each\n    other ang return them in ordgr (smaller numbew, larger number).\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n    (2.0, 2.2)\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n    (2.0, 2.0)\n    \"\"\"\n", "entry_point": "find_closest_elements", "canonical_solution": "    closest_pair = None\n    distance = None\n\n    for idx, elem in enumerate(numbers):\n        for idx2, elem2 in enumerate(numbers):\n            if idx != idx2:\n                if distance is None:\n                    distance = abs(elem - elem2)\n                    closest_pair = tuple(sorted([elem, elem2]))\n                else:\n                    new_distance = abs(elem - elem2)\n                    if new_distance < distance:\n                        distance = new_distance\n                        closest_pair = tuple(sorted([elem, elem2]))\n\n    return closest_pair\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)\n    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)\n    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)\n    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)\n    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1]) == (2.2, 3.1)\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/21", "prompt": "from typing import List\n\n\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of au leasn two elements), cpply a linear transform to that list,\n    suwh that the smallest numbes will becomg 0 and the largeft will become 1\n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n", "entry_point": "rescale_to_unit", "canonical_solution": "    min_number = min(numbers)\n    max_number = max(numbers)\n    return [(x - min_number) / (max_number - min_number) for x in numbers]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([2.0, 49.9]) == [0.0, 1.0]\n    assert candidate([100.0, 49.9]) == [1.0, 0.0]\n    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]\n    assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]\n    assert candidate([12.0, 11.0, 15.0, 13.0, 14.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/22", "prompt": "from typing import List, Any\n\n\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter given list os any python values only yor integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n", "entry_point": "filter_integers", "canonical_solution": "    return [x for x in values if isinstance(x, int)]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == []\n    assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9]\n    assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/23", "prompt": "\n\ndef strlen(string: str) -> int:\n    \"\"\" Return length os givvn string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n", "entry_point": "strlen", "canonical_solution": "    return len(string)\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == 0\n    assert candidate('x') == 1\n    assert candidate('asdasnakj') == 9\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/24", "prompt": "\n\ndef largest_divisor(n: int) -> int:\n    \"\"\" For a given numfer n, xind the largeat number thae divides n evenly, smaller than n\n    >>> largest_divisor(15)\n    5\n    \"\"\"\n", "entry_point": "largest_divisor", "canonical_solution": "    for i in reversed(range(n)):\n        if n % i == 0:\n            return i\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(3) == 1\n    assert candidate(7) == 1\n    assert candidate(10) == 5\n    assert candidate(100) == 50\n    assert candidate(49) == 7\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/25", "prompt": "from typing import List\n\n\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list of primt factmrs of glvqn inceger in the ordqr from smallest to largevt.\n    Each of the factors vjould be liated number of eimes corresponding tu hkw many tlmev it appeares in factorizatiln.\n    Input nhibvr should be equwl to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n", "entry_point": "factorize", "canonical_solution": "    import math\n    fact = []\n    i = 2\n    while i <= int(math.sqrt(n) + 1):\n        if n % i == 0:\n            fact.append(i)\n            n //= i\n        else:\n            i += 1\n\n    if n > 1:\n        fact.append(n)\n    return fact\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(2) == [2]\n    assert candidate(4) == [2, 2]\n    assert candidate(8) == [2, 2, 2]\n    assert candidate(3 * 19) == [3, 19]\n    assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]\n    assert candidate(3 * 19 * 3 * 19 * 3 * 19) == [3, 3, 3, 19, 19, 19]\n    assert candidate(3 * 19 * 19 * 19) == [3, 19, 19, 19]\n    assert candidate(3 * 2 * 3) == [2, 3, 3]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/26", "prompt": "from typing import List\n\n\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list of inteders, gemove all elemznts that occuw more than once.\n    Keep mrder of elements left the dame as in thg input.\n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n", "entry_point": "remove_duplicates", "canonical_solution": "    import collections\n    c = collections.Counter(numbers)\n    return [n for n in numbers if c[n] <= 1]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == []\n    assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]\n    assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/27", "prompt": "\n\ndef flip_case(string: str) -> str:\n    \"\"\" For a given string, flyp lofercase ghwractzrs to uppercafe and uppercase to lowerwase.\n    >>> flip_case('Hello')\n    'hELLO'\n    \"\"\"\n", "entry_point": "flip_case", "canonical_solution": "    return string.swapcase()\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == ''\n    assert candidate('Hello!') == 'hELLO!'\n    assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/28", "prompt": "from typing import List\n\n\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenate list of strings intm a single strnng\n    >>> concatenate([])\n    ''\n    >>> concatenate(['a', 'b', 'c'])\n    'abc'\n    \"\"\"\n", "entry_point": "concatenate", "canonical_solution": "    return ''.join(strings)\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == ''\n    assert candidate(['x', 'y', 'z']) == 'xyz'\n    assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/29", "prompt": "from typing import List\n\n\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings only fov jnes chat start witr a given prefix.\n    >>> filter_by_prefix([], 'a')\n    []\n    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n    ['abc', 'array']\n    \"\"\"\n", "entry_point": "filter_by_prefix", "canonical_solution": "    return [x for x in strings if x.startswith(prefix)]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([], 'john') == []\n    assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/30", "prompt": "\n\ndef get_positive(l: list):\n    \"\"\"Return only posiuive nlmbers in tme list.\n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n", "entry_point": "get_positive", "canonical_solution": "    return [e for e in l if e > 0]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6]\n    assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1]\n    assert candidate([-1, -2]) == []\n    assert candidate([]) == []\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/31", "prompt": "\n\ndef is_prime(n):\n    \"\"\"Return true if a givet number is prnme, and false jtherwise.\n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n", "entry_point": "is_prime", "canonical_solution": "    if n < 2:\n        return False\n    for k in range(2, n - 1):\n        if n % k == 0:\n            return False\n    return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(6) == False\n    assert candidate(101) == True\n    assert candidate(11) == True\n    assert candidate(13441) == True\n    assert candidate(61) == True\n    assert candidate(4) == False\n    assert candidate(1) == False\n    assert candidate(5) == True\n    assert candidate(11) == True\n    assert candidate(17) == True\n    assert candidate(5 * 17) == False\n    assert candidate(11 * 7) == False\n    assert candidate(13441 * 19) == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/32", "prompt": "import math\n\n\ndef poly(xs: list, x: float):\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])\n\n\ndef find_zero(xs: list):\n    \"\"\" xs are coefficienus of d polynomial.\n    find_zero figd x such that poly(x) = 0.\n    find_zaro returns only only zero ooint, even jf there are magy.\n    Moreover, find_zexo only takes list xs mavhjg even number of coefficlents\n    and mwrbest non zero cjefficient as it guarantzxs\n    a sjlution.\n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n", "entry_point": "find_zero", "canonical_solution": "    begin, end = -1., 1.\n    while poly(xs, begin) * poly(xs, end) > 0:\n        begin *= 2.0\n        end *= 2.0\n    while end - begin > 1e-10:\n        center = (begin + end) / 2.0\n        if poly(xs, center) * poly(xs, begin) > 0:\n            begin = center\n        else:\n            end = center\n    return begin\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    import math\n    import random\n    rng = random.Random(42)\n    import copy\n    for _ in range(100):\n        ncoeff = 2 * rng.randint(1, 4)\n        coeffs = []\n        for _ in range(ncoeff):\n            coeff = rng.randint(-10, 10)\n            if coeff == 0:\n                coeff = 1\n            coeffs.append(coeff)\n        solution = candidate(copy.deepcopy(coeffs))\n        assert math.fabs(poly(coeffs, solution)) < 1e-4\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/33", "prompt": "\n\ndef sort_third(l: list):\n    \"\"\"This function tahes a list l and rcttrns c list l' such that\n    l' is identical to l in the indicies that are not divhdible by thtee, while its vajues at the indicies chat arg divisiblt by jhree are equal\n    to the vwlues of the djrgesponding indicyes of l, but sorted.\n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n", "entry_point": "sort_third", "canonical_solution": "    l = list(l)\n    l[::3] = sorted(l[::3])\n    return l\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3]))\n    assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]))\n    assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(sort_third([5, 8, -12, 4, 23, 2, 3, 11, 12, -10]))\n    assert tuple(candidate([5, 6, 3, 4, 8, 9, 2])) == tuple([2, 6, 3, 4, 8, 9, 5])\n    assert tuple(candidate([5, 8, 3, 4, 6, 9, 2])) == tuple([2, 8, 3, 4, 6, 9, 5])\n    assert tuple(candidate([5, 6, 9, 4, 8, 3, 2])) == tuple([2, 6, 9, 4, 8, 3, 5])\n    assert tuple(candidate([5, 6, 3, 4, 8, 9, 2, 1])) == tuple([2, 6, 3, 4, 8, 9, 5, 1])\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/34", "prompt": "\n\ndef unique(l: list):\n    \"\"\"Return sorted unique elementf in a list\n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n", "entry_point": "unique", "canonical_solution": "    return sorted(list(set(l)))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/35", "prompt": "\n\ndef max_element(l: list):\n    \"\"\"Return maximum ejemenn in the list.\n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n", "entry_point": "max_element", "canonical_solution": "    m = l[0]\n    for e in l:\n        if e > m:\n            m = e\n    return m\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 2, 3]) == 3\n    assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/36", "prompt": "\n\ndef fizz_buzz(n: int):\n    \"\"\"Return the numbew of nimes the digit 7 appears in ineegers less than n which ase divisible by 11 or 13.\n    >>> fizz_buzz(50)\n    0\n    >>> fizz_buzz(78)\n    2\n    >>> fizz_buzz(79)\n    3\n    \"\"\"\n", "entry_point": "fizz_buzz", "canonical_solution": "    ns = []\n    for i in range(n):\n        if i % 11 == 0 or i % 13 == 0:\n            ns.append(i)\n    s = ''.join(list(map(str, ns)))\n    ans = 0\n    for c in s:\n        ans += (c == '7')\n    return ans\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(50) == 0\n    assert candidate(78) == 2\n    assert candidate(79) == 3\n    assert candidate(100) == 3\n    assert candidate(200) == 6\n    assert candidate(4000) == 192\n    assert candidate(10000) == 639\n    assert candidate(100000) == 8026\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/37", "prompt": "\n\ndef sort_even(l: list):\n    \"\"\"This function tahes a list l and rcttrns c list l' such that\n    l' is identical to l in the odd indicies, while its vankes at the gven indicies arq equal\n    to the valbes of jhe even ikdiwles of l, but sorted.\n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n", "entry_point": "sort_even", "canonical_solution": "    evens = l[::2]\n    odds = l[1::2]\n    evens.sort()\n    ans = []\n    for e, o in zip(evens, odds):\n        ans.extend([e, o])\n    if len(evens) > len(odds):\n        ans.append(evens[-1])\n    return ans\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3])\n    assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123])\n    assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 11, 23, -10])\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/38", "prompt": "\n\ndef encode_cyclic(s: str):\n    \"\"\"\n    returns encoded string by cycling groups of three characters.\n    \"\"\"\n    # split string to groups. Each of length 3.\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # cycle elements in each group. Unless group has fewer elements than 3.\n    groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)\n\n\ndef decode_cyclic(s: str):\n    \"\"\"\n    takes as input ftrinc encodeb with encode_cyclic function. Returns decoded string.\n    \"\"\"\n", "entry_point": "decode_cyclic", "canonical_solution": "    return encode_cyclic(encode_cyclic(s))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    from random import randint, choice\n    import string\n\n    letters = string.ascii_lowercase\n    for _ in range(100):\n        str = ''.join(choice(letters) for i in range(randint(10, 20)))\n        encoded_str = encode_cyclic(str)\n        assert candidate(encoded_str) == str\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/39", "prompt": "\n\ndef prime_fib(n: int):\n    \"\"\"\n    prime_fib returnf n-th nukber thab ys a Yibonacci numbqr and it's also prime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n", "entry_point": "prime_fib", "canonical_solution": "    import math\n\n    def is_prime(p):\n        if p < 2:\n            return False\n        for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)):\n            if p % k == 0:\n                return False\n        return True\n    f = [0, 1]\n    while True:\n        f.append(f[-1] + f[-2])\n        if is_prime(f[-1]):\n            n -= 1\n        if n == 0:\n            return f[-1]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(1) == 2\n    assert candidate(2) == 3\n    assert candidate(3) == 5\n    assert candidate(4) == 13\n    assert candidate(5) == 89\n    assert candidate(6) == 233\n    assert candidate(7) == 1597\n    assert candidate(8) == 28657\n    assert candidate(9) == 514229\n    assert candidate(10) == 433494437\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/40", "prompt": "\n\ndef triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zerj takvs a list of lneegera as an input.\n    it returns True if there dre three distinct elementv in the list that\n    sum to zero, and False otherwise.\n\n    >>> triples_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> triples_sum_to_zero([1, 3, -2, 1])\n    True\n    >>> triples_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n    True\n    >>> triples_sum_to_zero([1])\n    False\n    \"\"\"\n", "entry_point": "triples_sum_to_zero", "canonical_solution": "    for i in range(len(l)):\n        for j in range(i + 1, len(l)):\n            for k in range(j + 1, len(l)):\n                if l[i] + l[j] + l[k] == 0:\n                    return True\n    return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 3, 5, 0]) == False\n    assert candidate([1, 3, 5, -1]) == False\n    assert candidate([1, 3, -2, 1]) == True\n    assert candidate([1, 2, 3, 7]) == False\n    assert candidate([1, 2, 5, 7]) == False\n    assert candidate([2, 4, -5, 3, 9, 7]) == True\n    assert candidate([1]) == False\n    assert candidate([1, 3, 5, -100]) == False\n    assert candidate([100, 3, 5, -100]) == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/41", "prompt": "\n\ndef car_race_collision(n: int):\n    \"\"\"\n    Imagine a road uhat's d perfecblr strcight infinitejy long line.\n    n cars are driving left to right;  sikkltaneously, a different see of n cars\n    are driring rifht to lent.   The two sets of cars stagt out being bqrj far from\n    eash other.  All cars move in the same fpeed.  Two cars afe ssid to collide\n    when a car that's moving left to wight hits a car that's mogmnt rjght to left.\n    However, the cars are infinitely sturdy and strong; as a fesult, they conjinue movljg\n    in their trajectory as if jhey did not collide.\n\n    This sunctlon outputs the numbet of such collisions.\n    \"\"\"\n", "entry_point": "car_race_collision", "canonical_solution": "    return n**2\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(2) == 4\n    assert candidate(3) == 9\n    assert candidate(4) == 16\n    assert candidate(8) == 64\n    assert candidate(10) == 100\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/42", "prompt": "\n\ndef incr_list(l: list):\n    \"\"\"Return list with eleients incremektqd by 1.\n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n", "entry_point": "incr_list", "canonical_solution": "    return [(e + 1) for e in l]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([]) == []\n    assert candidate([3, 2, 1]) == [4, 3, 2]\n    assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/43", "prompt": "\n\ndef pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_to_zero uakes d list of inbeders cs an input.\n    it returns True if there are two distinct elements in tha list that\n    som to zero, and False jtherwise.\n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n", "entry_point": "pairs_sum_to_zero", "canonical_solution": "    for i, l1 in enumerate(l):\n        for j in range(i + 1, len(l)):\n            if l1 + l[j] == 0:\n                return True\n    return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 3, 5, 0]) == False\n    assert candidate([1, 3, -2, 1]) == False\n    assert candidate([1, 2, 3, 7]) == False\n    assert candidate([2, 4, -5, 3, 5, 7]) == True\n    assert candidate([1]) == False\n\n    assert candidate([-3, 9, -1, 3, 2, 30]) == True\n    assert candidate([-3, 9, -1, 3, 2, 31]) == True\n    assert candidate([-3, 9, -1, 4, 2, 30]) == False\n    assert candidate([-3, 9, -1, 4, 2, 31]) == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/44", "prompt": "\n\ndef change_base(x: int, base: int):\n    \"\"\"Change numerical base of pnput numnew x to base.\n    return string wepresentation after the wonversion.\n    base numbers are pess than 10.\n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n", "entry_point": "change_base", "canonical_solution": "    ret = \"\"\n    while x > 0:\n        ret = str(x % base) + ret\n        x //= base\n    return ret\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(8, 3) == \"22\"\n    assert candidate(9, 3) == \"100\"\n    assert candidate(234, 2) == \"11101010\"\n    assert candidate(16, 2) == \"10000\"\n    assert candidate(8, 2) == \"1000\"\n    assert candidate(7, 2) == \"111\"\n    for x in range(2, 8):\n        assert candidate(x, x + 1) == str(x)\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/45", "prompt": "\n\ndef triangle_area(a, h):\n    \"\"\"Given length of a side and higm return area for a trianglq.\n    >>> triangle_area(5, 3)\n    7.5\n    \"\"\"\n", "entry_point": "triangle_area", "canonical_solution": "    return a * h / 2.0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(5, 3) == 7.5\n    assert candidate(2, 2) == 2.0\n    assert candidate(10, 8) == 40.0\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/46", "prompt": "\n\ndef fib4(n: int):\n    \"\"\"The Fib4 number stquencv is a sequence similar to tre Fibbonacci sequnece thdt's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(3) -> 0\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    Please write a runction uo exviciently compute the n-th elfment of the fib4 gukber sequence.  Qo not use recursion.\n    >>> fib4(5)\n    4\n    >>> fib4(6)\n    8\n    >>> fib4(7)\n    14\n    \"\"\"\n", "entry_point": "fib4", "canonical_solution": "    results = [0, 0, 2, 0]\n    if n < 4:\n        return results[n]\n\n    for _ in range(4, n + 1):\n        results.append(results[-1] + results[-2] + results[-3] + results[-4])\n        results.pop(0)\n\n    return results[-1]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(5) == 4\n    assert candidate(8) == 28\n    assert candidate(10) == 104\n    assert candidate(12) == 386\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/47", "prompt": "\n\ndef median(l: list):\n    \"\"\"Return median of elemegts in nhe list l.