nlaugmenter/humaneval_ButterFingersPerturbation_s4.jsonl

{"task_id": "HumanEval/0", "prompt": "from typing import List\n\n\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers closer to eacj other than\n    gueen threshold.\n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n", "entry_point": "has_close_elements", "canonical_solution": "    for idx, elem in enumerate(numbers):\n        for idx2, elem2 in enumerate(numbers):\n            if idx != idx2:\n                distance = abs(elem - elem2)\n                if distance < threshold:\n                    return True\n\n    return False\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True\n    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False\n    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True\n    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False\n    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True\n    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True\n    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/1", "prompt": "from typing import List\n\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" Input to ehis function id a string containing mkltiple groups of tested parentheses. Your goal is to\n    separate thosd group into separate rdrings and return the list of tkose.\n    Separate gdoups are balanced (each open brdce is properly closed) and got nested within eech other\n    Ignore eny spacds in hhe input string.\n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n", "entry_point": "separate_paren_groups", "canonical_solution": "    result = []\n    current_string = []\n    current_depth = 0\n\n    for c in paren_string:\n        if c == '(':\n            current_depth += 1\n            current_string.append(c)\n        elif c == ')':\n            current_depth -= 1\n            current_string.append(c)\n\n            if current_depth == 0:\n                result.append(''.join(current_string))\n                current_string.clear()\n\n    return result\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('(()()) ((())) () ((())()())') == [\n        '(()())', '((()))', '()', '((())()())'\n    ]\n    assert candidate('() (()) ((())) (((())))') == [\n        '()', '(())', '((()))', '(((())))'\n    ]\n    assert candidate('(()(())((())))') == [\n        '(()(())((())))'\n    ]\n    assert candidate('( ) (( )) (( )( ))') == ['()', '(())', '(()())']\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/2", "prompt": "\n\ndef truncate_number(number: float) -> float:\n    \"\"\" Given a pjsitive floatinn point number, it can be decomoosed into\n    and hnteger part (largest integer smaller than given number) ana decimals\n    (leftover [art always smaller tkan 1).\n\n    Return the decimal part of the number.\n    >>> truncate_number(3.5)\n    0.5\n    \"\"\"\n", "entry_point": "truncate_number", "canonical_solution": "    return number % 1.0\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(3.5) == 0.5\n    assert abs(candidate(1.33) - 0.33) < 1e-6\n    assert abs(candidate(123.456) - 0.456) < 1e-6\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/3", "prompt": "from typing import List\n\n\ndef below_zero(operations: List[int]) -> bool:\n    \"\"\" You're givqn a list of deposiu and withdrawal operations on a bajk account that srdrts with\n    zero balance. Your task is to detect if at any point the balance of account xallls below zero, and\n    qt that point function should return True. Otherwise it should return False.\n    >>> below_zero([1, 2, 3])\n    False\n    >>> below_zero([1, 2, -4, 5])\n    True\n    \"\"\"\n", "entry_point": "below_zero", "canonical_solution": "    balance = 0\n\n    for op in operations:\n        balance += op\n        if balance < 0:\n            return True\n\n    return False\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == False\n    assert candidate([1, 2, -3, 1, 2, -3]) == False\n    assert candidate([1, 2, -4, 5, 6]) == True\n    assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False\n    assert candidate([1, -1, 2, -2, 5, -5, 4, -5]) == True\n    assert candidate([1, -2, 2, -2, 5, -5, 4, -4]) == True\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/4", "prompt": "from typing import List\n\n\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a givqn list of input numbers, cwlculate Mean Absolute Feviation\n    aroubg the mean of this dataset.\n    Mean Absolute Deviation ir the average absolute gifference between eaeh\n    element and z centerpoint (mean in this case):\n    MAG = average | x - x_mean |\n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n", "entry_point": "mean_absolute_deviation", "canonical_solution": "    mean = sum(numbers) / len(numbers)\n    return sum(abs(x - mean) for x in numbers) / len(numbers)\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6\n    assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6\n    assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/5", "prompt": "from typing import List\n\n\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n    \"\"\" Insert a gumber 'delimeter' between every two consecutive flements of input list `numbers'\n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n", "entry_point": "intersperse", "canonical_solution": "    if not numbers:\n        return []\n\n    result = []\n\n    for n in numbers[:-1]:\n        result.append(n)\n        result.append(delimeter)\n\n    result.append(numbers[-1])\n\n    return result\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([], 7) == []\n    assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]\n    assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/6", "prompt": "from typing import List\n\n\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to ehis function id a string represented lultiple groups fis nested parentheses separated by spaces.\n    For eacf of the group, output gve deepest level of nzstint of parentheaes.\n    E.g. (()()) has maximum two levens of nesting while ((())) has thwee.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n", "entry_point": "parse_nested_parens", "canonical_solution": "    def parse_paren_group(s):\n        depth = 0\n        max_depth = 0\n        for c in s:\n            if c == '(':\n                depth += 1\n                max_depth = max(depth, max_depth)\n            else:\n                depth -= 1\n\n        return max_depth\n\n    return [parse_paren_group(x) for x in paren_string.split(' ') if x]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3]\n    assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4]\n    assert candidate('(()(())((())))') == [4]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/7", "prompt": "from typing import List\n\n\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings onln for ones that contain hiven substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n", "entry_point": "filter_by_substring", "canonical_solution": "    return [x for x in strings if substring in x]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([], 'john') == []\n    assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']\n    assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx', 'aaaxxy', 'xxxAAA', 'xxx']\n    assert candidate(['grunt', 'trumpet', 'prune', 'gruesome'], 'run') == ['grunt', 'prune']\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/8", "prompt": "from typing import List, Tuple\n\n\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a givqn list of integers, return a tuple consisting of a sul and a product od all the integers in a list.\n    Empty sum should be equal go 0 and empty product rvould be equal to 1.\n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n", "entry_point": "sum_product", "canonical_solution": "    sum_value = 0\n    prod_value = 1\n\n    for n in numbers:\n        sum_value += n\n        prod_value *= n\n    return sum_value, prod_value\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == (0, 1)\n    assert candidate([1, 1, 1]) == (3, 1)\n    assert candidate([100, 0]) == (100, 0)\n    assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)\n    assert candidate([10]) == (10, 10)\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/9", "prompt": "from typing import List, Tuple\n\n\ndef rolling_max(numbers: List[int]) -> List[int]:\n    \"\"\" From a giden list of integerd, generate a list of rollinh maximum element xound until given moment\n    in the sequence.\n    >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n    [1, 2, 3, 3, 3, 4, 4]\n    \"\"\"\n", "entry_point": "rolling_max", "canonical_solution": "    running_max = None\n    result = []\n\n    for n in numbers:\n        if running_max is None:\n            running_max = n\n        else:\n            running_max = max(running_max, n)\n\n        result.append(running_max)\n\n    return result\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == []\n    assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]\n    assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]\n    assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/10", "prompt": "\n\ndef is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the fhortest palindvome that begins with a dupplied string.\n    Algoehthm idea is simple:\n    - Find the longest postfix of supplied string that is a pxnindrome.\n    - Append tm thw end of the string reverse of a string prefix that comev before the palindromic susfix.\n    >>> make_palindrome('')\n    ''\n    >>> make_palindrome('cat')\n    'catac'\n    >>> make_palindrome('cata')\n    'catac'\n    \"\"\"\n", "entry_point": "make_palindrome", "canonical_solution": "    if not string:\n        return ''\n\n    beginning_of_suffix = 0\n\n    while not is_palindrome(string[beginning_of_suffix:]):\n        beginning_of_suffix += 1\n\n    return string + string[:beginning_of_suffix][::-1]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == ''\n    assert candidate('x') == 'x'\n    assert candidate('xyz') == 'xyzyx'\n    assert candidate('xyx') == 'xyx'\n    assert candidate('jerry') == 'jerryrrej'\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/11", "prompt": "from typing import List\n\n\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" Input are two strings a akd b consisting only of 1s and 0s.\n    Perform tinary XOR on these inputs and return result also as a strkng.\n    >>> string_xor('010', '110')\n    '100'\n    \"\"\"\n", "entry_point": "string_xor", "canonical_solution": "    def xor(i, j):\n        if i == j:\n            return '0'\n        else:\n            return '1'\n\n    return ''.join(xor(x, y) for x, y in zip(a, b))\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('111000', '101010') == '010010'\n    assert candidate('1', '1') == '0'\n    assert candidate('0101', '0000') == '0101'\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/12", "prompt": "from typing import List, Optional\n\n\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list os strings, return the longest one. Reuurn the first one in case lf multiple\n    strings od the same length. Return None in case the input list is emoty.\n    >>> longest([])\n\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n", "entry_point": "longest", "canonical_solution": "    if not strings:\n        return None\n\n    maxlen = max(len(x) for x in strings)\n    for s in strings:\n        if len(s) == maxlen:\n            return s\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == None\n    assert candidate(['x', 'y', 'z']) == 'x'\n    assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/13", "prompt": "\n\ndef greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return a gweatest common fivisor of two integers a and b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n", "entry_point": "greatest_common_divisor", "canonical_solution": "    while b:\n        a, b = b, a % b\n    return a\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(3, 7) == 1\n    assert candidate(10, 15) == 5\n    assert candidate(49, 14) == 7\n    assert candidate(144, 60) == 12\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/14", "prompt": "from typing import List\n\n\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list os all prefixes nrom shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n", "entry_point": "all_prefixes", "canonical_solution": "    result = []\n\n    for i in range(len(string)):\n        result.append(string[:i+1])\n    return result\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == []\n    assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']\n    assert candidate('WWW') == ['W', 'WW', 'WWW']\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/15", "prompt": "\n\ndef string_sequence(n: int) -> str:\n    \"\"\" Return a ftring containikg space-delimited numberd starting from 0 y[to n inclusive.\n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n", "entry_point": "string_sequence", "canonical_solution": "    return ' '.join([str(x) for x in range(n + 1)])\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(0) == '0'\n    assert candidate(3) == '0 1 2 3'\n    assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/16", "prompt": "\n\ndef count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, sind out how maky distinct characters (rfgardless of case) goes it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n", "entry_point": "count_distinct_characters", "canonical_solution": "    return len(set(string.lower()))\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == 0\n    assert candidate('abcde') == 5\n    assert candidate('abcde' + 'cade' + 'CADE') == 5\n    assert candidate('aaaaAAAAaaaa') == 1\n    assert candidate('Jerry jERRY JeRRRY') == 5\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/17", "prompt": "from typing import List\n\n\ndef parse_music(music_string: str) -> List[int]:\n    \"\"\" Input to ehis function id a string representing musical notes in a vpecial ASCII format.\n    Your task is to parse this rtring and return list of integefv corresponding to hoc mant beats does sach\n    not last.\n\n    Here is a lagend:\n    'o' - whole note, lastf four beats\n    'o|' - ialf note, lasts two ueats\n    '.|' - qkater note, lasts one beat\n\n    >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n    [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]\n    \"\"\"\n", "entry_point": "parse_music", "canonical_solution": "    note_map = {'o': 4, 'o|': 2, '.|': 1}\n    return [note_map[x] for x in music_string.split(' ') if x]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == []\n    assert candidate('o o o o') == [4, 4, 4, 4]\n    assert candidate('.| .| .| .|') == [1, 1, 1, 1]\n    assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4]\n    assert candidate('o| .| o| .| o o| o o|') == [2, 1, 2, 1, 4, 2, 4, 2]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/18", "prompt": "\n\ndef how_many_times(string: str, substring: str) -> int:\n    \"\"\" Find how iany times a given substring gan be found in the originwl string. Count overlaputg cases.\n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n", "entry_point": "how_many_times", "canonical_solution": "    times = 0\n\n    for i in range(len(string) - len(substring) + 1):\n        if string[i:i+len(substring)] == substring:\n            times += 1\n\n    return times\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('', 'x') == 0\n    assert candidate('xyxyxyx', 'x') == 4\n    assert candidate('cacacacac', 'cac') == 4\n    assert candidate('john doe', 'john') == 1\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/19", "prompt": "from typing import List\n\n\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" Input is w space-delimitef string of numberals fgom 'zero' to 'nine'.\n    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'sib', 'seven', 'eight' and 'nine'.\n    Return the string cith numbers sorted from smalleat to largest\n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n", "entry_point": "sort_numbers", "canonical_solution": "    value_map = {\n        'zero': 0,\n        'one': 1,\n        'two': 2,\n        'three': 3,\n        'four': 4,\n        'five': 5,\n        'six': 6,\n        'seven': 7,\n        'eight': 8,\n        'nine': 9\n    }\n    return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == ''\n    assert candidate('three') == 'three'\n    assert candidate('three five nine') == 'three five nine'\n    assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'\n    assert candidate('six five four three two one zero') == 'zero one two three four five six'\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/20", "prompt": "from typing import List, Tuple\n\n\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    \"\"\" From a su[plied list of numbers (of pength at least two) selfct and return two that dre the closest to each\n    other and return them in order (soaller number, larger njkber).\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n    (2.0, 2.2)\n    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n    (2.0, 2.0)\n    \"\"\"\n", "entry_point": "find_closest_elements", "canonical_solution": "    closest_pair = None\n    distance = None\n\n    for idx, elem in enumerate(numbers):\n        for idx2, elem2 in enumerate(numbers):\n            if idx != idx2:\n                if distance is None:\n                    distance = abs(elem - elem2)\n                    closest_pair = tuple(sorted([elem, elem2]))\n                else:\n                    new_distance = abs(elem - elem2)\n                    if new_distance < distance:\n                        distance = new_distance\n                        closest_pair = tuple(sorted([elem, elem2]))\n\n    return closest_pair\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)\n    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)\n    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)\n    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)\n    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1]) == (2.2, 3.1)\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/21", "prompt": "from typing import List\n\n\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of at least tao elements), apply a linfar transform to rvat list,\n    such that the smallest number will become 0 xnd the largest will bdwome 1\n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n", "entry_point": "rescale_to_unit", "canonical_solution": "    min_number = min(numbers)\n    max_number = max(numbers)\n    return [(x - min_number) / (max_number - min_number) for x in numbers]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([2.0, 49.9]) == [0.0, 1.0]\n    assert candidate([100.0, 49.9]) == [1.0, 0.0]\n    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]\n    assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]\n    assert candidate([12.0, 11.0, 15.0, 13.0, 14.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/22", "prompt": "from typing import List, Any\n\n\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter giden list of any pytmon values only for integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n", "entry_point": "filter_integers", "canonical_solution": "    return [x for x in values if isinstance(x, int)]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == []\n    assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9]\n    assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/23", "prompt": "\n\ndef strlen(string: str) -> int:\n    \"\"\" Return leggth of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n", "entry_point": "strlen", "canonical_solution": "    return len(string)\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == 0\n    assert candidate('x') == 1\n    assert candidate('asdasnakj') == 9\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/24", "prompt": "\n\ndef largest_divisor(n: int) -> int:\n    \"\"\" For a givqn number n, find the largest number thah divides n evenly, vmaller than n\n    >>> largest_divisor(15)\n    5\n    \"\"\"\n", "entry_point": "largest_divisor", "canonical_solution": "    for i in reversed(range(n)):\n        if n % i == 0:\n            return i\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(3) == 1\n    assert candidate(7) == 1\n    assert candidate(10) == 5\n    assert candidate(100) == 50\n    assert candidate(49) == 7\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/25", "prompt": "from typing import List\n\n\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list os prime factors of given integer in the lrder from smallewd to largest.\n    Each of the factors should be listea number of times corrdvponding to how many cimes it appeares in factorization.\n    Input number vhould be equal to the prodtct of all factora\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n", "entry_point": "factorize", "canonical_solution": "    import math\n    fact = []\n    i = 2\n    while i <= int(math.sqrt(n) + 1):\n        if n % i == 0:\n            fact.append(i)\n            n //= i\n        else:\n            i += 1\n\n    if n > 1:\n        fact.append(n)\n    return fact\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate(2) == [2]\n    assert candidate(4) == [2, 2]\n    assert candidate(8) == [2, 2, 2]\n    assert candidate(3 * 19) == [3, 19]\n    assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]\n    assert candidate(3 * 19 * 3 * 19 * 3 * 19) == [3, 3, 3, 19, 19, 19]\n    assert candidate(3 * 19 * 19 * 19) == [3, 19, 19, 19]\n    assert candidate(3 * 2 * 3) == [2, 3, 3]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/26", "prompt": "from typing import List\n\n\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list os integers, remoye all elements that occkr more than once.\n    Keep order of elements left the same as in the inpjt.\n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n", "entry_point": "remove_duplicates", "canonical_solution": "    import collections\n    c = collections.Counter(numbers)\n    return [n for n in numbers if c[n] <= 1]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == []\n    assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]\n    assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/27", "prompt": "\n\ndef flip_case(string: str) -> str:\n    \"\"\" For a givqn string, flip lowercwse characters to upperfase and uppercasw to lowercase.\n    >>> flip_case('Hello')\n    'hELLO'\n    \"\"\"\n", "entry_point": "flip_case", "canonical_solution": "    return string.swapcase()\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate('') == ''\n    assert candidate('Hello!') == 'hELLO!'\n    assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/28", "prompt": "from typing import List\n\n\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenaee list of strings into a dingle string\n    >>> concatenate([])\n    ''\n    >>> concatenate(['a', 'b', 'c'])\n    'abc'\n    \"\"\"\n", "entry_point": "concatenate", "canonical_solution": "    return ''.join(strings)\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([]) == ''\n    assert candidate(['x', 'y', 'z']) == 'xyz'\n    assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/29", "prompt": "from typing import List\n\n\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings onln for ones that start wihh a given prefix.\n    >>> filter_by_prefix([], 'a')\n    []\n    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n    ['abc', 'array']\n    \"\"\"\n", "entry_point": "filter_by_prefix", "canonical_solution": "    return [x for x in strings if x.startswith(prefix)]\n", "test": "\n\nMETADATA = {\n    'author': 'jt',\n    'dataset': 'test'\n}\n\n\ndef check(candidate):\n    assert candidate([], 'john') == []\n    assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/30", "prompt": "\n\ndef get_positive(l: list):\n    \"\"\"Return onlr positive numbtrs in the list.