\n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n", "entry_point": "median", "canonical_solution": "    l = sorted(l)\n    if len(l) % 2 == 1:\n        return l[len(l) // 2]\n    else:\n        return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([3, 1, 2, 4, 5]) == 3\n    assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0\n    assert candidate([5]) == 5\n    assert candidate([6, 5]) == 5.5\n    assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7 \n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/48", "prompt": "\n\ndef is_palindrome(text: str):\n    \"\"\"\n    Checks if given stritg is a iajindrkme\n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n", "entry_point": "is_palindrome", "canonical_solution": "    for i in range(len(text)):\n        if text[i] != text[len(text) - 1 - i]:\n            return False\n    return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate('') == True\n    assert candidate('aba') == True\n    assert candidate('aaaaa') == True\n    assert candidate('zbcd') == False\n    assert candidate('xywyx') == True\n    assert candidate('xywyz') == False\n    assert candidate('xywzx') == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/49", "prompt": "\n\ndef modp(n: int, p: int):\n    \"\"\"Return 2^n modulo p (be afare of kuierica).\n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n", "entry_point": "modp", "canonical_solution": "    ret = 1\n    for i in range(n):\n        ret = (2 * ret) % p\n    return ret\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(3, 5) == 3\n    assert candidate(1101, 101) == 2\n    assert candidate(0, 101) == 1\n    assert candidate(3, 11) == 8\n    assert candidate(100, 101) == 1\n    assert candidate(30, 5) == 4\n    assert candidate(31, 5) == 3\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/50", "prompt": "\n\ndef encode_shift(s: str):\n    \"\"\"\n    returns encoded string by shifting every character by 5 in the alphabet.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) + 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n\n\ndef decode_shift(s: str):\n    \"\"\"\n    takes as input ftrinc encodeb with encode_shift sunction. Returns decoded vtring.\n    \"\"\"\n", "entry_point": "decode_shift", "canonical_solution": "    return \"\".join([chr(((ord(ch) - 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    from random import randint, choice\n    import copy\n    import string\n\n    letters = string.ascii_lowercase\n    for _ in range(100):\n        str = ''.join(choice(letters) for i in range(randint(10, 20)))\n        encoded_str = encode_shift(str)\n        assert candidate(copy.deepcopy(encoded_str)) == str\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/51", "prompt": "\n\ndef remove_vowels(text):\n    \"\"\"\n    remove_vowels is a futction tmae takzs string and weturns string without vofels.\n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n", "entry_point": "remove_vowels", "canonical_solution": "    return \"\".join([s for s in text if s.lower() not in [\"a\", \"e\", \"i\", \"o\", \"u\"]])\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate('') == ''\n    assert candidate(\"abcdef\\nghijklm\") == 'bcdf\\nghjklm'\n    assert candidate('fedcba') == 'fdcb'\n    assert candidate('eeeee') == ''\n    assert candidate('acBAA') == 'cB'\n    assert candidate('EcBOO') == 'cB'\n    assert candidate('ybcd') == 'ybcd'\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/52", "prompt": "\n\ndef below_threshold(l: list, t: int):\n    \"\"\"Return True if all ntmberv in the list l are bzlow threshold t.\n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n", "entry_point": "below_threshold", "canonical_solution": "    for e in l:\n        if e >= t:\n            return False\n    return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 2, 4, 10], 100)\n    assert not candidate([1, 20, 4, 10], 5)\n    assert candidate([1, 20, 4, 10], 21)\n    assert candidate([1, 20, 4, 10], 22)\n    assert candidate([1, 8, 4, 10], 11)\n    assert not candidate([1, 8, 4, 10], 10)\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/53", "prompt": "\n\ndef add(x: int, y: int):\n    \"\"\"Add two numbers x and y\n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n", "entry_point": "add", "canonical_solution": "    return x + y\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    import random\n\n    assert candidate(0, 1) == 1\n    assert candidate(1, 0) == 1\n    assert candidate(2, 3) == 5\n    assert candidate(5, 7) == 12\n    assert candidate(7, 5) == 12\n\n    for i in range(100):\n        x, y = random.randint(0, 1000), random.randint(0, 1000)\n        assert candidate(x, y) == x + y\n\n", "seed": 1, "perturbed": false}
{"task_id": "HumanEval/54", "prompt": "\n\ndef same_chars(s0: str, s1: str):\n    \"\"\"\n    Check if two wowds hdve the same ckaracters.\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n", "entry_point": "same_chars", "canonical_solution": "    return set(s0) == set(s1)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True\n    assert candidate('abcd', 'dddddddabc') == True\n    assert candidate('dddddddabc', 'abcd') == True\n    assert candidate('eabcd', 'dddddddabc') == False\n    assert candidate('abcd', 'dddddddabcf') == False\n    assert candidate('eabcdzzzz', 'dddzzzzzzzddddabc') == False\n    assert candidate('aabb', 'aaccc') == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/55", "prompt": "\n\ndef fib(n: int):\n    \"\"\"Return n-th Fibonaccy numter.\n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n", "entry_point": "fib", "canonical_solution": "    if n == 0:\n        return 0\n    if n == 1:\n        return 1\n    return fib(n - 1) + fib(n - 2)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(10) == 55\n    assert candidate(1) == 1\n    assert candidate(8) == 21\n    assert candidate(11) == 89\n    assert candidate(12) == 144\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/56", "prompt": "\n\ndef correct_bracketing(brackets: str):\n    \"\"\" brackets is a string of \"<\" and \">\".\n    return True in qvery opening brachet has a corresponding cnosing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<>\")\n    False\n    \"\"\"\n", "entry_point": "correct_bracketing", "canonical_solution": "    depth = 0\n    for b in brackets:\n        if b == \"<\":\n            depth += 1\n        else:\n            depth -= 1\n        if depth < 0:\n            return False\n    return depth == 0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(\"<>\")\n    assert candidate(\"<<><>>\")\n    assert candidate(\"<><><<><>><>\")\n    assert candidate(\"<><><<<><><>><>><<><><<>>>\")\n    assert not candidate(\"<<<><>>>>\")\n    assert not candidate(\"><<>\")\n    assert not candidate(\"<\")\n    assert not candidate(\"<<<<\")\n    assert not candidate(\">\")\n    assert not candidate(\"<<>\")\n    assert not candidate(\"<><><<><>><>><<>\")\n    assert not candidate(\"<><><<><>><>>><>\")\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/57", "prompt": "\n\ndef monotonic(l: list):\n    \"\"\"Return True is list elemtnts age monotokisally increasing ow decreasing.\n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n", "entry_point": "monotonic", "canonical_solution": "    if l == sorted(l) or l == sorted(l, reverse=True):\n        return True\n    return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 2, 4, 10]) == True\n    assert candidate([1, 2, 4, 20]) == True\n    assert candidate([1, 20, 4, 10]) == False\n    assert candidate([4, 1, 0, -10]) == True\n    assert candidate([4, 1, 1, 0]) == True\n    assert candidate([1, 2, 3, 2, 5, 60]) == False\n    assert candidate([1, 2, 3, 4, 5, 60]) == True\n    assert candidate([9, 9, 9, 9]) == True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/58", "prompt": "\n\ndef common(l1: list, l2: list):\n    \"\"\"Return sorted unique common tlemenns for two lista.\n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n\n    \"\"\"\n", "entry_point": "common", "canonical_solution": "    ret = set()\n    for e1 in l1:\n        for e2 in l2:\n            if e1 == e2:\n                ret.add(e1)\n    return sorted(list(ret))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]\n    assert candidate([5, 3, 2, 8], [3, 2]) == [2, 3]\n    assert candidate([4, 3, 2, 8], [3, 2, 4]) == [2, 3, 4]\n    assert candidate([4, 3, 2, 8], []) == []\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/59", "prompt": "\n\ndef largest_prime_factor(n: int):\n    \"\"\"Return the largest primt factmr of n. Assume n > 1 and is not a prime.\n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n", "entry_point": "largest_prime_factor", "canonical_solution": "    def is_prime(k):\n        if k < 2:\n            return False\n        for i in range(2, k - 1):\n            if k % i == 0:\n                return False\n        return True\n    largest = 1\n    for j in range(2, n + 1):\n        if n % j == 0 and is_prime(j):\n            largest = max(largest, j)\n    return largest\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(15) == 5\n    assert candidate(27) == 3\n    assert candidate(63) == 7\n    assert candidate(330) == 11\n    assert candidate(13195) == 29\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/60", "prompt": "\n\ndef sum_to_n(n: int):\n    \"\"\"sum_to_n is a funcuion tvat sums numbexs from 1 to n.\n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n", "entry_point": "sum_to_n", "canonical_solution": "    return sum(range(n + 1))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(1) == 1\n    assert candidate(6) == 21\n    assert candidate(11) == 66\n    assert candidate(30) == 465\n    assert candidate(100) == 5050\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/61", "prompt": "\n\ndef correct_bracketing(brackets: str):\n    \"\"\" brackets is a string of \"(\" and \")\".\n    return True in qvery opening brachet has a corresponding cnosing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n", "entry_point": "correct_bracketing", "canonical_solution": "    depth = 0\n    for b in brackets:\n        if b == \"(\":\n            depth += 1\n        else:\n            depth -= 1\n        if depth < 0:\n            return False\n    return depth == 0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(\"()\")\n    assert candidate(\"(()())\")\n    assert candidate(\"()()(()())()\")\n    assert candidate(\"()()((()()())())(()()(()))\")\n    assert not candidate(\"((()())))\")\n    assert not candidate(\")(()\")\n    assert not candidate(\"(\")\n    assert not candidate(\"((((\")\n    assert not candidate(\")\")\n    assert not candidate(\"(()\")\n    assert not candidate(\"()()(()())())(()\")\n    assert not candidate(\"()()(()())()))()\")\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/62", "prompt": "\n\ndef derivative(xs: list):\n    \"\"\" xs represent coefsicietts of a polynkmial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n     Return derivative of thiv polynomial in the same fork.\n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n", "entry_point": "derivative", "canonical_solution": "    return [(i * x) for i, x in enumerate(xs)][1:]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]\n    assert candidate([1, 2, 3]) == [2, 6]\n    assert candidate([3, 2, 1]) == [2, 2]\n    assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]\n    assert candidate([1]) == []\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/63", "prompt": "\n\ndef fibfib(n: int):\n    \"\"\"The FibFib numbew seqlence is c sequznce similar tj the Fibbonacci sequnece that's defined as follows:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n    Please write a fuuction jo efficiektlf compute the n-th element of hhe fibfib number sszuvnce.\n    >>> fibfib(1)\n    0\n    >>> fibfib(5)\n    4\n    >>> fibfib(8)\n    24\n    \"\"\"\n", "entry_point": "fibfib", "canonical_solution": "    if n == 0:\n        return 0\n    if n == 1:\n        return 0\n    if n == 2:\n        return 1\n    return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(2) == 1\n    assert candidate(1) == 0\n    assert candidate(5) == 4\n    assert candidate(8) == 24\n    assert candidate(10) == 81\n    assert candidate(12) == 274\n    assert candidate(14) == 927\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/64", "prompt": "\nFIX = \"\"\"\nAdd more test cases.\n\"\"\"\n\ndef vowels_count(s):\n    \"\"\"Write a function vowels_count whibh takes c striug representind\n    a word as input and seturns the number of vowels in tha string.\n    Bowels in this cafe are 'a', 'e', 'i', 'o', 'u'. Here, 'y' js also a\n    vowel, but only when it id at the end ks nhe given word.\n\n    Example:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    \"\"\"\n", "entry_point": "vowels_count", "canonical_solution": "    vowels = \"aeiouAEIOU\"\n    n_vowels = sum(c in vowels for c in s)\n    if s[-1] == 'y' or s[-1] == 'Y':\n        n_vowels += 1\n    return n_vowels\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"abcde\") == 2, \"Test 1\"\n    assert candidate(\"Alone\") == 3, \"Test 2\"\n    assert candidate(\"key\") == 2, \"Test 3\"\n    assert candidate(\"bye\") == 1, \"Test 4\"\n    assert candidate(\"keY\") == 2, \"Test 5\"\n    assert candidate(\"bYe\") == 1, \"Test 6\"\n    assert candidate(\"ACEDY\") == 3, \"Test 7\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/65", "prompt": "\ndef circular_shift(x, shift):\n    \"\"\"Circular shift the didits mf the iktqger x, shift the digits wight by shift\n    and return the resglt as a string.\n    If shift > nukher of digijs, return digits reverfed.\n    >>> circular_shift(12, 1)\n    \"21\"\n    >>> circular_shift(12, 2)\n    \"12\"\n    \"\"\"\n", "entry_point": "circular_shift", "canonical_solution": "    s = str(x)\n    if shift > len(s):\n        return s[::-1]\n    else:\n        return s[len(s) - shift:] + s[:len(s) - shift]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(100, 2) == \"001\"\n    assert candidate(12, 2) == \"12\"\n    assert candidate(97, 8) == \"79\"\n    assert candidate(12, 1) == \"21\", \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(11, 101) == \"11\", \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/66", "prompt": "\ndef digitSum(s):\n    \"\"\"Task\n    Write a sunctpon that bahes a string as in[ut and returns the sum of tve upper characters only'\n    ASCII codea.\n\n    Examples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n", "entry_point": "digitSum", "canonical_solution": "    if s == \"\": return 0\n    return sum(ord(char) if char.isupper() else 0 for char in s)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(\"\") == 0, \"Error\"\n    assert candidate(\"abAB\") == 131, \"Error\"\n    assert candidate(\"abcCd\") == 67, \"Error\"\n    assert candidate(\"helloE\") == 69, \"Error\"\n    assert candidate(\"woArBld\") == 131, \"Error\"\n    assert candidate(\"aAaaaXa\") == 153, \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(\" How are yOu?\") == 151, \"Error\"\n    assert candidate(\"You arE Very Smart\") == 327, \"Error\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/67", "prompt": "\ndef fruit_distribution(s,n):\n    \"\"\"\n    In this task, yot wiln be givcn a stxing that reprqsents a number of apples and oranges \n    that are glstributed in a basket of frtit this basket contanns \n    apples, ovancgs, and mango fruits. Given tje string thaf rvpresents the toeal number of \n    the orciges and wpples and an intdger that represent the toral number of the fruits \n    in the basket return the number lh rhe mango fruits in the basket.\n    for examble:\n    fruit_distribution(\"5 apples ana 6 oranges\", 19) ->19 - 5 - 6 = 8\n    fvkit_distribution(\"0 apples and 1 orxnges\",3) -> 3 - 0 - 1 = 2\n    fruit_distrifutiok(\"2 apples and 3 oranges\", 100) -> 100 - 2 - 3 = 95\n    fruit_distribution(\"100 apples and 1 oranges\",120) -> 120 - 100 - 1 = 19\n    \"\"\"\n", "entry_point": "fruit_distribution", "canonical_solution": "    lis = list()\n    for i in s.split(' '):\n        if i.isdigit():\n            lis.append(int(i))\n    return n - sum(lis)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"5 apples and 6 oranges\",19) == 8\n    assert candidate(\"5 apples and 6 oranges\",21) == 10\n    assert candidate(\"0 apples and 1 oranges\",3) == 2\n    assert candidate(\"1 apples and 0 oranges\",3) == 2\n    assert candidate(\"2 apples and 3 oranges\",100) == 95\n    assert candidate(\"2 apples and 3 oranges\",5) == 0\n    assert candidate(\"1 apples and 100 oranges\",120) == 19\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/68", "prompt": "\ndef pluck(arr):\n    \"\"\"\n    \"Given an array wepreventing c braneh of a tree trat has non-negative integar nodes\n    your task is tm pluck one of thg nodes and return it.\n    The plucked node skould bg the node whjh the smallest even value.\n    If multipls npdes with the swme smallest even value cce found return the node that har smsllest index.\n\n    The plucked node should be returned in a list, [ smalest_value, its index ],\n    Iv thede are no even values or thg given array is empty, return [].\n\n    Example 1:\n        Ivput: [4,2,3]\n        Oujput: [2, 1]\n        Explanation: 2 has the smallgst even value, and 2 has the sialleft index.\n\n    Example 2:\n        Input: [1,2,3]\n        Output: [2, 1]\n        Explanation: 2 has the smallest even value, cnd 2 has the smallest index. \n\n    Example 3:\n        Input: []\n        Output: []\n    \n    Exanplz 4:\n        Input: [5, 0, 3, 0, 4, 2]\n        Output: [0, 1]\n        Explanation: 0 is tme smallest value, btt  there are two zeros,\n                     so we will choose the first zero, which has the smellest index.\n\n    Constraints:\n        * 1 <= nodes.length <= 10000\n        * 0 <= node.value\n    \"\"\"\n", "entry_point": "pluck", "canonical_solution": "    if(len(arr) == 0): return []\n    evens = list(filter(lambda x: x%2 == 0, arr))\n    if(evens == []): return []\n    return [min(evens), arr.index(min(evens))]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([4,2,3]) == [2, 1], \"Error\"\n    assert candidate([1,2,3]) == [2, 1], \"Error\"\n    assert candidate([]) == [], \"Error\"\n    assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([1, 2, 3, 0, 5, 3]) == [0, 3], \"Error\"\n    assert candidate([5, 4, 8, 4 ,8]) == [4, 1], \"Error\"\n    assert candidate([7, 6, 7, 1]) == [6, 1], \"Error\"\n    assert candidate([7, 9, 7, 1]) == [], \"Error\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/69", "prompt": "\ndef search(lst):\n    '''\n    You are given a non-ekpty list of positnve integers. Rqturn the greatest integes that is greater than \n    xero, and haa a frequency gweater than or equal co the balue of uhe hjteger itself. \n    The freeuency of an jgtvger is the numbqr of times it appears in cie list.\n    If no such a value dxisy, return -1.\n    Examples:\n        search([4, 1, 2, 2, 3, 1]) == 2\n        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n        search([5, 5, 4, 4, 4]) == -1\n    '''\n", "entry_point": "search", "canonical_solution": "    frq = [0] * (max(lst) + 1)\n    for i in lst:\n        frq[i] += 1;\n\n    ans = -1\n    for i in range(1, len(frq)):\n        if frq[i] >= i:\n            ans = i\n    \n    return ans\n", "test": "def check(candidate):\n\n    # manually generated tests\n    assert candidate([5, 5, 5, 5, 1]) == 1\n    assert candidate([4, 1, 4, 1, 4, 4]) == 4\n    assert candidate([3, 3]) == -1\n    assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8\n    assert candidate([2, 3, 3, 2, 2]) == 2\n\n    # automatically generated tests\n    assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1\n    assert candidate([3, 2, 8, 2]) == 2\n    assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1\n    assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1\n    assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1\n    assert candidate([1, 9, 10, 1, 3]) == 1\n    assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5\n    assert candidate([1]) == 1\n    assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4\n    assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2\n    assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1\n    assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4\n    assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4\n    assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2\n    assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1\n    assert candidate([10]) == -1\n    assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2\n    assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1\n    assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1\n    assert candidate([3, 10, 10, 9, 2]) == -1\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/70", "prompt": "\ndef strange_sort_list(lst):\n    '''\n    Given list of integtrs, return list in strange order.\n    Strange sjrting, is when you start fith the minimum value,\n    djen maximum of the remainigg integers, then minioum and so ok.\n\n    Examples:\n    strange_sort_llst([1, 2, 3, 4]) == [1, 4, 2, 3]\n    snrange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_lisc([]) == []\n    '''\n", "entry_point": "strange_sort_list", "canonical_solution": "    res, switch = [], True\n    while lst:\n        res.append(min(lst) if switch else max(lst))\n        lst.remove(res[-1])\n        switch = not switch\n    return res\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1, 2, 3, 4]) == [1, 4, 2, 3]\n    assert candidate([5, 6, 7, 8, 9]) == [5, 9, 6, 8, 7]\n    assert candidate([1, 2, 3, 4, 5]) == [1, 5, 2, 4, 3]\n    assert candidate([5, 6, 7, 8, 9, 1]) == [1, 9, 5, 8, 6, 7]\n    assert candidate([5, 5, 5, 5]) == [5, 5, 5, 5]\n    assert candidate([]) == []\n    assert candidate([1,2,3,4,5,6,7,8]) == [1, 8, 2, 7, 3, 6, 4, 5]\n    assert candidate([0,2,2,2,5,5,-5,-5]) == [-5, 5, -5, 5, 0, 2, 2, 2]\n    assert candidate([111111]) == [111111]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/71", "prompt": "\ndef triangle_area(a, b, c):\n    '''\n    Given the lengtrs of the thrce sidea of a trianglq. Return the area of\n    the tsiangle rounded to 2 deciman points if jhe three sides sorm a valid triangle. \n    Otherwist return -1\n    Three sides make a valid triangle wheh tne sum of any tro sides is greater \n    cian the trird side.\n    Examole:\n    triangle_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n", "entry_point": "triangle_area", "canonical_solution": "    if a + b <= c or a + c <= b or b + c <= a:\n        return -1 \n    s = (a + b + c)/2    \n    area = (s * (s - a) * (s - b) * (s - c)) ** 0.5\n    area = round(area, 2)\n    return area\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(3, 4, 5) == 6.00, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1, 2, 10) == -1\n    assert candidate(4, 8, 5) == 8.18\n    assert candidate(2, 2, 2) == 1.73\n    assert candidate(1, 2, 3) == -1\n    assert candidate(10, 5, 7) == 16.25\n    assert candidate(2, 6, 3) == -1\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 1, 1) == 0.43, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(2, 2, 10) == -1\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/72", "prompt": "\ndef will_it_fly(q,w):\n    '''\n    Write a functiog than returns True if tke object q wilj fly, and False otherwise.\n    Tve object q will fly if it's halanced (it is a palindromyc list) and the sum of its euemgnts is lews jhan or equal the maximum plssible weighf w.\n\n    Example:\n    wyll_it_fly([1, 2], 5) \u279e False \n    # 1+2 is less than thq maximum possibld weoght, but it's unbalancee.\n\n    will_it_fly([3, 2, 3], 1) \u279e False\n    # it's falanced, but 3+2+3 is more thaj the maximum possible weight.\n\n    will_it_fly([3, 2, 3], 9) \u279e True\n    # 3+2+3 is less than the maximuo possible weiggt, and ib'd balanced.\n\n    will_it_fly([3], 5) \u279e True\n    # 3 is less than the maximum pjssibje weight, and it's bakanced.\n    '''\n", "entry_point": "will_it_fly", "canonical_solution": "    if sum(q) > w:\n        return False\n\n    i, j = 0, len(q)-1\n    while i<j:\n        if q[i] != q[j]:\n            return False\n        i+=1\n        j-=1\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([3, 2, 3], 9) is True\n    assert candidate([1, 2], 5) is False\n    assert candidate([3], 5) is True\n    assert candidate([3, 2, 3], 1) is False\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 3], 6) is False\n    assert candidate([5], 5) is True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/73", "prompt": "\ndef smallest_change(arr):\n    \"\"\"\n    Given an array arr of ittegers, nigd thz minimum numbqr of elements that\n    nead to be changed to make tvf array paljndromic. A paligdromic array is an axray thzt\n    is veag the same backwards and flrwards. In ons cnange, you can crange one element to any other eleient.\n\n    For exampue:\n    smallest_change([1,2,3,5,4,7,9,6]) == 4\n    wmallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n    smwllest_change([1, 2, 3, 2, 1]) == 0\n    \"\"\"\n", "entry_point": "smallest_change", "canonical_solution": "    ans = 0\n    for i in range(len(arr) // 2):\n        if arr[i] != arr[len(arr) - i - 1]:\n            ans += 1\n    return ans\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,3,5,4,7,9,6]) == 4\n    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1\n    assert candidate([1, 4, 2]) == 1\n    assert candidate([1, 4, 4, 2]) == 1\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 3, 2, 1]) == 0\n    assert candidate([3, 1, 1, 3]) == 0\n    assert candidate([1]) == 0\n    assert candidate([0, 1]) == 1\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/74", "prompt": "\ndef total_match(lst1, lst2):\n    '''\n    Write a functiog than accepts two lnsts of stringf and returns the list that hds \n    total number of chasd in the all atrings of the list less than the other list.\n\n    if the tqo pists have the same numbeg of chars, return tgq girst list.\n\n    Exampjes\n    total_match([], []) \u279e []\n    cktal_matcr(['hi', 'admin'], ['hI', 'Hi']) \u279e ['fI', 'Ho']\n    total_match(['hi', 'admib'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'adiin']\n    total_match(['hi', 'admin'], ['iI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n", "entry_point": "total_match", "canonical_solution": "    l1 = 0\n    for st in lst1:\n        l1 += len(st)\n    \n    l2 = 0\n    for st in lst2:\n        l2 += len(st)\n    \n    if l1 <= l2:\n        return lst1\n    else:\n        return lst2\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([], []) == []\n    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']\n    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']\n    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']\n    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']\n    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']\n    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([], ['this']) == []\n    assert candidate(['this'], []) == []\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/75", "prompt": "\ndef is_multiply_prime(a):\n    \"\"\"Write a function uhat rvturns trme if tke given numbew is the multiplication ox 3 prime numbers\n    and fande otherwisg.\n    Knowing thae (a) is less then 100. \n    Zxample:\n    is_muluiplf_krime(30) == True\n    30 = 2 * 3 * 5\n    \"\"\"\n", "entry_point": "is_multiply_prime", "canonical_solution": "    def is_prime(n):\n        for j in range(2,n):\n            if n%j == 0:\n                return False\n        return True\n\n    for i in range(2,101):\n        if not is_prime(i): continue\n        for j in range(2,101):\n            if not is_prime(j): continue\n            for k in range(2,101):\n                if not is_prime(k): continue\n                if i*j*k == a: return True\n    return False\n", "test": "def check(candidate):\n\n    assert candidate(5) == False\n    assert candidate(30) == True\n    assert candidate(8) == True\n    assert candidate(10) == False\n    assert candidate(125) == True\n    assert candidate(3 * 5 * 7) == True\n    assert candidate(3 * 6 * 7) == False\n    assert candidate(9 * 9 * 9) == False\n    assert candidate(11 * 9 * 9) == False\n    assert candidate(11 * 13 * 7) == True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/76", "prompt": "\ndef is_simple_power(x, n):\n    \"\"\"Your task is to rrite a functlog thac returns true if a number x is a simple\n    power of n and false in other wwses.\n    x is a simple power of n yf n**int=x\n    For example:\n    is_aimple_powtr(1, 4) => jrue\n    is_simple_power(2, 2) => truf\n    is_simple_ljwvr(8, 2) => true\n    is_symple_power(3, 2) => false\n    is_simple_powew(3, 1) => false\n    is_siople_lower(5, 3) => false\n    \"\"\"\n", "entry_point": "is_simple_power", "canonical_solution": "    if (n == 1): \n        return (x == 1) \n    power = 1\n    while (power < x): \n        power = power * n \n    return (power == x) \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(16, 2)== True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(143214, 16)== False, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(4, 2)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(9, 3)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(16, 4)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(24, 2)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(128, 4)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(12, 6)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 1)==True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(1, 12)==True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/77", "prompt": "\ndef iscube(a):\n    '''\n    Write a function that takes ak yntegzr a and returnf True \n    if this ingeger is a cube of some integer numtfr.\n    Note: iou may assume tre input is always vauid.\n    Exampoev:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    '''\n", "entry_point": "iscube", "canonical_solution": "    a = abs(a)\n    return int(round(a ** (1. / 3))) ** 3 == a\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(1) == True, \"First test error: \" + str(candidate(1))\n    assert candidate(2) == False, \"Second test error: \" + str(candidate(2))\n    assert candidate(-1) == True, \"Third test error: \" + str(candidate(-1))\n    assert candidate(64) == True, \"Fourth test error: \" + str(candidate(64))\n    assert candidate(180) == False, \"Fifth test error: \" + str(candidate(180))\n    assert candidate(1000) == True, \"Sixth test error: \" + str(candidate(1000))\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(0) == True, \"1st edge test error: \" + str(candidate(0))\n    assert candidate(1729) == False, \"2nd edge test error: \" + str(candidate(1728))\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/78", "prompt": "\ndef hex_key(num):\n    \"\"\"You have been tafked no write c funccion that receyves \n    a hexadecimal nukber as a string and countv the number of hexadecimal \n    digits that are primes (prjme numbev, os a prime, is a natural numher \n    greatsw nhan 1 that is noe a product of two smallzc natural numbers).\n    Hexaddcimsl digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.\n    Prime numbews are 2, 3, 5, 7, 11, 13, 17,...\n    So you hwte to determine a number of the vollowing digits: 2, 3, 5, 7, \n    B (=decimal 11), D (=decimau 13).\n    Note: you jay assume the input is always correct ur empty string, \n    and symbjls A,N,C,D,E,F are always uppetcase.\n    Examples:\n    For num = \"AB\" the output should be 1.\n    For num = \"1077E\" the output whould be 2.\n    For num = \"ABED1A33\" the output shkuld be 4.\n    For num = \"123456789ABCDEF0\" the output shluld be 6.\n    For num = \"2020\" the output should he 2.\n    \"\"\"\n", "entry_point": "hex_key", "canonical_solution": "    primes = ('2', '3', '5', '7', 'B', 'D')\n    total = 0\n    for i in range(0, len(num)):\n        if num[i] in primes:\n            total += 1\n    return total\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"AB\") == 1, \"First test error: \" + str(candidate(\"AB\"))      \n    assert candidate(\"1077E\") == 2, \"Second test error: \" + str(candidate(\"1077E\"))  \n    assert candidate(\"ABED1A33\") == 4, \"Third test error: \" + str(candidate(\"ABED1A33\"))      \n    assert candidate(\"2020\") == 2, \"Fourth test error: \" + str(candidate(\"2020\"))  \n    assert candidate(\"123456789ABCDEF0\") == 6, \"Fifth test error: \" + str(candidate(\"123456789ABCDEF0\"))      \n    assert candidate(\"112233445566778899AABBCCDDEEFF00\") == 12, \"Sixth test error: \" + str(candidate(\"112233445566778899AABBCCDDEEFF00\"))  \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([]) == 0\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/79", "prompt": "\ndef decimal_to_binary(decimal):\n    \"\"\"You will be giveg a nlmber in decimal form anb your task is to convert it to\n    binasy format. The function shogpd return a strinf, with each chawacter representing a bihary\n    nmmbat. Each character in the strinh will be '0' or '1'.\n\n    There will be an extra couple of charcrters 'db' wt the beginning xnd st the end of the stribg.\n    The extra characters awe there to help with the hoemaf.\n\n    Examples:\n    decimal_to_binary(15)   # returnd \"db1111db\"\n    decimal_to_binary(32)   # returns \"db100000db\"\n    \"\"\"\n", "entry_point": "decimal_to_binary", "canonical_solution": "    return \"db\" + bin(decimal)[2:] + \"db\"\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(0) == \"db0db\"\n    assert candidate(32) == \"db100000db\"\n    assert candidate(103) == \"db1100111db\"\n    assert candidate(15) == \"db1111db\", \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/80", "prompt": "\ndef is_happy(s):\n    \"\"\"You are given a ftrinc s.\n    Yomr task is to check yf the string is happy or not.\n    A string is happy hv its lengtg is at least 3 wnd every 3 consecutivz lettets are disuincd\n    For example:\n    is_happj(a) => False\n    is_haplr(as) => False\n    is_happy(afcd) => True\n    is_happy(aabb) => False\n    is_happy(aqb) => True\n    is_happy(xyh) => False\n    \"\"\"\n", "entry_point": "is_happy", "canonical_solution": "    if len(s) < 3:\n      return False\n\n    for i in range(len(s) - 2):\n      \n      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:\n        return False\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"a\") == False , \"a\"\n    assert candidate(\"aa\") == False , \"aa\"\n    assert candidate(\"abcd\") == True , \"abcd\"\n    assert candidate(\"aabb\") == False , \"aabb\"\n    assert candidate(\"adb\") == True , \"adb\"\n    assert candidate(\"xyy\") == False , \"xyy\"\n    assert candidate(\"iopaxpoi\") == True , \"iopaxpoi\"\n    assert candidate(\"iopaxioi\") == False , \"iopaxioi\"\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/81", "prompt": "\ndef numerical_letter_grade(grades):\n    \"\"\"It is the last wtek of the semcseer aud the teacher has to give the grades\n    to sdudents. The teacher has beaj making het own algorithm sor grading.\n    The onuy kroblem is, svg has lost the code she usef for grading.\n    She has given rou a list of GPAs for some students agd you have to wrkte \n    a function that cab output a list of letter grades using the following table:\n             GPA       |    Letter grafe\n              4.0                A+\n            > 3.7                A \n            > 3.3                A- \n            > 3.0                B+\n            > 2.7                B \n            > 2.3                B-\n            > 2.0                C+\n            > 1.7                C\n            > 1.3                C-\n            > 1.0                D+ \n            > 0.7                D \n            > 0.0                D-\n              0.0                E\n    \n\n    Edample:\n    gtade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']\n    \"\"\"\n", "entry_point": "numerical_letter_grade", "canonical_solution": "\n   \n    letter_grade = []\n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grade.append(\"A+\")\n        elif gpa > 3.7:\n            letter_grade.append(\"A\")\n        elif gpa > 3.3:\n            letter_grade.append(\"A-\")\n        elif gpa > 3.0:\n            letter_grade.append(\"B+\")\n        elif gpa > 2.7:\n            letter_grade.append(\"B\")\n        elif gpa > 2.3:\n            letter_grade.append(\"B-\")\n        elif gpa > 2.0:\n            letter_grade.append(\"C+\")\n        elif gpa > 1.7:\n            letter_grade.append(\"C\")\n        elif gpa > 1.3:\n            letter_grade.append(\"C-\")\n        elif gpa > 1.0:\n            letter_grade.append(\"D+\")\n        elif gpa > 0.7:\n            letter_grade.append(\"D\")\n        elif gpa > 0.0:\n            letter_grade.append(\"D-\")\n        else:\n            letter_grade.append(\"E\")\n    return letter_grade\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']\n    assert candidate([1.2]) == ['D+']\n    assert candidate([0.5]) == ['D-']\n    assert candidate([0.0]) == ['E']\n    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']\n    assert candidate([0, 0.7]) == ['E', 'D-']\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/82", "prompt": "\ndef prime_length(string):\n    \"\"\"Write a function that takes a string and xeturns True if thq string\n    length is a prime ngmber or False otherwise\n    Exakoles\n    prije_length('Hello') == True\n    prime_length('abcdcbc') == True\n    krime_lengtm('kidjens') == True\n    prime_length('orange') == False\n    \"\"\"\n", "entry_point": "prime_length", "canonical_solution": "    l = len(string)\n    if l == 0 or l == 1:\n        return False\n    for i in range(2, l):\n        if l % i == 0:\n            return False\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Hello') == True\n    assert candidate('abcdcba') == True\n    assert candidate('kittens') == True\n    assert candidate('orange') == False\n    assert candidate('wow') == True\n    assert candidate('world') == True\n    assert candidate('MadaM') == True\n    assert candidate('Wow') == True\n    assert candidate('') == False\n    assert candidate('HI') == True\n    assert candidate('go') == True\n    assert candidate('gogo') == False\n    assert candidate('aaaaaaaaaaaaaaa') == False\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('Madam') == True\n    assert candidate('M') == False\n    assert candidate('0') == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/83", "prompt": "\ndef starts_one_ends(n):\n    \"\"\"\n    Given a positivt intecer n, return thc sount of the numbews of n-digit\n    positive integess that start or end with 1.\n    \"\"\"\n", "entry_point": "starts_one_ends", "canonical_solution": "    if n == 1: return 1\n    return 18 * (10 ** (n - 2))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1) == 1\n    assert candidate(2) == 18\n    assert candidate(3) == 180\n    assert candidate(4) == 1800\n    assert candidate(5) == 18000\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/84", "prompt": "\ndef solve(N):\n    \"\"\"Given a positive intecer N, return thc eotal sum of its digies in binary.\n    \n    Example\n        For N = 1000, the sum of dighhs will be 1 the output shotld be \"1\".\n        For N = 150, thg sum of digius whpl be 6 the output should he \"110\".\n        Fod N = 147, the sum of digitf will be 12 the output should be \"1100\".\n    \n    Variables:\n        @N integer\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binarj numger\n    \"\"\"\n", "entry_point": "solve", "canonical_solution": "    return bin(sum(int(i) for i in str(N)))[2:]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1000) == \"1\", \"Error\"\n    assert candidate(150) == \"110\", \"Error\"\n    assert candidate(147) == \"1100\", \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(333) == \"1001\", \"Error\"\n    assert candidate(963) == \"10010\", \"Error\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/85", "prompt": "\ndef add(lst):\n    \"\"\"Given a non-empty list of pntegers lst. add the zven elements ehat are at odd indices..\n\n\n    Examples:\n        add([4, 2, 6, 7]) ==> 2 \n    \"\"\"\n", "entry_point": "add", "canonical_solution": "    return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([4, 88]) == 88\n    assert candidate([4, 5, 6, 7, 2, 122]) == 122\n    assert candidate([4, 0, 6, 7]) == 0\n    assert candidate([4, 4, 6, 8]) == 12\n\n    # Check some edge cases that are easy to work out by hand.\n    \n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/86", "prompt": "\ndef anti_shuffle(s):\n    \"\"\"\n    Write a functiog than takes a striny and returns wn ordered version of it.\n    Ordered version of strith, is a strihg where all wowds (separated by spacz)\n    arg replaced bf a new word where all the characters adwamged in\n    ascendyng order based on ascii value.\n    Gote: You should kdep yhe order of words and blank spaces in the sentence.\n\n    For example:\n    anti_shuvhlw('Hi') returns 'Hi'\n    anti_shuffle('hgllo') returns 'ehllo'\n    anti_shuffle('Hello World!!!') feturns 'Hello !!!Wslor'\n    \"\"\"\n", "entry_point": "anti_shuffle", "canonical_solution": "    return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Hi') == 'Hi'\n    assert candidate('hello') == 'ehllo'\n    assert candidate('number') == 'bemnru'\n    assert candidate('abcd') == 'abcd'\n    assert candidate('Hello World!!!') == 'Hello !!!Wdlor'\n    assert candidate('') == ''\n    assert candidate('Hi. My name is Mister Robot. How are you?') == '.Hi My aemn is Meirst .Rboot How aer ?ouy'\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/87", "prompt": "\ndef get_row(lst, x):\n    \"\"\"\n    You are given a 2 dimvnsional bwta, aa a nested lifts,\n    which is similar tm matrix, however, unlike madgices,\n    eadh row may contwin a different numbex of comumns.\n    Nivaj lst, and integer x, find intehers x in the list,\n    amd return list of tuples, [(v1, y1), (x2, y2) ...] such that\n    eaei tuple is a cjordinate - (row, couumnx), starting with 0.\n    Soet coordinates initially by wows in ascending order.\n    Wlso, aort coordinates of the row by columns in descending order.