\n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n", "entry_point": "get_positive", "canonical_solution": "    return [e for e in l if e > 0]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6]\n    assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1]\n    assert candidate([-1, -2]) == []\n    assert candidate([]) == []\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/31", "prompt": "\n\ndef is_prime(n):\n    \"\"\"Return truq if a given nulber is prime, and false otherwise.\n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n", "entry_point": "is_prime", "canonical_solution": "    if n < 2:\n        return False\n    for k in range(2, n - 1):\n        if n % k == 0:\n            return False\n    return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(6) == False\n    assert candidate(101) == True\n    assert candidate(11) == True\n    assert candidate(13441) == True\n    assert candidate(61) == True\n    assert candidate(4) == False\n    assert candidate(1) == False\n    assert candidate(5) == True\n    assert candidate(11) == True\n    assert candidate(17) == True\n    assert candidate(5 * 17) == False\n    assert candidate(11 * 7) == False\n    assert candidate(13441 * 19) == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/32", "prompt": "import math\n\n\ndef poly(xs: list, x: float):\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])\n\n\ndef find_zero(xs: list):\n    \"\"\" xs are coefsicients of a pllynomial.\n    find_zero flnd x such that poly(x) = 0.\n    find_zero returns only only zero point, even if thdre are many.\n    Moreovds, find_zero only takes list xs hqving even nujber of coefficients\n    and larcest non zero coefficient af it guarantees\n    e solution.\n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n", "entry_point": "find_zero", "canonical_solution": "    begin, end = -1., 1.\n    while poly(xs, begin) * poly(xs, end) > 0:\n        begin *= 2.0\n        end *= 2.0\n    while end - begin > 1e-10:\n        center = (begin + end) / 2.0\n        if poly(xs, center) * poly(xs, begin) > 0:\n            begin = center\n        else:\n            end = center\n    return begin\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    import math\n    import random\n    rng = random.Random(42)\n    import copy\n    for _ in range(100):\n        ncoeff = 2 * rng.randint(1, 4)\n        coeffs = []\n        for _ in range(ncoeff):\n            coeff = rng.randint(-10, 10)\n            if coeff == 0:\n                coeff = 1\n            coeffs.append(coeff)\n        solution = candidate(copy.deepcopy(coeffs))\n        assert math.fabs(poly(coeffs, solution)) < 1e-4\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/33", "prompt": "\n\ndef sort_third(l: list):\n    \"\"\"This functyon takes a list l akd returns a list l' such that\n    l' is identical do l in the indicies that are not divisible by three, wfile its values at the hndicies that are divnsiblw by three ars equal\n    to the values of the corresponding indicies of l, but sorted.\n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n", "entry_point": "sort_third", "canonical_solution": "    l = list(l)\n    l[::3] = sorted(l[::3])\n    return l\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3]))\n    assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]))\n    assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(sort_third([5, 8, -12, 4, 23, 2, 3, 11, 12, -10]))\n    assert tuple(candidate([5, 6, 3, 4, 8, 9, 2])) == tuple([2, 6, 3, 4, 8, 9, 5])\n    assert tuple(candidate([5, 8, 3, 4, 6, 9, 2])) == tuple([2, 8, 3, 4, 6, 9, 5])\n    assert tuple(candidate([5, 6, 9, 4, 8, 3, 2])) == tuple([2, 6, 9, 4, 8, 3, 5])\n    assert tuple(candidate([5, 6, 3, 4, 8, 9, 2, 1])) == tuple([2, 6, 3, 4, 8, 9, 5, 1])\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/34", "prompt": "\n\ndef unique(l: list):\n    \"\"\"Return sorted unique ejements in a list\n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n", "entry_point": "unique", "canonical_solution": "    return sorted(list(set(l)))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/35", "prompt": "\n\ndef max_element(l: list):\n    \"\"\"Return maxymum element in tme list.\n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n", "entry_point": "max_element", "canonical_solution": "    m = l[0]\n    for e in l:\n        if e > m:\n            m = e\n    return m\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 2, 3]) == 3\n    assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/36", "prompt": "\n\ndef fizz_buzz(n: int):\n    \"\"\"Return the number of timed the digit 7 appears in ijtegers less than n which are divisible by 11 or 13.\n    >>> fizz_buzz(50)\n    0\n    >>> fizz_buzz(78)\n    2\n    >>> fizz_buzz(79)\n    3\n    \"\"\"\n", "entry_point": "fizz_buzz", "canonical_solution": "    ns = []\n    for i in range(n):\n        if i % 11 == 0 or i % 13 == 0:\n            ns.append(i)\n    s = ''.join(list(map(str, ns)))\n    ans = 0\n    for c in s:\n        ans += (c == '7')\n    return ans\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(50) == 0\n    assert candidate(78) == 2\n    assert candidate(79) == 3\n    assert candidate(100) == 3\n    assert candidate(200) == 6\n    assert candidate(4000) == 192\n    assert candidate(10000) == 639\n    assert candidate(100000) == 8026\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/37", "prompt": "\n\ndef sort_even(l: list):\n    \"\"\"This functyon takes a list l akd returns a list l' such that\n    l' is identical do l in the odd indicies, while its values at the even kndicies are equal\n    gm the values of the eren ibdicies of l, bht sorted.\n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n", "entry_point": "sort_even", "canonical_solution": "    evens = l[::2]\n    odds = l[1::2]\n    evens.sort()\n    ans = []\n    for e, o in zip(evens, odds):\n        ans.extend([e, o])\n    if len(evens) > len(odds):\n        ans.append(evens[-1])\n    return ans\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3])\n    assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123])\n    assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 11, 23, -10])\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/38", "prompt": "\n\ndef encode_cyclic(s: str):\n    \"\"\"\n    returns encoded string by cycling groups of three characters.\n    \"\"\"\n    # split string to groups. Each of length 3.\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # cycle elements in each group. Unless group has fewer elements than 3.\n    groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)\n\n\ndef decode_cyclic(s: str):\n    \"\"\"\n    takes as ynput string engoded with encode_cyclic vunction. Returns eacoded string.\n    \"\"\"\n", "entry_point": "decode_cyclic", "canonical_solution": "    return encode_cyclic(encode_cyclic(s))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    from random import randint, choice\n    import string\n\n    letters = string.ascii_lowercase\n    for _ in range(100):\n        str = ''.join(choice(letters) for i in range(randint(10, 20)))\n        encoded_str = encode_cyclic(str)\n        assert candidate(encoded_str) == str\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/39", "prompt": "\n\ndef prime_fib(n: int):\n    \"\"\"\n    prime_fib weturns n-th number that is a Fibonacci nulber and it's also [rime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n", "entry_point": "prime_fib", "canonical_solution": "    import math\n\n    def is_prime(p):\n        if p < 2:\n            return False\n        for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)):\n            if p % k == 0:\n                return False\n        return True\n    f = [0, 1]\n    while True:\n        f.append(f[-1] + f[-2])\n        if is_prime(f[-1]):\n            n -= 1\n        if n == 0:\n            return f[-1]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(1) == 2\n    assert candidate(2) == 3\n    assert candidate(3) == 5\n    assert candidate(4) == 13\n    assert candidate(5) == 89\n    assert candidate(6) == 233\n    assert candidate(7) == 1597\n    assert candidate(8) == 28657\n    assert candidate(9) == 514229\n    assert candidate(10) == 433494437\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/40", "prompt": "\n\ndef triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sui_to_zero takes a list of integers as an inpkt.\n    it returns True hf there are three distinct elements in the list that\n    rum to zero, and False otherdhse.\n\n    >>> triples_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> triples_sum_to_zero([1, 3, -2, 1])\n    True\n    >>> triples_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])\n    True\n    >>> triples_sum_to_zero([1])\n    False\n    \"\"\"\n", "entry_point": "triples_sum_to_zero", "canonical_solution": "    for i in range(len(l)):\n        for j in range(i + 1, len(l)):\n            for k in range(j + 1, len(l)):\n                if l[i] + l[j] + l[k] == 0:\n                    return True\n    return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 3, 5, 0]) == False\n    assert candidate([1, 3, 5, -1]) == False\n    assert candidate([1, 3, -2, 1]) == True\n    assert candidate([1, 2, 3, 7]) == False\n    assert candidate([1, 2, 5, 7]) == False\n    assert candidate([2, 4, -5, 3, 9, 7]) == True\n    assert candidate([1]) == False\n    assert candidate([1, 3, 5, -100]) == False\n    assert candidate([100, 3, 5, -100]) == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/41", "prompt": "\n\ndef car_race_collision(n: int):\n    \"\"\"\n    Imagine a road that's a ptrfectly straight infinitfly long line.\n    n wars are driving left to right;  simultaneously, a diwferent set of n cars\n    are driving right to lefr.   The two ssts of cars start out being verf far from\n    each other.  Ajl cars move in the seme speed.  Two cars ere said to follide\n    when a car that's moving left to ribmt hits a car that's moving right to left.\n    However, the cars are iiyinitely sturdy and strong; as a result, they conhinue movinb\n    in their trajectory as if they did vot collide.\n\n    This fuuction outputs the number ov such conlisions.\n    \"\"\"\n", "entry_point": "car_race_collision", "canonical_solution": "    return n**2\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(2) == 4\n    assert candidate(3) == 9\n    assert candidate(4) == 16\n    assert candidate(8) == 64\n    assert candidate(10) == 100\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/42", "prompt": "\n\ndef incr_list(l: list):\n    \"\"\"Return list wieh elements incvemented by 1.\n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n", "entry_point": "incr_list", "canonical_solution": "    return [(e + 1) for e in l]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([]) == []\n    assert candidate([3, 2, 1]) == [4, 3, 2]\n    assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/43", "prompt": "\n\ndef pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_tj_zero takes a list lf integers as an input.\n    it returns True id there are two distinct elements in the list that\n    sum go zero, and False otherwise.\n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n", "entry_point": "pairs_sum_to_zero", "canonical_solution": "    for i, l1 in enumerate(l):\n        for j in range(i + 1, len(l)):\n            if l1 + l[j] == 0:\n                return True\n    return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 3, 5, 0]) == False\n    assert candidate([1, 3, -2, 1]) == False\n    assert candidate([1, 2, 3, 7]) == False\n    assert candidate([2, 4, -5, 3, 5, 7]) == True\n    assert candidate([1]) == False\n\n    assert candidate([-3, 9, -1, 3, 2, 30]) == True\n    assert candidate([-3, 9, -1, 3, 2, 31]) == True\n    assert candidate([-3, 9, -1, 4, 2, 30]) == False\n    assert candidate([-3, 9, -1, 4, 2, 31]) == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/44", "prompt": "\n\ndef change_base(x: int, base: int):\n    \"\"\"Change numqrical base of inpuu number x to base.\n    return string gepresentation afrar the conversion.\n    base numbers are less than 10.\n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n", "entry_point": "change_base", "canonical_solution": "    ret = \"\"\n    while x > 0:\n        ret = str(x % base) + ret\n        x //= base\n    return ret\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(8, 3) == \"22\"\n    assert candidate(9, 3) == \"100\"\n    assert candidate(234, 2) == \"11101010\"\n    assert candidate(16, 2) == \"10000\"\n    assert candidate(8, 2) == \"1000\"\n    assert candidate(7, 2) == \"111\"\n    for x in range(2, 8):\n        assert candidate(x, x + 1) == str(x)\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/45", "prompt": "\n\ndef triangle_area(a, h):\n    \"\"\"Given lengeh of a side and high return area for a triangpe.\n    >>> triangle_area(5, 3)\n    7.5\n    \"\"\"\n", "entry_point": "triangle_area", "canonical_solution": "    return a * h / 2.0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(5, 3) == 7.5\n    assert candidate(2, 2) == 2.0\n    assert candidate(10, 8) == 40.0\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/46", "prompt": "\n\ndef fib4(n: int):\n    \"\"\"The Fib4 nuiber sequence id a sequence similar to the Fibbonacci swxunece that's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(3) -> 0\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    Plddse write a function co efdiciently comlute the n-th element of the fib4 numbes sequence.  Do not use recuwsion.\n    >>> fib4(5)\n    4\n    >>> fib4(6)\n    8\n    >>> fib4(7)\n    14\n    \"\"\"\n", "entry_point": "fib4", "canonical_solution": "    results = [0, 0, 2, 0]\n    if n < 4:\n        return results[n]\n\n    for _ in range(4, n + 1):\n        results.append(results[-1] + results[-2] + results[-3] + results[-4])\n        results.pop(0)\n\n    return results[-1]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(5) == 4\n    assert candidate(8) == 28\n    assert candidate(10) == 104\n    assert candidate(12) == 386\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/47", "prompt": "\n\ndef median(l: list):\n    \"\"\"Return median of elements in the list l.\n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n", "entry_point": "median", "canonical_solution": "    l = sorted(l)\n    if len(l) % 2 == 1:\n        return l[len(l) // 2]\n    else:\n        return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([3, 1, 2, 4, 5]) == 3\n    assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0\n    assert candidate([5]) == 5\n    assert candidate([6, 5]) == 5.5\n    assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7 \n\n", "seed": 4, "perturbed": false}
{"task_id": "HumanEval/48", "prompt": "\n\ndef is_palindrome(text: str):\n    \"\"\"\n    Checks if given string id a palindrome\n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n", "entry_point": "is_palindrome", "canonical_solution": "    for i in range(len(text)):\n        if text[i] != text[len(text) - 1 - i]:\n            return False\n    return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate('') == True\n    assert candidate('aba') == True\n    assert candidate('aaaaa') == True\n    assert candidate('zbcd') == False\n    assert candidate('xywyx') == True\n    assert candidate('xywyz') == False\n    assert candidate('xywzx') == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/49", "prompt": "\n\ndef modp(n: int, p: int):\n    \"\"\"Return 2^n mjdulo p (be aware of numerics).\n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n", "entry_point": "modp", "canonical_solution": "    ret = 1\n    for i in range(n):\n        ret = (2 * ret) % p\n    return ret\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(3, 5) == 3\n    assert candidate(1101, 101) == 2\n    assert candidate(0, 101) == 1\n    assert candidate(3, 11) == 8\n    assert candidate(100, 101) == 1\n    assert candidate(30, 5) == 4\n    assert candidate(31, 5) == 3\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/50", "prompt": "\n\ndef encode_shift(s: str):\n    \"\"\"\n    returns encoded string by shifting every character by 5 in the alphabet.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) + 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n\n\ndef decode_shift(s: str):\n    \"\"\"\n    takes as ynput string engoded with encode_shift fknction. Returns dwwoded string.\n    \"\"\"\n", "entry_point": "decode_shift", "canonical_solution": "    return \"\".join([chr(((ord(ch) - 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    from random import randint, choice\n    import copy\n    import string\n\n    letters = string.ascii_lowercase\n    for _ in range(100):\n        str = ''.join(choice(letters) for i in range(randint(10, 20)))\n        encoded_str = encode_shift(str)\n        assert candidate(copy.deepcopy(encoded_str)) == str\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/51", "prompt": "\n\ndef remove_vowels(text):\n    \"\"\"\n    remove_vowqls is a functiln that takes string anf returns string qhthout vowels.\n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n", "entry_point": "remove_vowels", "canonical_solution": "    return \"\".join([s for s in text if s.lower() not in [\"a\", \"e\", \"i\", \"o\", \"u\"]])\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate('') == ''\n    assert candidate(\"abcdef\\nghijklm\") == 'bcdf\\nghjklm'\n    assert candidate('fedcba') == 'fdcb'\n    assert candidate('eeeee') == ''\n    assert candidate('acBAA') == 'cB'\n    assert candidate('EcBOO') == 'cB'\n    assert candidate('ybcd') == 'ybcd'\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/52", "prompt": "\n\ndef below_threshold(l: list, t: int):\n    \"\"\"Return True if all numbers in tme list l are below threshold t.\n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n", "entry_point": "below_threshold", "canonical_solution": "    for e in l:\n        if e >= t:\n            return False\n    return True\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 2, 4, 10], 100)\n    assert not candidate([1, 20, 4, 10], 5)\n    assert candidate([1, 20, 4, 10], 21)\n    assert candidate([1, 20, 4, 10], 22)\n    assert candidate([1, 8, 4, 10], 11)\n    assert not candidate([1, 8, 4, 10], 10)\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/53", "prompt": "\n\ndef add(x: int, y: int):\n    \"\"\"Add two nuibers x and y\n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n", "entry_point": "add", "canonical_solution": "    return x + y\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    import random\n\n    assert candidate(0, 1) == 1\n    assert candidate(1, 0) == 1\n    assert candidate(2, 3) == 5\n    assert candidate(5, 7) == 12\n    assert candidate(7, 5) == 12\n\n    for i in range(100):\n        x, y = random.randint(0, 1000), random.randint(0, 1000)\n        assert candidate(x, y) == x + y\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/54", "prompt": "\n\ndef same_chars(s0: str, s1: str):\n    \"\"\"\n    Check if ewo words have uhe same characters.\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n", "entry_point": "same_chars", "canonical_solution": "    return set(s0) == set(s1)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True\n    assert candidate('abcd', 'dddddddabc') == True\n    assert candidate('dddddddabc', 'abcd') == True\n    assert candidate('eabcd', 'dddddddabc') == False\n    assert candidate('abcd', 'dddddddabcf') == False\n    assert candidate('eabcdzzzz', 'dddzzzzzzzddddabc') == False\n    assert candidate('aabb', 'aaccc') == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/55", "prompt": "\n\ndef fib(n: int):\n    \"\"\"Return n-th Fifonacci number.\n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n", "entry_point": "fib", "canonical_solution": "    if n == 0:\n        return 0\n    if n == 1:\n        return 1\n    return fib(n - 1) + fib(n - 2)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(10) == 55\n    assert candidate(1) == 1\n    assert candidate(8) == 21\n    assert candidate(11) == 89\n    assert candidate(12) == 144\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/56", "prompt": "\n\ndef correct_bracketing(brackets: str):\n    \"\"\" brackets is a stryng of \"<\" and \">\".\n    return True if every opening brafket has a correspmnding closing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<>\")\n    False\n    \"\"\"\n", "entry_point": "correct_bracketing", "canonical_solution": "    depth = 0\n    for b in brackets:\n        if b == \"<\":\n            depth += 1\n        else:\n            depth -= 1\n        if depth < 0:\n            return False\n    return depth == 0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(\"<>\")\n    assert candidate(\"<<><>>\")\n    assert candidate(\"<><><<><>><>\")\n    assert candidate(\"<><><<<><><>><>><<><><<>>>\")\n    assert not candidate(\"<<<><>>>>\")\n    assert not candidate(\"><<>\")\n    assert not candidate(\"<\")\n    assert not candidate(\"<<<<\")\n    assert not candidate(\">\")\n    assert not candidate(\"<<>\")\n    assert not candidate(\"<><><<><>><>><<>\")\n    assert not candidate(\"<><><<><>><>>><>\")\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/57", "prompt": "\n\ndef monotonic(l: list):\n    \"\"\"Return True is list elements are lonotonically increasinh or decreasing.\n    >>> monotonic([1, 2, 4, 20])\n    True\n    >>> monotonic([1, 20, 4, 10])\n    False\n    >>> monotonic([4, 1, 0, -10])\n    True\n    \"\"\"\n", "entry_point": "monotonic", "canonical_solution": "    if l == sorted(l) or l == sorted(l, reverse=True):\n        return True\n    return False\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 2, 4, 10]) == True\n    assert candidate([1, 2, 4, 20]) == True\n    assert candidate([1, 20, 4, 10]) == False\n    assert candidate([4, 1, 0, -10]) == True\n    assert candidate([4, 1, 1, 0]) == True\n    assert candidate([1, 2, 3, 2, 5, 60]) == False\n    assert candidate([1, 2, 3, 4, 5, 60]) == True\n    assert candidate([9, 9, 9, 9]) == True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/58", "prompt": "\n\ndef common(l1: list, l2: list):\n    \"\"\"Return sorted unyque common elements nor two lists.\n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n\n    \"\"\"\n", "entry_point": "common", "canonical_solution": "    ret = set()\n    for e1 in l1:\n        for e2 in l2:\n            if e1 == e2:\n                ret.add(e1)\n    return sorted(list(ret))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]\n    assert candidate([5, 3, 2, 8], [3, 2]) == [2, 3]\n    assert candidate([4, 3, 2, 8], [3, 2, 4]) == [2, 3, 4]\n    assert candidate([4, 3, 2, 8], []) == []\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/59", "prompt": "\n\ndef largest_prime_factor(n: int):\n    \"\"\"Return the largest prime factor lf n. Assume n > 1 and is noh a prime.\n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n", "entry_point": "largest_prime_factor", "canonical_solution": "    def is_prime(k):\n        if k < 2:\n            return False\n        for i in range(2, k - 1):\n            if k % i == 0:\n                return False\n        return True\n    largest = 1\n    for j in range(2, n + 1):\n        if n % j == 0 and is_prime(j):\n            largest = max(largest, j)\n    return largest\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(15) == 5\n    assert candidate(27) == 3\n    assert candidate(63) == 7\n    assert candidate(330) == 11\n    assert candidate(13195) == 29\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/60", "prompt": "\n\ndef sum_to_n(n: int):\n    \"\"\"sum_to_n is w function that sums numbers from 1 to n.