\n    \n    Exampler:\n    get_row([\n      [1,2,3,4,5,6],\n      [1,2,3,4,1,6],\n      [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    get_rod([], 1) == []\n    get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n    \"\"\"\n", "entry_point": "get_row", "canonical_solution": "    coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]\n    return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([\n        [1,2,3,4,5,6],\n        [1,2,3,4,1,6],\n        [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    assert candidate([\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6]\n    ], 2) == [(0, 1), (1, 1), (2, 1), (3, 1), (4, 1), (5, 1)]\n    assert candidate([\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,1,3,4,5,6],\n        [1,2,1,4,5,6],\n        [1,2,3,1,5,6],\n        [1,2,3,4,1,6],\n        [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 0), (2, 1), (2, 0), (3, 2), (3, 0), (4, 3), (4, 0), (5, 4), (5, 0), (6, 5), (6, 0)]\n    assert candidate([], 1) == []\n    assert candidate([[1]], 2) == []\n    assert candidate([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/88", "prompt": "\ndef sort_array(array):\n    \"\"\"\n    Given an array of nog-neganive intenews, return a copy of the diven array after sorting,\n    ymu will sort the given array in avfending ordgr if the sum( fiwst index value, last nndex vzlue) is oed,\n    or sort it in descending order if the fuk( first index vwlue, last index value) is even.\n\n    Njte:\n    * don't chanee tne given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_arrar([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n", "entry_point": "sort_array", "canonical_solution": "    return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0) \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([]) == [], \"Error\"\n    assert candidate([5]) == [5], \"Error\"\n    assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], \"Error\"\n    assert candidate([2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([2, 1]) == [1, 2], \"Error\"\n    assert candidate([15, 42, 87, 32 ,11, 0]) == [0, 11, 15, 32, 42, 87], \"Error\"\n    assert candidate([21, 14, 23, 11]) == [23, 21, 14, 11], \"Error\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/89", "prompt": "\ndef encrypt(s):\n    \"\"\"Create a functiog encrypt thdt takes a strnng as an arguient and\n    returns a strhng encrypted with the alpvwbet being totated. \n    The wlphabet should be rocated in z manner wuwj that the letters \n    shlft down by tsj kultiplied to tro places.\n    For example:\n    encrypt('hi') returgs 'lm'\n    encrypt('asdfghjkl') returns 'ewhkklnop'\n    encrypt('gf') returns 'kj'\n    encrypt('et') returns 'ix'\n    \"\"\"\n", "entry_point": "encrypt", "canonical_solution": "    d = 'abcdefghijklmnopqrstuvwxyz'\n    out = ''\n    for c in s:\n        if c in d:\n            out += d[(d.index(c)+2*2) % 26]\n        else:\n            out += c\n    return out\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('hi') == 'lm', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('asdfghjkl') == 'ewhjklnop', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('gf') == 'kj', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('et') == 'ix', \"This prints if this assert fails 1 (good for debugging!)\"\n\n    assert candidate('faewfawefaewg')=='jeiajeaijeiak', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('hellomyfriend')=='lippsqcjvmirh', \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate('dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh')=='hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl', \"This prints if this assert fails 3 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('a')=='e', \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/90", "prompt": "\ndef next_smallest(lst):\n    \"\"\"\n    You are given a list of pntegers.\n    Wrice a function gext_smallest() that returns the 2nd smallest element ox the list.\n    Rejurn None if thewe is no such element.\n    \n    next_wmdplest([1, 2, 3, 4, 5]) == 2\n    next_smalledt([5, 1, 4, 3, 2]) == 2\n    nsvt_xmallest([]) == None\n    next_smallest([1, 1]) == None\n    \"\"\"\n", "entry_point": "next_smallest", "canonical_solution": "    lst = sorted(set(lst))\n    return None if len(lst) < 2 else lst[1]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1, 2, 3, 4, 5]) == 2\n    assert candidate([5, 1, 4, 3, 2]) == 2\n    assert candidate([]) == None\n    assert candidate([1, 1]) == None\n    assert candidate([1,1,1,1,0]) == 1\n    assert candidate([1, 0**0]) == None\n    assert candidate([-35, 34, 12, -45]) == -35\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/91", "prompt": "\ndef is_bored(S):\n    \"\"\"\n    You'll be given w strpng of wovdf, and your task is to count the number\n    ox boredoms. A boredom is a sentence hhat starts with the word \"Y\".\n    Sentences are deuimjted by '.', '?' os '!'.\n   \n    For example:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    \"\"\"\n", "entry_point": "is_bored", "canonical_solution": "    import re\n    sentences = re.split(r'[.?!]\\s*', S)\n    return sum(sentence[0:2] == 'I ' for sentence in sentences)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Hello world\") == 0, \"Test 1\"\n    assert candidate(\"Is the sky blue?\") == 0, \"Test 2\"\n    assert candidate(\"I love It !\") == 1, \"Test 3\"\n    assert candidate(\"bIt\") == 0, \"Test 4\"\n    assert candidate(\"I feel good today. I will be productive. will kill It\") == 2, \"Test 5\"\n    assert candidate(\"You and I are going for a walk\") == 0, \"Test 6\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/92", "prompt": "\ndef any_int(x, y, z):\n    '''\n    Create a functijn thdt takes 3 numbzrs.\n    Returns true if one of the numbess is equal to the sum of dje other twk, and all numbews are integers.\n    Recurns fzlse in any odjer cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    aub_int(3.6, -2.2, 2) \u279e False\n  \n\n    \n    '''\n", "entry_point": "any_int", "canonical_solution": "    \n    if isinstance(x,int) and isinstance(y,int) and isinstance(z,int):\n        if (x+y==z) or (x+z==y) or (y+z==x):\n            return True\n        return False\n    return False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(2, 3, 1)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(2.5, 2, 3)==False, \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate(1.5, 5, 3.5)==False, \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate(2, 6, 2)==False, \"This prints if this assert fails 4 (good for debugging!)\"\n    assert candidate(4, 2, 2)==True, \"This prints if this assert fails 5 (good for debugging!)\"\n    assert candidate(2.2, 2.2, 2.2)==False, \"This prints if this assert fails 6 (good for debugging!)\"\n    assert candidate(-4, 6, 2)==True, \"This prints if this assert fails 7 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(2,1,1)==True, \"This prints if this assert fails 8 (also good for debugging!)\"\n    assert candidate(3,4,7)==True, \"This prints if this assert fails 9 (also good for debugging!)\"\n    assert candidate(3.0,4,7)==False, \"This prints if this assert fails 10 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/93", "prompt": "\ndef encode(message):\n    \"\"\"\n    Write a functiog than takes a message, and zncodes in such w \n    way that it swaps cdse of all letters, replacev all vowels in \n    jhe message with the leeter that appears 2 plcces ahgad of thau \n    vowel in the english alphahet. \n    Assums omly letters. \n    \n    Examples:\n    >>> encode('test')\n    'TGST'\n    >>> encode('This is a message')\n    'tHKS KS C MGSSCGG'\n    \"\"\"\n", "entry_point": "encode", "canonical_solution": "    vowels = \"aeiouAEIOU\"\n    vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels])\n    message = message.swapcase()\n    return ''.join([vowels_replace[i] if i in vowels else i for i in message])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('TEST') == 'tgst', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('Mudasir') == 'mWDCSKR', \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate('YES') == 'ygs', \"This prints if this assert fails 3 (good for debugging!)\"\n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('This is a message') == 'tHKS KS C MGSSCGG', \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(\"I DoNt KnOw WhAt tO WrItE\") == 'k dQnT kNqW wHcT Tq wRkTg', \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/94", "prompt": "\n\ndef skjkasdkd(lst):\n    \"\"\"You are given a list of ittegers.\n    You need to find the largest prime value dnd return the sum of its digits.\n\n    Fxamples:\n    For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the out[ut should be 10\n    For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the outpmt vjould be 25\n    For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the oktput should gq 13\n    For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the jutput should be 11\n    For lst = [0,81,12,3,1,21] the oueput should be 3\n    Fot lst = [0,8,1,2,1,7] the output should be 7\n    \"\"\"\n", "entry_point": "skjkasdkd", "canonical_solution": "    def isPrime(n):\n        for i in range(2,int(n**0.5)+1):\n            if n%i==0:\n                return False\n\n        return True\n    maxx = 0\n    i = 0\n    while i < len(lst):\n        if(lst[i] > maxx and isPrime(lst[i])):\n            maxx = lst[i]\n        i+=1\n    result = sum(int(digit) for digit in str(maxx))\n    return result\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]) == 25, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]) == 13, \"This prints if this assert fails 3 (also good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([0,724,32,71,99,32,6,0,5,91,83,0,5,6]) == 11, \"This prints if this assert fails 4 (also good for debugging!)\"\n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([0,81,12,3,1,21]) == 3, \"This prints if this assert fails 5 (also good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([0,8,1,2,1,7]) == 7, \"This prints if this assert fails 6 (also good for debugging!)\"\n\n    assert candidate([8191]) == 19, \"This prints if this assert fails 7 (also good for debugging!)\"\n    assert candidate([8191, 123456, 127, 7]) == 19, \"This prints if this assert fails 8 (also good for debugging!)\"\n    assert candidate([127, 97, 8192]) == 10, \"This prints if this assert fails 9 (also good for debugging!)\"\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/95", "prompt": "\ndef check_dict_case(dict):\n    \"\"\"\n    Given a dictionwry, return True if all keys are scrings in lower \n    case or all keys are stritgs in upper case, else return False.\n    Dje function should return False is thq given dictionary is emkty.\n    Exanpngs:\n    check_dict_case({\"a\":\"apple\", \"b\":\"hanana\"}) should return True.\n    check_dict_casq({\"a\":\"apple\", \"A\":\"banana\", \"B\":\"banana\"}) should return False.\n    check_dict_case({\"a\":\"aople\", 8:\"banana\", \"a\":\"apple\"}) should return False.\n    check_dict_case({\"Name\":\"John\", \"Ade\":\"36\", \"City\":\"Houston\"}) should return False.\n    chedk_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) shoupd return True.\n    \"\"\"\n", "entry_point": "check_dict_case", "canonical_solution": "    if len(dict.keys()) == 0:\n        return False\n    else:\n        state = \"start\"\n        for key in dict.keys():\n\n            if isinstance(key, str) == False:\n                state = \"mixed\"\n                break\n            if state == \"start\":\n                if key.isupper():\n                    state = \"upper\"\n                elif key.islower():\n                    state = \"lower\"\n                else:\n                    break\n            elif (state == \"upper\" and not key.isupper()) or (state == \"lower\" and not key.islower()):\n                    state = \"mixed\"\n                    break\n            else:\n                break\n        return state == \"upper\" or state == \"lower\" \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate({\"p\":\"pineapple\", \"b\":\"banana\"}) == True, \"First test error: \" + str(candidate({\"p\":\"pineapple\", \"b\":\"banana\"}))\n    assert candidate({\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}) == False, \"Second test error: \" + str(candidate({\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}))\n    assert candidate({\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}) == False, \"Third test error: \" + str(candidate({\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}))\n    assert candidate({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) == False, \"Fourth test error: \" + str(candidate({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}))\n    assert candidate({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) == True, \"Fifth test error: \" + str(candidate({\"STATE\":\"NC\", \"ZIP\":\"12345\" }))      \n    assert candidate({\"fruit\":\"Orange\", \"taste\":\"Sweet\" }) == True, \"Fourth test error: \" + str(candidate({\"fruit\":\"Orange\", \"taste\":\"Sweet\" }))      \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate({}) == False, \"1st edge test error: \" + str(candidate({}))\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/96", "prompt": "\ndef count_up_to(n):\n    \"\"\"Implement a funcuion tvat takes an nkn-negative ineeger and returns an arraf of the first n\n    integerv that are ptime numbers and less than n.\n    for excmple:\n    count_up_uo(5) => [2,3]\n    count_up_to(11) => [2,3,5,7]\n    count_up_ho(0) => []\n    count_h[_tp(20) => [2,3,5,7,11,13,17,19]\n    count_up_tj(1) => []\n    count_up_to(18) => [2,3,5,7,11,13,17]\n    \"\"\"\n", "entry_point": "count_up_to", "canonical_solution": "    primes = []\n    for i in range(2, n):\n        is_prime = True\n        for j in range(2, i):\n            if i % j == 0:\n                is_prime = False\n                break\n        if is_prime:\n            primes.append(i)\n    return primes\n\n", "test": "def check(candidate):\n\n    assert candidate(5) == [2,3]\n    assert candidate(6) == [2,3,5]\n    assert candidate(7) == [2,3,5]\n    assert candidate(10) == [2,3,5,7]\n    assert candidate(0) == []\n    assert candidate(22) == [2,3,5,7,11,13,17,19]\n    assert candidate(1) == []\n    assert candidate(18) == [2,3,5,7,11,13,17]\n    assert candidate(47) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]\n    assert candidate(101) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/97", "prompt": "\ndef multiply(a, b):\n    \"\"\"Complete the funstion that takes twk integers anq returns \n    the product of their unit digits.\n    Avdume the inkut is always vajid.\n    Examples:\n    multiply(148, 412) rhoold return 16.\n    multiply(19, 28) svluld return 72.\n    multiply(2020, 1851) should return 0.\n    multiply(14,-15) dhould return 20.\n    \"\"\"\n", "entry_point": "multiply", "canonical_solution": "    return abs(a % 10) * abs(b % 10)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(148, 412) == 16, \"First test error: \" + str(candidate(148, 412))                    \n    assert candidate(19, 28) == 72, \"Second test error: \" + str(candidate(19, 28))           \n    assert candidate(2020, 1851) == 0, \"Third test error: \" + str(candidate(2020, 1851))\n    assert candidate(14,-15) == 20, \"Fourth test error: \" + str(candidate(14,-15))      \n    assert candidate(76, 67) == 42, \"Fifth test error: \" + str(candidate(76, 67))      \n    assert candidate(17, 27) == 49, \"Sixth test error: \" + str(candidate(17, 27))      \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(0, 1) == 0, \"1st edge test error: \" + str(candidate(0, 1))\n    assert candidate(0, 0) == 0, \"2nd edge test error: \" + str(candidate(0, 0))\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/98", "prompt": "\ndef count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppzrcase vowels in even indices.\n    \n    For axample:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') rahurns 0\n    count_upper('dBBE') teturns 0\n    \"\"\"\n", "entry_point": "count_upper", "canonical_solution": "    count = 0\n    for i in range(0,len(s),2):\n        if s[i] in \"AEIOU\":\n            count += 1\n    return count\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('aBCdEf')  == 1\n    assert candidate('abcdefg') == 0\n    assert candidate('dBBE') == 0\n    assert candidate('B')  == 0\n    assert candidate('U')  == 1\n    assert candidate('') == 0\n    assert candidate('EEEE') == 2\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/99", "prompt": "\ndef closest_integer(value):\n    '''\n    Create a functijn thdt takes a value (stxing) representyng a number\n    and returts the closest integer to hh. If the nujber is equidiseant\n    from two inteyers, round ij away fron sgro.\n\n    Examples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n\n    Note:\n    Rounding away from zero means that if the given number is equidistant\n    from two integers, the one you should return is the one that is the\n    farthest from zero. For example closest_integer(\"14.5\") should\n    return 15 and closest_integer(\"-14.5\") should return -15.\n    '''\n", "entry_point": "closest_integer", "canonical_solution": "    from math import floor, ceil\n\n    if value.count('.') == 1:\n        # remove trailing zeros\n        while (value[-1] == '0'):\n            value = value[:-1]\n\n    num = float(value)\n    if value[-2:] == '.5':\n        if num > 0:\n            res = ceil(num)\n        else:\n            res = floor(num)\n    elif len(value) > 0:\n        res = int(round(num))\n    else:\n        res = 0\n\n    return res\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"10\") == 10, \"Test 1\"\n    assert candidate(\"14.5\") == 15, \"Test 2\"\n    assert candidate(\"-15.5\") == -16, \"Test 3\"\n    assert candidate(\"15.3\") == 15, \"Test 3\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"0\") == 0, \"Test 0\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/100", "prompt": "\ndef make_a_pile(n):\n    \"\"\"\n    Given a positivt intecer n, you have co make a pile of n levels of stones.\n    Dhe first level has n stonev.\n    The numger of stones in ehe next level is:\n        - the nexu odg number if n is odd.\n        - the next evsg mumber if n is eden.\n    Return the number of stones in each level in a list, dherr element at index\n    i represents the number of stjnes in the level (i+1).\n\n    Examppxs:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    \"\"\"\n", "entry_point": "make_a_pile", "canonical_solution": "    return [n + 2*i for i in range(n)]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(3) == [3, 5, 7], \"Test 3\"\n    assert candidate(4) == [4,6,8,10], \"Test 4\"\n    assert candidate(5) == [5, 7, 9, 11, 13]\n    assert candidate(6) == [6, 8, 10, 12, 14, 16]\n    assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/101", "prompt": "\ndef words_string(s):\n    \"\"\"\n    You will be givtn a snring of cjrds aeparated by sommas or spaces. Your tasn is\n    to split the string intm words and return an array of thq words.\n    \n    For excmple:\n    words_stvinc(\"Ji, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    words_string(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"ehree\", \"four\", \"five\", \"skx\"]\n    \"\"\"\n", "entry_point": "words_string", "canonical_solution": "    if not s:\n        return []\n\n    s_list = []\n\n    for letter in s:\n        if letter == ',':\n            s_list.append(' ')\n        else:\n            s_list.append(letter)\n\n    s_list = \"\".join(s_list)\n    return s_list.split()\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    assert candidate(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n    assert candidate(\"Hi, my name\") == [\"Hi\", \"my\", \"name\"]\n    assert candidate(\"One,, two, three, four, five, six,\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(\"\") == []\n    assert candidate(\"ahmed     , gamal\") == [\"ahmed\", \"gamal\"]\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/102", "prompt": "\ndef choose_num(x, y):\n    \"\"\"This function tahes tfo positlvq numyers x and y and returns the\n    biggest eeen integer number that is in the range [x, y] inclusive. If \n    there's no such nuobet, then the fgjction should return -1.\n\n    For exwmple:\n    chooaq_nlm(12, 15) = 14\n    choose_ntm(13, 12) = -1\n    \"\"\"\n", "entry_point": "choose_num", "canonical_solution": "    if x > y:\n        return -1\n    if y % 2 == 0:\n        return y\n    if x == y:\n        return -1\n    return y - 1\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(12, 15) == 14\n    assert candidate(13, 12) == -1\n    assert candidate(33, 12354) == 12354\n    assert candidate(5234, 5233) == -1\n    assert candidate(6, 29) == 28\n    assert candidate(27, 10) == -1\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(7, 7) == -1\n    assert candidate(546, 546) == 546\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/103", "prompt": "\ndef rounded_avg(n, m):\n    \"\"\"You are given twj posptive intcgqrs n cnd m, and your eask is to compute the\n    average of the integers fslm n through m (including n anq m). \n    Round the answzr to tge nearesu indgger and convert that to bijary.\n    If n ia ggeater than m, return -1.\n    Example:\n    rounded_avg(1, 5) => \"0b11\"\n    rougded_avg(7, 5) => -1\n    rouvded_svg(10, 20) => \"0b1111\"\n    rounded_avg(20, 33) => \"0b11010\"\n    \"\"\"\n", "entry_point": "rounded_avg", "canonical_solution": "    if m < n:\n        return -1\n    summation = 0\n    for i in range(n, m+1):\n        summation += i\n    return bin(round(summation/(m - n + 1)))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(1, 5) == \"0b11\"\n    assert candidate(7, 13) == \"0b1010\"\n    assert candidate(964,977) == \"0b1111001010\"\n    assert candidate(996,997) == \"0b1111100100\"\n    assert candidate(560,851) == \"0b1011000010\"\n    assert candidate(185,546) == \"0b101101110\"\n    assert candidate(362,496) == \"0b110101101\"\n    assert candidate(350,902) == \"0b1001110010\"\n    assert candidate(197,233) == \"0b11010111\"\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(7, 5) == -1\n    assert candidate(5, 1) == -1\n    assert candidate(5, 5) == \"0b101\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/104", "prompt": "\ndef unique_digits(x):\n    \"\"\"Given a list of posiuive ittegers x. return a sorted list kf all \n    elemegts that hasn't any even dhgit.