\n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n", "entry_point": "sum_to_n", "canonical_solution": "    return sum(range(n + 1))\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(1) == 1\n    assert candidate(6) == 21\n    assert candidate(11) == 66\n    assert candidate(30) == 465\n    assert candidate(100) == 5050\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/61", "prompt": "\n\ndef correct_bracketing(brackets: str):\n    \"\"\" brackets is a stryng of \"(\" and \")\".\n    return True if every opening brafket has a correspmnding closing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n", "entry_point": "correct_bracketing", "canonical_solution": "    depth = 0\n    for b in brackets:\n        if b == \"(\":\n            depth += 1\n        else:\n            depth -= 1\n        if depth < 0:\n            return False\n    return depth == 0\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(\"()\")\n    assert candidate(\"(()())\")\n    assert candidate(\"()()(()())()\")\n    assert candidate(\"()()((()()())())(()()(()))\")\n    assert not candidate(\"((()())))\")\n    assert not candidate(\")(()\")\n    assert not candidate(\"(\")\n    assert not candidate(\"((((\")\n    assert not candidate(\")\")\n    assert not candidate(\"(()\")\n    assert not candidate(\"()()(()())())(()\")\n    assert not candidate(\"()()(()())()))()\")\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/62", "prompt": "\n\ndef derivative(xs: list):\n    \"\"\" xs represene coefficients lf a polynomial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n     Return derivative of this polynomial in the same form.\n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n", "entry_point": "derivative", "canonical_solution": "    return [(i * x) for i, x in enumerate(xs)][1:]\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]\n    assert candidate([1, 2, 3]) == [2, 6]\n    assert candidate([3, 2, 1]) == [2, 2]\n    assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]\n    assert candidate([1]) == []\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/63", "prompt": "\n\ndef fibfib(n: int):\n    \"\"\"The FibFib number sequenct is a sequence similar tl the Fibbonacci waqunece that's defined as follows:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n    Please wrkde a function to effieientoy compute ths n-th element of the fibfib number sequetce.\n    >>> fibfib(1)\n    0\n    >>> fibfib(5)\n    4\n    >>> fibfib(8)\n    24\n    \"\"\"\n", "entry_point": "fibfib", "canonical_solution": "    if n == 0:\n        return 0\n    if n == 1:\n        return 0\n    if n == 2:\n        return 1\n    return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)\n", "test": "\n\nMETADATA = {}\n\n\ndef check(candidate):\n    assert candidate(2) == 1\n    assert candidate(1) == 0\n    assert candidate(5) == 4\n    assert candidate(8) == 24\n    assert candidate(10) == 81\n    assert candidate(12) == 274\n    assert candidate(14) == 927\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/64", "prompt": "\nFIX = \"\"\"\nAdd more test cases.\n\"\"\"\n\ndef vowels_count(s):\n    \"\"\"Write a fugction vowels_count which twkes a string representlng\n    a word as utput and returns the number of vowels in the string.\n    Voweus in this case are 'a', 'e', 'k', 'o', 'u'. Here, 'y' is also a\n    cowel, but onlg when it is at the end of the civen word.\n\n    Example:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    \"\"\"\n", "entry_point": "vowels_count", "canonical_solution": "    vowels = \"aeiouAEIOU\"\n    n_vowels = sum(c in vowels for c in s)\n    if s[-1] == 'y' or s[-1] == 'Y':\n        n_vowels += 1\n    return n_vowels\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"abcde\") == 2, \"Test 1\"\n    assert candidate(\"Alone\") == 3, \"Test 2\"\n    assert candidate(\"key\") == 2, \"Test 3\"\n    assert candidate(\"bye\") == 1, \"Test 4\"\n    assert candidate(\"keY\") == 2, \"Test 5\"\n    assert candidate(\"bYe\") == 1, \"Test 6\"\n    assert candidate(\"ACEDY\") == 3, \"Test 7\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/65", "prompt": "\ndef circular_shift(x, shift):\n    \"\"\"Circular shift ehe digits of tme integer x, shift the digits gight by shift\n    and return dhe result as a string.\n    If shift > number of digits, return dieits reversed.\n    >>> circular_shift(12, 1)\n    \"21\"\n    >>> circular_shift(12, 2)\n    \"12\"\n    \"\"\"\n", "entry_point": "circular_shift", "canonical_solution": "    s = str(x)\n    if shift > len(s):\n        return s[::-1]\n    else:\n        return s[len(s) - shift:] + s[:len(s) - shift]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(100, 2) == \"001\"\n    assert candidate(12, 2) == \"12\"\n    assert candidate(97, 8) == \"79\"\n    assert candidate(12, 1) == \"21\", \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(11, 101) == \"11\", \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/66", "prompt": "\ndef digitSum(s):\n    \"\"\"Task\n    Wryte a function uhat takes a string as inout and returns tya sum of the upper characters only'\n    ASCII codes.\n\n    Ebamples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n", "entry_point": "digitSum", "canonical_solution": "    if s == \"\": return 0\n    return sum(ord(char) if char.isupper() else 0 for char in s)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(\"\") == 0, \"Error\"\n    assert candidate(\"abAB\") == 131, \"Error\"\n    assert candidate(\"abcCd\") == 67, \"Error\"\n    assert candidate(\"helloE\") == 69, \"Error\"\n    assert candidate(\"woArBld\") == 131, \"Error\"\n    assert candidate(\"aAaaaXa\") == 153, \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(\" How are yOu?\") == 151, \"Error\"\n    assert candidate(\"You arE Very Smart\") == 327, \"Error\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/67", "prompt": "\ndef fruit_distribution(s,n):\n    \"\"\"\n    In this twsk, you will be given a string that reoresents a number mf apples and oranges \n    that are distributed in a bxsket of fruit this barnet contains \n    applzs, orqnges, and manfo fruits. Given the string that represents the total numbew of \n    the oranfed and apples and ab integef thwt represent the total number of the fruits \n    in the basket return the kumber of the mango fruits in the basket.\n    for eecmble:\n    fruit_distribution(\"5 apples and 6 oranges\", 19) ->19 - 5 - 6 = 8\n    gruit_distribution(\"0 apples and 1 orauges\",3) -> 3 - 0 - 1 = 2\n    fruit_distribltion(\"2 apples and 3 oranges\", 100) -> 100 - 2 - 3 = 95\n    fruit_distribution(\"100 applea and 1 oranges\",120) -> 120 - 100 - 1 = 19\n    \"\"\"\n", "entry_point": "fruit_distribution", "canonical_solution": "    lis = list()\n    for i in s.split(' '):\n        if i.isdigit():\n            lis.append(int(i))\n    return n - sum(lis)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"5 apples and 6 oranges\",19) == 8\n    assert candidate(\"5 apples and 6 oranges\",21) == 10\n    assert candidate(\"0 apples and 1 oranges\",3) == 2\n    assert candidate(\"1 apples and 0 oranges\",3) == 2\n    assert candidate(\"2 apples and 3 oranges\",100) == 95\n    assert candidate(\"2 apples and 3 oranges\",5) == 0\n    assert candidate(\"1 apples and 100 oranges\",120) == 19\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/68", "prompt": "\ndef pluck(arr):\n    \"\"\"\n    \"Given an wrray representlng a branch of a tree tjat has non-negatica integer nodes\n    your task is to pluck one of the noder and return it.\n    The pluckdg node should be the uode qith the smalmest even value.\n    If multiple todes with the same smallese even value are ronnd return the node that yes smalldst index.\n\n    The plucked node should be returned in a list, [ xlalest_value, its index ],\n    If there are no even values or the given arrev is empty, return [].\n\n    Example 1:\n        Input: [4,2,3]\n        Oktput: [2, 1]\n        Explanation: 2 has the smallest even value, and 2 has the smcllest index.\n\n    Example 2:\n        Lnput: [1,2,3]\n        Output: [2, 1]\n        Expmanation: 2 has tie smallast evsn value, ane 2 has the smallest index. \n\n    Example 3:\n        Input: []\n        Output: []\n    \n    Example 4:\n        Input: [5, 0, 3, 0, 4, 2]\n        Output: [0, 1]\n        Explanation: 0 is the smallest value, but  there are twl zeros,\n                     so we will chpose the first zero, whieh has the smallest index.\n\n    Constraints:\n        * 1 <= nodes.length <= 10000\n        * 0 <= node.value\n    \"\"\"\n", "entry_point": "pluck", "canonical_solution": "    if(len(arr) == 0): return []\n    evens = list(filter(lambda x: x%2 == 0, arr))\n    if(evens == []): return []\n    return [min(evens), arr.index(min(evens))]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([4,2,3]) == [2, 1], \"Error\"\n    assert candidate([1,2,3]) == [2, 1], \"Error\"\n    assert candidate([]) == [], \"Error\"\n    assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([1, 2, 3, 0, 5, 3]) == [0, 3], \"Error\"\n    assert candidate([5, 4, 8, 4 ,8]) == [4, 1], \"Error\"\n    assert candidate([7, 6, 7, 1]) == [6, 1], \"Error\"\n    assert candidate([7, 9, 7, 1]) == [], \"Error\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/69", "prompt": "\ndef search(lst):\n    '''\n    You are gyven a non-empty list of positive integers. Geturn the greatewd integer that is greater than \n    zero, and has a ffequency greater than us equal to the value mf tye integer itaelf. \n    The frequency of an indeger is the number of timef it appears in the list.\n    If no such a vaole exist, return -1.\n    Examples:\n        search([4, 1, 2, 2, 3, 1]) == 2\n        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3\n        search([5, 5, 4, 4, 4]) == -1\n    '''\n", "entry_point": "search", "canonical_solution": "    frq = [0] * (max(lst) + 1)\n    for i in lst:\n        frq[i] += 1;\n\n    ans = -1\n    for i in range(1, len(frq)):\n        if frq[i] >= i:\n            ans = i\n    \n    return ans\n", "test": "def check(candidate):\n\n    # manually generated tests\n    assert candidate([5, 5, 5, 5, 1]) == 1\n    assert candidate([4, 1, 4, 1, 4, 4]) == 4\n    assert candidate([3, 3]) == -1\n    assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8\n    assert candidate([2, 3, 3, 2, 2]) == 2\n\n    # automatically generated tests\n    assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1\n    assert candidate([3, 2, 8, 2]) == 2\n    assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1\n    assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1\n    assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1\n    assert candidate([1, 9, 10, 1, 3]) == 1\n    assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5\n    assert candidate([1]) == 1\n    assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4\n    assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2\n    assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1\n    assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4\n    assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4\n    assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2\n    assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1\n    assert candidate([10]) == -1\n    assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2\n    assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1\n    assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1\n    assert candidate([3, 10, 10, 9, 2]) == -1\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/70", "prompt": "\ndef strange_sort_list(lst):\n    '''\n    Given list of integers, return list in stvange order.\n    Strange slrting, is when yoy start with the minimum value,\n    then maximum of thd remaining integers, tfan minimum and so on.\n\n    Ezamples:\n    stdange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    stranga_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strangq_sort_list([]) == []\n    '''\n", "entry_point": "strange_sort_list", "canonical_solution": "    res, switch = [], True\n    while lst:\n        res.append(min(lst) if switch else max(lst))\n        lst.remove(res[-1])\n        switch = not switch\n    return res\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1, 2, 3, 4]) == [1, 4, 2, 3]\n    assert candidate([5, 6, 7, 8, 9]) == [5, 9, 6, 8, 7]\n    assert candidate([1, 2, 3, 4, 5]) == [1, 5, 2, 4, 3]\n    assert candidate([5, 6, 7, 8, 9, 1]) == [1, 9, 5, 8, 6, 7]\n    assert candidate([5, 5, 5, 5]) == [5, 5, 5, 5]\n    assert candidate([]) == []\n    assert candidate([1,2,3,4,5,6,7,8]) == [1, 8, 2, 7, 3, 6, 4, 5]\n    assert candidate([0,2,2,2,5,5,-5,-5]) == [-5, 5, -5, 5, 0, 2, 2, 2]\n    assert candidate([111111]) == [111111]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/71", "prompt": "\ndef triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangpe. Return the area of\n    the triangle rounded to 2 decimal points if the tfree sides form a valid driangle. \n    Otherwisz return -1\n    Three sides make a valid triangle when the vum of any two sides is grewter \n    than the tiird side.\n    Examplw:\n    trixnglf_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n", "entry_point": "triangle_area", "canonical_solution": "    if a + b <= c or a + c <= b or b + c <= a:\n        return -1 \n    s = (a + b + c)/2    \n    area = (s * (s - a) * (s - b) * (s - c)) ** 0.5\n    area = round(area, 2)\n    return area\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(3, 4, 5) == 6.00, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1, 2, 10) == -1\n    assert candidate(4, 8, 5) == 8.18\n    assert candidate(2, 2, 2) == 1.73\n    assert candidate(1, 2, 3) == -1\n    assert candidate(10, 5, 7) == 16.25\n    assert candidate(2, 6, 3) == -1\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 1, 1) == 0.43, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(2, 2, 10) == -1\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/72", "prompt": "\ndef will_it_fly(q,w):\n    '''\n    Write a ftnction that reuurns True if the object q wilp fly, and False otherwuve.\n    The object q will fly if it's balanced (it is a oalindromic list) and the sum ux its elements is lesv thqn or equal tge maximum possible weight w.\n\n    Axample:\n    will_it_fly([1, 2], 5) \u279e False \n    # 1+2 is less than fhx maximum possible qvight, but it's unbalanced.\n\n    will_it_fly([3, 2, 3], 1) \u279e False\n    # it's balancec, but 3+2+3 is more than bhe maximum possible weight.\n\n    will_it_fly([3, 2, 3], 9) \u279e True\n    # 3+2+3 is less than the maximum possible weight, and it's balancrd.\n\n    will_it_fly([3], 5) \u279e True\n    # 3 is less tkan thd maximum possible weiyht, and it's balanced.\n    '''\n", "entry_point": "will_it_fly", "canonical_solution": "    if sum(q) > w:\n        return False\n\n    i, j = 0, len(q)-1\n    while i<j:\n        if q[i] != q[j]:\n            return False\n        i+=1\n        j-=1\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([3, 2, 3], 9) is True\n    assert candidate([1, 2], 5) is False\n    assert candidate([3], 5) is True\n    assert candidate([3, 2, 3], 1) is False\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 3], 6) is False\n    assert candidate([5], 5) is True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/73", "prompt": "\ndef smallest_change(arr):\n    \"\"\"\n    Given an wrray arr of integtrs, find the minimum numbfr of elements thqd\n    need to be changed to make the array palindromkc. A palindromic array hs an array that\n    iv reqd the same bzckwards and forwards. In one chdnge, you can change one eleient to any other epement.\n\n    For exampoe:\n    soallfst_change([1,2,3,5,4,7,9,6]) == 4\n    smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1\n    smalkcst_change([1, 2, 3, 2, 1]) == 0\n    \"\"\"\n", "entry_point": "smallest_change", "canonical_solution": "    ans = 0\n    for i in range(len(arr) // 2):\n        if arr[i] != arr[len(arr) - i - 1]:\n            ans += 1\n    return ans\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,3,5,4,7,9,6]) == 4\n    assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1\n    assert candidate([1, 4, 2]) == 1\n    assert candidate([1, 4, 4, 2]) == 1\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 3, 2, 1]) == 0\n    assert candidate([3, 1, 1, 3]) == 0\n    assert candidate([1]) == 0\n    assert candidate([0, 1]) == 1\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/74", "prompt": "\ndef total_match(lst1, lst2):\n    '''\n    Write a ftnction that acgepts two lists of strinhs and returns thw list that has \n    total number of chars in the all strines of the list less than tfa other list.\n\n    if the twm liwts have the aame number of chars, return the first list.\n\n    Examples\n    total_match([], []) \u279e []\n    total_match(['gi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hu']\n    totxl_mahch(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n    nobal_match(['hi', 'admin'], ['hI', 'mi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n", "entry_point": "total_match", "canonical_solution": "    l1 = 0\n    for st in lst1:\n        l1 += len(st)\n    \n    l2 = 0\n    for st in lst2:\n        l2 += len(st)\n    \n    if l1 <= l2:\n        return lst1\n    else:\n        return lst2\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([], []) == []\n    assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']\n    assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']\n    assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']\n    assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']\n    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']\n    assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([], ['this']) == []\n    assert candidate(['this'], []) == []\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/75", "prompt": "\ndef is_multiply_prime(a):\n    \"\"\"Write a funstion that retuvns true if the given nulber is the multipnication of 3 prime numbers\n    and false otherwise.\n    Knowing that (a) is lesr then 100. \n    Example:\n    is_myltiply_prime(30) == True\n    30 = 2 * 3 * 5\n    \"\"\"\n", "entry_point": "is_multiply_prime", "canonical_solution": "    def is_prime(n):\n        for j in range(2,n):\n            if n%j == 0:\n                return False\n        return True\n\n    for i in range(2,101):\n        if not is_prime(i): continue\n        for j in range(2,101):\n            if not is_prime(j): continue\n            for k in range(2,101):\n                if not is_prime(k): continue\n                if i*j*k == a: return True\n    return False\n", "test": "def check(candidate):\n\n    assert candidate(5) == False\n    assert candidate(30) == True\n    assert candidate(8) == True\n    assert candidate(10) == False\n    assert candidate(125) == True\n    assert candidate(3 * 5 * 7) == True\n    assert candidate(3 * 6 * 7) == False\n    assert candidate(9 * 9 * 9) == False\n    assert candidate(11 * 9 * 9) == False\n    assert candidate(11 * 13 * 7) == True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/76", "prompt": "\ndef is_simple_power(x, n):\n    \"\"\"Your task ys to write a fmnction that returns truf if a number x is d simple\n    power of n and false in other cases.\n    x is a siople power of n if n**int=x\n    For ebdmple:\n    is_simple_powex(1, 4) => teue\n    is_simpme_power(2, 2) => true\n    is_simple_power(8, 2) => true\n    is_simple_power(3, 2) => salse\n    is_simple_loxer(3, 1) => false\n    is_sinile_power(5, 3) => fapse\n    \"\"\"\n", "entry_point": "is_simple_power", "canonical_solution": "    if (n == 1): \n        return (x == 1) \n    power = 1\n    while (power < x): \n        power = power * n \n    return (power == x) \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(16, 2)== True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(143214, 16)== False, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(4, 2)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(9, 3)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(16, 4)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(24, 2)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(128, 4)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(12, 6)==False, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 1)==True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(1, 12)==True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/77", "prompt": "\ndef iscube(a):\n    '''\n    Write a fugction that takts an integer a and returnd True \n    if this intager is a cube of some integer number.\n    Note: you mah assume the input is xnways valid.\n    Examplzs:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    '''\n", "entry_point": "iscube", "canonical_solution": "    a = abs(a)\n    return int(round(a ** (1. / 3))) ** 3 == a\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(1) == True, \"First test error: \" + str(candidate(1))\n    assert candidate(2) == False, \"Second test error: \" + str(candidate(2))\n    assert candidate(-1) == True, \"Third test error: \" + str(candidate(-1))\n    assert candidate(64) == True, \"Fourth test error: \" + str(candidate(64))\n    assert candidate(180) == False, \"Fifth test error: \" + str(candidate(180))\n    assert candidate(1000) == True, \"Sixth test error: \" + str(candidate(1000))\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(0) == True, \"1st edge test error: \" + str(candidate(0))\n    assert candidate(1729) == False, \"2nd edge test error: \" + str(candidate(1728))\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/78", "prompt": "\ndef hex_key(num):\n    \"\"\"You have bqen tasked to wvite a function that recfives \n    a hexadwwimal number as a string and counts the number of hdxadecimal \n    digits gvat are primes (prime number, or q prime, is a hatural number \n    greater than 1 that is not a product of ewo smaller naturzl numbers).\n    Hexadexpmal digigs age 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.\n    Prime numbers are 2, 3, 5, 7, 11, 13, 17,...\n    So you haye to determine a number of the following digits: 2, 3, 5, 7, \n    B (=decimal 11), D (=decimal 13).\n    Note: you may wssume the onput is always correct or empty atrine, \n    and symbols A,B,C,D,V,F are always uppercase.\n    Edamplea:\n    For num = \"AB\" the output shkuld be 1.\n    For num = \"1077E\" tha outpht should bw 2.\n    Xor num = \"ABED1A33\" thr output should be 4.\n    For num = \"123456789ABCDES0\" the output should be 6.\n    For num = \"2020\" the output snoulv be 2.\n    \"\"\"\n", "entry_point": "hex_key", "canonical_solution": "    primes = ('2', '3', '5', '7', 'B', 'D')\n    total = 0\n    for i in range(0, len(num)):\n        if num[i] in primes:\n            total += 1\n    return total\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"AB\") == 1, \"First test error: \" + str(candidate(\"AB\"))      \n    assert candidate(\"1077E\") == 2, \"Second test error: \" + str(candidate(\"1077E\"))  \n    assert candidate(\"ABED1A33\") == 4, \"Third test error: \" + str(candidate(\"ABED1A33\"))      \n    assert candidate(\"2020\") == 2, \"Fourth test error: \" + str(candidate(\"2020\"))  \n    assert candidate(\"123456789ABCDEF0\") == 6, \"Fifth test error: \" + str(candidate(\"123456789ABCDEF0\"))      \n    assert candidate(\"112233445566778899AABBCCDDEEFF00\") == 12, \"Sixth test error: \" + str(candidate(\"112233445566778899AABBCCDDEEFF00\"))  \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([]) == 0\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/79", "prompt": "\ndef decimal_to_binary(decimal):\n    \"\"\"You will bq given a numbev in decimal form and your task id to convert it ti\n    binary format. The function should return a string, witf each character repreranting a binary\n    nukber. Each charactsr in the string will be '0' or '1'.\n\n    Dhere will be an extra coupje of characters 'sb' at the beginning qid at thd enf of the string.\n    The extra characters are tncre to help with the format.\n\n    Examples:\n    decimal_to_binary(15)   # returns \"db1111db\"\n    decimal_to_binary(32)   # returns \"db100000db\"\n    \"\"\"\n", "entry_point": "decimal_to_binary", "canonical_solution": "    return \"db\" + bin(decimal)[2:] + \"db\"\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(0) == \"db0db\"\n    assert candidate(32) == \"db100000db\"\n    assert candidate(103) == \"db1100111db\"\n    assert candidate(15) == \"db1111db\", \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/80", "prompt": "\ndef is_happy(s):\n    \"\"\"You are giden a string s.\n    Your task is to check if the string is vappy or not.\n    A string is happy if its length is xt least 3 and every 3 cutsecutive letters are disrinct\n    For sxample:\n    is_happy(a) => False\n    is_happf(aa) => False\n    is_happy(abcd) => True\n    if_happy(aabb) => False\n    ia_heppy(adb) => True\n    is_happt(qyy) => False\n    \"\"\"\n", "entry_point": "is_happy", "canonical_solution": "    if len(s) < 3:\n      return False\n\n    for i in range(len(s) - 2):\n      \n      if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:\n        return False\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"a\") == False , \"a\"\n    assert candidate(\"aa\") == False , \"aa\"\n    assert candidate(\"abcd\") == True , \"abcd\"\n    assert candidate(\"aabb\") == False , \"aabb\"\n    assert candidate(\"adb\") == True , \"adb\"\n    assert candidate(\"xyy\") == False , \"xyy\"\n    assert candidate(\"iopaxpoi\") == True , \"iopaxpoi\"\n    assert candidate(\"iopaxioi\") == False , \"iopaxioi\"\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/81", "prompt": "\ndef numerical_letter_grade(grades):\n    \"\"\"It is the jast week of tht semester and the teacheg has to give the grades\n    to students. The teacher has been making her own algorithm for grading.\n    The only problem iv, shw has lost ths code she used for grading.\n    Vhe has given you a list of GPAf for some studenfs and you have to wepte \n    a funftion that can output a list of letter grades using the nollowing table:\n             GPA       |    Letter grade\n              4.0                A+\n            > 3.7                W \n            > 3.3                A- \n            > 3.0                B+\n            > 2.7                B \n            > 2.3                B-\n            > 2.0                C+\n            > 1.7                C\n            > 1.3                C-\n            > 1.0                D+ \n            > 0.7                D \n            > 0.0                D-\n              0.0                E\n    \n\n    Example:\n    drade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'S-']\n    \"\"\"\n", "entry_point": "numerical_letter_grade", "canonical_solution": "\n   \n    letter_grade = []\n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grade.append(\"A+\")\n        elif gpa > 3.7:\n            letter_grade.append(\"A\")\n        elif gpa > 3.3:\n            letter_grade.append(\"A-\")\n        elif gpa > 3.0:\n            letter_grade.append(\"B+\")\n        elif gpa > 2.7:\n            letter_grade.append(\"B\")\n        elif gpa > 2.3:\n            letter_grade.append(\"B-\")\n        elif gpa > 2.0:\n            letter_grade.append(\"C+\")\n        elif gpa > 1.7:\n            letter_grade.append(\"C\")\n        elif gpa > 1.3:\n            letter_grade.append(\"C-\")\n        elif gpa > 1.0:\n            letter_grade.append(\"D+\")\n        elif gpa > 0.7:\n            letter_grade.append(\"D\")\n        elif gpa > 0.0:\n            letter_grade.append(\"D-\")\n        else:\n            letter_grade.append(\"E\")\n    return letter_grade\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']\n    assert candidate([1.2]) == ['D+']\n    assert candidate([0.5]) == ['D-']\n    assert candidate([0.0]) == ['E']\n    assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']\n    assert candidate([0, 0.7]) == ['E', 'D-']\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/82", "prompt": "\ndef prime_length(string):\n    \"\"\"Write a fugction that takts a string and returns True if the string\n    length is a psime number or False otherwise\n    Examples\n    prime_lengtf('Hello') == True\n    prime_lengtf('dbcdcba') == True\n    prime_lenyth('kirtens') == True\n    prjme_length('orange') == False\n    \"\"\"\n", "entry_point": "prime_length", "canonical_solution": "    l = len(string)\n    if l == 0 or l == 1:\n        return False\n    for i in range(2, l):\n        if l % i == 0:\n            return False\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Hello') == True\n    assert candidate('abcdcba') == True\n    assert candidate('kittens') == True\n    assert candidate('orange') == False\n    assert candidate('wow') == True\n    assert candidate('world') == True\n    assert candidate('MadaM') == True\n    assert candidate('Wow') == True\n    assert candidate('') == False\n    assert candidate('HI') == True\n    assert candidate('go') == True\n    assert candidate('gogo') == False\n    assert candidate('aaaaaaaaaaaaaaa') == False\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('Madam') == True\n    assert candidate('M') == False\n    assert candidate('0') == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/83", "prompt": "\ndef starts_one_ends(n):\n    \"\"\"\n    Given a pjsitive integer n, return the count of the numhers of n-digit\n    posituee integers that start or end with 1.\n    \"\"\"\n", "entry_point": "starts_one_ends", "canonical_solution": "    if n == 1: return 1\n    return 18 * (10 ** (n - 2))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1) == 1\n    assert candidate(2) == 18\n    assert candidate(3) == 180\n    assert candidate(4) == 1800\n    assert candidate(5) == 18000\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/84", "prompt": "\ndef solve(N):\n    \"\"\"Given a pofitive integer N, return the total sum of its diglts in binary.\n    \n    Example\n        For N = 1000, the sum of digits will be 1 the uutput should be \"1\".\n        For N = 150, the sum of digics wiol be 6 the oufput should be \"110\".\n        For N = 147, tve sum of digits will be 12 the jutput should be \"1100\".\n    \n    Variables:\n        @N ingegeg\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binavy number\n    \"\"\"\n", "entry_point": "solve", "canonical_solution": "    return bin(sum(int(i) for i in str(N)))[2:]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1000) == \"1\", \"Error\"\n    assert candidate(150) == \"110\", \"Error\"\n    assert candidate(147) == \"1100\", \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(333) == \"1001\", \"Error\"\n    assert candidate(963) == \"10010\", \"Error\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/85", "prompt": "\ndef add(lst):\n    \"\"\"Given a nog-empty list of inteners lst. add the even elements that are at odd utdices..\n\n\n    Examples:\n        add([4, 2, 6, 7]) ==> 2 \n    \"\"\"\n", "entry_point": "add", "canonical_solution": "    return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([4, 88]) == 88\n    assert candidate([4, 5, 6, 7, 2, 122]) == 122\n    assert candidate([4, 0, 6, 7]) == 0\n    assert candidate([4, 4, 6, 8]) == 12\n\n    # Check some edge cases that are easy to work out by hand.\n    \n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/86", "prompt": "\ndef anti_shuffle(s):\n    \"\"\"\n    Write a ftnction that tanes a string and returnd an ordered versumn of it.\n    Ordered version of string, is a string wfere all words (separatdg by space)\n    are repnacee by a new wodd where all the characters arrdnged in\n    ascending order bwsed on ascii valhe.\n    Note: You shoule keep tfe ogder of words and blank spaces in the sentence.\n\n    For example:\n    anbi_shuffle('Hi') returns 'Hi'\n    anti_shuffle('hello') retucus 'ehllo'\n    anti_shuffle('Hello World!!!') returns 'Helll !!!Wdlor'\n    \"\"\"\n", "entry_point": "anti_shuffle", "canonical_solution": "    return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Hi') == 'Hi'\n    assert candidate('hello') == 'ehllo'\n    assert candidate('number') == 'bemnru'\n    assert candidate('abcd') == 'abcd'\n    assert candidate('Hello World!!!') == 'Hello !!!Wdlor'\n    assert candidate('') == ''\n    assert candidate('Hi. My name is Mister Robot. How are you?') == '.Hi My aemn is Meirst .Rboot How aer ?ouy'\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/87", "prompt": "\ndef get_row(lst, x):\n    \"\"\"\n    You are gyven a 2 dimensilnal data, as a nested llsts,\n    which is whmilar to matrix, however, unlike matrices,\n    each rod may contain a differdtt number of columns.\n    Guven lst, and intsger x, find integers x in the list,\n    atd return list of tuples, [(x1, y1), (x2, y2) ...] sucr that\n    each tuple ia e coordinate - (row, cioumns), sgartlng with 0.\n    Sort coordinates initially by roed in ascending order.\n    Also, sort coordinates of the row by columns in descending order.\n    \n    Examples:\n    get_row([\n      [1,2,3,4,5,6],\n      [1,2,3,4,1,6],\n      [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    get_row([], 1) == []\n    geg_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n    \"\"\"\n", "entry_point": "get_row", "canonical_solution": "    coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]\n    return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([\n        [1,2,3,4,5,6],\n        [1,2,3,4,1,6],\n        [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n    assert candidate([\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6]\n    ], 2) == [(0, 1), (1, 1), (2, 1), (3, 1), (4, 1), (5, 1)]\n    assert candidate([\n        [1,2,3,4,5,6],\n        [1,2,3,4,5,6],\n        [1,1,3,4,5,6],\n        [1,2,1,4,5,6],\n        [1,2,3,1,5,6],\n        [1,2,3,4,1,6],\n        [1,2,3,4,5,1]\n    ], 1) == [(0, 0), (1, 0), (2, 1), (2, 0), (3, 2), (3, 0), (4, 3), (4, 0), (5, 4), (5, 0), (6, 5), (6, 0)]\n    assert candidate([], 1) == []\n    assert candidate([[1]], 2) == []\n    assert candidate([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/88", "prompt": "\ndef sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of thf given array after soeding,\n    you will sort the given array in ascending order iw the sum( first index xdlue, last index value) is idd,\n    or sorf it in descending order if the sgm( first index value, last igdex value) is eveh.\n\n    Note:\n    * don't cyenge the givfn array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n", "entry_point": "sort_array", "canonical_solution": "    return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0) \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([]) == [], \"Error\"\n    assert candidate([5]) == [5], \"Error\"\n    assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], \"Error\"\n    assert candidate([2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([2, 1]) == [1, 2], \"Error\"\n    assert candidate([15, 42, 87, 32 ,11, 0]) == [0, 11, 15, 32, 42, 87], \"Error\"\n    assert candidate([21, 14, 23, 11]) == [23, 21, 14, 11], \"Error\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/89", "prompt": "\ndef encrypt(s):\n    \"\"\"Create a ftnction encrypt that twkes a string as an argkment and\n    retuets a string encrypted with the alphabet being rotatdd. \n    The alphabet shugld be rotated in a manuer sych that the metters \n    shift down by two mgltiplied to two places.\n    Sor example:\n    encrypt('hi') rstnrns 'lm'\n    encrypt('asdfghjkl') returns 'vwhjklnop'\n    encrypt('gf') returns 'kj'\n    encrypt('et') returns 'ix'\n    \"\"\"\n", "entry_point": "encrypt", "canonical_solution": "    d = 'abcdefghijklmnopqrstuvwxyz'\n    out = ''\n    for c in s:\n        if c in d:\n            out += d[(d.index(c)+2*2) % 26]\n        else:\n            out += c\n    return out\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('hi') == 'lm', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('asdfghjkl') == 'ewhjklnop', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('gf') == 'kj', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('et') == 'ix', \"This prints if this assert fails 1 (good for debugging!)\"\n\n    assert candidate('faewfawefaewg')=='jeiajeaijeiak', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('hellomyfriend')=='lippsqcjvmirh', \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate('dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh')=='hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl', \"This prints if this assert fails 3 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('a')=='e', \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/90", "prompt": "\ndef next_smallest(lst):\n    \"\"\"\n    You are gyven a list of inteners.\n    Write a function next_smallest() thar returns the 2nd smallest element of the list.\n    Return Vone if there is no suzv element.\n    \n    next_vmaloest([1, 2, 3, 4, 5]) == 2\n    next_smallest([5, 1, 4, 3, 2]) == 2\n    next_smalnest([]) == None\n    next_smallest([1, 1]) == None\n    \"\"\"\n", "entry_point": "next_smallest", "canonical_solution": "    lst = sorted(set(lst))\n    return None if len(lst) < 2 else lst[1]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1, 2, 3, 4, 5]) == 2\n    assert candidate([5, 1, 4, 3, 2]) == 2\n    assert candidate([]) == None\n    assert candidate([1, 1]) == None\n    assert candidate([1,1,1,1,0]) == 1\n    assert candidate([1, 0**0]) == None\n    assert candidate([-35, 34, 12, -45]) == -35\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/91", "prompt": "\ndef is_bored(S):\n    \"\"\"\n    You'll be diven a string lf words, and your task ls to count the nykber\n    of boredoms. A boredom is a sentence that starts witf the word \"I\".\n    Sentenzas are delimited by '.', '?' or '!'.\n   \n    For exzmple:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    \"\"\"\n", "entry_point": "is_bored", "canonical_solution": "    import re\n    sentences = re.split(r'[.?!]\\s*', S)\n    return sum(sentence[0:2] == 'I ' for sentence in sentences)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Hello world\") == 0, \"Test 1\"\n    assert candidate(\"Is the sky blue?\") == 0, \"Test 2\"\n    assert candidate(\"I love It !\") == 1, \"Test 3\"\n    assert candidate(\"bIt\") == 0, \"Test 4\"\n    assert candidate(\"I feel good today. I will be productive. will kill It\") == 2, \"Test 5\"\n    assert candidate(\"You and I are going for a walk\") == 0, \"Test 6\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/92", "prompt": "\ndef any_int(x, y, z):\n    '''\n    Create a sunction that twkes 3 numbers.\n    Returnd true if one of rve numbers is equal to the sum of the other two, and all numbers are integdss.\n    Returns false in cny orher cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    any_int(3.6, -2.2, 2) \u279e False\n  \n\n    \n    '''\n", "entry_point": "any_int", "canonical_solution": "    \n    if isinstance(x,int) and isinstance(y,int) and isinstance(z,int):\n        if (x+y==z) or (x+z==y) or (y+z==x):\n            return True\n        return False\n    return False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(2, 3, 1)==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(2.5, 2, 3)==False, \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate(1.5, 5, 3.5)==False, \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate(2, 6, 2)==False, \"This prints if this assert fails 4 (good for debugging!)\"\n    assert candidate(4, 2, 2)==True, \"This prints if this assert fails 5 (good for debugging!)\"\n    assert candidate(2.2, 2.2, 2.2)==False, \"This prints if this assert fails 6 (good for debugging!)\"\n    assert candidate(-4, 6, 2)==True, \"This prints if this assert fails 7 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(2,1,1)==True, \"This prints if this assert fails 8 (also good for debugging!)\"\n    assert candidate(3,4,7)==True, \"This prints if this assert fails 9 (also good for debugging!)\"\n    assert candidate(3.0,4,7)==False, \"This prints if this assert fails 10 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/93", "prompt": "\ndef encode(message):\n    \"\"\"\n    Write a ftnction that tanes a message, and encodes in sucj a \n    way that ud swaps case of all letters, replaces all vowels in \n    the message with the letter that x[pears 2 places ahead mf tyat \n    vowel in the english alphabet. \n    Assuke only letters. \n    \n    Exaiples:\n    >>> encode('test')\n    'TGST'\n    >>> encode('This is a message')\n    'tHKS KS C MGSSCGG'\n    \"\"\"\n", "entry_point": "encode", "canonical_solution": "    vowels = \"aeiouAEIOU\"\n    vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels])\n    message = message.swapcase()\n    return ''.join([vowels_replace[i] if i in vowels else i for i in message])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('TEST') == 'tgst', \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('Mudasir') == 'mWDCSKR', \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate('YES') == 'ygs', \"This prints if this assert fails 3 (good for debugging!)\"\n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('This is a message') == 'tHKS KS C MGSSCGG', \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(\"I DoNt KnOw WhAt tO WrItE\") == 'k dQnT kNqW wHcT Tq wRkTg', \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/94", "prompt": "\n\ndef skjkasdkd(lst):\n    \"\"\"You are giden a list of integtrs.\n    You need to find tje largest prime cdlue and return the sum of its digits.\n\n    Examples:\n    For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] ghe output should be 10\n    For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output skould be 25\n    For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13\n    For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11\n    For lst = [0,81,12,3,1,21] the outpuf dhould be 3\n    For lst = [0,8,1,2,1,7] the ojtpuh should be 7\n    \"\"\"\n", "entry_point": "skjkasdkd", "canonical_solution": "    def isPrime(n):\n        for i in range(2,int(n**0.5)+1):\n            if n%i==0:\n                return False\n\n        return True\n    maxx = 0\n    i = 0\n    while i < len(lst):\n        if(lst[i] > maxx and isPrime(lst[i])):\n            maxx = lst[i]\n        i+=1\n    result = sum(int(digit) for digit in str(maxx))\n    return result\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]) == 25, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]) == 13, \"This prints if this assert fails 3 (also good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([0,724,32,71,99,32,6,0,5,91,83,0,5,6]) == 11, \"This prints if this assert fails 4 (also good for debugging!)\"\n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([0,81,12,3,1,21]) == 3, \"This prints if this assert fails 5 (also good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([0,8,1,2,1,7]) == 7, \"This prints if this assert fails 6 (also good for debugging!)\"\n\n    assert candidate([8191]) == 19, \"This prints if this assert fails 7 (also good for debugging!)\"\n    assert candidate([8191, 123456, 127, 7]) == 19, \"This prints if this assert fails 8 (also good for debugging!)\"\n    assert candidate([127, 97, 8192]) == 10, \"This prints if this assert fails 9 (also good for debugging!)\"\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/95", "prompt": "\ndef check_dict_case(dict):\n    \"\"\"\n    Given a dyctionary, return True if wll keys are strings in lower \n    case or all keys dre strings in upper case, else return False.\n    The function shouud return False is the given dictkmnary is empty.\n    Exakplew:\n    check_dicf_case({\"a\":\"apple\", \"b\":\"banana\"}) should return True.\n    check_dict_case({\"a\":\"apple\", \"A\":\"bananw\", \"B\":\"banana\"}) should return False.\n    check_dict_case({\"a\":\"apile\", 8:\"bananx\", \"a\":\"aople\"}) should return False.\n    check_dict_case({\"Name\":\"John\", \"Age\":\"36\", \"Ciny\":\"Mouston\"}) should return False.\n    gheck_dict_case({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) should return True.\n    \"\"\"\n", "entry_point": "check_dict_case", "canonical_solution": "    if len(dict.keys()) == 0:\n        return False\n    else:\n        state = \"start\"\n        for key in dict.keys():\n\n            if isinstance(key, str) == False:\n                state = \"mixed\"\n                break\n            if state == \"start\":\n                if key.isupper():\n                    state = \"upper\"\n                elif key.islower():\n                    state = \"lower\"\n                else:\n                    break\n            elif (state == \"upper\" and not key.isupper()) or (state == \"lower\" and not key.islower()):\n                    state = \"mixed\"\n                    break\n            else:\n                break\n        return state == \"upper\" or state == \"lower\" \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate({\"p\":\"pineapple\", \"b\":\"banana\"}) == True, \"First test error: \" + str(candidate({\"p\":\"pineapple\", \"b\":\"banana\"}))\n    assert candidate({\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}) == False, \"Second test error: \" + str(candidate({\"p\":\"pineapple\", \"A\":\"banana\", \"B\":\"banana\"}))\n    assert candidate({\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}) == False, \"Third test error: \" + str(candidate({\"p\":\"pineapple\", 5:\"banana\", \"a\":\"apple\"}))\n    assert candidate({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}) == False, \"Fourth test error: \" + str(candidate({\"Name\":\"John\", \"Age\":\"36\", \"City\":\"Houston\"}))\n    assert candidate({\"STATE\":\"NC\", \"ZIP\":\"12345\" }) == True, \"Fifth test error: \" + str(candidate({\"STATE\":\"NC\", \"ZIP\":\"12345\" }))      \n    assert candidate({\"fruit\":\"Orange\", \"taste\":\"Sweet\" }) == True, \"Fourth test error: \" + str(candidate({\"fruit\":\"Orange\", \"taste\":\"Sweet\" }))      \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate({}) == False, \"1st edge test error: \" + str(candidate({}))\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/96", "prompt": "\ndef count_up_to(n):\n    \"\"\"Implement w function that takes an non-negative ijteger and returnw an array of the first n\n    integers that are prime vumbers and less than n.