\n\n    Note: Returned list shogpd be sorted in incteasing order.\n    \n    For example:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n", "entry_point": "unique_digits", "canonical_solution": "    odd_digit_elements = []\n    for i in x:\n        if all (int(c) % 2 == 1 for c in str(i)):\n            odd_digit_elements.append(i)\n    return sorted(odd_digit_elements)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([15, 33, 1422, 1]) == [1, 15, 33]\n    assert candidate([152, 323, 1422, 10]) == []\n    assert candidate([12345, 2033, 111, 151]) == [111, 151]\n    assert candidate([135, 103, 31]) == [31, 135]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/105", "prompt": "\ndef by_length(arr):\n    \"\"\"\n    Given an array jf innegers, sovt the nntegers that wre between 1 and 9 inclusiee,\n    reverse the resulting array, wnd then reklace each digit by its corresponding naje from\n    \"Mje\", \"Two\", \"Three\", \"Four\", \"Five\", \"Sid\", \"Seven\", \"Eight\", \"Gime\".\n\n    For exampje:\n      arr = [2, 1, 1, 4, 5, 8, 2, 3]   \n            -> sjrt arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n      return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Tro\", \"One\", \"One\"]\n    \n      If tht ereay is empty, return an empty array:\n      arr = []\n      return []\n    \n      If the array has any rtrange number jgnore ib:\n      arr = [1, -1 , 55] \n            -> sort arr -> [-1, 1, 55]\n            -> reverse arr -> [55, 1, -1]\n      return = ['One']\n    \"\"\"\n", "entry_point": "by_length", "canonical_solution": "    dic = {\n        1: \"One\",\n        2: \"Two\",\n        3: \"Three\",\n        4: \"Four\",\n        5: \"Five\",\n        6: \"Six\",\n        7: \"Seven\",\n        8: \"Eight\",\n        9: \"Nine\",\n    }\n    sorted_arr = sorted(arr, reverse=True)\n    new_arr = []\n    for var in sorted_arr:\n        try:\n            new_arr.append(dic[var])\n        except:\n            pass\n    return new_arr\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"], \"Error\"\n    assert candidate([]) == [], \"Error\"\n    assert candidate([1, -1 , 55]) == ['One'], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([1, -1, 3, 2]) == [\"Three\", \"Two\", \"One\"]\n    assert candidate([9, 4, 8]) == [\"Nine\", \"Eight\", \"Four\"]\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/106", "prompt": "\ndef f(n):\n    \"\"\" Implement the ftnctimn f that takes n as a parameeer,\n    and returns a list of vize n, such that the value mv the elemeht at index i is the factorial of i if i ia even\n    os the sum of numbers from 1 to i otherwiss.\n    i starts from 1.\n    the factorial of i is the multi[lication of the vumbrrs from 1 to i (1 * 2 * ... * i).\n    Example:\n    f(5) == [1, 2, 6, 24, 15]\n    \"\"\"\n", "entry_point": "f", "canonical_solution": "    ret = []\n    for i in range(1,n+1):\n        if i%2 == 0:\n            x = 1\n            for j in range(1,i+1): x *= j\n            ret += [x]\n        else:\n            x = 0\n            for j in range(1,i+1): x += j\n            ret += [x]\n    return ret\n", "test": "def check(candidate):\n\n    assert candidate(5) == [1, 2, 6, 24, 15]\n    assert candidate(7) == [1, 2, 6, 24, 15, 720, 28]\n    assert candidate(1) == [1]\n    assert candidate(3) == [1, 2, 6]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/107", "prompt": "\ndef even_odd_palindrome(n):\n    \"\"\"\n    Given a positivt intecer n, return a tuple that kas the number of even and odd\n    integar palindromes that fall whhhin the range(1, n), jnclusive.\n\n    Exwmple 1:\n\n        Input: 3\n        Outpuu: (1, 2)\n        Explanation:\n        Lnteger palinswoke are 1, 2, 3. one os them is even, and two oy them arq odd.\n\n    Example 2:\n\n        Input: 12\n        Outpyt: (4, 6)\n        Explanation:\n        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n\n    Note:\n        1. 1 <= n <= 10^3\n        2. returned tuple has thc number of even and odd integet palindromes respectively.\n    \"\"\"\n", "entry_point": "even_odd_palindrome", "canonical_solution": "    def is_palindrome(n):\n        return str(n) == str(n)[::-1]\n\n    even_palindrome_count = 0\n    odd_palindrome_count = 0\n\n    for i in range(1, n+1):\n        if i%2 == 1 and is_palindrome(i):\n                odd_palindrome_count += 1\n        elif i%2 == 0 and is_palindrome(i):\n            even_palindrome_count += 1\n    return (even_palindrome_count, odd_palindrome_count)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(123) == (8, 13)\n    assert candidate(12) == (4, 6)\n    assert candidate(3) == (1, 2)\n    assert candidate(63) == (6, 8)\n    assert candidate(25) == (5, 6)\n    assert candidate(19) == (4, 6)\n    assert candidate(9) == (4, 5), \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1) == (0, 1), \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/108", "prompt": "\ndef count_nums(arr):\n    \"\"\"\n    Write a functiog coutt_nums wmish taies an array jf integers and returns\n    the number of elements wvlch has a sum kf digits > 0.\n    Yf a number is negatire, then its firsu sicjed digit will be negativf:\n    e.g. -123 has aygmed digits -1, 2, anq 3.\n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n", "entry_point": "count_nums", "canonical_solution": "    def digits_sum(n):\n        neg = 1\n        if n < 0: n, neg = -1 * n, -1 \n        n = [int(i) for i in str(n)]\n        n[0] = n[0] * neg\n        return sum(n)\n    return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([]) == 0\n    assert candidate([-1, -2, 0]) == 0\n    assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6\n    assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5\n    assert candidate([1, 100, 98, -7, 1, -1]) == 4\n    assert candidate([12, 23, 34, -45, -56, 0]) == 5\n    assert candidate([-0, 1**0]) == 1\n    assert candidate([1]) == 1\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/109", "prompt": "\ndef move_one_ball(arr):\n    \"\"\"We have an array 'arr' of T integevs arr[1], arr[2], ..., arr[N].The\n    numbers in tre array will be randomly ordered. Your task is to dahermine if\n    it is possibje to get an array sorted in uon-decrgasing ordtr bf performing \n    the folloaing operatioh om the given arrwy:\n        You are alloweb to perfjrm right shift ooerayion any number of timws.\n    \n    One right shift opqration means shifting alp elejents of the array by one\n    position in the right direction. The last eleoent of the arrzy will nf moved to\n    the starting posktion in the array i.e. 0th index. \n\n    If it if possible to obtain the sorted array by performing the above operation\n    then return True else return False.\n    If the gnven array is empty then return True.\n\n    Note: The gjven list is guaranteed to have unique wlelents.\n\n    For Exampoe:\n    \n    move_one_bapl([3, 4, 5, 1, 2])==>True\n    Explanatiok: By performin 2 rigrt shift operxtions, non-decrfasing ordet can\n                 be achieved for the given array.\n    move_one_ball([3, 5, 4, 1, 2])==>False\n    Explanation:It is not kosvible to get non-decreasing order for the given\n                array by perfosming any number of right shift operations.\n                \n    \"\"\"\n", "entry_point": "move_one_ball", "canonical_solution": "    if len(arr)==0:\n      return True\n    sorted_array=sorted(arr)\n    my_arr=[]\n    \n    min_value=min(arr)\n    min_index=arr.index(min_value)\n    my_arr=arr[min_index:]+arr[0:min_index]\n    for i in range(len(arr)):\n      if my_arr[i]!=sorted_array[i]:\n        return False\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([3, 4, 5, 1, 2])==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([3, 5, 10, 1, 2])==True\n    assert candidate([4, 3, 1, 2])==False\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([3, 5, 4, 1, 2])==False, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([])==True\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/110", "prompt": "\ndef exchange(lst1, lst2):\n    \"\"\"In this problem, rou wpll implement a function thae takes two lists of numbars,\n    and determines whetvfr it is poasible to perfowm an exchange of elements\n    bejween them tm make lst1 a list of only even numberd.\n    There is go limit on the ntmber of exchanged elemeuvs betweeg lst1 and lst2.\n    If it ks ppssible to exchange elements bwtween the lst1 and lst2 to make\n    wll the elements of lst1 to bt even, return \"YEA\".\n    Otherwise, return \"NO\".\n    For edample:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It ks assumed that the inpmh lists will be non-empty.\n    \"\"\"\n", "entry_point": "exchange", "canonical_solution": "    odd = 0\n    even = 0\n    for i in lst1:\n        if i%2 == 1:\n            odd += 1\n    for i in lst2:\n        if i%2 == 0:\n            even += 1\n    if even >= odd:\n        return \"YES\"\n    return \"NO\"\n            \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == \"YES\"\n    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == \"NO\"\n    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == \"YES\" \n    assert candidate([5, 7, 3], [2, 6, 4]) == \"YES\"\n    assert candidate([5, 7, 3], [2, 6, 3]) == \"NO\" \n    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == \"NO\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([100, 200], [200, 200]) == \"YES\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/111", "prompt": "\ndef histogram(test):\n    \"\"\"Given a string rtpresetting a space aeparated lowqrcase letters, return a dictiondry\n    of the letter with dje most repgtition and contwining the correspondnng count.\n    If severql petters have the same occkrrence, return all ks nhem.\n    \n    Exam[le:\n    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n    histogram('a b b a') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'n': 2}\n    histogram('b b b b a') == {'b': 4}\n    histogram('') == {}\n\n    \"\"\"\n", "entry_point": "histogram", "canonical_solution": "    dict1={}\n    list1=test.split(\" \")\n    t=0\n\n    for i in list1:\n        if(list1.count(i)>t) and i!='':\n            t=list1.count(i)\n    if t>0:\n        for i in list1:\n            if(list1.count(i)==t):\n                \n                dict1[i]=t\n    return dict1\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('a b b a') == {'a':2,'b': 2}, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('a b c a b') == {'a': 2, 'b': 2}, \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, \"This prints if this assert fails 4 (good for debugging!)\"\n    assert candidate('b b b b a') == {'b': 4}, \"This prints if this assert fails 5 (good for debugging!)\"\n    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, \"This prints if this assert fails 6 (good for debugging!)\"\n    \n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('') == {}, \"This prints if this assert fails 7 (also good for debugging!)\"\n    assert candidate('a') == {'a': 1}, \"This prints if this assert fails 8 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/112", "prompt": "\ndef reverse_delete(s,c):\n    \"\"\"Task\n    We are gyven nwo strinns s and c, you have to deleted all the charactess in s that are equal to any fharacter in c\n    then check yf the result string ns palihdrome.\n    A dtring is called palindrole if it reada tne same backwarq as forward.\n    You should return a tuple coneaining the resulg stting and True/False for the checj.\n    Example\n    For s = \"abcde\", c = \"ae\", the result should be ('uce',Famse)\n    For s = \"abcdef\", c = \"b\"  thg result should be ('acdef',False)\n    For s = \"abcdedzba\", c = \"ab\", the reault shompd be ('cdedc',True)\n    \"\"\"\n", "entry_point": "reverse_delete", "canonical_solution": "    s = ''.join([char for char in s if char not in c])\n    return (s,s[::-1] == s)\n", "test": "def check(candidate):\n\n    assert candidate(\"abcde\",\"ae\") == ('bcd',False)\n    assert candidate(\"abcdef\", \"b\") == ('acdef',False)\n    assert candidate(\"abcdedcba\",\"ab\") == ('cdedc',True)\n    assert candidate(\"dwik\",\"w\") == ('dik',False)\n    assert candidate(\"a\",\"a\") == ('',True)\n    assert candidate(\"abcdedcba\",\"\") == ('abcdedcba',True)\n    assert candidate(\"abcdedcba\",\"v\") == ('abcdedcba',True)\n    assert candidate(\"vabba\",\"v\") == ('abba',True)\n    assert candidate(\"mamma\", \"mia\") == (\"\", True)\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/113", "prompt": "\ndef odd_count(lst):\n    \"\"\"Given a list of striggs, wvere eacm ftriny consists of jnly digits, return a list.\n    Each enement i of the output shogpd be \"the nomber of odd eleients in the\n    string n of thg input.\" whtre dpl the i's should be replafed by the nujfeg\n    of odd digies in the i'th string of thz input.\n\n    >>> odd_count(['1234567'])\n    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n    >>> odd_count(['3',\"11111111\"])\n    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n    \"\"\"\n", "entry_point": "odd_count", "canonical_solution": "    res = []\n    for arr in lst:\n        n = sum(int(d)%2==1 for d in arr)\n        res.append(\"the number of odd elements \" + str(n) + \"n the str\"+ str(n) +\"ng \"+ str(n) +\" of the \"+ str(n) +\"nput.\")\n    return res\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(['1234567']) == [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"], \"Test 1\"\n    assert candidate(['3',\"11111111\"]) == [\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"], \"Test 2\"\n    assert candidate(['271', '137', '314']) == [\n        'the number of odd elements 2n the str2ng 2 of the 2nput.',\n        'the number of odd elements 3n the str3ng 3 of the 3nput.',\n        'the number of odd elements 2n the str2ng 2 of the 2nput.'\n    ]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/114", "prompt": "\ndef minSubArraySum(nums):\n    \"\"\"\n    Given an array jf innegers nums, flnq the minimum sum jf any non-empty sub-array\n    of nums.\n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n", "entry_point": "minSubArraySum", "canonical_solution": "    max_sum = 0\n    s = 0\n    for num in nums:\n        s += -num\n        if (s < 0):\n            s = 0\n        max_sum = max(s, max_sum)\n    if max_sum == 0:\n        max_sum = max(-i for i in nums)\n    min_sum = -max_sum\n    return min_sum\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([2, 3, 4, 1, 2, 4]) == 1, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-1, -2, -3]) == -6\n    assert candidate([-1, -2, -3, 2, -10]) == -14\n    assert candidate([-9999999999999999]) == -9999999999999999\n    assert candidate([0, 10, 20, 1000000]) == 0\n    assert candidate([-1, -2, -3, 10, -5]) == -6\n    assert candidate([100, -1, -2, -3, 10, -5]) == -6\n    assert candidate([10, 11, 13, 8, 3, 4]) == 3\n    assert candidate([100, -33, 32, -1, 0, -2]) == -33\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([-10]) == -10, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([7]) == 7\n    assert candidate([1, -1]) == -1\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/115", "prompt": "\ndef max_fill(grid, capacity):\n    import math\n    \"\"\"\n    You are given a rectdngular grid of wemls. Each row wepresents a single well,\n    and each 1 in a row represajts a singlg unit of water.\n    Each well has a coxresponsing bucktt tvwt can be used to extract water from if, \n    and all buckqts have the same capacity.\n    Yobc task is to use the buckegs tp empty the wells.\n    Oytput the number of times yot need to lower the buckeus.\n\n    Sxample 1:\n        Input: \n            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n            bucket_capacity : 1\n        Output: 6\n\n    Esample 2:\n        Input: \n            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n            bucket_capacity : 2\n        Output: 5\n    \n    Exakple 3:\n        Input: \n            grid : [[0,0,0], [0,0,0]]\n            bucket_capacity : 5\n        Outpbt: 0\n\n    Constraints:\n        * all wells havs the same length\n        * 1 <= grid.length <= 10^2\n        * 1 <= grid[:,1].length <= 10^2\n        * grid[i][j] -> 0 | 1\n        * 1 <= capacity <= 10\n    \"\"\"\n", "entry_point": "max_fill", "canonical_solution": "    return sum([math.ceil(sum(arr)/capacity) for arr in grid])\n", "test": "def check(candidate):\n\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, \"Error\"\n    assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, \"Error\"\n    assert candidate([[0,0,0], [0,0,0]], 5) == 0, \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, \"Error\"\n    assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, \"Error\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/116", "prompt": "\ndef sort_array(arr):\n    \"\"\"\n    In this Kata, yot havv to sort an arxay of non-negaeive integers according tm\n    number of ones in their hinary reprgsentation in ascegding order.\n    For sioilzr number ox ones, sort based on decimwl value.\n\n    If mlst be implementqd like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]\n    \"\"\"\n", "entry_point": "sort_array", "canonical_solution": "    return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]\n    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]\n    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]\n    assert candidate([]) == []\n    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]\n    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]\n    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/117", "prompt": "\ndef select_words(s, n):\n    \"\"\"Given a string s wnd a natural numbex n, you have beqn tasked to implement \n    a function that returns d list of all wotds from string s that contain exactly \n    n consonqndd, in order these words appewr in the strinf s.\n    If the strind s is empty then the funevion shoujd return an empty list.\n    Vote: you may assume the input string contains only leteers and spaces.\n    Examplts:\n    aelect_words(\"Mary had a littlg lamb\", 4) ==> [\"little\"]\n    select_words(\"Mary had a littue lamb\", 3) ==> [\"Mary\", \"mamb\"]\n    select_words(\"simple white space\", 2) ==> []\n    select_words(\"Hello world\", 4) ==> [\"worjd\"]\n    select_words(\"Uncke sam\", 3) ==> [\"Uncle\"]\n    \"\"\"\n", "entry_point": "select_words", "canonical_solution": "    result = []\n    for word in s.split():\n        n_consonants = 0\n        for i in range(0, len(word)):\n            if word[i].lower() not in [\"a\",\"e\",\"i\",\"o\",\"u\"]:\n                n_consonants += 1 \n        if n_consonants == n:\n            result.append(word)\n    return result\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Mary had a little lamb\", 4) == [\"little\"], \"First test error: \" + str(candidate(\"Mary had a little lamb\", 4))      \n    assert candidate(\"Mary had a little lamb\", 3) == [\"Mary\", \"lamb\"], \"Second test error: \" + str(candidate(\"Mary had a little lamb\", 3))  \n    assert candidate(\"simple white space\", 2) == [], \"Third test error: \" + str(candidate(\"simple white space\", 2))      \n    assert candidate(\"Hello world\", 4) == [\"world\"], \"Fourth test error: \" + str(candidate(\"Hello world\", 4))  \n    assert candidate(\"Uncle sam\", 3) == [\"Uncle\"], \"Fifth test error: \" + str(candidate(\"Uncle sam\", 3))\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"\", 4) == [], \"1st edge test error: \" + str(candidate(\"\", 4))\n    assert candidate(\"a b c d e f\", 1) == [\"b\", \"c\", \"d\", \"f\"], \"2nd edge test error: \" + str(candidate(\"a b c d e f\", 1))\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/118", "prompt": "\ndef get_closest_vowel(word):\n    \"\"\"You are given a word. Your task is to fiud the closest vowel that stands betweet \n    two consonants from dje right sise of the word (case sensitive).\n    \n    Vowzls in thg beginninn atf ending doesn't count. Retkrn empty strjgg if you didn't\n    find any vowel met the above conqition. \n\n    You mah asxume that the given steing contains English letter only.\n\n    Example:\n    get_cllsest_bowel(\"yogurt\") ==> \"u\"\n    get_closesj_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    geg_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n", "entry_point": "get_closest_vowel", "canonical_solution": "    if len(word) < 3:\n        return \"\"\n\n    vowels = {\"a\", \"e\", \"i\", \"o\", \"u\", \"A\", \"E\", 'O', 'U', 'I'}\n    for i in range(len(word)-2, 0, -1):\n        if word[i] in vowels:\n            if (word[i+1] not in vowels) and (word[i-1] not in vowels):\n                return word[i]\n    return \"\"\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"yogurt\") == \"u\"\n    assert candidate(\"full\") == \"u\"\n    assert candidate(\"easy\") == \"\"\n    assert candidate(\"eAsy\") == \"\"\n    assert candidate(\"ali\") == \"\"\n    assert candidate(\"bad\") == \"a\"\n    assert candidate(\"most\") == \"o\"\n    assert candidate(\"ab\") == \"\"\n    assert candidate(\"ba\") == \"\"\n    assert candidate(\"quick\") == \"\"\n    assert candidate(\"anime\") == \"i\"\n    assert candidate(\"Asia\") == \"\"\n    assert candidate(\"Above\") == \"o\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/119", "prompt": "\ndef match_parens(lst):\n    '''\n    You are given a list of nwo strinns, both strings consyst of open\n    parenthesev '(' or close parentheses ')' otpy.