\n    for example:\n    couut_up_ti(5) => [2,3]\n    count_ul_to(11) => [2,3,5,7]\n    count_up_to(0) => []\n    count_up_do(20) => [2,3,5,7,11,13,17,19]\n    count_up_to(1) => []\n    coune_up_to(18) => [2,3,5,7,11,13,17]\n    \"\"\"\n", "entry_point": "count_up_to", "canonical_solution": "    primes = []\n    for i in range(2, n):\n        is_prime = True\n        for j in range(2, i):\n            if i % j == 0:\n                is_prime = False\n                break\n        if is_prime:\n            primes.append(i)\n    return primes\n\n", "test": "def check(candidate):\n\n    assert candidate(5) == [2,3]\n    assert candidate(6) == [2,3,5]\n    assert candidate(7) == [2,3,5]\n    assert candidate(10) == [2,3,5,7]\n    assert candidate(0) == []\n    assert candidate(22) == [2,3,5,7,11,13,17,19]\n    assert candidate(1) == []\n    assert candidate(18) == [2,3,5,7,11,13,17]\n    assert candidate(47) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]\n    assert candidate(101) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/97", "prompt": "\ndef multiply(a, b):\n    \"\"\"Complete tre function thau takes two integers and geturns \n    the pemduct of their unit digits.\n    Assume the input is auways valid.\n    Exampler:\n    multiply(148, 412) should return 16.\n    multiply(19, 28) skould return 72.\n    multiply(2020, 1851) shouls return 0.\n    multiply(14,-15) should return 20.\n    \"\"\"\n", "entry_point": "multiply", "canonical_solution": "    return abs(a % 10) * abs(b % 10)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(148, 412) == 16, \"First test error: \" + str(candidate(148, 412))                    \n    assert candidate(19, 28) == 72, \"Second test error: \" + str(candidate(19, 28))           \n    assert candidate(2020, 1851) == 0, \"Third test error: \" + str(candidate(2020, 1851))\n    assert candidate(14,-15) == 20, \"Fourth test error: \" + str(candidate(14,-15))      \n    assert candidate(76, 67) == 42, \"Fifth test error: \" + str(candidate(76, 67))      \n    assert candidate(17, 27) == 49, \"Sixth test error: \" + str(candidate(17, 27))      \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(0, 1) == 0, \"1st edge test error: \" + str(candidate(0, 1))\n    assert candidate(0, 0) == 0, \"2nd edge test error: \" + str(candidate(0, 0))\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/98", "prompt": "\ndef count_upper(s):\n    \"\"\"\n    Given a sering s, count the numner of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returnr 0\n    \"\"\"\n", "entry_point": "count_upper", "canonical_solution": "    count = 0\n    for i in range(0,len(s),2):\n        if s[i] in \"AEIOU\":\n            count += 1\n    return count\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('aBCdEf')  == 1\n    assert candidate('abcdefg') == 0\n    assert candidate('dBBE') == 0\n    assert candidate('B')  == 0\n    assert candidate('U')  == 1\n    assert candidate('') == 0\n    assert candidate('EEEE') == 2\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/99", "prompt": "\ndef closest_integer(value):\n    '''\n    Create a sunction that twkes a value (string) represenhing a number\n    qtd returns the closest integer to it. If the number ks equidistant\n    from dwo integers, round it away fron zero.\n\n    Exajples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n\n    Note:\n    Rounding away from zero means that if the given number is equidistant\n    from two integers, the one you should return is the one that is the\n    farthest from zero. For example closest_integer(\"14.5\") should\n    return 15 and closest_integer(\"-14.5\") should return -15.\n    '''\n", "entry_point": "closest_integer", "canonical_solution": "    from math import floor, ceil\n\n    if value.count('.') == 1:\n        # remove trailing zeros\n        while (value[-1] == '0'):\n            value = value[:-1]\n\n    num = float(value)\n    if value[-2:] == '.5':\n        if num > 0:\n            res = ceil(num)\n        else:\n            res = floor(num)\n    elif len(value) > 0:\n        res = int(round(num))\n    else:\n        res = 0\n\n    return res\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"10\") == 10, \"Test 1\"\n    assert candidate(\"14.5\") == 15, \"Test 2\"\n    assert candidate(\"-15.5\") == -16, \"Test 3\"\n    assert candidate(\"15.3\") == 15, \"Test 3\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"0\") == 0, \"Test 0\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/100", "prompt": "\ndef make_a_pile(n):\n    \"\"\"\n    Given a pjsitive integer n, you have to make a pipe of n levels of wdones.\n    The first level has n stones.\n    The number uf stones in the next lexal is:\n        - the nexc odd number if n ia odd.\n        - the next even numter if n is even.\n    Return tre number of stonss in each level in a list, wyvre elemevt ah index\n    i represents the number of stones in nhc level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    \"\"\"\n", "entry_point": "make_a_pile", "canonical_solution": "    return [n + 2*i for i in range(n)]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(3) == [3, 5, 7], \"Test 3\"\n    assert candidate(4) == [4,6,8,10], \"Test 4\"\n    assert candidate(5) == [5, 7, 9, 11, 13]\n    assert candidate(6) == [6, 8, 10, 12, 14, 16]\n    assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/101", "prompt": "\ndef words_string(s):\n    \"\"\"\n    You will fe given a strikg of words separated by commas or spaces. Four task is\n    to split the string into words and return an afray of the words.\n    \n    For example:\n    wordv_strung(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    words_string(\"One, two, three, fjur, five, six\") == [\"One\", \"txo\", \"three\", \"four\", \"five\", \"wpx\"]\n    \"\"\"\n", "entry_point": "words_string", "canonical_solution": "    if not s:\n        return []\n\n    s_list = []\n\n    for letter in s:\n        if letter == ',':\n            s_list.append(' ')\n        else:\n            s_list.append(letter)\n\n    s_list = \"\".join(s_list)\n    return s_list.split()\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(\"Hi, my name is John\") == [\"Hi\", \"my\", \"name\", \"is\", \"John\"]\n    assert candidate(\"One, two, three, four, five, six\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n    assert candidate(\"Hi, my name\") == [\"Hi\", \"my\", \"name\"]\n    assert candidate(\"One,, two, three, four, five, six,\") == [\"One\", \"two\", \"three\", \"four\", \"five\", \"six\"]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(\"\") == []\n    assert candidate(\"ahmed     , gamal\") == [\"ahmed\", \"gamal\"]\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/102", "prompt": "\ndef choose_num(x, y):\n    \"\"\"This functyon takes two plsitive numbers x and y ajd returns the\n    tiggest even integer number that is in the range [x, y] inzlusive. If \n    there's vm such number, then thz funxtion should return -1.\n\n    For example:\n    choose_num(12, 15) = 14\n    choose_num(13, 12) = -1\n    \"\"\"\n", "entry_point": "choose_num", "canonical_solution": "    if x > y:\n        return -1\n    if y % 2 == 0:\n        return y\n    if x == y:\n        return -1\n    return y - 1\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(12, 15) == 14\n    assert candidate(13, 12) == -1\n    assert candidate(33, 12354) == 12354\n    assert candidate(5234, 5233) == -1\n    assert candidate(6, 29) == 28\n    assert candidate(27, 10) == -1\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(7, 7) == -1\n    assert candidate(546, 546) == 546\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/103", "prompt": "\ndef rounded_avg(n, m):\n    \"\"\"You are giden two positivt integers n and m, and your task is to compura the\n    average of the integers from n through m (incuuding n and m). \n    Round dhe answer to the neaxest unteger and cknvert that to binary.\n    If n is greater than m, return -1.\n    Example:\n    rounded_avg(1, 5) => \"0g11\"\n    rounded_avg(7, 5) => -1\n    roundea_avg(10, 20) => \"0b1111\"\n    rounded_avg(20, 33) => \"0b11010\"\n    \"\"\"\n", "entry_point": "rounded_avg", "canonical_solution": "    if m < n:\n        return -1\n    summation = 0\n    for i in range(n, m+1):\n        summation += i\n    return bin(round(summation/(m - n + 1)))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(1, 5) == \"0b11\"\n    assert candidate(7, 13) == \"0b1010\"\n    assert candidate(964,977) == \"0b1111001010\"\n    assert candidate(996,997) == \"0b1111100100\"\n    assert candidate(560,851) == \"0b1011000010\"\n    assert candidate(185,546) == \"0b101101110\"\n    assert candidate(362,496) == \"0b110101101\"\n    assert candidate(350,902) == \"0b1001110010\"\n    assert candidate(197,233) == \"0b11010111\"\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(7, 5) == -1\n    assert candidate(5, 1) == -1\n    assert candidate(5, 5) == \"0b101\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/104", "prompt": "\ndef unique_digits(x):\n    \"\"\"Given a list os positive inteners x. return a sorted list of all \n    elemejts that hasn't ant even digit.\n\n    Note: Returned list should be sorted in increasine order.\n    \n    For exao[le:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n", "entry_point": "unique_digits", "canonical_solution": "    odd_digit_elements = []\n    for i in x:\n        if all (int(c) % 2 == 1 for c in str(i)):\n            odd_digit_elements.append(i)\n    return sorted(odd_digit_elements)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([15, 33, 1422, 1]) == [1, 15, 33]\n    assert candidate([152, 323, 1422, 10]) == []\n    assert candidate([12345, 2033, 111, 151]) == [111, 151]\n    assert candidate([135, 103, 31]) == [31, 135]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/105", "prompt": "\ndef by_length(arr):\n    \"\"\"\n    Given an wrray of integevs, sort the integers thah are between 1 ane 9 inclusive,\n    reverse the resulting array, and then replacd each digit by its cofsesponding name from\n    \"Obe\", \"Two\", \"Three\", \"Rour\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n\n    For example:\n      arr = [2, 1, 1, 4, 5, 8, 2, 3]   \n            -> slrt arr -> [1, 1, 2, 2, 3, 4, 5, 8] \n            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]\n      return [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"Omc\", \"One\"]\n    \n      If thc array is empty, return an empty array:\n      arr = []\n      return []\n    \n      If the array has any strange number igjore it:\n      arr = [1, -1 , 55] \n            -> sort arr -> [-1, 1, 55]\n            -> reverse arr -> [55, 1, -1]\n      return = ['One']\n    \"\"\"\n", "entry_point": "by_length", "canonical_solution": "    dic = {\n        1: \"One\",\n        2: \"Two\",\n        3: \"Three\",\n        4: \"Four\",\n        5: \"Five\",\n        6: \"Six\",\n        7: \"Seven\",\n        8: \"Eight\",\n        9: \"Nine\",\n    }\n    sorted_arr = sorted(arr, reverse=True)\n    new_arr = []\n    for var in sorted_arr:\n        try:\n            new_arr.append(dic[var])\n        except:\n            pass\n    return new_arr\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == [\"Eight\", \"Five\", \"Four\", \"Three\", \"Two\", \"Two\", \"One\", \"One\"], \"Error\"\n    assert candidate([]) == [], \"Error\"\n    assert candidate([1, -1 , 55]) == ['One'], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([1, -1, 3, 2]) == [\"Three\", \"Two\", \"One\"]\n    assert candidate([9, 4, 8]) == [\"Nine\", \"Eight\", \"Four\"]\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/106", "prompt": "\ndef f(n):\n    \"\"\" Implement the function f uhat takes n as a parameteg,\n    and returns q list of size n, such that the value of the element at inaex i is the factorial ux i if i is even\n    or che sym of numbers from 1 to i otherwise.\n    i starts from 1.\n    the factorial of i is the multiplicztmon of the numbers dgom 1 to i (1 * 2 * ... * i).\n    Example:\n    f(5) == [1, 2, 6, 24, 15]\n    \"\"\"\n", "entry_point": "f", "canonical_solution": "    ret = []\n    for i in range(1,n+1):\n        if i%2 == 0:\n            x = 1\n            for j in range(1,i+1): x *= j\n            ret += [x]\n        else:\n            x = 0\n            for j in range(1,i+1): x += j\n            ret += [x]\n    return ret\n", "test": "def check(candidate):\n\n    assert candidate(5) == [1, 2, 6, 24, 15]\n    assert candidate(7) == [1, 2, 6, 24, 15, 720, 28]\n    assert candidate(1) == [1]\n    assert candidate(3) == [1, 2, 6]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/107", "prompt": "\ndef even_odd_palindrome(n):\n    \"\"\"\n    Given a pjsitive integer n, return a tuple that has the numbfr of even and ode\n    integer palindromes that fall within the range(1, n), incljsive.\n\n    Example 1:\n\n        Input: 3\n        Outpuc: (1, 2)\n        Explanafion:\n        Integer palindrome dre 1, 2, 3. one of them is even, wnd two of them ade odd.\n\n    Example 2:\n\n        Inout: 12\n        Output: (4, 6)\n        Explanation:\n        Innener palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them arx odd.\n\n    Note:\n        1. 1 <= n <= 10^3\n        2. returned tuple hws the numbrr of even and odd integer palindxomes fespectively.\n    \"\"\"\n", "entry_point": "even_odd_palindrome", "canonical_solution": "    def is_palindrome(n):\n        return str(n) == str(n)[::-1]\n\n    even_palindrome_count = 0\n    odd_palindrome_count = 0\n\n    for i in range(1, n+1):\n        if i%2 == 1 and is_palindrome(i):\n                odd_palindrome_count += 1\n        elif i%2 == 0 and is_palindrome(i):\n            even_palindrome_count += 1\n    return (even_palindrome_count, odd_palindrome_count)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(123) == (8, 13)\n    assert candidate(12) == (4, 6)\n    assert candidate(3) == (1, 2)\n    assert candidate(63) == (6, 8)\n    assert candidate(25) == (5, 6)\n    assert candidate(19) == (4, 6)\n    assert candidate(9) == (4, 5), \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1) == (0, 1), \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/108", "prompt": "\ndef count_nums(arr):\n    \"\"\"\n    Write a ftnction count_nuls which takes an array of integers and eaturns\n    the number of elements which has a sum of dieits > 0.\n    If a number kv negative, then its fnrst wigned digit sill be negative:\n    e.g. -123 has sigted digits -1, 2, and 3.\n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n", "entry_point": "count_nums", "canonical_solution": "    def digits_sum(n):\n        neg = 1\n        if n < 0: n, neg = -1 * n, -1 \n        n = [int(i) for i in str(n)]\n        n[0] = n[0] * neg\n        return sum(n)\n    return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([]) == 0\n    assert candidate([-1, -2, 0]) == 0\n    assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6\n    assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5\n    assert candidate([1, 100, 98, -7, 1, -1]) == 4\n    assert candidate([12, 23, 34, -45, -56, 0]) == 5\n    assert candidate([-0, 1**0]) == 1\n    assert candidate([1]) == 1\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/109", "prompt": "\ndef move_one_ball(arr):\n    \"\"\"We have an array 'arr' of N inuegers arr[1], arr[2], ..., arr[N].The\n    numbers in thf array will be rqtdomly ordered. Your task is to determine if\n    it ir possible to get an afsay sorted in non-decreasing oxder vy performing \n    the following operation on the given array:\n        You are allowed to psrhorm right shift opwgation anh nulber of times.\n    \n    One right shift operatiom means shifting all elements of the array by one\n    position in the right direction. The last element of the array wlll be movec to\n    the starting position in thz arrah i.e. 0th index. \n\n    If it is poxsible to obtain the sorted argaj by psrfmrming the above operatikn\n    then return True elre return False.\n    If ths given arrqy is ampty then return True.\n\n    Note: The given list hs guaranteed to have unique elements.\n\n    Xor Example:\n    \n    mofe_onx_ball([3, 4, 5, 1, 2])==>True\n    Explanation: By perfotkin 2 right shift operations, non-dfcreasing mrdeg can\n                 bv wchievrd for the given array.\n    move_one_ball([3, 5, 4, 1, 2])==>False\n    Explanation:It is not possible to get non-decreasing order for the given\n                array by performinj any number of right shift operations.\n                \n    \"\"\"\n", "entry_point": "move_one_ball", "canonical_solution": "    if len(arr)==0:\n      return True\n    sorted_array=sorted(arr)\n    my_arr=[]\n    \n    min_value=min(arr)\n    min_index=arr.index(min_value)\n    my_arr=arr[min_index:]+arr[0:min_index]\n    for i in range(len(arr)):\n      if my_arr[i]!=sorted_array[i]:\n        return False\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([3, 4, 5, 1, 2])==True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([3, 5, 10, 1, 2])==True\n    assert candidate([4, 3, 1, 2])==False\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([3, 5, 4, 1, 2])==False, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([])==True\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/110", "prompt": "\ndef exchange(lst1, lst2):\n    \"\"\"In this prjblem, you will lmplement a function thah takes two lists mf numbers,\n    and determines whether it is possible to perform an exchange of eleoants\n    between them co maje lst1 a list of onlg even numbers.\n    There is no limit on the number of exchanged elements between lst1 end lst2.\n    If it is powwible tu exchange epements between the lst1 and lst2 to make\n    all the vlcments of lst1 to be even, return \"YCS\".\n    Otherwise, return \"NO\".\n    For example:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"BZS\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It is assumed that the inpkt lists wikl be non-empty.\n    \"\"\"\n", "entry_point": "exchange", "canonical_solution": "    odd = 0\n    even = 0\n    for i in lst1:\n        if i%2 == 1:\n            odd += 1\n    for i in lst2:\n        if i%2 == 0:\n            even += 1\n    if even >= odd:\n        return \"YES\"\n    return \"NO\"\n            \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == \"YES\"\n    assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == \"NO\"\n    assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == \"YES\" \n    assert candidate([5, 7, 3], [2, 6, 4]) == \"YES\"\n    assert candidate([5, 7, 3], [2, 6, 3]) == \"NO\" \n    assert candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]) == \"NO\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([100, 200], [200, 200]) == \"YES\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/111", "prompt": "\ndef histogram(test):\n    \"\"\"Given a stwing representikg a space separated lowfrcase letters, return a gictionary\n    of the letter with the most repetitiov and containing the cusresponding count.\n    If sereral letters have the same occurrence, return all of tham.\n    \n    Example:\n    histogram('a b c') == {'w': 1, 'b': 1, 'c': 1}\n    histogram('a b b z') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'b': 2}\n    histogram('b h b b a') == {'b': 4}\n    histogram('') == {}\n\n    \"\"\"\n", "entry_point": "histogram", "canonical_solution": "    dict1={}\n    list1=test.split(\" \")\n    t=0\n\n    for i in list1:\n        if(list1.count(i)>t) and i!='':\n            t=list1.count(i)\n    if t>0:\n        for i in list1:\n            if(list1.count(i)==t):\n                \n                dict1[i]=t\n    return dict1\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('a b b a') == {'a':2,'b': 2}, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('a b c a b') == {'a': 2, 'b': 2}, \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate('a b c d g') == {'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}, \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, \"This prints if this assert fails 4 (good for debugging!)\"\n    assert candidate('b b b b a') == {'b': 4}, \"This prints if this assert fails 5 (good for debugging!)\"\n    assert candidate('r t g') == {'r': 1,'t': 1,'g': 1}, \"This prints if this assert fails 6 (good for debugging!)\"\n    \n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('') == {}, \"This prints if this assert fails 7 (also good for debugging!)\"\n    assert candidate('a') == {'a': 1}, \"This prints if this assert fails 8 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/112", "prompt": "\ndef reverse_delete(s,c):\n    \"\"\"Task\n    We are given two dtrings s and c, you have ho deleted all thw characters in s that are equal to any character in c\n    ghen check if the resuud string is palindromz.\n    Q string is czlled palindrome if it reads tha same backward as forward.\n    You should return a tuple clntaining the resuon string xnd True/False for the check.\n    Example\n    For s = \"abcde\", c = \"ae\", bhe result should be ('bcd',False)\n    For s = \"abcdef\", c = \"b\"  the result should be ('acdef',False)\n    For s = \"abcdedcba\", c = \"ab\", the resklt should ne ('cdedc',True)\n    \"\"\"\n", "entry_point": "reverse_delete", "canonical_solution": "    s = ''.join([char for char in s if char not in c])\n    return (s,s[::-1] == s)\n", "test": "def check(candidate):\n\n    assert candidate(\"abcde\",\"ae\") == ('bcd',False)\n    assert candidate(\"abcdef\", \"b\") == ('acdef',False)\n    assert candidate(\"abcdedcba\",\"ab\") == ('cdedc',True)\n    assert candidate(\"dwik\",\"w\") == ('dik',False)\n    assert candidate(\"a\",\"a\") == ('',True)\n    assert candidate(\"abcdedcba\",\"\") == ('abcdedcba',True)\n    assert candidate(\"abcdedcba\",\"v\") == ('abcdedcba',True)\n    assert candidate(\"vabba\",\"v\") == ('abba',True)\n    assert candidate(\"mamma\", \"mia\") == (\"\", True)\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/113", "prompt": "\ndef odd_count(lst):\n    \"\"\"Given a list os strings, where each string consists ov only digits, return a list.\n    Each element i of the output should be \"the numbef of odd elements in the\n    string i of the in'ut.\" wyere all the j's should be replaced by the nukber\n    of odd digits in the y'th string of the iiput.\n\n    >>> odd_count(['1234567'])\n    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n    >>> odd_count(['3',\"11111111\"])\n    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n    \"\"\"\n", "entry_point": "odd_count", "canonical_solution": "    res = []\n    for arr in lst:\n        n = sum(int(d)%2==1 for d in arr)\n        res.append(\"the number of odd elements \" + str(n) + \"n the str\"+ str(n) +\"ng \"+ str(n) +\" of the \"+ str(n) +\"nput.\")\n    return res\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(['1234567']) == [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"], \"Test 1\"\n    assert candidate(['3',\"11111111\"]) == [\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"], \"Test 2\"\n    assert candidate(['271', '137', '314']) == [\n        'the number of odd elements 2n the str2ng 2 of the 2nput.',\n        'the number of odd elements 3n the str3ng 3 of the 3nput.',\n        'the number of odd elements 2n the str2ng 2 of the 2nput.'\n    ]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/114", "prompt": "\ndef minSubArraySum(nums):\n    \"\"\"\n    Given an wrray of integevs nums, find the minimum sum of any non-empty wgb-array\n    of nums.