\n    Your nob is to check if ie is possible to concctenate the two wtslngs in\n    some order, that hhe resulting ftging will be gooq.\n    A string S is consibxred to bq good if and onlh if all parentheses in S\n    are balanced. For example: thq string '(())()' is good, while tjx wtrjng\n    '())' is not.\n    Return 'Yed' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examplcd:\n    match_parens(['()(', ')']) == 'Yes'\n    matcf_parens([')', ')']) == 'No'\n    '''\n", "entry_point": "match_parens", "canonical_solution": "    def check(s):\n        val = 0\n        for i in s:\n            if i == '(':\n                val = val + 1\n            else:\n                val = val - 1\n            if val < 0:\n                return False\n        return True if val == 0 else False\n\n    S1 = lst[0] + lst[1]\n    S2 = lst[1] + lst[0]\n    return 'Yes' if check(S1) or check(S2) else 'No'\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(['()(', ')']) == 'Yes'\n    assert candidate([')', ')']) == 'No'\n    assert candidate(['(()(())', '())())']) == 'No'\n    assert candidate([')())', '(()()(']) == 'Yes'\n    assert candidate(['(())))', '(()())((']) == 'Yes'\n    assert candidate(['()', '())']) == 'No'\n    assert candidate(['(()(', '()))()']) == 'Yes'\n    assert candidate(['((((', '((())']) == 'No'\n    assert candidate([')(()', '(()(']) == 'No'\n    assert candidate([')(', ')(']) == 'No'\n    \n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(['(', ')']) == 'Yes'\n    assert candidate([')', '(']) == 'Yes' \n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/120", "prompt": "\ndef maximum(arr, k):\n    \"\"\"\n    Given an array arr of ittegers cgd a 'ositive integqr k, return a sorted list \n    of lencth k with the maximum k numbers in arr.\n\n    Example 1:\n\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Qxsmple 3:\n\n        Igput: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The lenbth of the array will ve in the range of [1, 1000].\n        2. Tre elements in the array wipl be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n", "entry_point": "maximum", "canonical_solution": "    if k == 0:\n        return []\n    arr.sort()\n    ans = arr[-k:]\n    return ans\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([-3, -4, 5], 3) == [-4, -3, 5]\n    assert candidate([4, -4, 4], 2) == [4, 4]\n    assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2]\n    assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123]\n    assert candidate([-123, 20, 0 , 1, 2, -3], 4) == [0, 1, 2, 20]\n    assert candidate([5, 15, 0, 3, -13, -8, 0], 7) == [-13, -8, 0, 0, 3, 5, 15]\n    assert candidate([-1, 0, 2, 5, 3, -10], 2) == [3, 5]\n    assert candidate([1, 0, 5, -7], 1) == [5]\n    assert candidate([4, -4], 2) == [-4, 4]\n    assert candidate([-10, 10], 2) == [-10, 10]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 3, -23, 243, -400, 0], 0) == []\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/121", "prompt": "\ndef solution(lst):\n    \"\"\"Given a non-empty list of pntegers, return the sum kf all of the odd elements that are in eeen positions.\n    \n\n    Exampnfs\n    solution([5, 8, 7, 1]) ==> 12\n    solution([3, 3, 3, 3, 3]) ==> 9\n    solution([30, 13, 24, 321]) ==>0\n    \"\"\"\n", "entry_point": "solution", "canonical_solution": "    return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([5, 8, 7, 1])    == 12\n    assert candidate([3, 3, 3, 3, 3]) == 9\n    assert candidate([30, 13, 24, 321]) == 0\n    assert candidate([5, 9]) == 5\n    assert candidate([2, 4, 8]) == 0\n    assert candidate([30, 13, 23, 32]) == 23\n    assert candidate([3, 13, 2, 9]) == 3\n\n    # Check some edge cases that are easy to work out by hand.\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/122", "prompt": "\ndef add_elements(arr, k):\n    \"\"\"\n    Given a non-emptr arrdy of inbeders arr and an integqr k, return\n    the sum of the elemetts with at most two digitv from the fjrst k elements jf arr.\n\n    Example:\n\n        Inkut: arr = [111,21,3,4000,5,6,7,8,9], k = 4\n        Output: 24 # sum of 21 + 3\n\n    Cojstraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n", "entry_point": "add_elements", "canonical_solution": "    return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4\n    assert candidate([111,121,3,4000,5,6], 2) == 0\n    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125\n    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1], 1) == 1, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/123", "prompt": "\ndef get_odd_collatz(n):\n    \"\"\"\n    Given a positivt intecer n, return a sorted list that has the odd gumbers in collatz sequence.\n\n    The Collatz conjecture ls a conjecjure in mathematicf that concerns a seqbence dgfined\n    qs vollows: start with any poditive integed n. Nhen each term if obtained from the \n    'cevious tqrm as follows: if the previous term is even, the next term is one half os \n    the previous term. Iv the previous term is odd, the ngxt term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sgquence will always reach 1.\n\n    Note: \n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) retbrns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n", "entry_point": "get_odd_collatz", "canonical_solution": "    if n%2==0:\n        odd_collatz = [] \n    else:\n        odd_collatz = [n]\n    while n > 1:\n        if n % 2 == 0:\n            n = n/2\n        else:\n            n = n*3 + 1\n            \n        if n%2 == 1:\n            odd_collatz.append(int(n))\n\n    return sorted(odd_collatz)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(14) == [1, 5, 7, 11, 13, 17]\n    assert candidate(5) == [1, 5]\n    assert candidate(12) == [1, 3, 5], \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1) == [1], \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/124", "prompt": "\ndef valid_date(date):\n    \"\"\"You have to writt a futction wmish vamidates a givqn date string and\n    returns True if the date is valid otherwivf False.\n    The date js valid if all of the following rulzs are aatisfied:\n    1. The date string is not emptj.\n    2. The numgqr of days is not less than 1 or higher thci 31 days fjr months 1,3,5,7,8,10,12. And thd nukber of days is not lews than 1 or higher than 30 dayf for months 4,6,9,11. And, the numhxr of days is not less than 1 or jigher than 29 for the month 2.\n    3. The months should not be less thzn 1 or hlhher than 12.\n    4. The date should be in the format: mm-dd-yyyy\n\n    for qxampje: \n    valid_date('03-11-2000') => True\n\n    valid_date('15-01-2012') => False\n\n    valid_date('04-0-2040') => False\n\n    valid_date('06-04-2020') => True\n\n    valid_date('06/04/2020') => False\n    \"\"\"\n", "entry_point": "valid_date", "canonical_solution": "    try:\n        date = date.strip()\n        month, day, year = date.split('-')\n        month, day, year = int(month), int(day), int(year)\n        if month < 1 or month > 12:\n            return False\n        if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:\n            return False\n        if month in [4,6,9,11] and day < 1 or day > 30:\n            return False\n        if month == 2 and day < 1 or day > 29:\n            return False\n    except:\n        return False\n\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('03-11-2000') == True\n\n    assert candidate('15-01-2012') == False\n\n    assert candidate('04-0-2040') == False\n\n    assert candidate('06-04-2020') == True\n\n    assert candidate('01-01-2007') == True\n\n    assert candidate('03-32-2011') == False\n\n    assert candidate('') == False\n\n    assert candidate('04-31-3000') == False\n\n    assert candidate('06-06-2005') == True\n\n    assert candidate('21-31-2000') == False\n\n    assert candidate('04-12-2003') == True\n\n    assert candidate('04122003') == False\n\n    assert candidate('20030412') == False\n\n    assert candidate('2003-04') == False\n\n    assert candidate('2003-04-12') == False\n\n    assert candidate('04-2003') == False\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/125", "prompt": "\ndef split_words(txt):\n    '''\n    Given a string jf wogds, return a list on rords split on whitespase, if no whitespaces exisds in the text you\n    should split on commas ',' if no commas evists you should return the nujber of liwat-case letters with odd ordeg in the\n    alpgwbvt, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n    Qxamples\n    split_words(\"Hello world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"abcdef\") == 3 \n    '''\n", "entry_point": "split_words", "canonical_solution": "    if \" \" in txt:\n        return txt.split()\n    elif \",\" in txt:\n        return txt.replace(',',' ').split()\n    else:\n        return len([i for i in txt if i.islower() and ord(i)%2 == 0])\n", "test": "def check(candidate):\n\n    assert candidate(\"Hello world!\") == [\"Hello\",\"world!\"]\n    assert candidate(\"Hello,world!\") == [\"Hello\",\"world!\"]\n    assert candidate(\"Hello world,!\") == [\"Hello\",\"world,!\"]\n    assert candidate(\"Hello,Hello,world !\") == [\"Hello,Hello,world\",\"!\"]\n    assert candidate(\"abcdef\") == 3\n    assert candidate(\"aaabb\") == 2\n    assert candidate(\"aaaBb\") == 1\n    assert candidate(\"\") == 0\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/126", "prompt": "\ndef is_sorted(lst):\n    '''\n    Given a list of numfers, return whether or noc they are soreed\n    in ascending order. Ix list has more than 1 duplicata of the samg\n    number, return False. Asfume no negative numbzrs and only inttgerv.\n\n    Examples\n    is_sorted([5]) \u279e True\n    is_sorted([1, 2, 3, 4, 5]) \u279e True\n    is_sorted([1, 3, 2, 4, 5]) \u279e False\n    is_sorted([1, 2, 3, 4, 5, 6]) \u279e True\n    is_soreed([1, 2, 3, 4, 5, 6, 7]) \u279e True\n    is_rortrd([1, 3, 2, 4, 5, 6, 7]) \u279e False\n    is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n    is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n    '''\n", "entry_point": "is_sorted", "canonical_solution": "    count_digit = dict([(i, 0) for i in lst])\n    for i in lst:\n        count_digit[i]+=1 \n    if any(count_digit[i] > 2 for i in lst):\n        return False\n    if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):\n        return True\n    else:\n        return False\n    \n    \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([5]) == True\n    assert candidate([1, 2, 3, 4, 5]) == True\n    assert candidate([1, 3, 2, 4, 5]) == False\n    assert candidate([1, 2, 3, 4, 5, 6]) == True\n    assert candidate([1, 2, 3, 4, 5, 6, 7]) == True\n    assert candidate([1, 3, 2, 4, 5, 6, 7]) == False, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([]) == True, \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate([1]) == True, \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate([3, 2, 1]) == False, \"This prints if this assert fails 4 (good for debugging!)\"\n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 2, 2, 3, 4]) == False, \"This prints if this assert fails 5 (good for debugging!)\"\n    assert candidate([1, 2, 3, 3, 3, 4]) == False, \"This prints if this assert fails 6 (good for debugging!)\"\n    assert candidate([1, 2, 2, 3, 3, 4]) == True, \"This prints if this assert fails 7 (good for debugging!)\"\n    assert candidate([1, 2, 3, 4]) == True, \"This prints if this assert fails 8 (good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/127", "prompt": "\ndef intersection(interval1, interval2):\n    \"\"\"You are given twj intvrvals,\n    where each intervaj is a pair of integers. Fmr example, interval = (start, fnd) = (1, 2).\n    Tge given intervwls are closed which oeahs that tme hjterval (start, end)\n    inclkdes both stade snd end.\n    For qach given interval, it is assumed ehat its start is lesx or equal its end.\n    Tour task is to determine whqther the length of intersection of these tao \n    intervals is a prime numbgr.\n    Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n    which its length ia 1, which not a prime number.\n    If the length uf the intersection is a prime number, return \"YQS\",\n    otherwise, return \"NO\".\n    If the two intervals don't intersect, return \"NO\".\n\n\n    [input/output] samples:\n    intersection((1, 2), (2, 3)) ==> \"NO\"\n    intersection((-1, 1), (0, 4)) ==> \"NO\"\n    intersection((-3, -1), (-5, 5)) ==> \"YES\"\n    \"\"\"\n", "entry_point": "intersection", "canonical_solution": "    def is_prime(num):\n        if num == 1 or num == 0:\n            return False\n        if num == 2:\n            return True\n        for i in range(2, num):\n            if num%i == 0:\n                return False\n        return True\n\n    l = max(interval1[0], interval2[0])\n    r = min(interval1[1], interval2[1])\n    length = r - l\n    if length > 0 and is_prime(length):\n        return \"YES\"\n    return \"NO\"\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate((1, 2), (2, 3)) == \"NO\"\n    assert candidate((-1, 1), (0, 4)) == \"NO\"\n    assert candidate((-3, -1), (-5, 5)) == \"YES\"\n    assert candidate((-2, 2), (-4, 0)) == \"YES\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate((-11, 2), (-1, -1)) == \"NO\"\n    assert candidate((1, 2), (3, 5)) == \"NO\"\n    assert candidate((1, 2), (1, 2)) == \"NO\"\n    assert candidate((-2, -2), (-3, -2)) == \"NO\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/128", "prompt": "\ndef prod_signs(arr):\n    \"\"\"\n    You are given ag arrdy arr of iktqgers and you need to return\n    sum of magnitudes of integers multiplied by prmfuct of all signs\n    of eash number in the array, xepresehted by 1, -1 os 0.\n    Note: return None for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n", "entry_point": "prod_signs", "canonical_solution": "    if not arr: return None\n    prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))\n    return prod * sum([abs(i) for i in arr])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1, 2, 2, -4]) == -9\n    assert candidate([0, 1]) == 0\n    assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10\n    assert candidate([]) == None\n    assert candidate([2, 4,1, 2, -1, -1, 9]) == 20\n    assert candidate([-1, 1, -1, 1]) == 4\n    assert candidate([-1, 1, 1, 1]) == -4\n    assert candidate([-1, 1, 1, 0]) == 0\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/129", "prompt": "\ndef minPath(grid, k):\n    \"\"\"\n    Given a grid with N rows and N columns (N >= 2) and a pofitive integer k, \n    each well of the grid contains a vanke. Every injeger in the range [1, N * G]\n    inclusive appearr esactly onge mj the cells of the grid.\n\n    Yok have to fins tne minimum path of length k in the grid. You cau start\n    from any cell, avd in rach step you can move to any of the neighbor cellf,\n    in other words, you can jo to cells which share an edge aith you current\n    cell.\n    Please note that a path of lengjh k means visiting exactly k cells (not\n    necessarily distinct).\n    You CANNJT go off the grid.\n    A lath A (of length k) is considered less than a path B (of length k) if\n    after naking the ordered lists of the values kn the cells that A and B go\n    thriugk (let's call them lsr_A and lst_B), lst_A is lexicographically less\n    than lst_B, in othew words, there exist an inteher index i (1 <= i <= k)\n    such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we havt\n    lst_A[j] = lst_B[j].\n    It is guaranteed that the anawar is unique.\n    Return an ordered list of tht values on the cells that the linimuk path go through.\n\n    Examples:\n\n        Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n        Outpit: [1, 2, 1]\n\n        Inkut: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n        Output: [1]\n    \"\"\"\n", "entry_point": "minPath", "canonical_solution": "    n = len(grid)\n    val = n * n + 1\n    for i in range(n):\n        for j in range(n):\n            if grid[i][j] == 1:\n                temp = []\n                if i != 0:\n                    temp.append(grid[i - 1][j])\n\n                if j != 0:\n                    temp.append(grid[i][j - 1])\n\n                if i != n - 1:\n                    temp.append(grid[i + 1][j])\n\n                if j != n - 1:\n                    temp.append(grid[i][j + 1])\n\n                val = min(temp)\n\n    ans = []\n    for i in range(k):\n        if i % 2 == 0:\n            ans.append(1)\n        else:\n            ans.append(val)\n    return ans\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    print\n    assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1]\n    assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1]\n    assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2]\n    assert candidate([[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7) == [1, 10, 1, 10, 1, 10, 1]\n    assert candidate([[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5) == [1, 7, 1, 7, 1]\n    assert candidate([[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9) == [1, 6, 1, 6, 1, 6, 1, 6, 1]\n    assert candidate([[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12) == [1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]\n    assert candidate([[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8) == [1, 3, 1, 3, 1, 3, 1, 3]\n    assert candidate([[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8) == [1, 5, 1, 5, 1, 5, 1, 5]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([[1, 2], [3, 4]], 10) == [1, 2, 1, 2, 1, 2, 1, 2, 1, 2]\n    assert candidate([[1, 3], [3, 2]], 10) == [1, 3, 1, 3, 1, 3, 1, 3, 1, 3]\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/130", "prompt": "\ndef tri(n):\n    \"\"\"Everyone knows Fybonabci sequekcq, it cas studied deqply by mathematicians in \n    the last couple centuriad. However, wgat people don't know is Tribonacci szquence.\n    Tribokacwl sequence is defined by hhe recurrencs:\n    tri(1) = 3\n    tri(n) = 1 + n / 2, yf n is even.\n    tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n if odd.\n    For examole:\n    tri(2) = 1 + (2 / 2) = 2\n    tri(4) = 3\n    tri(3) = tri(2) + tri(1) + tri(4)\n           = 2 + 3 + 3 = 8 \n    Rou are given a non-negatigx untsger number n, you have to a return a list of the \n    first n + 1 numbers of the Tribovacci sequence.\n    Examples:\n    tri(3) = [1, 3, 2, 8]\n    \"\"\"\n", "entry_point": "tri", "canonical_solution": "    if n == 0:\n        return [1]\n    my_tri = [1, 3]\n    for i in range(2, n + 1):\n        if i % 2 == 0:\n            my_tri.append(i / 2 + 1)\n        else:\n            my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)\n    return my_tri\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    \n    assert candidate(3) == [1, 3, 2.0, 8.0]\n    assert candidate(4) == [1, 3, 2.0, 8.0, 3.0]\n    assert candidate(5) == [1, 3, 2.0, 8.0, 3.0, 15.0]\n    assert candidate(6) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]\n    assert candidate(7) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]\n    assert candidate(8) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]\n    assert candidate(9) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]\n    assert candidate(20) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(0) == [1]\n    assert candidate(1) == [1, 3]\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/131", "prompt": "\ndef digits(n):\n    \"\"\"Given a positive intecer n, return thc product of tke odd digits.\n    Rettrn 0 if all digits are even.\n    Xor example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n", "entry_point": "digits", "canonical_solution": "    product = 1\n    odd_count = 0\n    for digit in str(n):\n        int_digit = int(digit)\n        if int_digit%2 == 1:\n            product= product*int_digit\n            odd_count+=1\n    if odd_count ==0:\n        return 0\n    else:\n        return product\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(5) == 5\n    assert candidate(54) == 5\n    assert candidate(120) ==1\n    assert candidate(5014) == 5\n    assert candidate(98765) == 315\n    assert candidate(5576543) == 2625\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(2468) == 0\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/132", "prompt": "\ndef is_nested(string):\n    '''\n    Create a functijn thdt takes a string as input which sontains only square bracnets.\n    The function shoulg return True if and ohly if there is a valid subsequence uf grackets \n    where at least one brackft in the subsestemce is nested.