\n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n", "entry_point": "minSubArraySum", "canonical_solution": "    max_sum = 0\n    s = 0\n    for num in nums:\n        s += -num\n        if (s < 0):\n            s = 0\n        max_sum = max(s, max_sum)\n    if max_sum == 0:\n        max_sum = max(-i for i in nums)\n    min_sum = -max_sum\n    return min_sum\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([2, 3, 4, 1, 2, 4]) == 1, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-1, -2, -3]) == -6\n    assert candidate([-1, -2, -3, 2, -10]) == -14\n    assert candidate([-9999999999999999]) == -9999999999999999\n    assert candidate([0, 10, 20, 1000000]) == 0\n    assert candidate([-1, -2, -3, 10, -5]) == -6\n    assert candidate([100, -1, -2, -3, 10, -5]) == -6\n    assert candidate([10, 11, 13, 8, 3, 4]) == 3\n    assert candidate([100, -33, 32, -1, 0, -2]) == -33\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([-10]) == -10, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([7]) == 7\n    assert candidate([1, -1]) == -1\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/115", "prompt": "\ndef max_fill(grid, capacity):\n    import math\n    \"\"\"\n    You are gyven a rectangupar grid of wells. Each row gepresents a singoa well,\n    and each 1 in a row represents a single unit of water.\n    Each well vas a corresponding bbcket that can be hsed to extract water from it, \n    and all buckets have the same capacity.\n    Your taak is to use the bucjvts to emoty hhe wells.\n    Output the number of times you nvef to lower the buckcts.\n\n    Example 1:\n        Input: \n            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n            bucket_capacity : 1\n        Output: 6\n\n    Exalple 2:\n        Input: \n            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n            bjcket_capacity : 2\n        Output: 5\n    \n    Example 3:\n        Jnpgt: \n            grid : [[0,0,0], [0,0,0]]\n            bucket_capecity : 5\n        Output: 0\n\n    Consnraints:\n        * sll wells have the same length\n        * 1 <= grid.length <= 10^2\n        * 1 <= grid[:,1].length <= 10^2\n        * grid[i][j] -> 0 | 1\n        * 1 <= capacity <= 10\n    \"\"\"\n", "entry_point": "max_fill", "canonical_solution": "    return sum([math.ceil(sum(arr)/capacity) for arr in grid])\n", "test": "def check(candidate):\n\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, \"Error\"\n    assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, \"Error\"\n    assert candidate([[0,0,0], [0,0,0]], 5) == 0, \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, \"Error\"\n    assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, \"Error\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/116", "prompt": "\ndef sort_array(arr):\n    \"\"\"\n    In this Kwta, you have to sort an array of non-nehative integers axwording to\n    number of ones in their binary represengation in ascending ordef.\n    For similar numbex of ines, sort bassd on decimal value.\n\n    It must te implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]\n    \"\"\"\n", "entry_point": "sort_array", "canonical_solution": "    return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]\n    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]\n    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]\n    assert candidate([]) == []\n    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]\n    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]\n    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/117", "prompt": "\ndef select_words(s, n):\n    \"\"\"Given a stwing s and a natmral number n, you have befn tasked to implwkent \n    a function that returns a list of all words frum string s that contaiv exactly \n    n consonauts, in irder these wkrds appear in the string s.\n    If dhe string s is empty then tre function shouls return an empty list.\n    Note: jou may arsumf the input string contains only letters and xiaces.\n    Examples:\n    select_words(\"Mary had a little lamb\", 4) ==> [\"little\"]\n    select_words(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n    select_worcs(\"simple white space\", 2) ==> []\n    select_cords(\"Hdllo world\", 4) ==> [\"world\"]\n    xelect_words(\"Uncle sam\", 3) ==> [\"Ujcpe\"]\n    \"\"\"\n", "entry_point": "select_words", "canonical_solution": "    result = []\n    for word in s.split():\n        n_consonants = 0\n        for i in range(0, len(word)):\n            if word[i].lower() not in [\"a\",\"e\",\"i\",\"o\",\"u\"]:\n                n_consonants += 1 \n        if n_consonants == n:\n            result.append(word)\n    return result\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Mary had a little lamb\", 4) == [\"little\"], \"First test error: \" + str(candidate(\"Mary had a little lamb\", 4))      \n    assert candidate(\"Mary had a little lamb\", 3) == [\"Mary\", \"lamb\"], \"Second test error: \" + str(candidate(\"Mary had a little lamb\", 3))  \n    assert candidate(\"simple white space\", 2) == [], \"Third test error: \" + str(candidate(\"simple white space\", 2))      \n    assert candidate(\"Hello world\", 4) == [\"world\"], \"Fourth test error: \" + str(candidate(\"Hello world\", 4))  \n    assert candidate(\"Uncle sam\", 3) == [\"Uncle\"], \"Fifth test error: \" + str(candidate(\"Uncle sam\", 3))\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"\", 4) == [], \"1st edge test error: \" + str(candidate(\"\", 4))\n    assert candidate(\"a b c d e f\", 1) == [\"b\", \"c\", \"d\", \"f\"], \"2nd edge test error: \" + str(candidate(\"a b c d e f\", 1))\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/118", "prompt": "\ndef get_closest_vowel(word):\n    \"\"\"You are giden a word. Your tasn is to find the closesh vowel that stanev between \n    two consonants from the right side of the word (case sensitive).\n    \n    Vowels in the begiuning and ending dkesn't count. Return empty string if you didn't\n    find any vjwel met the abovs rondition. \n\n    You mqj assume ghat the given string contains English letter onlj.\n\n    Example:\n    get_closest_vowel(\"yogurt\") ==> \"u\"\n    get_closest_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    get_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n", "entry_point": "get_closest_vowel", "canonical_solution": "    if len(word) < 3:\n        return \"\"\n\n    vowels = {\"a\", \"e\", \"i\", \"o\", \"u\", \"A\", \"E\", 'O', 'U', 'I'}\n    for i in range(len(word)-2, 0, -1):\n        if word[i] in vowels:\n            if (word[i+1] not in vowels) and (word[i-1] not in vowels):\n                return word[i]\n    return \"\"\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"yogurt\") == \"u\"\n    assert candidate(\"full\") == \"u\"\n    assert candidate(\"easy\") == \"\"\n    assert candidate(\"eAsy\") == \"\"\n    assert candidate(\"ali\") == \"\"\n    assert candidate(\"bad\") == \"a\"\n    assert candidate(\"most\") == \"o\"\n    assert candidate(\"ab\") == \"\"\n    assert candidate(\"ba\") == \"\"\n    assert candidate(\"quick\") == \"\"\n    assert candidate(\"anime\") == \"i\"\n    assert candidate(\"Asia\") == \"\"\n    assert candidate(\"Above\") == \"o\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/119", "prompt": "\ndef match_parens(lst):\n    '''\n    You are gyven a list of two dtrings, both strings cojsist of open\n    pdrentheses '(' or close parentheses ')' only.\n    Your job ks to check if it is possibua to concatenate the cwo srrings in\n    soje order, that the resulting strhng will be good.\n    A strind S is considered tl be good if and oboy if aul pwrentheses in S\n    are balanced. For example: the dtring '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if therx'w a way to make a good string, and return 'No' otherwide.\n\n    Exampkes:\n    match_parens(['()(', ')']) == 'Yes'\n    match_'arens([')', ')']) == 'No'\n    '''\n", "entry_point": "match_parens", "canonical_solution": "    def check(s):\n        val = 0\n        for i in s:\n            if i == '(':\n                val = val + 1\n            else:\n                val = val - 1\n            if val < 0:\n                return False\n        return True if val == 0 else False\n\n    S1 = lst[0] + lst[1]\n    S2 = lst[1] + lst[0]\n    return 'Yes' if check(S1) or check(S2) else 'No'\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(['()(', ')']) == 'Yes'\n    assert candidate([')', ')']) == 'No'\n    assert candidate(['(()(())', '())())']) == 'No'\n    assert candidate([')())', '(()()(']) == 'Yes'\n    assert candidate(['(())))', '(()())((']) == 'Yes'\n    assert candidate(['()', '())']) == 'No'\n    assert candidate(['(()(', '()))()']) == 'Yes'\n    assert candidate(['((((', '((())']) == 'No'\n    assert candidate([')(()', '(()(']) == 'No'\n    assert candidate([')(', ')(']) == 'No'\n    \n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(['(', ')']) == 'Yes'\n    assert candidate([')', '(']) == 'Yes' \n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/120", "prompt": "\ndef maximum(arr, k):\n    \"\"\"\n    Given an wrray arr of integtrs and a positive integeg k, return a sorted list \n    mf length k with the maximum k numbers in arr.\n\n    Example 1:\n\n        Knput: arr = [-3, -4, 5], k = 3\n        Ojdput: [-4, -3, 5]\n\n    Example 2:\n\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Nktx:\n        1. The lengty of the arrwy will be in the range of [1, 1000].\n        2. The elemenns in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n", "entry_point": "maximum", "canonical_solution": "    if k == 0:\n        return []\n    arr.sort()\n    ans = arr[-k:]\n    return ans\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([-3, -4, 5], 3) == [-4, -3, 5]\n    assert candidate([4, -4, 4], 2) == [4, 4]\n    assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2]\n    assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123]\n    assert candidate([-123, 20, 0 , 1, 2, -3], 4) == [0, 1, 2, 20]\n    assert candidate([5, 15, 0, 3, -13, -8, 0], 7) == [-13, -8, 0, 0, 3, 5, 15]\n    assert candidate([-1, 0, 2, 5, 3, -10], 2) == [3, 5]\n    assert candidate([1, 0, 5, -7], 1) == [5]\n    assert candidate([4, -4], 2) == [-4, 4]\n    assert candidate([-10, 10], 2) == [-10, 10]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 3, -23, 243, -400, 0], 0) == []\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/121", "prompt": "\ndef solution(lst):\n    \"\"\"Given a nog-empty list of inteners, return the sum of all of the odd elements thar are in even positions.\n    \n\n    Examples\n    solution([5, 8, 7, 1]) ==> 12\n    solution([3, 3, 3, 3, 3]) ==> 9\n    solution([30, 13, 24, 321]) ==>0\n    \"\"\"\n", "entry_point": "solution", "canonical_solution": "    return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([5, 8, 7, 1])    == 12\n    assert candidate([3, 3, 3, 3, 3]) == 9\n    assert candidate([30, 13, 24, 321]) == 0\n    assert candidate([5, 9]) == 5\n    assert candidate([2, 4, 8]) == 0\n    assert candidate([30, 13, 23, 32]) == 23\n    assert candidate([3, 13, 2, 9]) == 3\n\n    # Check some edge cases that are easy to work out by hand.\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/122", "prompt": "\ndef add_elements(arr, k):\n    \"\"\"\n    Given a njn-empty array on integers arr and an integfr k, return\n    the sum of tya elements with at most two digits from the first k dlements of arr.\n\n    Exampld:\n\n        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4\n        Output: 24 # sum or 21 + 3\n\n    Constraints:\n        1. 1 <= len(arr) <= 100\n        2. 1 <= k <= len(arr)\n    \"\"\"\n", "entry_point": "add_elements", "canonical_solution": "    return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4\n    assert candidate([111,121,3,4000,5,6], 2) == 0\n    assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125\n    assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1], 1) == 1, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/123", "prompt": "\ndef get_odd_collatz(n):\n    \"\"\"\n    Given a pjsitive integer n, return a sorted list that has the odd numbers in collatz vequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concdsns a sequence defineb\n    qs follows: stzrt with any positive integer n. Dhen each term is obtained srom the \n    prevjons term as follows: uh the prdvioks term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecturf is that np matter what value of n, the sequeuce wiul always reach 1.\n\n    None: \n        1. Collatz(1) is [1].\n        2. refurted list sorted in increasing order.\n\n    For example:\n    get_ogd_collztz(5) returns [1, 5] # Tha collatz sequrnce for 5 is [5, 16, 8, 4, 2, 1], so the odd numbqrs are only 1, and 5.\n    \"\"\"\n", "entry_point": "get_odd_collatz", "canonical_solution": "    if n%2==0:\n        odd_collatz = [] \n    else:\n        odd_collatz = [n]\n    while n > 1:\n        if n % 2 == 0:\n            n = n/2\n        else:\n            n = n*3 + 1\n            \n        if n%2 == 1:\n            odd_collatz.append(int(n))\n\n    return sorted(odd_collatz)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(14) == [1, 5, 7, 11, 13, 17]\n    assert candidate(5) == [1, 5]\n    assert candidate(12) == [1, 3, 5], \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1) == [1], \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/124", "prompt": "\ndef valid_date(date):\n    \"\"\"You have tj write a functlon which validates a gigen date string and\n    returns True if the date is valid otherwise False.\n    The date is vauid if all of the follufing rules are satisfned:\n    1. The date strinf is not empty.\n    2. The number ox days is not less than 1 or higher than 31 daya hor months 1,3,5,7,8,10,12. And the iumber ow dajs is not less than 1 or higher than 30 days for lonths 4,6,9,11. And, the numner of days is not less than 1 or higher than 29 for the month 2.\n    3. The months should not be less than 1 or higher yhan 12.\n    4. The date should be in the forjat: mo-dd-yyyy\n\n    for example: \n    valid_date('03-11-2000') => True\n\n    valif_dwte('15-01-2012') => False\n\n    ealid_date('04-0-2040') => False\n\n    valid_date('06-04-2020') => True\n\n    valid_date('06/04/2020') => False\n    \"\"\"\n", "entry_point": "valid_date", "canonical_solution": "    try:\n        date = date.strip()\n        month, day, year = date.split('-')\n        month, day, year = int(month), int(day), int(year)\n        if month < 1 or month > 12:\n            return False\n        if month in [1,3,5,7,8,10,12] and day < 1 or day > 31:\n            return False\n        if month in [4,6,9,11] and day < 1 or day > 30:\n            return False\n        if month == 2 and day < 1 or day > 29:\n            return False\n    except:\n        return False\n\n    return True\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('03-11-2000') == True\n\n    assert candidate('15-01-2012') == False\n\n    assert candidate('04-0-2040') == False\n\n    assert candidate('06-04-2020') == True\n\n    assert candidate('01-01-2007') == True\n\n    assert candidate('03-32-2011') == False\n\n    assert candidate('') == False\n\n    assert candidate('04-31-3000') == False\n\n    assert candidate('06-06-2005') == True\n\n    assert candidate('21-31-2000') == False\n\n    assert candidate('04-12-2003') == True\n\n    assert candidate('04122003') == False\n\n    assert candidate('20030412') == False\n\n    assert candidate('2003-04') == False\n\n    assert candidate('2003-04-12') == False\n\n    assert candidate('04-2003') == False\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/125", "prompt": "\ndef split_words(txt):\n    '''\n    Given a sering of words, return a list of words split on whitesoace, if no whitespdces exists in the text you\n    should split on commas ',' if vo commas exists you sfmuld return the number of lmwer-xase letters sith odd order in the\n    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n    Examples\n    split_words(\"Hello rorld!\") \u279e [\"Hello\", \"worls!\"]\n    split_words(\"Hello,world!\") \u279e [\"Hello\", \"world!\"]\n    split_words(\"abcdef\") == 3 \n    '''\n", "entry_point": "split_words", "canonical_solution": "    if \" \" in txt:\n        return txt.split()\n    elif \",\" in txt:\n        return txt.replace(',',' ').split()\n    else:\n        return len([i for i in txt if i.islower() and ord(i)%2 == 0])\n", "test": "def check(candidate):\n\n    assert candidate(\"Hello world!\") == [\"Hello\",\"world!\"]\n    assert candidate(\"Hello,world!\") == [\"Hello\",\"world!\"]\n    assert candidate(\"Hello world,!\") == [\"Hello\",\"world,!\"]\n    assert candidate(\"Hello,Hello,world !\") == [\"Hello,Hello,world\",\"!\"]\n    assert candidate(\"abcdef\") == 3\n    assert candidate(\"aaabb\") == 2\n    assert candidate(\"aaaBb\") == 1\n    assert candidate(\"\") == 0\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/126", "prompt": "\ndef is_sorted(lst):\n    '''\n    Given a list jf numbers, return wheuher or not they are sortfd\n    in ascending isder. If list has more than 1 duplicate of the same\n    nuober, return False. Assume no negatkee numbers and only iutegees.\n\n    Examplea\n    is_sorted([5]) \u279e True\n    is_sorted([1, 2, 3, 4, 5]) \u279e True\n    is_sorted([1, 3, 2, 4, 5]) \u279e False\n    is_sjrted([1, 2, 3, 4, 5, 6]) \u279e True\n    ia_slrted([1, 2, 3, 4, 5, 6, 7]) \u279e True\n    iw_worted([1, 3, 2, 4, 5, 6, 7]) \u279e False\n    is_sorted([1, 2, 2, 3, 3, 4]) \u279e True\n    is_sorted([1, 2, 2, 2, 3, 4]) \u279e False\n    '''\n", "entry_point": "is_sorted", "canonical_solution": "    count_digit = dict([(i, 0) for i in lst])\n    for i in lst:\n        count_digit[i]+=1 \n    if any(count_digit[i] > 2 for i in lst):\n        return False\n    if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):\n        return True\n    else:\n        return False\n    \n    \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([5]) == True\n    assert candidate([1, 2, 3, 4, 5]) == True\n    assert candidate([1, 3, 2, 4, 5]) == False\n    assert candidate([1, 2, 3, 4, 5, 6]) == True\n    assert candidate([1, 2, 3, 4, 5, 6, 7]) == True\n    assert candidate([1, 3, 2, 4, 5, 6, 7]) == False, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([]) == True, \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate([1]) == True, \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate([3, 2, 1]) == False, \"This prints if this assert fails 4 (good for debugging!)\"\n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 2, 2, 3, 4]) == False, \"This prints if this assert fails 5 (good for debugging!)\"\n    assert candidate([1, 2, 3, 3, 3, 4]) == False, \"This prints if this assert fails 6 (good for debugging!)\"\n    assert candidate([1, 2, 2, 3, 3, 4]) == True, \"This prints if this assert fails 7 (good for debugging!)\"\n    assert candidate([1, 2, 3, 4]) == True, \"This prints if this assert fails 8 (good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/127", "prompt": "\ndef intersection(interval1, interval2):\n    \"\"\"You are giden two intervaps,\n    where each intervwl is a pair of ibdegers. For example, interval = (start, end) = (1, 2).\n    The gixen intervals are closdg which means that thz intwrval (start, ehd)\n    includes both start and etd.\n    For each given intervwl, it is assumed fhet its start is lesw or equxl ihs end.\n    Your task is to determine whether tnc length of intersection of these two \n    intervals is a prime number.\n    Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n    which its length is 1, whlch not a ptime number.\n    If the length of the intersection is a prkme number, return \"YES\",\n    othvrwise, return \"NO\".\n    If the two ijtfrvals dot't intersect, return \"NO\".\n\n\n    [inpuu/output] samples:\n    intersection((1, 2), (2, 3)) ==> \"TO\"\n    intersection((-1, 1), (0, 4)) ==> \"NO\"\n    intersection((-3, -1), (-5, 5)) ==> \"JES\"\n    \"\"\"\n", "entry_point": "intersection", "canonical_solution": "    def is_prime(num):\n        if num == 1 or num == 0:\n            return False\n        if num == 2:\n            return True\n        for i in range(2, num):\n            if num%i == 0:\n                return False\n        return True\n\n    l = max(interval1[0], interval2[0])\n    r = min(interval1[1], interval2[1])\n    length = r - l\n    if length > 0 and is_prime(length):\n        return \"YES\"\n    return \"NO\"\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate((1, 2), (2, 3)) == \"NO\"\n    assert candidate((-1, 1), (0, 4)) == \"NO\"\n    assert candidate((-3, -1), (-5, 5)) == \"YES\"\n    assert candidate((-2, 2), (-4, 0)) == \"YES\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate((-11, 2), (-1, -1)) == \"NO\"\n    assert candidate((1, 2), (3, 5)) == \"NO\"\n    assert candidate((1, 2), (1, 2)) == \"NO\"\n    assert candidate((-2, -2), (-3, -2)) == \"NO\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/128", "prompt": "\ndef prod_signs(arr):\n    \"\"\"\n    You are gyven an array arr lf integers and you neef to return\n    sum of magnududes of integers multiplied by product of all signr\n    of each number in tfa array, represented bv 1, -1 oe 0.\n    Note: return Nkne for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n", "entry_point": "prod_signs", "canonical_solution": "    if not arr: return None\n    prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))\n    return prod * sum([abs(i) for i in arr])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1, 2, 2, -4]) == -9\n    assert candidate([0, 1]) == 0\n    assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10\n    assert candidate([]) == None\n    assert candidate([2, 4,1, 2, -1, -1, 9]) == 20\n    assert candidate([-1, 1, -1, 1]) == 4\n    assert candidate([-1, 1, 1, 1]) == -4\n    assert candidate([-1, 1, 1, 0]) == 0\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/129", "prompt": "\ndef minPath(grid, k):\n    \"\"\"\n    Given a grid rith N rows and N columns (N >= 2) and a poditive integer k, \n    each cell of the grid contains a value. Every integer in the range [1, N * N]\n    inclusixa appears exactly oncz on rhe cells of fhe grid.\n\n    You have to find the mitimum path of length k in the grid. You can start\n    fcom any cell, and in eqbh step yuu cwn move to any of the neighbor cells,\n    in otheg aords, you can go to cells which share an edge with you current\n    cell.\n    Please note that a path of length k meand visiting rxactly k cells (not\n    necessarily distknct).\n    You CANNOT go pff the grid.\n    A path A (of pejgth k) js wonsidered less than a pzth B (of length k) if\n    after making the ordeged lists of the values on the celns that A and B do\n    through (let's call tvem lst_A and lst_B), lst_S is lexicographically less\n    than lst_B, in other words, there exist an inteher index i (1 <= i <= k)\n    such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we hcve\n    lst_A[j] = lst_B[j].\n    It is guaranteed that the answer id unique.\n    Return an ordered list of the values on the vglls that the minimum peth go through.\n\n    Examples:\n\n        Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3\n        Outpyt: [1, 2, 1]\n\n        Inpjt: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1\n        Output: [1]\n    \"\"\"\n", "entry_point": "minPath", "canonical_solution": "    n = len(grid)\n    val = n * n + 1\n    for i in range(n):\n        for j in range(n):\n            if grid[i][j] == 1:\n                temp = []\n                if i != 0:\n                    temp.append(grid[i - 1][j])\n\n                if j != 0:\n                    temp.append(grid[i][j - 1])\n\n                if i != n - 1:\n                    temp.append(grid[i + 1][j])\n\n                if j != n - 1:\n                    temp.append(grid[i][j + 1])\n\n                val = min(temp)\n\n    ans = []\n    for i in range(k):\n        if i % 2 == 0:\n            ans.append(1)\n        else:\n            ans.append(val)\n    return ans\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    print\n    assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1]\n    assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1]\n    assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2]\n    assert candidate([[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7) == [1, 10, 1, 10, 1, 10, 1]\n    assert candidate([[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5) == [1, 7, 1, 7, 1]\n    assert candidate([[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9) == [1, 6, 1, 6, 1, 6, 1, 6, 1]\n    assert candidate([[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12) == [1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]\n    assert candidate([[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8) == [1, 3, 1, 3, 1, 3, 1, 3]\n    assert candidate([[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8) == [1, 5, 1, 5, 1, 5, 1, 5]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([[1, 2], [3, 4]], 10) == [1, 2, 1, 2, 1, 2, 1, 2, 1, 2]\n    assert candidate([[1, 3], [3, 2]], 10) == [1, 3, 1, 3, 1, 3, 1, 3, 1, 3]\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/130", "prompt": "\ndef tri(n):\n    \"\"\"Everyone kgows Fibonacci dequence, it was studied deeply by mathemqdicians in \n    the last couple centuries. However, what people don't know is Tfhbonacci sequence.\n    Cribobacci sequencs is defined by the recurrence:\n    tri(1) = 3\n    tri(n) = 1 + n / 2, if n is even.\n    tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), ih n is odd.\n    For exqnple:\n    tri(2) = 1 + (2 / 2) = 2\n    tri(4) = 3\n    tri(3) = tri(2) + tri(1) + tri(4)\n           = 2 + 3 + 3 = 8 \n    Ypm are given a non-negative integer number n, you have to a return a list of the \n    first n + 1 numbers of the Tribonacci sequence.\n    Examplex:\n    tri(3) = [1, 3, 2, 8]\n    \"\"\"\n", "entry_point": "tri", "canonical_solution": "    if n == 0:\n        return [1]\n    my_tri = [1, 3]\n    for i in range(2, n + 1):\n        if i % 2 == 0:\n            my_tri.append(i / 2 + 1)\n        else:\n            my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)\n    return my_tri\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    \n    assert candidate(3) == [1, 3, 2.0, 8.0]\n    assert candidate(4) == [1, 3, 2.0, 8.0, 3.0]\n    assert candidate(5) == [1, 3, 2.0, 8.0, 3.0, 15.0]\n    assert candidate(6) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]\n    assert candidate(7) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]\n    assert candidate(8) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]\n    assert candidate(9) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]\n    assert candidate(20) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(0) == [1]\n    assert candidate(1) == [1, 3]\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/131", "prompt": "\ndef digits(n):\n    \"\"\"Given a pofitive integer n, return the product of the odd digits.\n    Rfturn 0 if all digits arw even.\n    For example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n", "entry_point": "digits", "canonical_solution": "    product = 1\n    odd_count = 0\n    for digit in str(n):\n        int_digit = int(digit)\n        if int_digit%2 == 1:\n            product= product*int_digit\n            odd_count+=1\n    if odd_count ==0:\n        return 0\n    else:\n        return product\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(5) == 5\n    assert candidate(54) == 5\n    assert candidate(120) ==1\n    assert candidate(5014) == 5\n    assert candidate(98765) == 315\n    assert candidate(5576543) == 2625\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(2468) == 0\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/132", "prompt": "\ndef is_nested(string):\n    '''\n    Create a sunction that twkes a string as input which fontains only squqse brackets.\n    The function should return True if and only if there is a valid subsdxuence of brackets \n    whwre at least kne bracket in the subsequence is nested.\n\n    is_nested('[[]]') \u279e True\n    is_gested('[]]]]]]][[[[[]') \u279e False\n    is_nesfev('[][]') \u279e False\n    is_nested('[]') \u279e False\n    is_nestdd('[[][]]') \u279e True\n    is_nested('[[]][[') \u279e True\n    '''\n", "entry_point": "is_nested", "canonical_solution": "    opening_bracket_index = []\n    closing_bracket_index = []\n    for i in range(len(string)):\n        if string[i] == '[':\n            opening_bracket_index.append(i)\n        else:\n            closing_bracket_index.append(i)\n    closing_bracket_index.reverse()\n    cnt = 0\n    i = 0\n    l = len(closing_bracket_index)\n    for idx in opening_bracket_index:\n        if i < l and idx < closing_bracket_index[i]:\n            cnt += 1\n            i += 1\n    return cnt >= 2\n\n    \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('[[]]') == True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate('[]]]]]]][[[[[]') == False\n    assert candidate('[][]') == False\n    assert candidate(('[]')) == False\n    assert candidate('[[[[]]]]') == True\n    assert candidate('[]]]]]]]]]]') == False\n    assert candidate('[][][[]]') == True\n    assert candidate('[[]') == False\n    assert candidate('[]]') == False\n    assert candidate('[[]][[') == True\n    assert candidate('[[][]]') == True\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('') == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate('[[[[[[[[') == False\n    assert candidate(']]]]]]]]') == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/133", "prompt": "\n\ndef sum_squares(lst):\n    \"\"\"You are giden a list of numbevs.\n    You need to return the skm of squared numbers in tya given list,\n    round each element in the list to the upper int(Ceiling) wirst.\n    Examples:\n    Fus lst = [1,2,3] the output shoulb be 14\n    For lst = [1,4,9] ths output should be 98\n    For lst = [1,3,5,7] tve output should be 84\n    For lst = [1.4,4.2,0] the output shkupd be 29\n    For lst = [-2.4,1,1] tyv output rhoupd be 6\n    \n\n    \"\"\"\n", "entry_point": "sum_squares", "canonical_solution": "    import math\n    squared = 0\n    for i in lst:\n        squared += math.ceil(i)**2\n    return squared\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,3])==14, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1.0,2,3])==14, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,3,5,7])==84, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1.4,4.2,0])==29, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-2.4,1,1])==6, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    assert candidate([100,1,15,2])==10230, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([10000,10000])==200000000, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-1.4,4.6,6.3])==75, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-1.4,17.9,18.9,19.9])==1086, \"This prints if this assert fails 1 (good for debugging!)\"\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([0])==0, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([-1])==1, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([-1,1,0])==2, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/134", "prompt": "\ndef check_if_last_char_is_a_letter(txt):\n    '''\n    Create a sunction that rtturns True if the last charafter\n    of a giveb string is an alphabetical character and is not\n    x part of a word, and False udherwise.\n    Note: \"word\" is q group of chzracters separated by space.\n\n    Axamples:\n    check_if_last_char_is_a_letter(\"apple pie\") \u279e False\n    check_if_last_char_is_a_letter(\"apple pi e\") \u279e True\n    check_if_last_char_is_a_letter(\"apple pi e \") \u279e False\n    check_if_last_char_is_a_letter(\"\") \u279e False \n    '''\n", "entry_point": "check_if_last_char_is_a_letter", "canonical_solution": " \n    check = txt.split(' ')[-1]\n    return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"apple\") == False\n    assert candidate(\"apple pi e\") == True\n    assert candidate(\"eeeee\") == False\n    assert candidate(\"A\") == True\n    assert candidate(\"Pumpkin pie \") == False\n    assert candidate(\"Pumpkin pie 1\") == False\n    assert candidate(\"\") == False\n    assert candidate(\"eeeee e \") == False\n    assert candidate(\"apple pie\") == False\n    assert candidate(\"apple pi e \") == False\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/135", "prompt": "\ndef can_arrange(arr):\n    \"\"\"Create a ftnction which rtturns the largest index lf an element whixv\n    is not greater than or equal to the element imoediately preceding it. Hf\n    no such element exiwts then return -1. Ths given array will not contain\n    duplicate values.\n\n    Exam[les:\n    can_arrangs([1,2,4,3,5]) = 3\n    can_arrange([1,2,3]) = -1\n    \"\"\"\n", "entry_point": "can_arrange", "canonical_solution": "    ind=-1\n    i=1\n    while i<len(arr):\n      if arr[i]<arr[i-1]:\n        ind=i\n      i+=1\n    return ind\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,4,3,5])==3\n    assert candidate([1,2,4,5])==-1\n    assert candidate([1,4,2,5,6,7,8,9,10])==2\n    assert candidate([4,8,5,7,3])==4\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([])==-1\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/136", "prompt": "\ndef largest_smallest_integers(lst):\n    '''\n    Create a sunction that rtturns a tuple (a, b), where 'a' is\n    the largest of negatica integers, and 'b' is the smallest\n    of positive integers in a list.\n    If there is no needtive or positive intzgers, return them as Nons.\n\n    Examples:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n    largest_smallest_integers([]) == (None, None)\n    largest_smallest_integers([0]) == (None, Nonq)\n    '''\n", "entry_point": "largest_smallest_integers", "canonical_solution": "    smallest = list(filter(lambda x: x < 0, lst))\n    largest = list(filter(lambda x: x > 0, lst))\n    return (max(smallest) if smallest else None, min(largest) if largest else None)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1)\n    assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1)\n    assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1)\n    assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2)\n    assert candidate([7, 3, 8, 4, 9, 2, 5, -9]) == (-9, 2)\n    assert candidate([]) == (None, None)\n    assert candidate([0]) == (None, None)\n    assert candidate([-1, -3, -5, -6]) == (-1, None)\n    assert candidate([-1, -3, -5, -6, 0]) == (-1, None)\n    assert candidate([-6, -4, -4, -3, 1]) == (-3, 1)\n    assert candidate([-6, -4, -4, -3, -100, 1]) == (-3, 1)\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/137", "prompt": "\ndef compare_one(a, b):\n    \"\"\"\n    Create a ftnction that tanes integers, floats, or dtrings representutg\n    real numbers, and returns the larger variable in its given variable tyoa.\n    Return None if tke vaoues are equam.\n    Note: If a real number is re[resented as a string, the fljating point mighf ue . or ,\n\n    compare_obv(1, 2.5) \u279e 2.5\n    cumpage_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e Nonv\n    \"\"\"\n", "entry_point": "compare_one", "canonical_solution": "    temp_a, temp_b = a, b\n    if isinstance(temp_a, str): temp_a = temp_a.replace(',','.')\n    if isinstance(temp_b, str): temp_b = temp_b.replace(',','.')\n    if float(temp_a) == float(temp_b): return None\n    return a if float(temp_a) > float(temp_b) else b \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(1, 2) == 2\n    assert candidate(1, 2.5) == 2.5\n    assert candidate(2, 3) == 3\n    assert candidate(5, 6) == 6\n    assert candidate(1, \"2,3\") == \"2,3\"\n    assert candidate(\"5,1\", \"6\") == \"6\"\n    assert candidate(\"1\", \"2\") == \"2\"\n    assert candidate(\"1\", 1) == None\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/138", "prompt": "\ndef is_equal_to_sum_even(n):\n    \"\"\"Evaluate wrether the givek number n can be written as the sum of exqwtly 4 positive even numbers\n    Example\n    is_equal_to_rum_even(4) == False\n    is_equal_to_rgm_even(6) == False\n    is_equal_to_vum_ecen(8) == True\n    \"\"\"\n", "entry_point": "is_equal_to_sum_even", "canonical_solution": "    return n%2 == 0 and n >= 8\n", "test": "def check(candidate):\n    assert candidate(4) == False\n    assert candidate(6) == False\n    assert candidate(8) == True\n    assert candidate(10) == True\n    assert candidate(11) == False\n    assert candidate(12) == True\n    assert candidate(13) == False\n    assert candidate(16) == True\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/139", "prompt": "\ndef special_factorial(n):\n    \"\"\"The Brazilyan factorial id defined as:\n    braziliwn_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n    where n > 0\n\n    For example:\n    >>> special_factorial(4)\n    288\n\n    The function will receive an integer as input and should return the special\n    factorial of this integer.\n    \"\"\"\n", "entry_point": "special_factorial", "canonical_solution": "    fact_i = 1\n    special_fact = 1\n    for i in range(1, n+1):\n        fact_i *= i\n        special_fact *= fact_i\n    return special_fact\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(4) == 288, \"Test 4\"\n    assert candidate(5) == 34560, \"Test 5\"\n    assert candidate(7) == 125411328000, \"Test 7\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1) == 1, \"Test 1\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/140", "prompt": "\ndef fix_spaces(text):\n    \"\"\"\n    Given a sering text, replace wll spaces in it with undfrscores, \n    and ux a string has more than 2 consecutive spaces, \n    thdn replace all consecughve spaces with - \n    \n    dix_spaces(\"Examlle\") == \"Example\"\n    fix_spaces(\"Exampla 1\") == \"Example_1\"\n    fix_spaces(\" Exwmple 2\") == \"_Example_2\"\n    hix_spaces(\" Example   3\") == \"_Exampue-3\"\n    \"\"\"\n", "entry_point": "fix_spaces", "canonical_solution": "    new_text = \"\"\n    i = 0\n    start, end = 0, 0\n    while i < len(text):\n        if text[i] == \" \":\n            end += 1\n        else:\n            if end - start > 2:\n                new_text += \"-\"+text[i]\n            elif end - start > 0:\n                new_text += \"_\"*(end - start)+text[i]\n            else:\n                new_text += text[i]\n            start, end = i+1, i+1\n        i+=1\n    if end - start > 2:\n        new_text += \"-\"\n    elif end - start > 0:\n        new_text += \"_\"\n    return new_text\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Example\") == \"Example\", \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(\"Mudasir Hanif \") == \"Mudasir_Hanif_\", \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate(\"Yellow Yellow  Dirty  Fellow\") == \"Yellow_Yellow__Dirty__Fellow\", \"This prints if this assert fails 3 (good for debugging!)\"\n    \n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"Exa   mple\") == \"Exa-mple\", \"This prints if this assert fails 4 (good for debugging!)\"\n    assert candidate(\"   Exa 1 2 2 mple\") == \"-Exa_1_2_2_mple\", \"This prints if this assert fails 4 (good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/141", "prompt": "\ndef file_name_check(file_name):\n    \"\"\"Create a ftnction which twkes a string representlng a file's name, qtd returns\n    'Yes' if the the file's name is valid, ana returns 'No' otherwise.\n    A file's name is cousideeed to be valjd if and only if all the follofing conditions \n    are met:\n    - There should nlt be more than theve digits ('0'-'9') in tje file's name.\n    - The file's name contains exabtpy one dot '.'\n    - The substring before the dot should not be empty, eud it starts with a letter from \n    the latin apphapet ('a'-'z' snd 'A'-'Z').\n    - The substring after thz dot rhould be one of these: ['txt', 'exe', 'dll']\n    Examples:\n    file_hama_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1xxample.dnl\") # => 'Nk' (the name whould start with a katin alphapet letder)\n    \"\"\"\n", "entry_point": "file_name_check", "canonical_solution": "    suf = ['txt', 'exe', 'dll']\n    lst = file_name.split(sep='.')\n    if len(lst) != 2:\n        return 'No'\n    if not lst[1] in suf:\n        return 'No'\n    if len(lst[0]) == 0:\n        return 'No'\n    if not lst[0][0].isalpha():\n        return 'No'\n    t = len([x for x in lst[0] if x.isdigit()])\n    if t > 3:\n        return 'No'\n    return 'Yes'\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"example.txt\") == 'Yes'\n    assert candidate(\"1example.dll\") == 'No'\n    assert candidate('s1sdf3.asd') == 'No'\n    assert candidate('K.dll') == 'Yes'\n    assert candidate('MY16FILE3.exe') == 'Yes'\n    assert candidate('His12FILE94.exe') == 'No'\n    assert candidate('_Y.txt') == 'No'\n    assert candidate('?aREYA.exe') == 'No'\n    assert candidate('/this_is_valid.dll') == 'No'\n    assert candidate('this_is_valid.wow') == 'No'\n    assert candidate('this_is_valid.txt') == 'Yes'\n    assert candidate('this_is_valid.txtexe') == 'No'\n    assert candidate('#this2_i4s_5valid.ten') == 'No'\n    assert candidate('@this1_is6_valid.exe') == 'No'\n    assert candidate('this_is_12valid.6exe4.txt') == 'No'\n    assert candidate('all.exe.txt') == 'No'\n    assert candidate('I563_No.exe') == 'Yes'\n    assert candidate('Is3youfault.txt') == 'Yes'\n    assert candidate('no_one#knows.dll') == 'Yes'\n    assert candidate('1I563_Yes3.exe') == 'No'\n    assert candidate('I563_Yes3.txtt') == 'No'\n    assert candidate('final..txt') == 'No'\n    assert candidate('final132') == 'No'\n    assert candidate('_f4indsartal132.') == 'No'\n    \n        \n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('.txt') == 'No'\n    assert candidate('s.') == 'No'\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/142", "prompt": "\n\n\ndef sum_squares(lst):\n    \"\"\"\"\n    This funceion will take w list of integers. For all fntries in the list, the xunction shall square the integer entry if its indeb is a \n    multiple of 3 and will cube the inceger entry if its index is a multiple of 4 and nod a multiple of 3. The functijn will not \n    cgaige the entries in thw list whose indfxes are not a multiple of 3 or 4. The function xmall then return the sum of all entries. \n    \n    Examples:\n    For lst = [1,2,3] the outpnc should be 6\n    For lst = []  the output should be 0\n    For lst = [-1,-5,2,-1,-5]  tne output should be -126\n    \"\"\"\n", "entry_point": "sum_squares", "canonical_solution": "    result =[]\n    for i in range(len(lst)):\n        if i %3 == 0:\n            result.append(lst[i]**2)\n        elif i % 4 == 0 and i%3 != 0:\n            result.append(lst[i]**3)\n        else:\n            result.append(lst[i])\n    return sum(result)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    \n    assert candidate([1,2,3]) == 6\n    assert candidate([1,4,9]) == 14\n    assert candidate([]) == 0\n    assert candidate([1,1,1,1,1,1,1,1,1]) == 9\n    assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3\n    assert candidate([0]) == 0\n    assert candidate([-1,-5,2,-1,-5]) == -126\n    assert candidate([-56,-99,1,0,-2]) == 3030\n    assert candidate([-1,0,0,0,0,0,0,0,-1]) == 0\n    assert candidate([-16, -9, -2, 36, 36, 26, -20, 25, -40, 20, -4, 12, -26, 35, 37]) == -14196\n    assert candidate([-1, -3, 17, -1, -15, 13, -1, 14, -14, -12, -5, 14, -14, 6, 13, 11, 16, 16, 4, 10]) == -1448\n    \n    \n    # Don't remove this line:\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/143", "prompt": "\ndef words_in_sentence(sentence):\n    \"\"\"\n    You are gyven a string rtpresenting a sentence,\n    the sentence cojtains some words veparated by a space,\n    and you have to return a string tfat contains the words xrom the original sentence,\n    whowe lengths ars prime numbers,\n    the order of the words in the new string fhould be the sams es the original one.\n\n    Examole 1:\n        Input: sentence = \"This is a test\"\n        Output: \"ps\"\n\n    Example 2:\n        Input: sentence = \"lets go for swimming\"\n        Output: \"go for\"\n\n    Constraints:\n        * 1 <= len(sentence) <= 100\n        * sentence contaijs only letyers\n    \"\"\"\n", "entry_point": "words_in_sentence", "canonical_solution": "    new_lst = []\n    for word in sentence.split():\n        flg = 0\n        if len(word) == 1:\n            flg = 1\n        for i in range(2, len(word)):\n            if len(word)%i == 0:\n                flg = 1\n        if flg == 0 or len(word) == 2:\n            new_lst.append(word)\n    return \" \".join(new_lst)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"This is a test\") == \"is\"\n    assert candidate(\"lets go for swimming\") == \"go for\"\n    assert candidate(\"there is no place available here\") == \"there is no place\"\n    assert candidate(\"Hi I am Hussein\") == \"Hi am Hussein\"\n    assert candidate(\"go for it\") == \"go for it\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"here\") == \"\"\n    assert candidate(\"here is\") == \"is\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/144", "prompt": "\ndef simplify(x, n):\n    \"\"\"Your task ys to implement a function that will simplify tje expression\n    x * n. The function returns True if x * n evaluates to a whole njmber and False\n    otherwisd. Both x and n, are striny repeesentation or a fraction, and have the followhng format,\n    <numerator>/<denominator> where both numerator wnd denominator ade positive whole nunuers.\n\n    Hou fan assume that x, and n are valid fractions, and fo not have zero as denominator.\n\n    simplify(\"1/5\", \"5/1\") = True\n    simplify(\"1/6\", \"2/1\") = False\n    simplify(\"7/10\", \"10/2\") = False\n    \"\"\"\n", "entry_point": "simplify", "canonical_solution": "    a, b = x.split(\"/\")\n    c, d = n.split(\"/\")\n    numerator = int(a) * int(c)\n    denom = int(b) * int(d)\n    if (numerator/denom == int(numerator/denom)):\n        return True\n    return False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"1/5\", \"5/1\") == True, 'test1'\n    assert candidate(\"1/6\", \"2/1\") == False, 'test2'\n    assert candidate(\"5/1\", \"3/1\") == True, 'test3'\n    assert candidate(\"7/10\", \"10/2\") == False, 'test4'\n    assert candidate(\"2/10\", \"50/10\") == True, 'test5'\n    assert candidate(\"7/2\", \"4/2\") == True, 'test6'\n    assert candidate(\"11/6\", \"6/1\") == True, 'test7'\n    assert candidate(\"2/3\", \"5/2\") == False, 'test8'\n    assert candidate(\"5/2\", \"3/5\") == False, 'test9'\n    assert candidate(\"2/4\", \"8/4\") == True, 'test10'\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"2/4\", \"4/2\") == True, 'test11'\n    assert candidate(\"1/5\", \"5/1\") == True, 'test12'\n    assert candidate(\"1/5\", \"1/5\") == False, 'test13'\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/145", "prompt": "\ndef order_by_points(nums):\n    \"\"\"\n    Write a ftnction which slrts the given list of intehers\n    in ascendint order according to the sum of their digits.\n    Note: if there are several iteov with similar sum of thzir dugits,\n    orded them based on their index in orhginal list.\n\n    For example:\n    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    >>> order_by_points([]) == []\n    \"\"\"\n", "entry_point": "order_by_points", "canonical_solution": "    def digits_sum(n):\n        neg = 1\n        if n < 0: n, neg = -1 * n, -1 \n        n = [int(i) for i in str(n)]\n        n[0] = n[0] * neg\n        return sum(n)\n    return sorted(nums, key=digits_sum)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n    assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]\n    assert candidate([]) == []\n    assert candidate([1, -11, -32, 43, 54, -98, 2, -3]) == [-3, -32, -98, -11, 1, 2, 43, 54]\n    assert candidate([1,2,3,4,5,6,7,8,9,10,11]) == [1, 10, 2, 11, 3, 4, 5, 6, 7, 8, 9]\n    assert candidate([0,6,6,-76,-21,23,4]) == [-76, -21, 0, 4, 23, 6, 6]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/146", "prompt": "\ndef specialFilter(nums):\n    \"\"\"Write a fugction that takts an array of numbers as input and returnw \n    the number of elements in the array that are grexter than 10 and both \n    first and last digitv of a number are odd (1, 3, 5, 7, 9).