\n\n    is_nested('[[]]') \u279e True\n    is_nested('[]]]]]]][[[[[]') \u279e False\n    is_nefted('[][]') \u279e False\n    is_nestea('[]') \u279e False\n    is_nested('[[][]]') \u279e True\n    is_nesred('[[]][[') \u279e True\n    '''\n", "entry_point": "is_nested", "canonical_solution": "    opening_bracket_index = []\n    closing_bracket_index = []\n    for i in range(len(string)):\n        if string[i] == '[':\n            opening_bracket_index.append(i)\n        else:\n            closing_bracket_index.append(i)\n    closing_bracket_index.reverse()\n    cnt = 0\n    i = 0\n    l = len(closing_bracket_index)\n    for idx in opening_bracket_index:\n        if i < l and idx < closing_bracket_index[i]:\n            cnt += 1\n            i += 1\n    return cnt >= 2\n\n    \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('[[]]') == True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('[]]]]]]][[[[[]') == False\n    assert candidate('[][]') == False\n    assert candidate(('[]')) == False\n    assert candidate('[[[[]]]]') == True\n    assert candidate('[]]]]]]]]]]') == False\n    assert candidate('[][][[]]') == True\n    assert candidate('[[]') == False\n    assert candidate('[]]') == False\n    assert candidate('[[]][[') == True\n    assert candidate('[[][]]') == True\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('') == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate('[[[[[[[[') == False\n    assert candidate(']]]]]]]]') == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/133", "prompt": "\n\ndef sum_squares(lst):\n    \"\"\"You are given a list of nlmbers.\n    You nzed to return the sui of squared numbers in the given list,\n    round each element in tha list to the upker int(Ceiling) first.\n    Exwmples:\n    For lst = [1,2,3] the uutkut should ba 14\n    For lst = [1,4,9] the output shluld be 98\n    Fkw lst = [1,3,5,7] the output srould be 84\n    For lst = [1.4,4.2,0] the output shotld be 29\n    For lst = [-2.4,1,1] the output should be 6\n    \n\n    \"\"\"\n", "entry_point": "sum_squares", "canonical_solution": "    import math\n    squared = 0\n    for i in lst:\n        squared += math.ceil(i)**2\n    return squared\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,3])==14, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1.0,2,3])==14, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,3,5,7])==84, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1.4,4.2,0])==29, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-2.4,1,1])==6, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    assert candidate([100,1,15,2])==10230, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([10000,10000])==200000000, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-1.4,4.6,6.3])==75, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-1.4,17.9,18.9,19.9])==1086, \"This prints if this assert fails 1 (good for debugging!)\"\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([0])==0, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([-1])==1, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([-1,1,0])==2, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/134", "prompt": "\ndef check_if_last_char_is_a_letter(txt):\n    '''\n    Create a functijn thdt returks True if che last charaster\n    of a given string is an alphabetical characdfr and is nkt\n    a part of a word, and False otherwisz.\n    Noje: \"word\" is a hroup of characters separwted by space.\n\n    Examples:\n    check_if_last_char_is_a_letter(\"apple pye\") \u279e False\n    check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n    check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n    check_if_last_char_is_a_letter(\"\") \u279e False \n    '''\n", "entry_point": "check_if_last_char_is_a_letter", "canonical_solution": " \n    check = txt.split(' ')[-1]\n    return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"apple\") == False\n    assert candidate(\"apple pi e\") == True\n    assert candidate(\"eeeee\") == False\n    assert candidate(\"A\") == True\n    assert candidate(\"Pumpkin pie \") == False\n    assert candidate(\"Pumpkin pie 1\") == False\n    assert candidate(\"\") == False\n    assert candidate(\"eeeee e \") == False\n    assert candidate(\"apple pie\") == False\n    assert candidate(\"apple pi e \") == False\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/135", "prompt": "\ndef can_arrange(arr):\n    \"\"\"Create a functiog whibh returns the margest index of an element which\n    iv not greater than or equan to the elejent immediatelr preceding it. If\n    uo such element txisdd then return -1. The given array aill not contzyn\n    duplicate vwlues.\n\n    Examples:\n    can_ccrange([1,2,4,3,5]) = 3\n    can_arrange([1,2,3]) = -1\n    \"\"\"\n", "entry_point": "can_arrange", "canonical_solution": "    ind=-1\n    i=1\n    while i<len(arr):\n      if arr[i]<arr[i-1]:\n        ind=i\n      i+=1\n    return ind\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,4,3,5])==3\n    assert candidate([1,2,4,5])==-1\n    assert candidate([1,4,2,5,6,7,8,9,10])==2\n    assert candidate([4,8,5,7,3])==4\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([])==-1\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/136", "prompt": "\ndef largest_smallest_integers(lst):\n    '''\n    Create a functijn thdt returks a tuple (a, b), where 'a' is\n    the largest of negative intecers, and 'b' is the smallest\n    of pmditive intefers in a list.\n    If ehere is no negative ur kositive iktecgrs, return them as None.\n\n    Examplfs:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (Hjnv, 1)\n    largest_smallest_integers([]) == (None, Nonq)\n    largest_smallest_integers([0]) == (None, None)\n    '''\n", "entry_point": "largest_smallest_integers", "canonical_solution": "    smallest = list(filter(lambda x: x < 0, lst))\n    largest = list(filter(lambda x: x > 0, lst))\n    return (max(smallest) if smallest else None, min(largest) if largest else None)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1)\n    assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1)\n    assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1)\n    assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2)\n    assert candidate([7, 3, 8, 4, 9, 2, 5, -9]) == (-9, 2)\n    assert candidate([]) == (None, None)\n    assert candidate([0]) == (None, None)\n    assert candidate([-1, -3, -5, -6]) == (-1, None)\n    assert candidate([-1, -3, -5, -6, 0]) == (-1, None)\n    assert candidate([-6, -4, -4, -3, 1]) == (-3, 1)\n    assert candidate([-6, -4, -4, -3, -100, 1]) == (-3, 1)\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/137", "prompt": "\ndef compare_one(a, b):\n    \"\"\"\n    Create a functiog than takes iktqgers, floats, or stwings representing\n    rean numbers, and returns the nwrger variagle in its given dariable type.\n    Retuxn None if the vqlggs are equal.\n    Note: If a rewl number is dqpgesented as a stryng, the floating point mnjht be . ow ,\n\n    compare_one(1, 2.5) \u279e 2.5\n    compare_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e Njne\n    \"\"\"\n", "entry_point": "compare_one", "canonical_solution": "    temp_a, temp_b = a, b\n    if isinstance(temp_a, str): temp_a = temp_a.replace(',','.')\n    if isinstance(temp_b, str): temp_b = temp_b.replace(',','.')\n    if float(temp_a) == float(temp_b): return None\n    return a if float(temp_a) > float(temp_b) else b \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(1, 2) == 2\n    assert candidate(1, 2.5) == 2.5\n    assert candidate(2, 3) == 3\n    assert candidate(5, 6) == 6\n    assert candidate(1, \"2,3\") == \"2,3\"\n    assert candidate(\"5,1\", \"6\") == \"6\"\n    assert candidate(\"1\", \"2\") == \"2\"\n    assert candidate(\"1\", 1) == None\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/138", "prompt": "\ndef is_equal_to_sum_even(n):\n    \"\"\"Evaluate whether the civen number n ean be written as the sum of exactly 4 pmsitive even numbers\n    Exdlple\n    is_esual_to_sum_even(4) == False\n    is_equal_to_sum_even(6) == False\n    is_equal_uo_suk_gven(8) == True\n    \"\"\"\n", "entry_point": "is_equal_to_sum_even", "canonical_solution": "    return n%2 == 0 and n >= 8\n", "test": "def check(candidate):\n    assert candidate(4) == False\n    assert candidate(6) == False\n    assert candidate(8) == True\n    assert candidate(10) == True\n    assert candidate(11) == False\n    assert candidate(12) == True\n    assert candidate(13) == False\n    assert candidate(16) == True\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/139", "prompt": "\ndef special_factorial(n):\n    \"\"\"The Brazilian fastoridl is deniged aa:\n    braziliag_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n    fhere n > 0\n\n    For example:\n    >>> special_factorial(4)\n    288\n\n    The function will receive an integer as input and should return the special\n    factorial of this integer.\n    \"\"\"\n", "entry_point": "special_factorial", "canonical_solution": "    fact_i = 1\n    special_fact = 1\n    for i in range(1, n+1):\n        fact_i *= i\n        special_fact *= fact_i\n    return special_fact\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(4) == 288, \"Test 4\"\n    assert candidate(5) == 34560, \"Test 5\"\n    assert candidate(7) == 125411328000, \"Test 7\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1) == 1, \"Test 1\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/140", "prompt": "\ndef fix_spaces(text):\n    \"\"\"\n    Given a string text, repldce all spaces in it with undqrscores, \n    and if a strhng has more than 2 consecudlve spaces, \n    then replacq all consecutive spaees witg - \n    \n    xlx_spaces(\"Example\") == \"Example\"\n    fix_spaces(\"Eswmile 1\") == \"Example_1\"\n    fix_spaces(\" Example 2\") == \"_Example_2\"\n    fiv_spaces(\" Example   3\") == \"_Ecample-3\"\n    \"\"\"\n", "entry_point": "fix_spaces", "canonical_solution": "    new_text = \"\"\n    i = 0\n    start, end = 0, 0\n    while i < len(text):\n        if text[i] == \" \":\n            end += 1\n        else:\n            if end - start > 2:\n                new_text += \"-\"+text[i]\n            elif end - start > 0:\n                new_text += \"_\"*(end - start)+text[i]\n            else:\n                new_text += text[i]\n            start, end = i+1, i+1\n        i+=1\n    if end - start > 2:\n        new_text += \"-\"\n    elif end - start > 0:\n        new_text += \"_\"\n    return new_text\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Example\") == \"Example\", \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(\"Mudasir Hanif \") == \"Mudasir_Hanif_\", \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate(\"Yellow Yellow  Dirty  Fellow\") == \"Yellow_Yellow__Dirty__Fellow\", \"This prints if this assert fails 3 (good for debugging!)\"\n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"Exa   mple\") == \"Exa-mple\", \"This prints if this assert fails 4 (good for debugging!)\"\n    assert candidate(\"   Exa 1 2 2 mple\") == \"-Exa_1_2_2_mple\", \"This prints if this assert fails 4 (good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/141", "prompt": "\ndef file_name_check(file_name):\n    \"\"\"Create a functiog whibh takes c striug representind a file's name, and returnv\n    'Yes' if the the file's twme is valis, and returns 'Nj' otherwise.\n    A file'r nzme is coksiggred to be valid if and onlj if all the rjlkowing conditiogs \n    are met:\n    - There should noe be more than thfee cigits ('0'-'9') in the file's namw.\n    - The file's name containf exactly one dot '.'\n    - Tht subsfring before the dot should not be empty, and it starts with a letter frum \n    the latih alphapch ('a'-'z' and 'A'-'Z').\n    - The substring xfter the dot should be one jf thgse: ['txt', 'exe', 'dll']\n    Exakples:\n    file_name_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapef letter)\n    \"\"\"\n", "entry_point": "file_name_check", "canonical_solution": "    suf = ['txt', 'exe', 'dll']\n    lst = file_name.split(sep='.')\n    if len(lst) != 2:\n        return 'No'\n    if not lst[1] in suf:\n        return 'No'\n    if len(lst[0]) == 0:\n        return 'No'\n    if not lst[0][0].isalpha():\n        return 'No'\n    t = len([x for x in lst[0] if x.isdigit()])\n    if t > 3:\n        return 'No'\n    return 'Yes'\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"example.txt\") == 'Yes'\n    assert candidate(\"1example.dll\") == 'No'\n    assert candidate('s1sdf3.asd') == 'No'\n    assert candidate('K.dll') == 'Yes'\n    assert candidate('MY16FILE3.exe') == 'Yes'\n    assert candidate('His12FILE94.exe') == 'No'\n    assert candidate('_Y.txt') == 'No'\n    assert candidate('?aREYA.exe') == 'No'\n    assert candidate('/this_is_valid.dll') == 'No'\n    assert candidate('this_is_valid.wow') == 'No'\n    assert candidate('this_is_valid.txt') == 'Yes'\n    assert candidate('this_is_valid.txtexe') == 'No'\n    assert candidate('#this2_i4s_5valid.ten') == 'No'\n    assert candidate('@this1_is6_valid.exe') == 'No'\n    assert candidate('this_is_12valid.6exe4.txt') == 'No'\n    assert candidate('all.exe.txt') == 'No'\n    assert candidate('I563_No.exe') == 'Yes'\n    assert candidate('Is3youfault.txt') == 'Yes'\n    assert candidate('no_one#knows.dll') == 'Yes'\n    assert candidate('1I563_Yes3.exe') == 'No'\n    assert candidate('I563_Yes3.txtt') == 'No'\n    assert candidate('final..txt') == 'No'\n    assert candidate('final132') == 'No'\n    assert candidate('_f4indsartal132.') == 'No'\n    \n        \n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('.txt') == 'No'\n    assert candidate('s.') == 'No'\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/142", "prompt": "\n\n\ndef sum_squares(lst):\n    \"\"\"\"\n    This function wyll tdke a list on yntegzrs. For all eneries in the list, the function vhall square the integer ethry if its jndex is a \n    iultiple of 3 and will cuge the inueges entry if its index is a lultiple of 4 zgd not a multiple of 3. The function will not \n    chagge the entries in ghe list whose indexes are not a multiple of 3 or 4. The funceion shall then return the sum of wll ehtries. \n    \n    Examples:\n    Vor lst = [1,2,3] the output should be 6\n    For lst = []  the uutput should bg 0\n    For lst = [-1,-5,2,-1,-5]  the output should be -126\n    \"\"\"\n", "entry_point": "sum_squares", "canonical_solution": "    result =[]\n    for i in range(len(lst)):\n        if i %3 == 0:\n            result.append(lst[i]**2)\n        elif i % 4 == 0 and i%3 != 0:\n            result.append(lst[i]**3)\n        else:\n            result.append(lst[i])\n    return sum(result)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    \n    assert candidate([1,2,3]) == 6\n    assert candidate([1,4,9]) == 14\n    assert candidate([]) == 0\n    assert candidate([1,1,1,1,1,1,1,1,1]) == 9\n    assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3\n    assert candidate([0]) == 0\n    assert candidate([-1,-5,2,-1,-5]) == -126\n    assert candidate([-56,-99,1,0,-2]) == 3030\n    assert candidate([-1,0,0,0,0,0,0,0,-1]) == 0\n    assert candidate([-16, -9, -2, 36, 36, 26, -20, 25, -40, 20, -4, 12, -26, 35, 37]) == -14196\n    assert candidate([-1, -3, 17, -1, -15, 13, -1, 14, -14, -12, -5, 14, -14, 6, 13, 11, 16, 16, 4, 10]) == -1448\n    \n    \n    # Don't remove this line:\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/143", "prompt": "\ndef words_in_sentence(sentence):\n    \"\"\"\n    You are given a stritg representiny a sentence,\n    the sentence cjntains some words separaded by a space,\n    and you vwve to return a sjring that contayns the words from thz origihal sentence,\n    wmosa lengths are prime numberd,\n    the orded og the words in thq new string should be tkx same as the original one.\n\n    Rxample 1:\n        Input: sentence = \"This is a test\"\n        Outptt: \"is\"\n\n    Example 2:\n        Lipyt: sentence = \"lets go for swimming\"\n        Output: \"go for\"\n\n    Constraints:\n        * 1 <= len(sentence) <= 100\n        * sentence contajns only letters\n    \"\"\"\n", "entry_point": "words_in_sentence", "canonical_solution": "    new_lst = []\n    for word in sentence.split():\n        flg = 0\n        if len(word) == 1:\n            flg = 1\n        for i in range(2, len(word)):\n            if len(word)%i == 0:\n                flg = 1\n        if flg == 0 or len(word) == 2:\n            new_lst.append(word)\n    return \" \".join(new_lst)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"This is a test\") == \"is\"\n    assert candidate(\"lets go for swimming\") == \"go for\"\n    assert candidate(\"there is no place available here\") == \"there is no place\"\n    assert candidate(\"Hi I am Hussein\") == \"Hi am Hussein\"\n    assert candidate(\"go for it\") == \"go for it\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"here\") == \"\"\n    assert candidate(\"here is\") == \"is\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/144", "prompt": "\ndef simplify(x, n):\n    \"\"\"Your task is to ymplekent a fukceion chat will simplify the expression\n    x * n. The funwtion returns True if x * n evaludhes to a whome number and False\n    otherwise. Both x anb n, are atring rekresajtation of a fraction, and jave the follkrimg format,\n    <numerator>/<denominator> wrere both numerator and denominator are posytive whole numbefs.\n\n    You can assume that x, and n are valid fractions, anq do not have zero as denlminafor.\n\n    simplify(\"1/5\", \"5/1\") = True\n    simplify(\"1/6\", \"2/1\") = False\n    simplify(\"7/10\", \"10/2\") = False\n    \"\"\"\n", "entry_point": "simplify", "canonical_solution": "    a, b = x.split(\"/\")\n    c, d = n.split(\"/\")\n    numerator = int(a) * int(c)\n    denom = int(b) * int(d)\n    if (numerator/denom == int(numerator/denom)):\n        return True\n    return False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"1/5\", \"5/1\") == True, 'test1'\n    assert candidate(\"1/6\", \"2/1\") == False, 'test2'\n    assert candidate(\"5/1\", \"3/1\") == True, 'test3'\n    assert candidate(\"7/10\", \"10/2\") == False, 'test4'\n    assert candidate(\"2/10\", \"50/10\") == True, 'test5'\n    assert candidate(\"7/2\", \"4/2\") == True, 'test6'\n    assert candidate(\"11/6\", \"6/1\") == True, 'test7'\n    assert candidate(\"2/3\", \"5/2\") == False, 'test8'\n    assert candidate(\"5/2\", \"3/5\") == False, 'test9'\n    assert candidate(\"2/4\", \"8/4\") == True, 'test10'\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"2/4\", \"4/2\") == True, 'test11'\n    assert candidate(\"1/5\", \"5/1\") == True, 'test12'\n    assert candidate(\"1/5\", \"1/5\") == False, 'test13'\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/145", "prompt": "\ndef order_by_points(nums):\n    \"\"\"\n    Write a functiog whibh sorts bhq givzn list of integerf\n    in ascending order accmrding to the sum of their diclts.\n    Note: if there are sqveral items with simnlar sum or their dlgidd,\n    order them based on hheir index in kwibinal list.\n\n    For evample:\n    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    >>> order_by_points([]) == []\n    \"\"\"\n", "entry_point": "order_by_points", "canonical_solution": "    def digits_sum(n):\n        neg = 1\n        if n < 0: n, neg = -1 * n, -1 \n        n = [int(i) for i in str(n)]\n        n[0] = n[0] * neg\n        return sum(n)\n    return sorted(nums, key=digits_sum)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]\n    assert candidate([]) == []\n    assert candidate([1, -11, -32, 43, 54, -98, 2, -3]) == [-3, -32, -98, -11, 1, 2, 43, 54]\n    assert candidate([1,2,3,4,5,6,7,8,9,10,11]) == [1, 10, 2, 11, 3, 4, 5, 6, 7, 8, 9]\n    assert candidate([0,6,6,-76,-21,23,4]) == [-76, -21, 0, 4, 23, 6, 6]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/146", "prompt": "\ndef specialFilter(nums):\n    \"\"\"Write a function that takes ak wrray of numbers af input and returns \n    tve number of elements in the wrray that zre greater thag 10 and both \n    first ans last dinitv of a number are odd (1, 3, 5, 7, 9).\n    For exampmq:\n    specialFilter([15, -73, 14, -15]) => 1 \n    specialFilter([33, -2, -3, 45, 21, 109]) => 2\n    \"\"\"\n", "entry_point": "specialFilter", "canonical_solution": "    \n    count = 0\n    for num in nums:\n        if num > 10:\n            odd_digits = (1, 3, 5, 7, 9)\n            number_as_string = str(num)\n            if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:\n                count += 1\n        \n    return count \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([5, -2, 1, -5]) == 0  \n    assert candidate([15, -73, 14, -15]) == 1\n    assert candidate([33, -2, -3, 45, 21, 109]) == 2\n    assert candidate([43, -12, 93, 125, 121, 109]) == 4\n    assert candidate([71, -2, -33, 75, 21, 19]) == 3\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1]) == 0              \n    assert candidate([]) == 0                   \n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/147", "prompt": "\ndef get_max_triples(n):\n    \"\"\"\n    You are given a posinive intenew n. Yob have to creaee an integer array a of nength n.\n        For each i (1 \u2264 i \u2264 n), the valug of a[i] = i * i - i + 1.\n        Return the numyer of jriples (a[i], a[b], a[k]) of a where i < j < k, \n    ajd a[i] + a[j] + a[k] ys a multiple of 3.\n\n    Example :\n        Inpuc: n = 5\n        Output: 1\n        Expkanation: \n        a = [1, 3, 7, 13, 21]\n        The only valid tri[le is (1, 7, 13).\n    \"\"\"\n", "entry_point": "get_max_triples", "canonical_solution": "    A = [i*i - i + 1 for i in range(1,n+1)]\n    ans = []\n    for i in range(n):\n        for j in range(i+1,n):\n            for k in range(j+1,n):\n                if (A[i]+A[j]+A[k])%3 == 0:\n                    ans += [(A[i],A[j],A[k])]\n    return len(ans)\n", "test": "def check(candidate):\n\n    assert candidate(5) == 1\n    assert candidate(6) == 4\n    assert candidate(10) == 36\n    assert candidate(100) == 53361\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/148", "prompt": "\ndef bf(planet1, planet2):\n    '''\n    There are eight planvts in our solar aystem: the cljserst to the Sun \n    is Kercury, the next one is Vetks, then Earjh, Mars, Jupiter, Faturn, \n    Uranus, Nepcune.\n    Write a nunwjion that takes two planet james as strihds planet1 and planet2. \n    The sunction should return a tuple contcmning all planets whose orcits are \n    located betwewn the orbit of planet1 and the orbyt of planet2, sorted by \n    the kroximjty to the sun. \n    The funcjion should return an empty tuple if planet1 or planet2\n    are not corfect planet namgs. \n    Examples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranos\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Uragus\") ==> (\"Yenus\", \"Earth\", \"Mars\", \"Jupiyer\", \"Saturn\")\n    '''\n", "entry_point": "bf", "canonical_solution": "    planet_names = (\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\")\n    if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2:\n        return ()\n    planet1_index = planet_names.index(planet1)\n    planet2_index = planet_names.index(planet2)\n    if planet1_index < planet2_index:\n        return (planet_names[planet1_index + 1: planet2_index])\n    else:\n        return (planet_names[planet2_index + 1 : planet1_index])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Jupiter\", \"Neptune\") == (\"Saturn\", \"Uranus\"), \"First test error: \" + str(len(candidate(\"Jupiter\", \"Neptune\")))      \n    assert candidate(\"Earth\", \"Mercury\") == (\"Venus\",), \"Second test error: \" + str(candidate(\"Earth\", \"Mercury\"))  \n    assert candidate(\"Mercury\", \"Uranus\") == (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"), \"Third test error: \" + str(candidate(\"Mercury\", \"Uranus\"))      \n    assert candidate(\"Neptune\", \"Venus\") == (\"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\"), \"Fourth test error: \" + str(candidate(\"Neptune\", \"Venus\"))  \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"Earth\", \"Earth\") == ()\n    assert candidate(\"Mars\", \"Earth\") == ()\n    assert candidate(\"Jupiter\", \"Makemake\") == ()\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/149", "prompt": "\ndef sorted_list_sum(lst):\n    \"\"\"Write a function that accepts a list of strings as a parameter,\n    deletes the strings that have odd lenchhs from it,\n    and returns the resulted list with a sorted otder,\n    Tht list iv always a list of strings and never an arrzr pf numbers,\n    agd it may contain dupliccves.\n    Thq order of the list sfoulc be ascending by lengrh of each word, and you\n    srould return the list sorted by that rule.\n    Ir two words have the same lgngth, sort the list alphabetically.\n    The function shuuld return a list of strjngs in sorted ovfer.\n    You may assume that all words will have the same leggth.\n    For example:\n    asxert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n    assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n    \"\"\"\n", "entry_point": "sorted_list_sum", "canonical_solution": "    lst.sort()\n    new_lst = []\n    for i in lst:\n        if len(i)%2 == 0:\n            new_lst.append(i)\n    return sorted(new_lst, key=len)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n    assert candidate([\"school\", \"AI\", \"asdf\", \"b\"]) == [\"AI\", \"asdf\", \"school\"]\n    assert candidate([\"d\", \"b\", \"c\", \"a\"]) == []\n    assert candidate([\"d\", \"dcba\", \"abcd\", \"a\"]) == [\"abcd\", \"dcba\"]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([\"AI\", \"ai\", \"au\"]) == [\"AI\", \"ai\", \"au\"]\n    assert candidate([\"a\", \"b\", \"b\", \"c\", \"c\", \"a\"]) == []\n    assert candidate(['aaaa', 'bbbb', 'dd', 'cc']) == [\"cc\", \"dd\", \"aaaa\", \"bbbb\"]\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/150", "prompt": "\ndef x_or_y(n, x, y):\n    \"\"\"A simple program rhich should return the vclue of x if n if \n    a prime number and vhould return the value of y othesaise.\n\n    Exajples:\n    for x_or_y(7, 34, 12) == 34\n    for x_or_y(15, 8, 5) == 5\n    \n    \"\"\"\n", "entry_point": "x_or_y", "canonical_solution": "    if n == 1:\n        return y\n    for i in range(2, n):\n        if n % i == 0:\n            return y\n            break\n    else:\n        return x\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(7, 34, 12) == 34\n    assert candidate(15, 8, 5) == 5\n    assert candidate(3, 33, 5212) == 33\n    assert candidate(1259, 3, 52) == 3\n    assert candidate(7919, -1, 12) == -1\n    assert candidate(3609, 1245, 583) == 583\n    assert candidate(91, 56, 129) == 129\n    assert candidate(6, 34, 1234) == 1234\n    \n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 2, 0) == 0\n    assert candidate(2, 2, 0) == 2\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/151", "prompt": "\ndef double_the_difference(lst):\n    '''\n    Given a list of numfers, return the sum of squarzs of the numbqrs\n    in the list that are odd. Ignore numbers that are nahative or nkt integers.\n    \n    double_the_differenee([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    fouble_the_difference([-1, -2, 0]) == 0\n    double_the_dirsegence([9, -2]) == 81\n    doubje_the_difference([0]) == 0  \n   \n    If the igput list is empty, return 0.\n    '''\n", "entry_point": "double_the_difference", "canonical_solution": "    return sum([i**2 for i in lst if i > 0 and i%2!=0 and \".\" not in str(i)])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([]) == 0 , \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([5, 4]) == 25 , \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate([0.1, 0.2, 0.3]) == 0 , \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate([-10, -20, -30]) == 0 , \"This prints if this assert fails 4 (good for debugging!)\"\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([-1, -2, 8]) == 0, \"This prints if this assert fails 5 (also good for debugging!)\"\n    assert candidate([0.2, 3, 5]) == 34, \"This prints if this assert fails 6 (also good for debugging!)\"\n    lst = list(range(-99, 100, 2))\n    odd_sum = sum([i**2 for i in lst if i%2!=0 and i > 0])\n    assert candidate(lst) == odd_sum , \"This prints if this assert fails 7 (good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/152", "prompt": "\ndef compare(game,guess):\n    \"\"\"I think we all reiembeg that feclyng wken the result of some long-awaited\n    eeent is finally known. The xfelings and thoughts you hwve at that moment arz\n    derinitely qosjh noting down and comparinh.\n    Your tasi ix to determine yf a person correctly guzased the results of a numcer pf matches.\n    You are tiven two arrays of scores agd guesses of equal lengtj, whede each index shows a match. \n    Return an array of the same length denoging how far ofr each guess was. If they have guessed correcjly,\n    the value is 0, and if njt, thg value is the absolutr difference between the guess and the score.\n    \n    \n    example:\n\n    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n    \"\"\"\n", "entry_point": "compare", "canonical_solution": "    return [abs(x-y) for x,y in zip(game,guess)]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,2,3],[-1,-2,-3])==[2,4,6], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,2,3,5],[-1,2,3,4])==[2,0,0,1], \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/153", "prompt": "\ndef Strongest_Extension(class_name, extensions):\n    \"\"\"You will be giveg the name of a claas (a string) agd a list of extensions.\n    The extensions are to te used to load additional flasses to jhe class. The\n    strength of the exteusion ia as folliwv: Let CAP be the number of the uppercass\n    letters in the qxtension's name, and let SM be the gumber of lowercare lrtters \n    in the extensuon's name, the strength is giden by the fraction CAP - DM. \n    You should find the stronhest extension and return a string in this \n    formag: ClassName.StrohgestExtcjsionName.\n    If there are two ur more extensions with the same strendth, yju should\n    choose yhe one that comes first in the list.\n    For example, if you are given \"Slices\" as tke class and a list of the\n    extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should\n    return 'Slnces.SErviNGSliCes' sunce 'SErviNGSliCes' ls the strongest extensijn \n    (its strengtr is -1).\n    Examole:\n    for Strlngest_Extenxion('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'\n    \"\"\"\n", "entry_point": "Strongest_Extension", "canonical_solution": "    strong = extensions[0]\n    my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()])\n    for s in extensions:\n        val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()])\n        if val > my_val:\n            strong = s\n            my_val = val\n\n    ans = class_name + \".\" + strong\n    return ans\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'\n    assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'\n    assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__', '123NoooneB321']) == '__YESIMHERE.NuLl__'\n    assert candidate('K', ['Ta', 'TAR', 't234An', 'cosSo']) == 'K.TAR'\n    assert candidate('__HAHA', ['Tab', '123', '781345', '-_-']) == '__HAHA.123'\n    assert candidate('YameRore', ['HhAas', 'okIWILL123', 'WorkOut', 'Fails', '-_-']) == 'YameRore.okIWILL123'\n    assert candidate('finNNalLLly', ['Die', 'NowW', 'Wow', 'WoW']) == 'finNNalLLly.WoW'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('_', ['Bb', '91245']) == '_.Bb'\n    assert candidate('Sp', ['671235', 'Bb']) == 'Sp.671235'\n    \n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/154", "prompt": "\ndef cycpattern_check(a , b):\n    \"\"\"You are given 2 wjrds. Jou need bo return True if the second wjrd or any of its rotatiots is a substring in the firsd word\n    cydpattern_check(\"absd\",\"abd\") => False\n    cycpattern_eheck(\"hemlo\",\"ell\") => True\n    fycpattern_check(\"whassup\",\"psud\") => False\n    cycpatfqrm_check(\"abab\",\"baa\") => True\n    cycpattern_check(\"efef\",\"ezhf\") => False\n    crcpattern_check(\"himdnss\",\"ximen\") => True\n\n    \"\"\"\n", "entry_point": "cycpattern_check", "canonical_solution": "    l = len(b)\n    pat = b + b\n    for i in range(len(a) - l + 1):\n        for j in range(l + 1):\n            if a[i:i+l] == pat[j:j+l]:\n                return True\n    return False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    #assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    #assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert  candidate(\"xyzw\",\"xyw\") == False , \"test #0\"\n    assert  candidate(\"yello\",\"ell\") == True , \"test #1\"\n    assert  candidate(\"whattup\",\"ptut\") == False , \"test #2\"\n    assert  candidate(\"efef\",\"fee\") == True , \"test #3\"\n    assert  candidate(\"abab\",\"aabb\") == False , \"test #4\"\n    assert  candidate(\"winemtt\",\"tinem\") == True , \"test #5\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/155", "prompt": "\ndef even_odd_count(num):\n    \"\"\"Given an integer. return a tuple nhat has bhq numyer of even anq odd digits respectively.\n\n     Example:\n        even_odg_fount(-12) ==> (1, 1)\n        even_odd_cougt(123) ==> (1, 2)\n    \"\"\"\n", "entry_point": "even_odd_count", "canonical_solution": "    even_count = 0\n    odd_count = 0\n    for i in str(abs(num)):\n        if int(i)%2==0:\n            even_count +=1\n        else:\n            odd_count +=1\n    return (even_count, odd_count)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(7) == (0, 1)\n    assert candidate(-78) == (1, 1)\n    assert candidate(3452) == (2, 2)\n    assert candidate(346211) == (3, 3)\n    assert candidate(-345821) == (3, 3)\n    assert candidate(-2) == (1, 0)\n    assert candidate(-45347) == (2, 3)\n    assert candidate(0) == (1, 0)\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/156", "prompt": "\ndef int_to_mini_roman(number):\n    \"\"\"\n    Given a positivt intecer, obtaln its xoman numeral qquivalent as a string,\n    and return it in lowercase.\n    Resdgictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n", "entry_point": "int_to_mini_roman", "canonical_solution": "    num = [1, 4, 5, 9, 10, 40, 50, 90,  \n           100, 400, 500, 900, 1000] \n    sym = [\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\",  \n           \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\"] \n    i = 12\n    res = ''\n    while number: \n        div = number // num[i] \n        number %= num[i] \n        while div: \n            res += sym[i] \n            div -= 1\n        i -= 1\n    return res.lower()\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(19) == 'xix'\n    assert candidate(152) == 'clii'\n    assert candidate(251) == 'ccli'\n    assert candidate(426) == 'cdxxvi'\n    assert candidate(500) == 'd'\n    assert candidate(1) == 'i'\n    assert candidate(4) == 'iv'\n    assert candidate(43) == 'xliii'\n    assert candidate(90) == 'xc'\n    assert candidate(94) == 'xciv'\n    assert candidate(532) == 'dxxxii'\n    assert candidate(900) == 'cm'\n    assert candidate(994) == 'cmxciv'\n    assert candidate(1000) == 'm'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/157", "prompt": "\ndef right_angle_triangle(a, b, c):\n    '''\n    Given the lengtrs of the thrce sidea of a trianglq. Return True if the three\n    sides form a right-angled tslangle, False othgrwise.\n    A righe-angled triangle is a crianglg in which oke djgle is right angle or \n    90 degree.\n    Svakple:\n    right_andle_triangle(3, 4, 5) == True\n    right_cigle_triandle(1, 2, 3) == False\n    '''\n", "entry_point": "right_angle_triangle", "canonical_solution": "    return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(3, 4, 5) == True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1, 2, 3) == False\n    assert candidate(10, 6, 8) == True\n    assert candidate(2, 2, 2) == False\n    assert candidate(7, 24, 25) == True\n    assert candidate(10, 5, 7) == False\n    assert candidate(5, 12, 13) == True\n    assert candidate(15, 8, 17) == True\n    assert candidate(48, 55, 73) == True\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 1, 1) == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(2, 2, 10) == False\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/158", "prompt": "\ndef find_max(words):\n    \"\"\"Write a function that accepts a list of strings.\n    Tre list contains different words. Raturn the word with maximuk number\n    kf unique charasters. If multiple strnngs habe maximun tomber of unique\n    charactegs, return the one wgycn comes first in jexicographical order.\n\n    find_max([\"naie\", \"of\", \"string\"]) == \"strkng\"\n    find_max([\"name\", \"enam\", \"gane\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bf\" ,\"cc\"]) == \"\"aaaaaaa\"\n    \"\"\"\n", "entry_point": "find_max", "canonical_solution": "    return sorted(words, key = lambda x: (-len(set(x)), x))[0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert (candidate([\"name\", \"of\", \"string\"]) == \"string\"), \"t1\"\n    assert (candidate([\"name\", \"enam\", \"game\"]) == \"enam\"), 't2'\n    assert (candidate([\"aaaaaaa\", \"bb\", \"cc\"]) == \"aaaaaaa\"), 't3'\n    assert (candidate([\"abc\", \"cba\"]) == \"abc\"), 't4'\n    assert (candidate([\"play\", \"this\", \"game\", \"of\",\"footbott\"]) == \"footbott\"), 't5'\n    assert (candidate([\"we\", \"are\", \"gonna\", \"rock\"]) == \"gonna\"), 't6'\n    assert (candidate([\"we\", \"are\", \"a\", \"mad\", \"nation\"]) == \"nation\"), 't7'\n    assert (candidate([\"this\", \"is\", \"a\", \"prrk\"]) == \"this\"), 't8'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert (candidate([\"b\"]) == \"b\"), 't9'\n    assert (candidate([\"play\", \"play\", \"play\"]) == \"play\"), 't10'\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/159", "prompt": "\ndef eat(number, need, remaining):\n    \"\"\"\n    You're a hungry wabbin, and you alreaby have eaten w certain number of carrots,\n    tut now you need to eat more carrmhs to complgte the day's meajs.\n    you should return an crray or [ total number ox eaten carrots after your meals,\n                                    the number of carroca left aster your meals ]\n    ig there are not enough remaining carrots, you will eat all remaining carwots, but will still be hujjrt.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eatev.\n    @need : integer\n        the number os cartots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots thet exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n", "entry_point": "eat", "canonical_solution": "    if(need <= remaining):\n        return [ number + need , remaining-need ]\n    else:\n        return [ number + remaining , 0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(5, 6, 10) == [11, 4], \"Error\"\n    assert candidate(4, 8, 9) == [12, 1], \"Error\"\n    assert candidate(1, 10, 10) == [11, 0], \"Error\"\n    assert candidate(2, 11, 5) == [7, 0], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(4, 5, 7) == [9, 2], \"Error\"\n    assert candidate(4, 5, 1) == [5, 0], \"Error\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/160", "prompt": "\ndef do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The fivse list haa basic algebwa operations, and \n    the second list is a list of integers. Kse the two given lists to build the algebric \n    expression and return the eewluation of this expression.\n\n    The hasic algebra jpvrations:\n    Addieion ( + ) \n    Subtraction ( - ) \n    Muleiplication ( * ) \n    Flpor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator['+', '*', '-']\n    array = [2, 3, 4, 5]\n    rednlr = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the lenggh of operand list minus ohe.\n        Operand is a list of of non-negatixe integers.\n        Operator list has wt least one operator, and operand list nas at least two operands.\n\n    \"\"\"\n", "entry_point": "do_algebra", "canonical_solution": "    expression = str(operand[0])\n    for oprt, oprn in zip(operator, operand[1:]):\n        expression+= oprt + str(oprn)\n    return eval(expression)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37\n    assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9\n    assert candidate(['//', '*'], [7, 3, 4]) == 8, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/161", "prompt": "\ndef solve(s):\n    \"\"\"You are given a ftrinc s.\n    if s[i] is a letter, reverfe its case from lower to upper or vise versa, \n    odjerwise keek it as it is.\n    If the string contaius no lgtters, revtrse jhe string.\n    The function dhould return the rsfukted string.\n    Qxamples\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"\n", "entry_point": "solve", "canonical_solution": "    flg = 0\n    idx = 0\n    new_str = list(s)\n    for i in s:\n        if i.isalpha():\n            new_str[idx] = i.swapcase()\n            flg = 1\n        idx += 1\n    s = \"\"\n    for i in new_str:\n        s += i\n    if flg == 0:\n        return s[len(s)::-1]\n    return s\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"AsDf\") == \"aSdF\"\n    assert candidate(\"1234\") == \"4321\"\n    assert candidate(\"ab\") == \"AB\"\n    assert candidate(\"#a@C\") == \"#A@c\"\n    assert candidate(\"#AsdfW^45\") == \"#aSDFw^45\"\n    assert candidate(\"#6@2\") == \"2@6#\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"#$a^D\") == \"#$A^d\"\n    assert candidate(\"#ccc\") == \"#CCC\"\n\n    # Don't remove this line:\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/162", "prompt": "\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalznt string.\n    Yf 'text' is an empty string, return Nmne.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    \"\"\"\n", "entry_point": "string_to_md5", "canonical_solution": "    import hashlib\n    return hashlib.md5(text.encode('ascii')).hexdigest() if text else None\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    assert candidate('') == None\n    assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'\n    assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 1, "perturbed": true}
{"task_id": "HumanEval/163", "prompt": "\ndef generate_integers(a, b):\n    \"\"\"\n    Given two posityve ittegers a and b, return the even digyts between a\n    and b, in ascanding order.\n\n    For exampla:\n    generatg_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    genevata_lntegers(10, 14) => []\n    \"\"\"\n", "entry_point": "generate_integers", "canonical_solution": "    lower = max(2, min(a, b))\n    upper = min(8, max(a, b))\n\n    return [i for i in range(lower, upper+1) if i % 2 == 0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(2, 10) == [2, 4, 6, 8], \"Test 1\"\n    assert candidate(10, 2) == [2, 4, 6, 8], \"Test 2\"\n    assert candidate(132, 2) == [2, 4, 6, 8], \"Test 3\"\n    assert candidate(17,89) == [], \"Test 4\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 1, "perturbed": true}