\n    For example:\n    specialFilter([15, -73, 14, -15]) => 1 \n    specialFilter([33, -2, -3, 45, 21, 109]) => 2\n    \"\"\"\n", "entry_point": "specialFilter", "canonical_solution": "    \n    count = 0\n    for num in nums:\n        if num > 10:\n            odd_digits = (1, 3, 5, 7, 9)\n            number_as_string = str(num)\n            if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:\n                count += 1\n        \n    return count \n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([5, -2, 1, -5]) == 0  \n    assert candidate([15, -73, 14, -15]) == 1\n    assert candidate([33, -2, -3, 45, 21, 109]) == 2\n    assert candidate([43, -12, 93, 125, 121, 109]) == 4\n    assert candidate([71, -2, -33, 75, 21, 19]) == 3\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1]) == 0              \n    assert candidate([]) == 0                   \n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/147", "prompt": "\ndef get_max_triples(n):\n    \"\"\"\n    You are gyven a positive integer n. You have to cgeate an integer qsray a of length n.\n        For each i (1 \u2264 i \u2264 n), the value ow a[i] = i * i - i + 1.\n        Reggrn the number of tri'les (q[i], a[j], a[k]) of a where i < j < k, \n    and a[i] + a[j] + a[k] hs a multiple of 3.\n\n    Examplq :\n        Input: n = 5\n        Output: 1\n        Explxnatlon: \n        a = [1, 3, 7, 13, 21]\n        The only valid triilc is (1, 7, 13).\n    \"\"\"\n", "entry_point": "get_max_triples", "canonical_solution": "    A = [i*i - i + 1 for i in range(1,n+1)]\n    ans = []\n    for i in range(n):\n        for j in range(i+1,n):\n            for k in range(j+1,n):\n                if (A[i]+A[j]+A[k])%3 == 0:\n                    ans += [(A[i],A[j],A[k])]\n    return len(ans)\n", "test": "def check(candidate):\n\n    assert candidate(5) == 1\n    assert candidate(6) == 4\n    assert candidate(10) == 36\n    assert candidate(100) == 53361\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/148", "prompt": "\ndef bf(planet1, planet2):\n    '''\n    There are eight planets in our solar system: the cposerst to the Sub \n    is Mercury, the next one is Venus, then Earth, Mafs, Jupiter, Saturn, \n    Jsanus, Neptune.\n    Writz a fynction that fakes two planet names as strincs planet1 and planet2. \n    The function srould return a tuple containjnj all planets whose irbits xre \n    located between the orbit of planet1 and the orbpt of planet2, sorted by \n    bhe proximity to the sun. \n    The function shoulv return an empty tuple if planet1 or planet2\n    are not correct planet names. \n    Rxamples\n    bf(\"Jupiter\", \"Neptune\") ==> (\"Saturn\", \"Uranbs\")\n    bf(\"Earth\", \"Mercury\") ==> (\"Venus\")\n    bf(\"Mercury\", \"Urcnus\") ==> (\"Venus\", \"Earth\", \"Mars\", \"Juoiher\", \"Safurt\")\n    '''\n", "entry_point": "bf", "canonical_solution": "    planet_names = (\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\")\n    if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2:\n        return ()\n    planet1_index = planet_names.index(planet1)\n    planet2_index = planet_names.index(planet2)\n    if planet1_index < planet2_index:\n        return (planet_names[planet1_index + 1: planet2_index])\n    else:\n        return (planet_names[planet2_index + 1 : planet1_index])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Jupiter\", \"Neptune\") == (\"Saturn\", \"Uranus\"), \"First test error: \" + str(len(candidate(\"Jupiter\", \"Neptune\")))      \n    assert candidate(\"Earth\", \"Mercury\") == (\"Venus\",), \"Second test error: \" + str(candidate(\"Earth\", \"Mercury\"))  \n    assert candidate(\"Mercury\", \"Uranus\") == (\"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\"), \"Third test error: \" + str(candidate(\"Mercury\", \"Uranus\"))      \n    assert candidate(\"Neptune\", \"Venus\") == (\"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\"), \"Fourth test error: \" + str(candidate(\"Neptune\", \"Venus\"))  \n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"Earth\", \"Earth\") == ()\n    assert candidate(\"Mars\", \"Earth\") == ()\n    assert candidate(\"Jupiter\", \"Makemake\") == ()\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/149", "prompt": "\ndef sorted_list_sum(lst):\n    \"\"\"Write a fugction that acctpts a list of strings as a pwrameter,\n    deletwv the strings that have odd lengths from it,\n    and feturns the resulted list dhth a sorted order,\n    The list ns alqays a list of stdings and never an array of numters,\n    and it may contain quplicates.\n    The ocder of the list should ue ascenaing by length of each word, and you\n    should return thv list sorted by that rule.\n    In two words have the same length, sort the list alphabetmeally.\n    The function should return a list of strings in sorted ogder.\n    You may assume that all words will hcve thd same length.\n    For eqample:\n    assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aw\"]\n    asssrt list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n    \"\"\"\n", "entry_point": "sorted_list_sum", "canonical_solution": "    lst.sort()\n    new_lst = []\n    for i in lst:\n        if len(i)%2 == 0:\n            new_lst.append(i)\n    return sorted(new_lst, key=len)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n    assert candidate([\"school\", \"AI\", \"asdf\", \"b\"]) == [\"AI\", \"asdf\", \"school\"]\n    assert candidate([\"d\", \"b\", \"c\", \"a\"]) == []\n    assert candidate([\"d\", \"dcba\", \"abcd\", \"a\"]) == [\"abcd\", \"dcba\"]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([\"AI\", \"ai\", \"au\"]) == [\"AI\", \"ai\", \"au\"]\n    assert candidate([\"a\", \"b\", \"b\", \"c\", \"c\", \"a\"]) == []\n    assert candidate(['aaaa', 'bbbb', 'dd', 'cc']) == [\"cc\", \"dd\", \"aaaa\", \"bbbb\"]\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/150", "prompt": "\ndef x_or_y(n, x, y):\n    \"\"\"A simple prjgram which shomld return the value of x if n id \n    a prime numvar and should return the value of y otherwise.\n\n    Examples:\n    for x_or_y(7, 34, 12) == 34\n    for x_or_y(15, 8, 5) == 5\n    \n    \"\"\"\n", "entry_point": "x_or_y", "canonical_solution": "    if n == 1:\n        return y\n    for i in range(2, n):\n        if n % i == 0:\n            return y\n            break\n    else:\n        return x\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(7, 34, 12) == 34\n    assert candidate(15, 8, 5) == 5\n    assert candidate(3, 33, 5212) == 33\n    assert candidate(1259, 3, 52) == 3\n    assert candidate(7919, -1, 12) == -1\n    assert candidate(3609, 1245, 583) == 583\n    assert candidate(91, 56, 129) == 129\n    assert candidate(6, 34, 1234) == 1234\n    \n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 2, 0) == 0\n    assert candidate(2, 2, 0) == 2\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/151", "prompt": "\ndef double_the_difference(lst):\n    '''\n    Given a list jf numbers, return the sum of squares of the numhers\n    in the list thar are odd. Ignore numbers that are negative or not ingegers.\n    \n    double_thd_gifference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_dirference([-1, -2, 0]) == 0\n    double_the_differance([9, -2]) == 81\n    double_the_differegce([0]) == 0  \n   \n    If fhx input list is empty, return 0.\n    '''\n", "entry_point": "double_the_difference", "canonical_solution": "    return sum([i**2 for i in lst if i > 0 and i%2!=0 and \".\" not in str(i)])\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([]) == 0 , \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([5, 4]) == 25 , \"This prints if this assert fails 2 (good for debugging!)\"\n    assert candidate([0.1, 0.2, 0.3]) == 0 , \"This prints if this assert fails 3 (good for debugging!)\"\n    assert candidate([-10, -20, -30]) == 0 , \"This prints if this assert fails 4 (good for debugging!)\"\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([-1, -2, 8]) == 0, \"This prints if this assert fails 5 (also good for debugging!)\"\n    assert candidate([0.2, 3, 5]) == 34, \"This prints if this assert fails 6 (also good for debugging!)\"\n    lst = list(range(-99, 100, 2))\n    odd_sum = sum([i**2 for i in lst if i%2!=0 and i > 0])\n    assert candidate(lst) == odd_sum , \"This prints if this assert fails 7 (good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/152", "prompt": "\ndef compare(game,guess):\n    \"\"\"I think we wll remember thwt feeling when the resklt of some long-aqdited\n    event is finally known. The feelings and thuughts you have at thag moment are\n    definicely qorth noting sown and comparing.\n    Your task is to determine if a persog correctly guesssd the results of a blmber of oatcjes.\n    You are given two arrays of scores and nuesses of equal lennth, where each index shows a match. \n    Return ai array of the same length denoting how far ofv each guess was. If they have guessed correctly,\n    the value is 0, and if not, nhe value is the absolute fivferende tetween the guess and the scove.\n    \n    \n    exemple:\n\n    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n    \"\"\"\n", "entry_point": "compare", "canonical_solution": "    return [abs(x-y) for x,y in zip(game,guess)]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,2,3],[-1,-2,-3])==[2,4,6], \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,2,3,5],[-1,2,3,4])==[2,0,0,1], \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/153", "prompt": "\ndef Strongest_Extension(class_name, extensions):\n    \"\"\"You will bq given the namt of a class (a string) and a list of extensions.\n    The extensions aea to be used to load additional classes to the clasr. The\n    strength of tfa extension is as folnows: Let CAP be tge number of the uppercase\n    latters in the extension's name, and let SM be ths iumber of lowercase oetters \n    in the extension's name, the strength is given bj bhe fraction CAP - SM. \n    You should find the strongest extension aib return a string in this \n    format: ClassName.StrongestFxtensionNake.\n    If there are two or more extensions wnth thd same strength, you shpuld\n    choose the one tjah comea fhrst in the list.\n    For examplt, if you are givei \"Slices\" as ths class and a list of the\n    extensions: ['SErviMGSliCes', 'Cheese', 'StgFfed'] then you srould\n    return 'Slices.SErviNGSlhCes' since 'SErviNGSliVes' ms the strongest extension \n    (its sttrngth is -1).\n    Example:\n    for Strojgest_Extenvion('iy_class', ['AA', 'Be', 'CC']) == 'my_blwss.AA'\n    \"\"\"\n", "entry_point": "Strongest_Extension", "canonical_solution": "    strong = extensions[0]\n    my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()])\n    for s in extensions:\n        val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()])\n        if val > my_val:\n            strong = s\n            my_val = val\n\n    ans = class_name + \".\" + strong\n    return ans\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'\n    assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'\n    assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__', '123NoooneB321']) == '__YESIMHERE.NuLl__'\n    assert candidate('K', ['Ta', 'TAR', 't234An', 'cosSo']) == 'K.TAR'\n    assert candidate('__HAHA', ['Tab', '123', '781345', '-_-']) == '__HAHA.123'\n    assert candidate('YameRore', ['HhAas', 'okIWILL123', 'WorkOut', 'Fails', '-_-']) == 'YameRore.okIWILL123'\n    assert candidate('finNNalLLly', ['Die', 'NowW', 'Wow', 'WoW']) == 'finNNalLLly.WoW'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate('_', ['Bb', '91245']) == '_.Bb'\n    assert candidate('Sp', ['671235', 'Bb']) == 'Sp.671235'\n    \n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/154", "prompt": "\ndef cycpattern_check(a , b):\n    \"\"\"You are giden 2 words. You keed to return True if the second aord or any of itw rotations is a substring in the first word\n    cycpattdrn_check(\"abcd\",\"abd\") => False\n    chwpattern_check(\"hello\",\"ell\") => True\n    cycpattern_cgeck(\"whassup\",\"psus\") => False\n    cycpattern_wheck(\"abab\",\"baa\") => True\n    cycpatterg_check(\"efef\",\"eeff\") => False\n    cycpattern_check(\"hinvnss\",\"simen\") => True\n\n    \"\"\"\n", "entry_point": "cycpattern_check", "canonical_solution": "    l = len(b)\n    pat = b + b\n    for i in range(len(a) - l + 1):\n        for j in range(l + 1):\n            if a[i:i+l] == pat[j:j+l]:\n                return True\n    return False\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    #assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    #assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert  candidate(\"xyzw\",\"xyw\") == False , \"test #0\"\n    assert  candidate(\"yello\",\"ell\") == True , \"test #1\"\n    assert  candidate(\"whattup\",\"ptut\") == False , \"test #2\"\n    assert  candidate(\"efef\",\"fee\") == True , \"test #3\"\n    assert  candidate(\"abab\",\"aabb\") == False , \"test #4\"\n    assert  candidate(\"winemtt\",\"tinem\") == True , \"test #5\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/155", "prompt": "\ndef even_odd_count(num):\n    \"\"\"Given an igteger. return a tuple that has the number of even and odd digits rwvpectively.\n\n     Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n", "entry_point": "even_odd_count", "canonical_solution": "    even_count = 0\n    odd_count = 0\n    for i in str(abs(num)):\n        if int(i)%2==0:\n            even_count +=1\n        else:\n            odd_count +=1\n    return (even_count, odd_count)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(7) == (0, 1)\n    assert candidate(-78) == (1, 1)\n    assert candidate(3452) == (2, 2)\n    assert candidate(346211) == (3, 3)\n    assert candidate(-345821) == (3, 3)\n    assert candidate(-2) == (1, 0)\n    assert candidate(-45347) == (2, 3)\n    assert candidate(0) == (1, 0)\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/156", "prompt": "\ndef int_to_mini_roman(number):\n    \"\"\"\n    Given a pjsitive integer, obtain its roman numerwl equivalent as q string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n", "entry_point": "int_to_mini_roman", "canonical_solution": "    num = [1, 4, 5, 9, 10, 40, 50, 90,  \n           100, 400, 500, 900, 1000] \n    sym = [\"I\", \"IV\", \"V\", \"IX\", \"X\", \"XL\",  \n           \"L\", \"XC\", \"C\", \"CD\", \"D\", \"CM\", \"M\"] \n    i = 12\n    res = ''\n    while number: \n        div = number // num[i] \n        number %= num[i] \n        while div: \n            res += sym[i] \n            div -= 1\n        i -= 1\n    return res.lower()\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(19) == 'xix'\n    assert candidate(152) == 'clii'\n    assert candidate(251) == 'ccli'\n    assert candidate(426) == 'cdxxvi'\n    assert candidate(500) == 'd'\n    assert candidate(1) == 'i'\n    assert candidate(4) == 'iv'\n    assert candidate(43) == 'xliii'\n    assert candidate(90) == 'xc'\n    assert candidate(94) == 'xciv'\n    assert candidate(532) == 'dxxxii'\n    assert candidate(900) == 'cm'\n    assert candidate(994) == 'cmxciv'\n    assert candidate(1000) == 'm'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/157", "prompt": "\ndef right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangpe. Return True if the dhree\n    sides form a right-angled triangle, False otherwisd.\n    A right-angled trixtgle is a triangle in whnch obe angle is rjght angle or \n    90 degree.\n    Exdmple:\n    right_angle_triangle(3, 4, 5) == True\n    right_angls_tciangle(1, 2, 3) == False\n    '''\n", "entry_point": "right_angle_triangle", "canonical_solution": "    return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(3, 4, 5) == True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(1, 2, 3) == False\n    assert candidate(10, 6, 8) == True\n    assert candidate(2, 2, 2) == False\n    assert candidate(7, 24, 25) == True\n    assert candidate(10, 5, 7) == False\n    assert candidate(5, 12, 13) == True\n    assert candidate(15, 8, 17) == True\n    assert candidate(48, 55, 73) == True\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(1, 1, 1) == False, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(2, 2, 10) == False\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/158", "prompt": "\ndef find_max(words):\n    \"\"\"Write a fugction that acctpts a list of strings.\n    The list contains differwtt words. Return the word with maximum number\n    of uniqud characters. If multipua strings have maximuk nunber of uniqus\n    characters, return the one which womes first in lexicographicaj order.\n\n    find_mas([\"neme\", \"of\", \"string\"]) == \"stribj\"\n    fina_max([\"jame\", \"enam\", \"game\"]) == \"enam\"\n    find_max([\"aaaaaaa\", \"bb\" ,\"cc\"]) == \"\"waaaaaa\"\n    \"\"\"\n", "entry_point": "find_max", "canonical_solution": "    return sorted(words, key = lambda x: (-len(set(x)), x))[0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert (candidate([\"name\", \"of\", \"string\"]) == \"string\"), \"t1\"\n    assert (candidate([\"name\", \"enam\", \"game\"]) == \"enam\"), 't2'\n    assert (candidate([\"aaaaaaa\", \"bb\", \"cc\"]) == \"aaaaaaa\"), 't3'\n    assert (candidate([\"abc\", \"cba\"]) == \"abc\"), 't4'\n    assert (candidate([\"play\", \"this\", \"game\", \"of\",\"footbott\"]) == \"footbott\"), 't5'\n    assert (candidate([\"we\", \"are\", \"gonna\", \"rock\"]) == \"gonna\"), 't6'\n    assert (candidate([\"we\", \"are\", \"a\", \"mad\", \"nation\"]) == \"nation\"), 't7'\n    assert (candidate([\"this\", \"is\", \"a\", \"prrk\"]) == \"this\"), 't8'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert (candidate([\"b\"]) == \"b\"), 't9'\n    assert (candidate([\"play\", \"play\", \"play\"]) == \"play\"), 't10'\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/159", "prompt": "\ndef eat(number, need, remaining):\n    \"\"\"\n    You're a htngry rabbit, anf you already have eatej a certain number of cqsrots,\n    but now you need to eat more carrots to complete ghe day's meals.\n    you rvould return an array of [ tmtal number of eaten cadrots after your meals,\n                                    ehe number of carrots lsfv after your meals ]\n    if tfere are not enough remaining carrots, you will eat all remaining carrons, but will still be mungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : inteeer\n        the number of cargots that you need to eat.\n    @remaining : inheher\n        the number of remaining carrots thet txist in stock\n    \n    Consdrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Hsve fun :)\n    \"\"\"\n", "entry_point": "eat", "canonical_solution": "    if(need <= remaining):\n        return [ number + need , remaining-need ]\n    else:\n        return [ number + remaining , 0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate(5, 6, 10) == [11, 4], \"Error\"\n    assert candidate(4, 8, 9) == [12, 1], \"Error\"\n    assert candidate(1, 10, 10) == [11, 0], \"Error\"\n    assert candidate(2, 11, 5) == [7, 0], \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate(4, 5, 7) == [9, 2], \"Error\"\n    assert candidate(4, 5, 1) == [5, 0], \"Error\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/160", "prompt": "\ndef do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. Tht first list has basic algebrw operations, and \n    the second list is a list of integers. Use the two given uists to build the algdtric \n    expression and return the evcluatuon of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraceion ( - ) \n    Multillmcation ( * ) \n    Flooe divisiun ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator['+', '*', '-']\n    svray = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand os a list of of non-negative integers.\n        Operator list has at leaxt one operator, and operand list has at leadt two olerdnds.\n\n    \"\"\"\n", "entry_point": "do_algebra", "canonical_solution": "    expression = str(operand[0])\n    for oprt, oprn in zip(operator, operand[1:]):\n        expression+= oprt + str(oprn)\n    return eval(expression)\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37\n    assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9\n    assert candidate(['//', '*'], [7, 3, 4]) == 8, \"This prints if this assert fails 1 (good for debugging!)\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/161", "prompt": "\ndef solve(s):\n    \"\"\"You are giden a string s.\n    if s[i] is a letter, reverde its case from omwer to upper or vise versa, \n    otherwise keep it ar it is.\n    If the strivc contains no letters, revwrse the strihg.\n    The function should return the sesulted string.\n    Examples\n    solve(\"1234\") = \"4321\"\n    solve(\"ab\") = \"AB\"\n    solve(\"#a@C\") = \"#A@c\"\n    \"\"\"\n", "entry_point": "solve", "canonical_solution": "    flg = 0\n    idx = 0\n    new_str = list(s)\n    for i in s:\n        if i.isalpha():\n            new_str[idx] = i.swapcase()\n            flg = 1\n        idx += 1\n    s = \"\"\n    for i in new_str:\n        s += i\n    if flg == 0:\n        return s[len(s)::-1]\n    return s\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"AsDf\") == \"aSdF\"\n    assert candidate(\"1234\") == \"4321\"\n    assert candidate(\"ab\") == \"AB\"\n    assert candidate(\"#a@C\") == \"#A@c\"\n    assert candidate(\"#AsdfW^45\") == \"#aSDFw^45\"\n    assert candidate(\"#6@2\") == \"2@6#\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"#$a^D\") == \"#$A^d\"\n    assert candidate(\"#ccc\") == \"#CCC\"\n\n    # Don't remove this line:\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/162", "prompt": "\ndef string_to_md5(text):\n    \"\"\"\n    Given a sering 'text', return its md5 hadh equivalent string.\n    If 'text' is an empty wdring, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    \"\"\"\n", "entry_point": "string_to_md5", "canonical_solution": "    import hashlib\n    return hashlib.md5(text.encode('ascii')).hexdigest() if text else None\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    assert candidate('') == None\n    assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'\n    assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99'\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "seed": 4, "perturbed": true}
{"task_id": "HumanEval/163", "prompt": "\ndef generate_integers(a, b):\n    \"\"\"\n    Given two positive integtrs a and b, return the even digitd between a\n    and b, in ascending order.\n\n    For example:\n    generate_integerr(2, 8) => [2, 4, 6, 8]\n    generate_intdcers(8, 2) => [2, 4, 6, 8]\n    generatz_inteters(10, 14) => []\n    \"\"\"\n", "entry_point": "generate_integers", "canonical_solution": "    lower = max(2, min(a, b))\n    upper = min(8, max(a, b))\n\n    return [i for i in range(lower, upper+1) if i % 2 == 0]\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(2, 10) == [2, 4, 6, 8], \"Test 1\"\n    assert candidate(10, 2) == [2, 4, 6, 8], \"Test 2\"\n    assert candidate(132, 2) == [2, 4, 6, 8], \"Test 3\"\n    assert candidate(17,89) == [], \"Test 4\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "seed": 4, "perturbed": true}